Plz help me I am timed
The Great Plains are also referred to as
a. marshes
b. lowlands
c. interior plains
d. plateaus

Answer:

1.204 g/mL

Explanation:

Step 1: Given data

Mass of the unknown liquid (m): 36.185 g

Volume of the unknown liquid (V): 30.05 mL

Step 2: Calculate the density of the unknown liquid

The density is an intrinsic property, which can help to identify an unknown substance. It is equal to the mass divided by the volume.

ρ = m / V

ρ = 36.185 g / 30.05 mL

ρ = 1.204 g/mL

The given question is incomplete. The complete question is:

A chemist adds 245.0 ml 0.0238 M of a aluminum chloride solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to two significant digits.

Answer: The millimoles of aluminum chloride are 5.8

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = milli moles of solute

[tex]V_s[/tex] = volume of solution in ml

Now put all the given values in the formula of molarity, we get

[tex]0.0238=\frac{n}{245.0}[/tex]

[tex]n=5.8[/tex]

Therefore, the millimoles of aluminum chloride are 5.8

Answer:the answer is B , the transform boundary

Explanation:

Answer:

Science is really reliable because there is research and math and brains. Actual science are results from experiments, so it's mainly always correct.

Explanation:

Answer:

Net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

44.9% as AgNO₃

Explanation:

When sodium nitrate, NaNO₃ and silver nitrate, AgNO₃ are dissolved in water, the Na⁺, NO₃⁻ and Ag⁺ ions are formed.

Then, the addition of NaCl (Na⁺ and Cl⁻) produce AgCl⁻ as precipitate. The net ionic equation is:

If 2.54g of AgCl are formed and represents the 95.9% of yield. The real amount of AgCl is:

2.54g AgCl * (100% / 95.9%) = 2.65g AgCl.

In moles (Molar mass AgCl = 143.32g/mol):

2.65g AgCl * (1mol / 143.32g) = 0.0185 moles of AgCl = Moles of AgNO₃

Because all Ag comes from AgNO₃

Thus, the original mass of silver nitrate and its precentage is (Molar mass AgNO₃ = 169.87g/mol):

0.0185 moles AgNO₃ * (169.87g / mol) = 3.14g of AgNO₃

Percentage:

3.14g AgNO₃ / 7.00g * 100 =  

Answer:

[tex]C. \: Helps \: the \: body \: absorb \: sugary \: food.[/tex]

Answer:

The moles of ammonia present in a 1.284 g sample are 0.075.

Explanation:

Molar mass is the mass of one mole of a substance, which can be an element or a compound. If the molar mass of ammonia is 17,030 g / mol, then in 1 mole of ammonia there are 17,030 g.

So, in this case, the following rule of three can be applied: if by definition of molar mass in there are 17.030 g in 1 mole of ammonia, 1.284 g of ammonia in how many moles will it be?

[tex]moles=\frac{1.284 g*1 mole}{17.030 g}[/tex]

moles=0.075

The moles of ammonia present in a 1.284 g sample are 0.075.

Answer:

. there are no lone pairs of electrons on the central atom.

Explanation:

According to the Valence Shell Electron Pair Repulsion  (VSEPR) thoery, the shape of a molecule is determined by the number of electron pairs present on the valence shell of the central atom in the molecule.

The number of electron pairs ultimately determines how they will be arranged in space. However, the presence of lone pairs on the central atom causes a greater repulsion of electron pairs and a consequent deviation of the molecular geometry from that predicted by the VSEPR theory. Hence the answer

Answer:

Mass = 14.7 g

Explanation:

Given data:

Mass in g =?

Moles of K = 0.375 mol

Solution:

The Molar mass of potassium is 39.1 g/mol.

Formula

Number of moles = mass/molar mass

Mass = Number of moles × molar mass

Mass = 0.375 mol × 39.1 g/mol

Mass = 14.7 g

14.7 g K

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

0.375 mol K

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

14.6625 g K ≈ 14.7 g K

Answer:

complimentary

Explanation:

Answer:

Proximal

Explanation:

0.1621 mol FeCl₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Compounds

Atomic Structure

Step 1: Define

26.29 g FeCl₃ (iron (III) chloride)

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of FeCl₃ - 55.85 + 3(35.45) = 162.2 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

0.162084 mol FeCl₃ ≈ 0.1621 mol FeCl₃

I don't know what you mean by the question, but in science it is Newton's second law.

"The second law explains how the velocity of an object changes when it is subjected to an external force."

I hope this helped!+*♡

Answer: the relationship between temperature and volume

Explanation:

Answer:

Explanation:

C

[tex]4.9 \times 10^{23}[/tex]  are present in 18.4L of argon (Ar).

To calculate the amount of particles present in a given amount of volume, it is necessary to have knowledge of the molar volume:

                                          [tex]1 mol = 22.4L[/tex]

Thus, in 22.4L there is 1 mol of an element, remembering that:

                                   [tex]1 mol = 6\times10^{23}[/tex] particles

In this way, it is enough to relate the value of the molar volume given with the value requested by the question:

                                     [tex]\frac{6\times10^{23}particles}{xparticles} = \frac{22.4L}{18.4L}[/tex]

                                    [tex]x = 4.9 \times 10^{23}[/tex] particles

 So, [tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).

Learn more about mole calculation in: brainly.com/question/15209553

Answer:

the answer is 11.111 and when you round it to the nearest one it’s 11, but to the nearest tenth it’s 10

Explanation:

Answer:  

Here is a picture of all the elements

Answer:

The periodic table is a tabular array of the chemical elements organized by atomic number, from the element with the lowest atomic number, hydrogen, to the element with the highest atomic number, oganesson. The atomic number of an element is the number of protons in the nucleus of an atom of that element.

Explanation:

PLEASE MARK ME AS BRAINLIEST

Answer:

b.oil

Explanation:

oil is a nonrewnewable resource

Answer:

[tex]M_{acid}=0.075M[/tex]

Explanation:

Hello!

In this case, since the reaction between NaOH and HNO3 is:

[tex]NaOH+HNO_3\rightarrow NaNO_3+H_2O[/tex]

Whereas there is a 1:1 mole ratio between the acid and base, thus, we can write:

[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]

In such a way, solving for the concentration of the acid, HNO3, we obtain:

[tex]M_{acid}=\frac{M_{base}V_{base}}{V_{acid}}[/tex]

Therefore, by plugging in we obtain:

[tex]M_{acid}=\frac{0.12L*0.2M}{0.32L}\\\\ M_{acid}=0.075M[/tex]

Best regards!

Answer:

700,000 holes

Explanation:

When heat energy occurs to produce free electrons, the number of free electrons produced is directly proportional and equal to the number of holes it produces at that time.

Hence, if silicon crystal (pure) has 700,000 free electrons, then the number of holes it have is also 700,000.

The given question is incomplete. The complete question is :

Which of the following Group 17 elements is the least reactive

a) Flourine

b) Chlorine

c) Astatine

d) Iodine

Answer: c) Astatine

Explanation:

Halogen is the name given to Group 17 family with general electronic configuration of [tex]ns^2np^5[/tex] which have 7 valence electrons and thus easily gain one electron to attain stable configuration.

As we move down the group from flourine to chlorine to bromine to iodine to astatine , the valence shell moves farther from nucleus and thus tendency to accept the electron decreases and thus reactivity also decreases.

Thus Astatine is the least reactive of all.

Answer:

2.00x10⁵L

Explanation:

...That contains 125g of mercury(I) chloride...

The molarity, M, of a solution represents the moles of solute (Mercury(I) chloride), per liter of solution.

To solve this question, we need to determine the moles of mercury(I) chloride present in 125g. Then, with molarity, we can find the volume of the solution:

Moles Mercury(I) chloride -Molar mass: 271.52g/mol-:

125g * (1mol / 271.52g) = 0.460 moles

Volume:

0.460 moles * (1L / 2.3x10⁻⁶mol) =

Answer:

V = 3.1 L      

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L         (M = mol/L)

Answer:

Space

Explanation:

Sound waves can't travel through space but radiant energy from the sun can, which is how it reaches Earth.

Answer:

D) Gastropod

Explanation:

It's higher classification is Mollusca on go o gle

Answer:

Invertebrates than eventually everything would die

Answer:

[tex]Kp=9.2x10^{-3}[/tex]

Explanation:

Hello!

In this case, for the undergoing chemical reaction at equilibrium:

[tex]2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)[/tex]

Which means that pressure-based equilibrium constant is computed via the following equilibrium expression:

[tex]Kp=\frac{p_{SO_3}^2}{p_{SO_2}^2p_{O_2}}[/tex]

Thus, by plugging in the given pressures at equilibrium, the required Kp turns out:

[tex]Kp=\frac{55.0^2}{70.2^2*66.7}\\\\Kp=9.2x10^{-3}[/tex]

Best regards!

Answer:

0.748M

Explanation:

Molarity is defined as the ratio between moles of solute (The substance in the lower amount, ethanol) and liters of solution.

To solve the problem we need to convert the mass of ethanol to moles using its molar mass and the mL of solution to liters:

Moles ethanol:

molar mass:

C₂H₆O:

2C = 2*12g/mol = 24g/mol

6H = 6*1g/mol = 6g/mol

O = 16g/mol

Molar mass: 24 + 6 + 16 = 46g/mol

Moles are:

17.2g * (1mol / 46g) = 0.374 moles

Volume of solution:

500mL * (1L / 1000mL) = 0.500L

Molarity:

0.374moles / 0.500L =

Answer: 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of aluminium}=\frac{11.0g}{27g/mol}=0.407moles[/tex]

[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]  

According to stoichiometry :

[tex]Al[/tex] is the limiting reagent as it limits the formation of product and [tex]Cl_2[/tex] is the excess reagent.

As 2 moles of [tex]Al[/tex] give = 2 moles of [tex]AlCl_3[/tex]

Thus moles of [tex]Al[/tex] give =[tex]\frac{2}{2}\times 0.407=0.407moles[/tex]  of [tex]AlCl_3[/tex]

Thus 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

Answer:

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Explanation:

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