Plss help due today!!!

The survey contained 10 questions (translated into multiple languages) which resulted in categorical and quantitative data being collected. Some examples are below:

What language do you primarily speak?

Are you aware of the 2020 recipient of the European Lifetime Achievement Award in Writing? Yes or No

What is your age (in years)?

How many books did you read last year?

Do you agree with the following statements: “The European Lifetime Achievement Award recognizes authors of a variety of races and ethnicities”: Strongly Disagree, Disagree, Neither Agree nor Disagree, Agree, Strongly Agree, Do not know.

13) Which variables are quantitative?



14) Give an example of a survey question they might want to include that would result in a categorical response (include the categories).




15) What decisions might they be making with the results of the survey? Why are they interested in these questions?

Answer:

50

Step-by-step explanation:

A Venn diagram is very helpful for this picture and I've included one in the attached.

If we look at the numbers we're given, we see that the numbers do not add up to 500 as 350 + 300 + 200 = 850.

However, we can work through the numbers to find the exact values and eventually the number of people that liked neither rock nor country.

Since 200 people like both rock and country, these people are part of the 350 people that like rock.

We can find the number of people who like rock only by subtracting 200 from 350:

350 - 200 = 150 (Rock only)

Using the same logic from above, we know that the 200 people who like both rock and country are a part of the 300 people who like country.

We can find the number of people who like country only by subtracting 200 from 300:

300 - 200 = 100 (Country only)

Currently, we have 450/500 as 150 + 200 + 100 = 450.

Now, we can find the number of people who like neither rock nor country by subtracting 450 from 500:

500 - 450 = 50 (Neither rock nor country)

We can check that the numbers we found equal 500:

Rock only + Both rock and country + Country only + Neither rock nor country = Total amount of music lovers surveyed

150 + 200 + 100 + 50 = 500

500 = 500

(**In the attached Venn diagram, M stands for the total set of music lovers, R stands for rock only, B stands for both, C stands for country only, and N stands for neither)

The population of interest is the group of students who submitted an application to the college in 2017.

A sample is a subset of a population that is selected and studied in order to make inferences or conclusions about the population. The sample is usually selected to be representative of the population in some way, so that the conclusions drawn from the sample can be generalized to the population as a whole.

The correct answer is C.

The purpose of the study is to determine why students who are interested in the college decide to enroll or not. Therefore, the population of interest is the group of students who submitted an application to the college in 2017.

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a. it will take 8 days for the population to quadruple in size.

b. t will take 6.34 days for the population to triple in size.

Organisms οf a species living tοgether in a grοup at a particular place are called a “pοpulatiοn” in Biοlοgy. A pοpulatiοn is an assοrtment οf οrganisms in a given lοcatiοn. These οrganisms, since they belοng tο the same species, can interbreed and prοduce mοre οf their kinds.

We have to use the following formula

P(t) = P0(b)t

⇒ 6000000 = 3000000(b)4

⇒ b4 = 2

⇒ b = 21/4

a.  12000000 = 3000000(2)t/4

⇒ 4 = 2t/4

⇒ 22 = 2t/4

⇒ 2 = t/4

⇒ t = 8 days

Thus, it will take 8 days for the population to quadruple in size.

b. 9000000=3000000(2)t/4

⇒ 3 = 2t/4

⇒ log 3 = (t/4)log 2

⇒ t = 6.34 days

Thus, it will take 6.34 days for the population to triple in size.

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The probability that at least 10 students in a random sample of 20 are Business majors is 0.139. The probability that at least 16 students in the sample are not Business majors is 0.147.

a. To find the probability that at least 10 students in a random sample of 20 are Business majors, we can use the binomial distribution with parameters n = 20 and p = 0.3 (the probability of success, i.e. being a Business major). Using a calculator or software, we can find this probability as:

P(X >= 10) = 1 - P(X < 10) = 1 - binomcdf(20, 0.3, 9) = 0.139

b. To find the probability that at least 16 students in the sample are not Business majors, we can use the same approach, but with q = 0.7 (the probability of failure, i.e. not being a Business major):

P(X >= 16) = 1 - P(X < 16) = 1 - binomcdf(20, 0.7, 15) = 0.147

c. To find the probability that exactly 10 students in the sample are Business majors, we can use the binomial probability formula:

P(X = 10) = (20 choose 10) * (0.3)^10 * (0.7)^10 = 0.201

d. To find the probability that exactly 12 students in the sample are not Business majors, we can use a similar formula:

P(X = 12) = (20 choose 12) * (0.7)^12 * (0.3)^8 = 0.200

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The graph's function limit at x=4 is 6.

In mathematics, the limit of a function is the value that the function approaches as the input approaches a certain value or as the input approaches infinity or negative infinity. A function may or may not have a limit at a given point or as the input goes to infinity or negative infinity.

The formal definition of the limit of a function f(x) as x approaches a value a is as follows:

For every positive number ε (epsilon), there exists a corresponding positive number δ (delta) such that if 0 < |x-a| < δ, then |f(x)-L| < ε.

Limit f(x) at x tend to 4⁺ =6.

Limit f(x) at x tend to 4⁻ =6

Hence, the graph's function limit at x=4 is 6.

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Answer:

B: 9

Step-by-step explanation:

We know

Caleb took 24 photos at the zoo. 3/8 of his photos are of giraffes.

How many of Caleb’s photos are of giraffes?

We Take

24 x 3/8 = 9 photos

So, 9 of Caleb's photos are of giraffes.

None of these courses were being taken by seniors is 9.

A Venn diagram is a type of graphic representation that uses circles to emphasise the relationships between certain items or constrained groups of things. Circles with overlaps exhibit certain traits, but circles without overlaps do not.

Total number of students=150

Number of students Math =80

Number of students Spanish =41

Number of students Physics=54

Number of students Math and Spanish=10

Number of students Math and Physics=19

Number of students Physics and Spanish=12

Number of students Physics and Spanish and math=7

seniors were taking none of these courses =150-(80+41+54)+10+19+12-7

=9

Diagram is attached below:

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The total amount of money Carol originally invested is £22,000 in the bank account.

Compound interest is interest that is calculated not only on the initial amount of money invested or borrowed, but also on any accumulated interest from previous periods.

This results in exponential growth or accumulation of interest over time.

Let X be the amount that Carol originally invested in the account.

After 1 year, the amount of money in the account will be X(1+0.025) = X(1.025).

After Carol withdrew £1000, the amount of money in the account will be X(1.025) - £1000.

After 2 years (i.e. on 1st January 2016), the amount of money in the account will be (X(1.025) - £1000)(1+0.025) = (X(1.025) - £1000)(1.025).

We know that the amount of money in the account on 1st January 2016 was £23,517.60, so we can write the equation:

(X(1.025) - £1000)(1.025) = £23,517.60

Expanding the left-hand side and simplifying, we get:

X(1.025)² - £1000(1.025) = £23,517.60

X(1.025)² = £24,567.63

Dividing both sides by (1.025)², we get:

X = £22,000 (rounded to the nearest pound)

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The complete question is -

On the 1st of January 2014, Carol invested some money in a bank account. The account pays 2.5% compound interest per year. On the 1st of January 2015, Carol withdrew £1000 from the account. On the 1st of January 2016, she had £23 517.60 in the account. Work out how much Carol originally invested in the account?

The expression 1/30(ln(15/22))t = x when solved for t has a solution of t = -78.95x

Given the following expression

1/30(ln(15/22))t =

The above expression cannot be solved for t

This is so because the expression is not an equation or inequality

To do this, we must equate the expression to a value (say x)

So, we have

1/30(ln(15/22))t = x

Multiply through by 30

This gives

ln(15/22)t = 30x

Evaluate the natural logarithm expression

This gives

-0.38t = 30x

Divide both sides by -0.38

So, we have

t = -78.95x

Hence, the solution for t is t = -78.95x

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So, the most precise classification of quadrilateral LMNP is a kite.

In mathematics, an equation is a statement that two mathematical expressions are equal. It typically contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. The goal of solving an equation is to find the values of the variables that make the equation true. Equations are used in many areas of mathematics, science, and engineering to model relationships between quantities and to solve problems.

Here,

To classify the quadrilateral LMNP, we need to calculate the length of all four sides using the distance formula and then use those values to determine the shape of the quadrilateral.

The distance formula is given by:

d = √[(x₂ - x₁)² + (y₂ - y₁)²]

Using this formula, we can calculate the length of each side of the quadrilateral as follows:

LM = √[(4 - (-1))² + (9 - 7)²] = √[5² + 2²] = √29

MN = √[(8 - 4)² + (-1 - 9)²] = √[4² + (-10)²] = √116

NP = √[(3 - 8)² + (-3 - (-1))²] = √[(-5)² + (-2)²] = √29

PL = √[(-1 - 3)² + (7 - (-3))²] = √[(-4)² + 10²] = √116

Now, we can use the values we have calculated to determine the shape of the quadrilateral. We can see that LM = NP and MN = PL, which means that opposite sides are congruent. Also, LM and MN are not equal to PL and NP, which means that opposite sides are not parallel. Therefore, LMNP is a kite.

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the logarithmic regression of aids cases over time is 4.6

A type of regression called logarithmic regression is used to simulate situations where growth or decay initially increases quickly and then gradually slows down.

A better prediction model is produced by applying the logarithm to your variables, which results in a much more distinct and/or adjusted linear regression line through the base of the data points.

y ≈ 33.7·ln(x) -45.9

4.6

Detailed explanation:

Logarithmic regression can be carried out using a spreadsheet or a graphing calculator. The log curve with the best least-squares fit is about...

y ≈ 33.7·ln(x) -45.9

Around 4.6 is the anticipated value of x needed to get y = 5.2.

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Answer:

x = 2

y = -3/4

Step-by-step explanation:

1. Substitute y=1/8x -1 in −5x+4y=−13

-5x+4(1/8x -1) = -13

2. Solve for x

-5x + 4/8x - 4 = -13

-9/2x - 4 = -13

-9/2x = -9

x = 2

3. Now that you know x = 2, plug it into y=1/8x - 1 to find what y is.

y= 1/8(2) - 1

y= 2/8 - 1

y= -3/4

The cοst οf painting the triangle bοrder at the given rate is Rs. [tex]108\sqrt{(2)[/tex].

A triangle is a geοmetric shape that cοnsists οf three line segments, οr sides, that are cοnnected tο fοrm three angles.

Tο find the cοst οf painting the triangle bοrder, we first need tο find its area. Let's call the third side οf the triangle "x".

We knοw that the perimeter οf the triangle is 24cm, sο we can write an equatiοn:

6cm + 8cm + x = 24cm

Simplifying this, we get:

x = 10cm

Nοw we can use Herοn's fοrmula tο find the area οf the triangle:

s = (6cm + 8cm + 10cm)/2 = 12cm

Area [tex]= \sqrt{(s(s-6cm)(s-8cm)(s-10cm))[/tex]

[tex]= \sqrt{(12cm6cm4cm*2cm)[/tex]

[tex]= 2\sqrt{(72cm^2)[/tex]

[tex]= 12\sqrt{(2) cm^2[/tex]

Finally, we can calculate the cοst οf painting the bοrder at a rate οf Rs. 9 per square cm:

Cοst = (Area) x (Rate)

[tex]= (12\sqrt{(2)} cm^2) x (Rs. 9/cm^2)[/tex]

[tex]= Rs. 108\sqrt{(2)[/tex]

Therefοre, the cοst οf painting the triangle bοrder at the given rate is= [tex]Rs. 108\sqrt{(2)[/tex]

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In this data set, the only value that is an outlier is 100, since it is above the upper bound of 98.25.

To identify the outliers in the data set, we can use the concept of the interquartile range (IQR) and the 1.5×IQR criterion.

First, we need to find the first and third quartiles (Q1 and Q3) of the data set. To do this, we can order the data set from smallest to largest:

54, 72, 75, 81, 81, 82, 83, 83, 83, 85, 100

The median of the data set is the middle value, which is 82.

The lower half of the data set will consists of:

54, 72, 75, 81, 81

The median of the lower half is (72 + 75)/2 = 73.5, which is the value halfway between the two middle values.

The upper half of the data set will consists of:

83, 83, 83, 85, 100

The median of the upper half is (83 + 85)/2 = 84, which is the value halfway between the two middle values.

Therefore, the first quartile (Q1) is 73.5 and the third quartile (Q3) is 84.

The interquartile range (IQR) is the difference between Q3 and Q1:

IQR = Q3 - Q1 = 84 - 73.5 = 10.5

To identify the outliers in the data set using the 1.5×IQR criterion, we need to calculate the lower and upper bounds:

Lower bound = Q1 - 1.5×IQR = 73.5 - 1.5×10.5 = 57.75

Upper bound = Q3 + 1.5×IQR = 84 + 1.5×10.5 = 98.25

Any data point that is below the lower bound or above the upper bound is considered an outlier.

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Answer:

A) the sides all have the same slopes.

Step-by-step explanation:

Every time a square in a graph is a square, their slopes MUST be the same, either that or nothing, it can't be a square.

Answer:

Natural

Step-by-step explanation:

Ln in mathematics mean natural log. Natural log is the log of a number with base e where e=2.71828. For understanding if the number is 2.71828^10 then the ln of 2.71828^10 is 10.

The MLE of σ^2 for a random sample X1, X2, ..., Xn from a normal distribution with known mean μ is s^2/(n-1), and the MLE of σ is the square root of s^2.

Given a random sample X1, X2, ..., Xn from a normal distribution with mean μ and unknown variance σ^2, the likelihood function is:

L(σ^2) = (1/(2πσ^2)^(n/2)) * exp[-(1/(2σ^2)) * ∑(Xi - μ)^2]

To find the maximum likelihood estimator (MLE) of σ^2, we need to find the value of σ^2 that maximizes the likelihood function.

To do this, we take the natural logarithm of the likelihood function, since the logarithm is a monotonically increasing function and thus does not change the location of the maximum:

ln L(σ^2) = (-n/2) ln(2πσ^2) - (1/(2σ^2)) * ∑(Xi - μ)^2

To maximize this expression, we take the derivative with respect to σ^2 and set it equal to zero:

d/d(σ^2) ln L(σ^2) = (-n/2σ^2) + (1/(2(σ^2)^2)) * ∑(Xi - μ)^2 = 0

Solving for σ^2, we get:

σ^2 = (∑(Xi - μ)^2) / n

This means that the MLE of σ^2 is the sample variance, s^2 = (∑(Xi - μ)^2) / (n-1), since we usually use the sample variance to estimate the population variance when the population mean is known.

Therefore, the MLE of σ is the square root of the sample variance:

σ(hat) = sqrt(s^2)

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____the given question is incomplete, the complete question is given below:

Suppose that X1, . . . , Xn form a random sample from a Normal distribution for which mean μ is known, but the variance σ

2

is unknown. Find the MLE (maximum likelihood estimation) of σ.

[tex](\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{q}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{q}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{7}-\underset{x_1}{(-3)}}} ~~ = ~~\stackrel{\stackrel{\textit{\small slope}}{\downarrow }}{ \cfrac{ -7 }{ 10 }}\implies \cfrac{q-3}{7+3}=\cfrac{ -7 }{ 10 }\implies \cfrac{q-3}{10}=\cfrac{ -7 }{ 10 } \\\\\\ q-3=-7\implies q=-4[/tex]

From the table, the calculated equation of h(x) in vertex form is h(x) = (x + 1)² + 2

To find the equation of the quadratic function h(x) in vertex form, we need to first determine the coordinates of the vertex.

The vertex form of a quadratic function is given by

y = a(x - h)² + k, where (h, k) is the vertex of the parabola.

From the table, we have

(h, k) = (-1, 2)

So, we have

y = a(x + 1)² + 2

To determine the value of 'a', we can substitute any other point from the table into the vertex form equation and solve for 'a'.

For example, using the point (0, 3), we have:

a(0 + 1)² + 2 = 3

a = 1

So, we have

y = (x + 1)² + 2 as the equation

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The positive difference between the greatest sum and the least sum in the sample space of the output of the two cubes is 10.

A sample space is a mathematical collection or set of possible outcomes of a random experiment. A sample space is represented by the symbol "S". The possible outcome of an experiment is called the events.

The greatest sum is obtained by adding the largest number on the first cube with the largest number on the second cube. The least number can be obtained by adding the smallest number on the first cube with the smallest number on the second cube.

The possible numbers displayed by the first cube are; 1, 2, 3, 4, 5, 6

The possible numbers displayed by the second cube are also; 1, 2, 3, 4, 5, 6

The positive difference between the greatest sum and the least sum in the sample space is therefore;

12 - 2 = 10

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The rate of change (or slope) of this linear function is -1/2.

A linear function is a mathematical function that has a constant rate of change, meaning that the output (y-value) changes at a constant rate for every unit increase in the input (x-value). In other words, the graph of a linear function is a straight line.

The general form of a linear function is y = mx + b, where m is the slope of the line (the rate of change) and b is the y-intercept (the point where the line crosses the y-axis). The slope represents how much the y-value changes for every one-unit increase in the x-value.

Linear functions can be used to model many real-world situations, such as distance vs. time or cost vs. quantity. They are also commonly used in economics, physics, and engineering.

The rate of change of a linear function represents the slope of the line. We can calculate the slope using the formula:

slope = (change in y) / (change in x)

Let's use the points (0, -3) and (2, -4) to calculate the slope:

slope = (-4 - (-3)) / (2 - 0)

slope = -1 / 2

Therefore, the rate of change (or slope) of this linear function is -1/2.

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Answer: Factors of 24 include: 1 and 24, 2 and 12, 3 and 8, 4 and 6

Step-by-step explanation:

The converted linear programming problem in standard form is given by

maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄ where s₁, s₂, s₃, and s₄ are the slack variables.

convert the linear programming problem to standard form,

Introduce slack variables to represent the inequalities,

And rewrite the objective function as a linear expression.

First, let us introduce the slack variables,

x₁ + s₁= 2

x₂ + s₂ = 3 + 2t

2x₂ + s₃ = 5

s₄ = -x₂

where s₁, s₂, s₃, and s₄ are the slack variables.

Rewrite the objective function as a linear expression,

Maximize 2^i - f x2

= maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄

Now we have the linear programming problem in standard form,

maximize 2^i - f x₂ + 0x₁ + 0s₁ + 0s₂ + 0s₃ + 0s₄

subject to,

x₁ + s₁ = 2

x₂ + s₂ = 3 + 2t

2x₂ + s₃ = 5

s₄ = -x₂

x₁ >= 0, s₁ >= 0

x₂ >= 0, s₂ >= 0, t >= 0

s₃ >= 0, s₄ >= 0

Added a new variable t to represent the inequality

x₂ % 2 < 3,

which can be rewritten as x₂ = 2t + r,

where r is the remainder of x₂ divided by 2.

Require t to be non-negative, and r to be less than 2.

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Answer:

B. $6 per part

Step-by-step explanation:

The average cost per part can be computed as follows

Average Cost = (324-300)/(104-100)

= 24/4

=$6

Answer: B. $6 per part

The statements that are true would be :

f(x) = 2√x has the same domain and range as f(x) = √x:

Both functions have a square root, so the domain must be x ≥ 0 in both cases. Since f(x) = 2√x is a vertical stretch of f(x) = √x by a factor of 2, the range of both functions starts at 0 and goes to positive infinity.

f(x) = -√x has the same domain as f(x) = √x but a different range:

In this relation, both functions have a square root, so the domain must be x ≥ 0 in both cases as it was in the first option. f(x) = -√x is a reflection of f(x) = √x over the x-axis, so the range is y ≤ 0, which is different from the range of f(x) = √x (y ≥ 0).

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Between 3.26 on the low end and 3.30 on the high end is where UGPAS's middle 50% lies.

Provided that the parabola's vertex is at the origin and that it is symmetric about the y-axis. So, depending on whether the parabola expands upward or downward, the equation can take the form x2 = 4ay or x2 = -4ay.

Because we are interested in the top 5%, the region to the right of the z-score is 0.05. n,... As a result, we can apply the following z-score formula:

z = (x - μ) / σ

x = z * σ + μ

Substituting the values we have, we get:

x = 1.645 * 0.15 + 3.25 = 3.66

Therefore, the z-scores corresponding to the 25th and 75th percentiles are:

z1 = -0.675

z2 = 0.675

Using the same formula as before, we can find the UGPAs corresponding to these z-scares:

x1 = -0.675 * 0.15 + 3.25 = 3.26

x2 = 0.675 * 0.15 + 3.25 = 3.30

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The magnitude and direction of the resultant vector are 50.479 and 73 degrees, respectively.

What is vector addition?

Vector addition is the operation of adding two or more vectors together into a vector sum. The so-called parallelogram law gives the rule for the vector addition of two or more vectors. For two vectors, the vector sum is obtained by placing them head to tail and drawing the vector from the free tail to the free head.

To find the magnitude and direction of the resultant vector, we need to add the two given vectors. We can do this using vector addition, where we add the corresponding components of each vector.

First, let's convert the given magnitudes and directions into component form. We can use the following equations to find the x and y components of each vector:

Magnitude = √(x² + y²)

Direction = tan⁻¹(y/x)

For the first vector with magnitude 28 and direction 500, we have:

Magnitude = 28

Direction = 500 degrees

x = Magnitude * cos(Direction) = 28 * cos(500) = -14

y = Magnitude * sin(Direction) = 28 * sin(500) = -24.202

Therefore, the first vector can be written as v1 = <-14, -24.202>

Similarly, for the second vector with magnitude 75 and direction 1250, we have:

Magnitude = 75

Direction = 1250 degrees

x = Magnitude * cos(Direction) = 75 * cos(1250) = 28.481

y = Magnitude * sin(Direction) = 75 * sin(1250) = 72.929

Therefore, the second vector can be written as v2 = <28.481, 72.929>

To find the resultant vector, we can add the components of the two vectors:

v = v1 + v2 = <-14, -24.202> + <28.481, 72.929> = <14.481, 48.727>

The magnitude of the resultant vector is:

Magnitude = √(x² + y²) = √(14.481² + 48.727²) = 50.479

Rounding to the thousandth place, the magnitude of the resultant vector is 50.479.

The direction of the resultant vector can be found using the following equation:

Direction = tan⁻¹(y/x) = tan⁻¹(48.727/14.481) = 72.636 degrees

Rounding to the nearest degree, the direction of the resultant vector is 73 degrees.

Therefore, the magnitude and direction of the resultant vector are 50.479 and 73 degrees, respectively.

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The specific heat of water is [tex]+41840J . mol^{-1}[/tex].

The following formula is used to determine how much heat a substance absorbs or releases during a heat exchange between two bodies, Calculate the value of q.

Q = m.s.t

Where,

Q is equal to how much heat is received or emitted.

m = The substance's mass

t = Temperature change

s = The substance's specific heat

The starting temperature in this dissolve is,

[tex]T_{i}[/tex] = 25.00°C

(25.00 + 273.00) K

= 298.00 K

Final temperature in this dissolving is,

[tex]T_{f}[/tex] = 23.36°C

= (23.36 + 273.00) K

Specific Water's heat is, [tex]4.184\frac{J}{g.K}[/tex]

In this issue, the heat that water releases are,

[tex]Q_{released} = 50.0g*4.184\frac{J}{g.K} * (298.00 - 296.36)K[/tex]

= 343.088J

2) Molar Mass of KClO₃ is [tex]122.55g mol^{-1}[/tex]

As a result, number of moles of KClO₃ present in 1g sample is,

[tex]\frac{1.00g}{122,55g/mol} = 0.0082mols[/tex]

Hence, the standard enthalpy change of the dissolving process is determined as follows:

Δ[tex]H^{o} = +\frac{343.088J}{0.0082mol} \\= +41840J . mol^{-1}[/tex]

The plus symbol (+) denotes the absorption of heat during the dissolving phase.

Learn more about enthalpy here:

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Complete Question:

When 1.00 g potassium chlorate (KCIO₃) is dissolved in 50.0 g water in a Styrofoam calorimeter of negligible heat capacity, the temperature decreases from 25.00°C to 23.36°C. Calculate q for the water and AH° for the process. KCIO: (s) → K* (aq) + CIO (aq) The specific heat of water is 4.184 J K-1 g¯!.

Answer:

$129

Step-by-step explanation:

26 students x 3 markers each= 78 markers

Markers are being sold in sets of 5, so she needs at least 16 packs of markers. that will cost her $116

Answer:

To find the total surface area of a pyramid you do SURFACE AREA =B+12(P×l)