Point O is the center of the circle.

Circle O is shown. Tangents D C and B C intersect at point C outside of the circle. Lines are drawn from points D and point B to center point O to form a quadrilateral. A line is drawn from point C to point A on the opposite side of the circle. The length of O D is 6, and the length of B C is 8. Angles D and B are right angles.

What is the perimeter of quadrilateral DOBC?

14 units
16 units
22 units
28 units

Answer:

The word for the blank would be "square".

Step-by-step explanation:

Since the area of a face of a cube would be square its side length, the total surface area of a cube would be that times 6.

Hope this helped!

Answer:

square

Step-by-step explanation:

the area of a cube is found by squaring the length

Answer:

[tex]18cm[/tex]

Step-by-step explanation:

A of triangle =

[tex] \frac{1}{2} bh[/tex]

[tex] \frac{1}{2} \times 9 \times 8[/tex]

[tex] = 36cm2[/tex]

A of square=

[tex]s2[/tex]

[tex]36 = s2[/tex]

[tex] \sqrt{36cm2} = \sqrt{s2} [/tex]

[tex]18cm = s[/tex]

Answer:

0.43 seconds

Step-by-step explanation:

Given Data

Initial height= 4feet

initial velocity u= 30ft per second

Final height = 17 feet

The distance travelled is the

Final-initial height

=17-4

=13ft

Hence the time taken is calculated using the expression below

Speed= distance/time

30=13/t

t= 13/30

t= 0.43 seconds

Hence the time taken is 0.43 seconds

Answe

Đáp án: A

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

The Richter scale measures the magnitude, M, of an earthquake as a function of its intensity, I, and the intensity of a reference earthquake, . Which equation could be used to find the intensity of an earthquake with a Richter scale magnitude of 4.8 in reference to an earthquake with an intensity of 1?

Solution:

The Richter magnitude scale was developed in 1935 by Charles F. Richter. The Richter scale is used to measure the strength of earthquakes.

The magnitude of an earthquake (M) using a Richter scale is given by:

[tex]M=log(\frac{I}{I_o} )\\\\Where\ I\ is\ the\ intensity\ of\ the \ earthquake,I_o\ is \ the\ intensity\ of\\the\ reference\ earthquake.\\\\Given\ that\ M=4.8,I_o=1.\ Hence:\\\\4.8=log(\frac{I}{1} )\\\\4.8=log(I)\\\\I=e^{4.8}\\\\I = 121.5[/tex]

Answer:

Q19 - x = 7

Q20 - x = 24

Step-by-step explanation:

Q19.

75 + x + 8 = 90°

83 + x = 90°

x = 90 - 83

x = 7

{CHECK: 75 + 7 + 8 = 90°}

Q20.

3x - 6 + x = 90°

4x - 6 = 90°

4x = 96

x = 96 / 4

x = 24

{CHECK: 3(24) - 6 + 24 = 90°}

hope this helps...

have a great day ahead ;)

Answer:

code = 56

Step-by-step explanation:

E = GCF(22,30) = 2

F = LCM(3,8) = 24

Given

3 * (7+10) = G +30 => 51 = G + 30 => G = 21

5 * (3+H) = 15 + 45 => 3+H = (60/5)  = 12 => H = 12 - 3 = 9

Sum E + F + G + H = 2 + 24 + 21 + 9 = 56

Answer:

code would be 56

Step-by-step explanation:

hope this helps mate !

Answer:

10

Step-by-step explanation:

a^2+b^2=c^2

9^2+3^2=c^2

81+9=c^2

100=c^2

c=10

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {√7}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex] =\frac{7}{ \sqrt{7} }\\ [/tex]

[tex] = \frac{7}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} }\\ [/tex]

[tex] = \frac{7 \sqrt{7} }{ \sqrt{7} \times \sqrt{7} }\\ [/tex]

[tex] = \frac{7 \sqrt{7} }{7}\\ [/tex]

[tex](∵ \sqrt{a} \times \sqrt{a} = a)\\[/tex]

[tex] = √7[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]

Step-by-step explanation:

Given,

7/√7

The denominator is √7.

We know that

Rationalising factor of √a is √a.

Therefore, the rationalising factor of √7 is √7.

On rationalising the denominator them

=> (7/√7) × (√7/√7)

=> 7(√7)/(√7 × 7)

=> 7√7/7.

Hence, the denominator is rationalised.

Answer:

x = log 2 / log 3

x=0.63092

Step-by-step explanation:

3^×=2

Take the log of each side

log 3^×= log2

We know that log a^b = b log a

x log 3 = log 2

Divide each side by log 3

x = log 2 / log 3

x=0.63092

Answer:

x ≈ 0.63093

Step-by-step explanation:

[tex] \small \sf \: 3 {}^{x} = 2[/tex]

Take the log of both side

[tex] \small \sf \: log 3 {}^{x} = log 2[/tex]

Use log a( a ^ x ) = x to simplify the equation

x log 3 = log 2

Divide each side by log 3

x = log 2 / log 3

x ≈ 0.63093

Answer:

A

Step-by-step explanation:

first graph

Answer:

A

Step-by-step explanation:

first graph

Answer

MULTIPLY 2.2 & 5.5

Step-by-step explanation:

Answer:

44

Step-by-step explanation:

substitute the 7 into the equation for x

f(x) = [tex]x^{2}[/tex] - 5

f(7)  = [tex]7^{2}[/tex] - 5

f(7) = 49 - 5

f(7) = 44

Answer:

f(7) = 44

Step-by-step explanation:

To evaluate the function f(x)=x^2-5 at x = 7, replace each instance of 'x' in this function by 7:

f(7) = 7^2 - 5 = 49 - 5 = 44

So:  f(7) = 44

Answer and Step-by-step explanation:

We're given an isosceles triangle, because it says the two side are congruent. That means the base pairs are congruent as well, meaning the other angle (not x) is 75.

We know that the sum of a triangle's angles is 180, so if we subtract the known angles, we can find x.

180 - 75 - 75 = x

30 = x

So, x = 30.

#teamtrees #PAW (Plant And Water)

We know that a triangles full degree is 180 and we can see that this triangle is symmetrical. So first you add 75 to 75 and get 150, then you subtract 150 from 180 and get 30.

x=30

Can I please have a brainliest? I want to rank up

Answer:

43º

Step-by-step explanation:

complementary angles total 90

(2x - 13) + (4x - 5) = 90

Combine like terms

6x - 18 = 90

6x = 72

x = 12

ZB = 4x - 5

ZB = 4(12) - 5

ZB = 43º

Answer:

Option D.

Step-by-step explanation:

Remember the Pythagorean theorem.

For a triangle rectangle of catheti A and B, and hypotenuse H, we have:

A^2 + B^2 = H^2

Now, also remember that for a square of sidelength L the area is:

area = L^2

First, you can see that square 1 has a side length equal to one of the catheti, and the same for square 2. While square 3 has a side lenght equal to the hypotenuse of the triangle.

If we define:

A = length of the smaller cathetus

then the area of square 1 is:

A^2

B = length of the larger cathetus.

The area of square 2 is then:

B^2

H as the length of the hypotenuse:

The area of square 3 is:

H^2

And by Pythagorean theorem we know that:

A^2 + B^2 = H^2

We can replace these by:

area of square 1 + area of square 2 = area of square 3.

Then the correct option is D.

Answer:

8

Step-by-step explanation:

count up from where s is (-7) to where v is (1) there are 8 numbers in between them. making that he length

Answer:

S= -7 to V= 1 so your answer is 8

Answer:

A square has all its four sides equal. So the length of one side is equal to the perimeter devided by four

Answer:

9 yards

Step-by-step explanation:

A square has 4 congruent sides

Given the perimeter, the sum of the 4 sides is 36 yards, then

length of side = 36 ÷ 4 = 9 yards

Refer to the pic ...(◕ᴗ◕✿)✌️✌️

Answer:

A. [tex](-1,-2)[/tex]

Step-by-step explanation:

Hope this helps you.

( -4, 1 ) and ( 2 , -5 )

Now,

mid point = ( 2 - 4 )/2 , ( -5 + 1 )/2

= ( -2 /2 ) , ( -4 /2)

= ( - 1, - 2 )

A ( - 1, - 2 )

I hope it's help you...

Mark me as brainliest...

Answer:

Step-by-step explanation:

sorry dont know ut

Answer:

c

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

12k^5 +24k⁴+30k³

Step-by-step explanation:

the area = 6k³(2k²+4k+5)

= 12k^5 +24k⁴+30k³

Answer:

35

Step-by-step explanation:

Perimeter of LMK = 14 + 11 + 17

Perimeter of LMK = 42

Perimeter GHJ/ Perimeter LMK = 5/6

Perimeter GHJ / 42 = 5/ 6                      Cross Multiply

6*Perimeter GHJ = 42 * 5

6*Perimeter GHJ = 210                           Divide by 6

Perimeter GHJ = 210/6

Perimeter GHJ = 35

Answer:

4 =x

Step-by-step explanation:

5 + 3x = 8x - 15

Subtract 3x from each side

5 + 3x-3x = 8x-3x - 15

5 = 5x -15

Add 15 to each side

5+15 = 5x -15+15

20 = 5x

Divide each side by 5

20/5 = 5x/5

4 =x

Answer:

Width = w

Length = 4w + 6

Area = 130 in2

Area = W X L = 130

So, w X (4w + 6) = 130

4w2 + 6w = 130  by distributing

-130           -130

4w2 + 6w - 130 = 0

Step-by-step explanation:

Answer:

Area = 6L² - 4L

Step-by-step explanation:

Let length be L

Given Width, w is 4 less than 6 times length :

That is ,

6 times length = 6 L

4 less than 6 times length means = 6L - 4

Therefore Length  =  L

               Width = 6L - 4

Area = Length x Width

       = L x ( 6L - 4)

       = 6L² - 4L