plssss help i just need the answer

Answer:

48 cupcakes divided by the boys age equals amout of cupcakes per person.

Step-by-step explanation:

Answer:

60 minutes which grade

are you in I did it I think

Step-by-step explanation:

I Finish Work in 2 hrs

Work done in 1 Hr = 1/2

Brother Finish work in 3 Hrs Work done in 1 hr = 1/3

Let Say both Complete Work in T hrs as it has to be painted on both sides

Then T (1/2+1/3) = 2

=> T × 5/6 = 2

=> T = 2 Hr 24 Mins

=> T = 12/5 I will Take 2 Hrs to finish my work & 24 Mins to finish after start Helping

Learn more here:

Ajay along with Vijay do a work in 10 days. If Ajay do a work in 1/2...

Atul, Bhaskar and Chetan can complete a work in 10, 20 and 25..

10 men can complete a job in 200 days. They started the work. After...

Answer:

Your solution is (-3,0)

Step-by-step explanation:

Hi,

We know what Y is, so we can plug it into the second equation.

2x + y = -6

2x + (x + 3) = -6

Now, add the like terms...

3x + 3 = -6

3x = -9

x = -3

Now, plug x back in to find y.

y = x + 3

y = (-3) + 3

y = 0

Your solution is (-3,0)

Hope this helps :)

Answer:

[tex]500(.75)^{n}[/tex]

Step-by-step explanation:

It is changing exponentially because if you are eating a fraction of the left over m & m's, that is a different amount each time so it can't be linear.

500(1-(1/4))^n

[tex]500(.75)^{n}[/tex]

Initial quantity of the candies = 500

If we eat [tex]\frac{1}{4}[/tex] candies each day, number of candies after one day

= 500 - [tex]\frac{1}{4}\times 500[/tex]

= 500 - 125

= 375

Number of candies after two days

= 375 - [tex]\frac{1}{4}\times (375)[/tex]

= 281.25

Therefore, sequence formed will be.

500, 375, 281.25.......n days

Ratio of 2nd and 1st term = [tex]\frac{375}{500}[/tex] = 0.75

Ratio of 3rd and 2nd term = [tex]\frac{281.75}{375}[/tex] = 0.75

Therefore, there is a common ratio of 0.75 in each successive and previous term.

And the sequence will be a geometric sequence.

Expression for the exponential decay is,

[tex]A=A_0(1-r)^n[/tex]

Here, A = Final amount

[tex]A_0=[/tex] Initial amount

r = percentage decrease

n = duration

From the given question,

[tex]A_0=500[/tex]

r = [tex]\frac{1}{4}=\frac{25}{100}[/tex]

Therefore, equation for the decrease in number of candies will be.

[tex]A=500(1-0.25)^n[/tex]

[tex]A=500(0.75)^n[/tex]

Learn more,

https://brainly.com/question/2193820

Answer:

t> - 15

I hope this helps, if it's right please give me brainless

<--------- -15      -10     -5      0

----------------------------------------

there would be an open dot under -15

Answer:

The thing u pasted is glitched and isn't loading

Step-by-step explanation:

Answer:

wouldnt the value of x be r?

Answer:

6

Step-by-step explanation:

-3 x (8 + [-10]) =

-3 x (8 - 10) =

-3 x -2 =

6

HOpe that helps!

Answer: 6

Step-by-step explanation:

finding the answer from an equation

replace the values of x and a in the equation:

(-3) * ( 8 + -10)

= (-3) * (-2)

recall :

(-) * (-) = +

hence -3 * -2

= 6

Hope this helps. Can u pls give me brainliest

Answer:

Step-by-step explanation:

Answer: C. Daphne's test score is 2.50 standard deviations above the average test score of students in the course.

Step-by-step explanation: That's what Z-score is

Answer:

The rate increases at 398mi/h

Step-by-step explanation:

Given

[tex]\frac{dx}{dt} = 460mi/h[/tex] --- rate when [tex]y = 2[/tex] --- distance

The given parameters is represented with the attached figure

Using Pythagoras theorem [take the attached image as a point of reference]

[tex]y^2 = x^2 + 1^2[/tex]

[tex]y^2 = x^2 + 1[/tex]

Differentiate with respect to time (t):

[tex]2y \frac{dy}{dt} = 2x \frac{dx}{dt}[/tex]

Divide both sides by 2

[tex]y \frac{dy}{dt} = x \frac{dx}{dt}[/tex] --- (1)

When y = 2:

[tex]y^2 = x^2 + 1^2[/tex] --- Pythagoras Theorem

[tex]2^2 = x^2 + 1[/tex]

[tex]4 = x^2 + 1[/tex]

Collect like terms

[tex]x^2 = 4 -1[/tex]

[tex]x^2 = 3[/tex]

Solve for x

[tex]x = \sqrt 3[/tex]

So:

[tex]y \frac{dy}{dt} = x \frac{dx}{dt}[/tex]

Substitute: [tex]x = \sqrt 3[/tex], [tex]\frac{dx}{dt} = 460mi/h[/tex] and [tex]y = 2[/tex]

[tex]2 * \frac{dy}{dt} = \sqrt 3 * 460[/tex]

[tex]2 * \frac{dy}{dt} = 460\sqrt 3[/tex]

Divide by 2

[tex]\frac{dy}{dt} = 230\sqrt 3[/tex]

[tex]\frac{dy}{dt} = 230*1.7321[/tex]

[tex]\frac{dy}{dt} = 398.383[/tex]

[tex]\frac{dy}{dt} \approx 398[/tex]

Answer:

$49.445 or $49.5 if they round

Step-by-step explanation:

Answer:

$948.45

Step-by-step explanation:

■ Sales tax: $49.45

■ Cost/Price before ST: $899.00

■ Total Cost/Price including ST: $948.45

Answer:

a and c

Step-by-step explanation:

Answer:

The cut-off dollar amount is $328.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean cost of $328, standard deviation of $82.

This means that [tex]\mu = 328, \sigma = 82[/tex]

If you want to be in the bottom 50%, what will be the cut-off dollar amount?

The 50th percentile, which is X when Z has a pvalue of 0.5. So X when Z = 0.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0 = \frac{X - 328}{82}[/tex]

[tex]X - 328 = 0*82[/tex]

[tex]X = 328[/tex]

The cut-off dollar amount is $328.

Answer:

4'3 = 6'2

=

Step-by-step explanation:

4 x 4 x 4 = 64

6 x 6 = 64

hope this helps

Answer:

3

Step-by-step explanation:

Answer: 3

3 would be the answer cuz the it goes down by 3 then 2 then 1

Answer:

16 + 2x

Step-by-step explanation:

Step-by-step explanation:

Literally, lets not waste anybody's time. Super simple fix, you'll thank me later!

Type in desmos graphing calculator.

Answer:

I think that the answer would be C .

hope it was helpful :)

Answer: 25.12

Step-by-step explanation: good luck

Answer:

No, the measurements given cannot be used to create a triangle.

Explanation:

The sum of all the angles of a triangle should be 180°.

Here,

55°+80°+55°=190°

which is not equal to 180°.

So, the traingle cannot be formed using the given measurements.

Answer: Yes, it is.

Step-by-step explanation:

Sorry, I just know the answer because I just did this in school. Like- right now

Answer:

Step-by-step explanation:

3x-11  = x+9

2x = 20

x = 10

Answer:

x=10

Step-by-step explanation:

Answer

37 ,123.52

Explanation

the image above, hope it helps

Answer: 92.4

Step-by-step explanation: Median is where you add up all numbers and then divide by how many numbers there are so it would be

98+97+83+94+90= 462 Then you divide that by 5 and get 92.4

Hope this helps ^^

Answer:

36 animals were expected to be adopted in October

Step-by-step explanation:

42%/100  = 0.42

0.42 * 85 = 35.7

35.7 rounds up to 36 animals! (Since you can't have 0.7 animals XD)

Good luck!!

Answer:

42

___ x 85 = 35.7

100

35.7 rounded would be about 36. Because that is what they are expecting to be adopted.

Answer:12

Step-by-step explanation:

Answer:

The null hypothesis is that there is no difference between the mean time it takes an online trained employee or a team-based trained employee to assemble the given part

Step-by-step explanation:

The information the director of the equipment manufacturing company is interested in determining is weather the productivity of assembly line employees is affected by the method used in their training

The total number newly hired employees in the sample = 42

The number of newly hired employees that receive training online = 21

The number of newly hired employees that receive training in a team = 21

The given data of the result of the time it takes an employee to assemble a part is presented as follows;

On-Line 19.4, 16.7, 20.7, 19.3, 21.8, 16.8, 14.1, 17.7, 16.1, 19.8, 16.8, 19.3, 14.7, 16.0, 16.5, 17.7, 16.2, 17.4, 16.4, 16.8, 18.5

Team; 22.4, 13.8, 18.7, 18.0, 19.3, 20.8, 15.6, 17.1, 18.0, 28.2, 21.7, 20.8, 30.7, 24.7, 23.7, 17.4, 23.2, 20.1, 12.3, 15.2, 16.0

The mean time for the of the on-line trained employee, [tex]\overline x_1[/tex] = 17.55714

The standard deviation of the time for the of the on-line trained employee, s₁ = 1.93328

The mean time for the of the team based trained employee, [tex]\overline x_2[/tex] = 19.89048

The standard deviation of the time for the of the team based trained employee, s₂ = 4.5667

The null hypothesis, H₀:  [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]

The alternative hypothesis, Hₐ:  [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]

[tex]t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}[/tex]

Therefore, we have;

[tex]t=\dfrac{(19.89048 - 17.55714)}{\sqrt{\dfrac{4.57667^{2}}{21} - \dfrac{1.93328^{2} }{21}}} \approx 2.5776[/tex]

The degrees of freedom, df = n₁ - 1 = 21 - 1 = 20

At 95% confidence level, we have α = 1 - 0.95 = 0.05, and t = 2.086

Therefore, given that the test statistic is larger than the critical 't' value, we reject the null hypothesis. There is sufficient statistical evidence to show that there is a difference between the mean time of assembly value for the on-line trained and team-based employee