problem 1.7 each of the four vertical links has an 8x36 mm uniform rectangular cross section and eash of the four pins has a 16mm diameter. determine the maximum calue of the average normal stress in the links connecting (a) points b and d, (b) points c and e.

Answer: 20-13=e

Step-by-step explanation: 20-13 is 7 so e=7 so you plug in 7 for e and which ever one makes sense, is the right answer so 20-13=e

46.53 is the Trimmed mean after removing, 20% of the trimmed mean from all the given lengths of 3-Point Kick for NCAA Division 1-A Football.

The given data is:

Lengths of 3-point kicks = 30 32 34 40 41 43 43 44 45 45 46 47 52 51 53 56 56 57 60.

Trimmed mean = 20%

The trimmed mean is defined as the statistical measure of central tendency. That means calculating the mean value of the given tendency of observations.

Trimmed observations = 20 x (20/100) = 4

These, trimmed observations denote that 2 observations must be trimmed from both sides when they are arranged in ascending order.

Ascending order of lengths =  30 32 34 40 41 43 43 44 45 45 46 47 51 52 53 56 56 57 60.

The trimmed Mean =  (34 40 41 43 43 44 45 45 46 47 51 52 53 56 56)/ 15

Trimmed mean = 698/15 = 46.53

Therefore, we can conclude that 46.53 is the Trimmed Mean after removing, 20% of the trimmed mean.

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For the first equation, -x + 3y + 2z = -8, the conditions for no solution are if a=0, b=-8, and c is not equal to 8. If a=0, b=-8, and c=8, then there will be one solution. If a does not equal 0, then there will be infinitely many solutions.

For the second equation, x + ay = 0, the conditions for no solution are if a=0, b=0, and c does not equal 0. If a=0, b=0, and c=0, then there will be one solution. If a does not equal 0, then there will be infinitely many solutions.

In both equations, the conditions for no solution involve setting the coefficients of the variables in the system to 0. If the coefficients of any of the variables in the system are set to 0, then the system will not have a solution. If two of the coefficients are set to 0, then the system will have one solution. Otherwise, there will be infinitely many solutions. This is because if all the coefficients of the variables in the system are not 0, then the system can be reduced to a simpler form, with infinitely many solutions.

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The volume of the solid generated when the region R is rotated around y = -5 is 7π/4. so the correct answer is (b).

To find the volume , we can use the method of cylindrical shells.

Consider a vertical slice of R at x = a, where a is a point on the x-axis. Let h be the height of this slice and r be the distance from the line y = -5 to the point (a, h). Then the volume of the cylindrical shell generated by rotating this slice around the line y = -5 is given by:

V(a) = 2πrh Δa

where Δa is the thickness of the slice. Note that we multiply by 2 because the slice can generate a shell both above and below the line y = -5.

To find the values of h and r in terms of x, we can use the fact that the centroid of R is (4, 3), which means that the equation of the line passing through the centroid and the point (x, h) is given by:

(y - 3) = m(x - 4)

where m is the slope of the line. Since the line passes through the point (x, h), we have:

(h - 3) = m(x - 4)

Solving for h, we get:

h = mx - (4m - 3)

To find the slope m, we can use the fact that R has area 1. Since R lies in quadrant I, we know that m > 0. Then we have:

1 = ∫[0, 4] h dx = ∫[0, 4] (mx - (4m - 3)) dx

Simplifying, we get: 1 = (1/2) m(4^2) - (4m - 3)(4)

Solving for m: m = 1/8

Substituting this into the equation for h, h = (x/8) - 11/8

To find the distance r from the line y = -5 to the point (x, h), we have:

r = h + 5 = (x/8) - 3/8

Now we can integrate V(a) over the interval [0, 4] to get the total volume:

V = ∫[0, 4] V(a) da = ∫[0, 4] 2πr(h + 5) Δa

Substituting for r and h, we get:

V = ∫[0, 4] 2π[(x/8) - 3/8][(x/8) - 11/8 + 5] Δx

Simplifying, V = π/2 ∫[0, 4] (x^2/64) - (27/64)x + 2.25 Δx

Integrating, V = π/2 [(1/192)x^3 - (27/128)x^2 + 2.25x] [0, 4]

V = (π/2) [(1/12) - (27/32) + 9]

V = 7π/4

Therefore, the volume of the solid generated when the region R is rotated around y = -5 is 7π/4. Answer: (b)

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Answer:3/4

Step-by-step explanation:Cho used 5/2

She used 13/4 to bake a loaf.

How much more is 13/4-5/2

=13-10/4

=3/4

Hope it helps!

Deal A is better if the cost of one gallon of gas under Deal A is less than $3.82.

percentage, a relative value indicating hundredth parts of any quantity.

Deal A offers % off the price of the gas. Let's say the regular price per gallon is $x. Then, the discounted price per gallon would be:

x - 0.5x = 0.5x

So, the cost of one gallon of gas under Deal A would be 0.5x.

We don't know the regular price per gallon, but we do know that the cost of % gallons under Deal A is $15.70. So, we can set up the following proportion:

% / 1 = $15.70 / 0.5x

% = 15.7 / 0.5x

Deal B offers 11 gallons of gas for $42.00. So, the cost of one gallon of gas under Deal B would be:

$42.00 / 11 = $3.82 (rounded to two decimal places)

Therefore, Deal A is better if the cost of one gallon of gas under Deal A is less than $3.82.

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Answer: The system of differential equations can be rewritten as a matrix equation:

[x', y']^T = [-4y, -6x]^T

The characteristic equation is obtained by setting the determinant of the matrix [A - λI] equal to 0, where A is the coefficient matrix, λ is an eigenvalue, and I is the identity matrix:

det([A - λI]) = det([-λ -4y; -6x, -λ]) = λ^2 + 24 = 0

Thus, λ = ±2i√6. The general solution to the system is then given by:

x(t) = c1cos(2√6t) + c2sin(2√6t)

y(t) = -2c1sin(2√6t) + 2c2cos(2√6t)

where c1 and c2 are constants determined by the initial conditions. Using the initial condition x(0) = -2, y(0) = -2, we can solve for c1 and c2:

-2 = c1cos(0) + c2sin(0)

-2 = -2c1sin(0) + 2c2cos(0)

c1 = -2

c2 = -2

So the particular solution to the system is:

x(t) = -2cos(2√6t) - 2sin(2√6t)

y(t) = 4sin(2√6t) - 4cos(2√6t)

The critical point (0,0) is a center, as the solution spirals towards the origin as t increases.

Step-by-step explanation:

We would expect approximately 132 flowers in the batch to not have eight petals.

If the probability of a flower having eight petals is 0.45, then the probability of a flower not having eight petals is 1 - 0.45 = 0.55.

So, for we to find the expected number of flowers that do not have eight petals in a randomly selected batch of 240 flowers, we have to multiply the total number of flowers (240) by the probability of a flower not having eight petals (0.55):

Expected number of flowers without eight petals = 240 × 0.55

Expected number of flowers without eight petals = 132

Therefore, we would expect approximately 132 flowers in the batch to not have eight petals.

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Answer:

10 1/4

Step-by-step explanation:

The following are the vector equations as a matrix equation.

(a)[tex]& \Rightarrow\left[\begin{array}{ccc}3 & 7 & -2 \\-2 & 3 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{c}1 \\-1\end{array}\right][/tex]

[tex]$A=\left[\begin{array}{ccc}3 & 7 & -2 \\ -2 & 3 & 1\end{array}\right][/tex] , [tex]x=\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]$[/tex] [tex]$b=\left[\begin{array}{c}1 \\ -1\end{array}\right]$[/tex]

(b) [tex]$\Rightarrow\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right]\left[\begin{array}{c}x_1 \\ x_2\end{array}\right]=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

[tex]$A=\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right][/tex], [tex]x = \left[\begin{array}{l}x_1 \\ x_2\end{array}\right]$[/tex] [tex]$b=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

(c) [tex]$\Rightarrow\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right]\left[\begin{array}{c}x_1 \\ x_2\end{array}\right]=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

[tex]$A=\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right][/tex], [tex]x = \left[\begin{array}{l}x_1 \\ x_2\end{array}\right]$[/tex] [tex]$b=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

(d) [tex]& \Rightarrow\left[\begin{array}{ccc}1 & 1-2 & 1 \\0 & 2 & -8 \\-4 & 5 & 9\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{c}0 \\8 \\-9\end{array}\right][/tex]

[tex]A=\left[\begin{array}{ccc}1 & 1-2 & 1 \\0 & 2 & -8 \\-4 & 5 & 9\end{array}\right], x=\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right] x[/tex] [tex]b=\left[\begin{array}{c}0 \\8 \\-9\end{array}\right] \\[/tex]

As per the given data here we have to determine each of the following vector equations as a matrix equation.

That means we have write them in the form of matrix equation that is in the form of Ax = b

a)

[tex]3 x_1+7 x_2-2 x_3=1 \\[/tex]

[tex]-2 x_1+3 x_2+1 x_3=-1[/tex]

Write the equations in the matrix form

[tex]& \Rightarrow\left[\begin{array}{ccc}3 & 7 & -2 \\-2 & 3 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{c}1 \\-1\end{array}\right][/tex]

This is in the form of  Ax = b .

Here, [tex]$A=\left[\begin{array}{ccc}3 & 7 & -2 \\ -2 & 3 & 1\end{array}\right][/tex] , [tex]x=\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]$[/tex] and [tex]$b=\left[\begin{array}{c}1 \\ -1\end{array}\right]$[/tex]

b)

[tex]& 3 x_1+5 x_2=2 \\[/tex]

[tex]& -2 x_1+0 x_2=-3 \\[/tex]

[tex]& 8 x_1+9 x_2=8[/tex]

Write the equations in the matrix form

[tex]$\Rightarrow\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right]\left[\begin{array}{c}x_1 \\ x_2\end{array}\right]=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

This is in the form of Ax = b.

Here, [tex]$A=\left[\begin{array}{cc}3 & 5 \\ -2 & 0 \\ 8 & 9\end{array}\right][/tex], [tex]x = \left[\begin{array}{l}x_1 \\ x_2\end{array}\right]$[/tex] and [tex]$b=\left[\begin{array}{c}2 \\ -3 \\ 8\end{array}\right]$[/tex]

(c)

[tex]& x_1-3 x_2+5 x_3=1 \\[/tex]

[tex]& -x_2+3 x_4=7 \\[/tex]

[tex]& \Rightarrow 0 x_1-x_2+0 x_3+3 x_4=7 \\[/tex]

Write the equations in the matrix form

[tex]& \Rightarrow\left[\begin{array}{llll}1 & -3 & 5 & 0 \\0 & -1 & 0 & 3\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3 \\x_4\end{array}\right]=\left[\begin{array}{l}1 \\7\end{array}\right][/tex]

This is in the form of Ax = b

Here, [tex]} A=\left[\begin{array}{llll}1 & -3 & 5 & 0 \\0 & -1 & 0 & 3\end{array}\right], x=\left[\begin{array}{l}x_1 \\x_2 \\x_3 \\x_4\end{array}\right][/tex] and [tex]b=\left[\begin{array}{l}1 \\7\end{array}\right] \\&\end{aligned}$$[/tex]

d)

[tex]& x_1-2 x_2+x_3=0 \\[/tex]

[tex]& 2 x_2-8 x_3=8 \\[/tex]

[tex]& -4 x_1+5 x_2+9 x_3=-9 \\[/tex]

Write the equations in the matrix form

[tex]& \Rightarrow\left[\begin{array}{ccc}1 & 1-2 & 1 \\0 & 2 & -8 \\-4 & 5 & 9\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{c}0 \\8 \\-9\end{array}\right][/tex]

This is in the form of Ax = b

Here, [tex]A=\left[\begin{array}{ccc}1 & 1-2 & 1 \\0 & 2 & -8 \\-4 & 5 & 9\end{array}\right], x=\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right] x[/tex] and [tex]b=\left[\begin{array}{c}0 \\8 \\-9\end{array}\right] \\[/tex]

Therefore all the vector equations are written as a matrix equations

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The area of a square with side length 2 inches greater than the area of a circle with radius 1.2 inches.

Area is the entire amount of space occupied by a flat (2-D) surface or an object's shape. The area of a plane figure is the area that its perimeter encloses. The quantity of unit squares that cover a closed figure's surface is its area.

Given:

Area of Square = side x side

we have side = 2 inches

So, Area of Square = side x side

                                = 2 x 2

                                = 4 inch²

and, Area of Circle = πr²

We have radius = 1.2 inch

So, Area of Circle = 3.14 x (1.2)²

                              = 4.5216 inch²

So, Area of Square is greater than Area of Circle.

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Answer:

y

a= ——

(r + 1 )t

Step-by-step explanation:

divide both sides

The argument provided by Johannes Kepler is deductive.

This is because it uses a logical inferential link between the premises and the conclusion. Kepler presents two premises. The first premise states that the daily movement which is common to both the planets and the fixed stars is seen to travel from the east to the west. The second premise states that the far-slower single movements of the single planets travel in the opposite direction from west to east. Kepler then draws the conclusion that these movements cannot depend on the common movement of the world but should be assigned to the planets themselves.

Kepler's argument does not contain any indicator words that are commonly used in inductive arguments, such as "probably," "usually," or "likely." Instead, the argument is based on the logical connection between the premises and the conclusion. Kepler is using deductive reasoning to draw a certain conclusion from the premises that he presents. Thus, the argument is best interpreted as being deductive.

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The argument is deductive.

The deductive nature of the argument is demonstrated by the inferential link between the premises and conclusion. The premises state that the apparent daily movement of both the planets and fixed stars is from east to west, and the single movements of the planets travel from west to east. The conclusion follows deductively from these premises, as Kepler asserts that the movements of the planets cannot depend on the common movement of the world and must instead be assigned to the planets themselves.

There are no indicator words in the argument that explicitly signal inductive reasoning. Instead, the argument is based on deductive reasoning, with the premises providing evidence that supports the conclusion in a logically necessary way.

The argument is deductive.

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The mass of the drug in the organ at time t depends on the concentration of the drug in the blood entering the organ and the rate at which the blood is entering and leaving the organ. This can be calculated by multiplying the volume of the organ by the concentration of the drug in the blood.

At time t, since the rate at which the blood is entering and leaving the organ is 3 cm^3/sec, the amount of drug in the organ is equal to the amount of drug entering the organ plus the amount of drug that was initially in the organ. As there was no trace of the drug initially, the mass of the drug in the organ at time t is 3 cm^3/sec multiplied by the concentration of the drug in the blood (1/3 gm/cm3) multiplied by the volume of the organ (150 cm^3).

Therefore, the mass of the drug in the organ at time t is 150 gm.

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Multiply 84,000 by 0.6 thus the answer is 50,400

(a) Solving initial value problem, P(t) = (1/k) [(kPo + M)e^(kt) - M]

(b)To keep P(t) constant and equal to Po, k must be negative and M must be positive.

(a) To solve the initial value problem:

dP/dt = kP + M, P(0) = Po

We can rewrite the differential equation as:

dP/(kP + M) = dt

Integrating both sides, we get:

(1/k) ln|kP + M| = t + C

where C is a constant of integration. Solving for P, we get:

P(t) = (1/k) (e^(k(t+C)) - M/k)

To find the value of C, we use the initial condition P(0) = Po:

Po = (1/k) (e^(kC) - M/k)

Solving for C, we get:

C = (1/k) ln(kPo + M) - (1/k) ln|kPo|

Substituting this back into the expression for P(t), we get:

P(t) = (1/k) [(kPo + M)e^(kt) - M]

(b) To determine the conditions under which P(t) remains constant and equal to Po, we set P(t) = Po and solve for k and M:

Po = (1/k) [(kPo + M)e^(kt) - M]

Simplifying and rearranging, we get:

(k - 1)e^(kt) = M/Po

If k = 1, then we get 0 = M/Po, which is impossible unless M = 0 (i.e., there is no migration). Therefore, we assume k ≠ 1.

Taking the natural logarithm of both sides, we get:

kt + ln(k - 1) = ln(M/Po)

Solving for k, we get:

k = [ln(M/Po) - ln(k - 1)]/t

To keep P(t) constant and equal to Po, k must be negative (i.e., P(t) is decreasing) and M must be positive (i.e., there is net migration into the population). Physically, this makes sense because if the migration rate is positive, then more individuals are entering the population than leaving, which will tend to increase the population size. Conversely, if the growth rate k is negative, then the population is decreasing in the absence of migration, so the positive migration rate can counteract this decrease and maintain a constant population size.

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By rearranging the given lines of code, we have created a method that takes in the width and height of a balloon and calculates its volume using the formula for the volume of an ellipsoid.

To start, we need to import the Scanner class from the Java.util package, as we will be taking input from the user. Then, we define a public class called "Balloon" and initialize a variable "c" to be half the value of the width input.

Next, we create the method "balloonVolume" which takes in two parameters: width and height. We specify that width is the horizontal diameter of the balloon and height is the vertical diameter of the balloon. We then set two variables, "a" and "b" to be half the value of width and height respectively.

Using the formula for the volume of an ellipsoid, which is V = 4/3 * pi * a * b * c, we calculate the volume of the balloon and store it in the variable "volume." Finally, we return the volume.

In the main method, we create a Scanner object and prompt the user to input the width and height of the balloon. We then call the "balloonVolume" method and pass in the user's input as arguments. The method calculates the volume of the balloon and returns it, which we can then print out to the user.

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The measure of angle ∠2 will be 111° by the supplementary property.

Lines are straight with little depth or width. Perpendicular lines, intersecting lines, transversal lines, and other types of lines will be covered. An angle is a shape formed by two rays emerging from a common point. In this field, you may also come across alternate and corresponding angles.

Supplementary angles are those that total 180 degrees. Angles 130° and 50°, for example, are supplementary angles because the sum of 130° and 50° equals 180°.

The value of the angle will be calculated as,

∠2 = 180 - 69

∠2 = 111°

Therefore, the value of the ∠2 is 111°.

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The number of students that speak  both French and Spanish are 7 students, 24 students speak French only, and 16 students speaks Spanish only.

To solve this problem, we can use the formula for the size of a union of two sets:

|A ∪ B| = |A| + |B| - |A ∩ B|,

where |A| represents the number of elements in set A.

Let F be the set of students who speak French, S be the set of students who speak Spanish, and N be the set of students who speak neither language. Then, we have:

|F| = 31,

|S| = 23,

|N| = 14.

We want to find the number of students who speak both French and Spanish, as well as the number who speak French only and the number who speak Spanish only. Let B be the set of students who speak both French and Spanish, F-only be the set of students who speak French only, and S-only be the set of students who speak Spanish only. Then:

|B| = (unknown),

|F-only| =  (unknown),

|S-only| =  (unknown).

We know that the total number of students is 60, so:

|F ∪ S ∪ N| = 60.

Using the formula for the size of a union, we get:

|F ∪ S ∪ N| = |F| + |S| + |N| - |F ∩ S| - |(F ∩ N) ∪ (S ∩ N)|.

We can simplify this expression using the fact that |N| = |(F ∩ N) ∪ (S ∩ N)|, since the sets (F ∩ N) and (S ∩ N) are disjoint:

60 = 31 + 23 + 14 - |B| - |N|.

|N| = 14.

Substituting |N| = 14, we get:

|B| = |F ∩ S| - 9.

So, to find |B|, we need to determine |F ∩ S|. We can use the formula for the size of an intersection:

|F ∩ S| = |F| + |S| - |F ∪ S|.

Substituting the known values, we get:

|F ∩ S| = 31 + 23 - |F ∪ S|.

|F ∪ S| = 31 + 23 - |F ∩ S|.

|F ∪ S| = 54 - |B|.

Substituting this into the expression for |F ∪ S ∪ N|, we get:

60 = 31 + 23 + 14 - |B| - 14 - |B|.

2|B| = 54 - 31 - 23 + 14 = 14.

|B| = 7.

So there are 7 students who speak both French and Spanish.

To find |F-only| and |S-only|, we can use the following formulas:

|F-only| = |F| - |B|,

|S-only| = |S| - |B|.

Substituting the known values, we get:

|F-only| = 31 - 7 = 24,

|S-only| = 23 - 7 = 16.

Therefore, there are 7 students who speak both French and Spanish, 24 students who speak French only, and 16 students who speak Spanish only.

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I got this answer off of

The difference in the areas of the pizza pies will be 40.82 square inches.

It is the close curve of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

Let d be the diameter of the circle. Then the area of the circle will be

A = (π/4)d² square units

Then the difference in the areas of the pizza pies is given as,

A = (π/4) {14² - 12²}

A = (3.14 / 4) x (196 - 144)

A = 0.785 x 52

A = 40.82 square inches

The difference in the areas of the pizza pies will be 40.82 square inches.

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Step-by-step explanation:

P(A | B) = P(AꓵB)/P(B) = 3/8 / 7/8 = 3/8 × 8/7 = 3/7

1 meter = 1.094 yard create a conversion factor to convert meters to yards.

Any instrument that detects and may store an electric or magnetic amount, such voltage or current, is referred to as a meter. Examples of meters include an ammeter and a voltmeter. One may refer to using this kind of device as "metering" or one could state that the volume being measured is now being "metered".

The yard (symbol: yd) is just an English unit of length that is equal to 3 feet or 36 inches according to the British imperial and American customary systems of measurement. According to an international agreement, it has been exactly regulated to 0.9144 metres since 1959. precise 0.9144 meters. One mile is 1,760 yards in length. One mile is 1,760 yards in length.

Given

[tex]1 yard=0.914 meter[/tex]

Create a convert meter to yard expression

[tex]1 yard=0.914 meter[/tex]

Divide both side by 0.914

[tex]\frac{1yard}{0.914} =\frac{0.914 meter}{0.914}[/tex]

[tex]\frac{1 yard}{0.914}= 1meter[/tex]

[tex]1.09409190372=1meter[/tex]

[tex]1meter=1.09409190372 yard[/tex]

[tex]1meter = 1.094 yard[/tex] Approx.

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Answer: The equation that represents this proportional relationship is D: 2/3w = 2h.

To find the average rate of change of a function on a given interval, we can calculate the difference between the values of the function at the endpoints of the interval, and divide it by the difference between the values of the independent variable (in this case x) at the endpoints of the interval.

For the function y = 1/x on the interval [1, 3], we can use this method to find the average rate of change:

y(3) - y(1) = 1/3 - 1 = -2/3

x(3) - x(1) = 3 - 1 = 2

Average rate of change = (y(3) - y(1)) / (x(3) - x(1)) = (-2/3) / 2 = -1/3

So, the average rate of change of the function y = 1/x on the interval [1, 3] is -1/3.

Step-by-step explanation:

Answer:

high BBC dry GB by in just he just had not had on

Step-by-step explanation:

no exception

This bar-interval graph suggests that there may be a difference in response rate between the three colors of paper. For a 90% confidence interval, the critical value is 1.64. Number of observations  n = 15 and number of groups k = 3, so the degrees of freedom is n-k = 15-3 = 12.

A bar-interval graph of the estimated factor level means can be created as follows:

Calculate the mean response rate for each color of paper:

Blue: (28 + 26 + 31 + 27 + 35)/5 = 30%

Green: (34 + 29 + 25 + 31 + 29)/5 = 29.4%

Orange: (31 + 25 + 27 + 29 + 28)/5 = 28%

Calculate the standard deviation for each color:

Blue: [tex]\sqrt{(((28-30)^2 + (26-30)^2 + (31-30)^2 + (27-30)^2 + (35-30)^2)/4)} = \sqrt{(6.8)} = 2.6[/tex]

Green: [tex]\sqrt{(((34-29.4)^2 + (29-29.4)^2 + (25-29.4)^2 + (31-29.4)^2 + (29-29.4)^2)/4)} = \sqrt{(11.96)} = 3.4[/tex]

Orange: [tex]\sqrt{(((31-28)^2 + (25-28)^2 + (27-28)^2 + (29-28)^2 + (28-28)^2)/4)} = \sqrt{(6)} = 2.4[/tex]

Calculate the standard error for each color:

Blue: 2.6/[tex]\sqrt{(5)}[/tex] = 1.5

Green: 3.4/[tex]\sqrt{(5)}[/tex] = 1.9

Orange: 2.4/[tex]\sqrt{(5)}[/tex] = 1.3

Calculate the 95% confidence interval for each color:

Blue: [30 - 1.96 * 1.5, 30 + 1.96 * 1.5] = [26.9, 33.1]

Green: [29.4 - 1.96 * 1.9, 29.4 + 1.96 * 1.9] = [25.2, 33.6]

Orange: [28 - 1.96 * 1.3, 28 + 1.96 * 1.3] = [25.4, 30.6]

This bar-interval graph suggests that there may be a difference in response rate between the three colors of paper. The 95% confidence interval for the mean response rate of blue paper does not overlap with the confidence intervals of the green or orange paper, which suggests that there is a significant difference in response rate between the colors.

To estimate the mean response rate for blue questionnaires with a 90% confidence interval, we can use the same calculations as above, but use a different critical value for the standard normal distribution. For a 90% confidence interval, the critical value is 1.64. The 90% confidence interval for the mean response rate of blue questionnaires is [30 - 1.64 * 1.5, 30 + 1.64 * 1.5] = [27.3, 32.7].

To test whether or not D = M3 - M2 = 0, we can use a t-test with n-k degrees of freedom, where n is the number of observations and k is the number of groups. In this case, n = 15 and k = 3, so the degrees of freedom is n-k = 15-3 = 12. The null hypothesis is H0: D = 0 and the alternative hypothesis is Ha: D ≠ 0. The decision rule is to reject.

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____ The given question is incomplete, the complete question is given below:

a. Prepare a bar-interval graph of the estimated factor level means Y. where the interval correspond to the confidence limits with a = .05. What does this plot suggest about the effect of color on the response rate? Is your conclusion in accord with the test result?

b. Estimate the mean response rate for blue questionnaires: use a 90 percent confidence interval.

c. Test whether or not D = M3-u2 = 0: use a = .10. State the alternatives, decision rule, and conclusion. In light of the result for the ANOVA test e, is your conclusion surprising? Explain.

In an experiment to investigate the effect of color of paper (blue, green, orange) on response rates for questionnaires distributed by the "windshield method" in supermarket parking lots, 15 representative supermarket parking lots were chosen in a metropolitan area and each color was assigned at random to five of the lots. The response rates (in percent) follow. Assume that ANOVA model is appropriate. i 1 2 3 4 5 1 Blue 28 26 31 27 35 2 Green 34 29 25 31 29 3 Orange 31 25 27 29 28

When two variable quantities have a constant ratio, their relationship is called a direct variation. It is said that one variable varies directly as the other. The formula for direct variation is

y

=

k

x

, where

k

is the constant of variation.

y

=

k

x

Solve the equation for

k

, the constant of variation.

k

=

y

x

Replace

x and ywith the values.k=−42Divide −4by 2.k=−2Use the formula y=kxto substitute −2for k and −6for x.y=(−2)⋅(−6)Multiply −2by −6.y=12

The Fraction 9/18 should be multiplied by 1/4 to get the value Equivalent to 9/18 ÷ 2.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

We have to solve,

9/18 ÷ 2

As, Fraction does not support the division as usually number does.

So, we have to perform the multiplication by reciprocating the number,

9/18 x 1/2

= 9/ 36

= 1/4

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Answer:

12

Step-by-step explanation:3/6 is 1/2 when u simplify it. Then u divide 24 in half and get 12