pls qmp

What is the purpose of the lab, the importance of the topic, and the question you are trying to answer?


Energy

Answer:

80 N

Explanation:

mass = 20 kg

acceleration = 4 m/s^2

Force = mass * acceleration

         = 20 *4  

         = 80 N

Answer:

2.83km/hr

Explanation:

Let stream flowing at the rat x km/hr

In still water

Speed of boat=4km/hr

Upstream speed=4-x

Downstream speed=4+x

Total time=2 hr

Time=Distance/speed

According to question

[tex]\frac{2}{4+x}+\frac{2}{4-x}=2[/tex]

[tex]\frac{8-2x+8+2x}{(4+x)(4-x)}=2[/tex]

[tex]\frac{16}{4^2-x^2}=2[/tex]

Using the formula

[tex](a+b)(a-b)=a^2-b^2[/tex]

[tex]4^2-x^2=\frac{16}{2}[/tex]

[tex]16-x^2=8[/tex]

[tex]16-8=x^2[/tex]

[tex]8=x^2[/tex]

[tex]x=\sqrt{8}=2.83km/hr[/tex]

Hence, the stream  is flowing at 2.83km/hr

Answer:

0.8A

Explanation:

because im very intelligent and beautiful so the answer is correct and its 0.8A

Answer:

See the explanation below.

Explanation:

Work in physics is defined as the product of force by the distance that the body travels in the direction of the force.

It can be represented by means of the following equation.

[tex]W=F*d[/tex]

where:

W = work [J]

F = force [N]

d = distance [m]

In the given example the work is zero since the tree does not move, therefore the bear exerts a force on the tree. But there is no talk of movement of the tree, therefore the work is zero.

Answer:

(10 L)(100° C) + (90 L)(10°) = (100 L)T

1,000 + 900 = 100T

1,900 = 100T

100T = 1,900

T = 1,900/100

Explanation:

Momentum = (mass) x (velocity)

Momentum m₁  =  (6 kg) x (13 m/s east)  =  78 kg-m/s east

Momentum m₂  =  (14 kg) x (7 m/s east)  =  98 kg-m/s east

Since they're both in exactly the same direction you can simply addum up to get their total momentum.  It's 176 kg-m/s east .

The  momentum of a system that consists of two objects should be 176 kg m/s on east hand side.

Since we know that

Momentum = (mass) x (velocity)

So,

Momentum m₁  =  (6 kg) x (13 m/s east)  =  78 kg-m/s east

Momentum m₂  =  (14 kg) x (7 m/s east)  =  98 kg-m/s east

Since they are on same direction so the total momentum should be

= 78 + 98

= 176 kg-m/s east

hence, The  momentum of a system that consists of two objects should be 176 kg m/s on east hand side.

Learn more about momentum here: https://brainly.com/question/24815698

Force of a crate : 300 N

Given

0.25 meters wide and 1.5 meters long

Pressure = 800 Pa

Required

Force

Solution

P = F/A

A = 0.25 x 1.5

A = 0.375 m²

P = 800 Pa = 800 N/m²

Input the value :

F = P x A

F = 800 N/m² x 0.375 m²

F = 300 N

Answer:

b. d. f.

Explanation:

Got it right on Edge

Answer:

2. Gina gathers information about a court case.

4. Hana interviews and advises a person who has been accused of a crime.

6. Dewayne creates the paperwork for a business contract.

v=u+at

v=0+8.0×30

v=240

PE = 450 m

Given

The initial problem might be like this

A 1.0-kg ball is thrown into the air with an initial velocity of 30 m/s.

Required

Potential energy

Solution

h max = vo²sin²θ/2g

h max = 30²sin²90/2.10

h max = 45 m

PE = m.g.h

PE = 1 x 10 x 45

PE = 450 m

Answer:

IVE BEEN TRYNA FIND THE ANSWER FOR THE PAST HOUR T-T

Explanation:

Answer:

3.2 x10^11 bits of storage

Explanation:

Answer:

KE = 1/2 m v^2

Explanation:

Answer:

D. blinking ofeyea

Explanation:

not really sure

Answer:

it is 9m/s , hope it helps

Answer:

A device that is used to break an electric circuit is called electric switch

Answer:

(a) The potential difference between the spheres is 750 kVA

(b) The charge on the smaller sphere is 6.[tex]\overline 6[/tex] μC

(c) The charge on the smaller sphere, Q₁ = 13.[tex]\overline 3[/tex] μC

Explanation:

(a) The given parameters are;

The charge on the inner sphere, q = 5.00 μC

The radius of the inner sphere, r = 3.00 cm = 0.03 m

The charge on the larger sphere, Q = 15.0 μμC

The radius of the larger sphere, R = 6.00 cm = 0.06 m

The potential difference between two concentric spheres is given according to the following equation;

[tex]V_r - V_R = k \times q \times \left ( \dfrac{1}{r} - \dfrac{1}{R} \right)[/tex]

Where;

R = The radius of the larger sphere = 0.06 m

r = The radius of the inner sphere = 0.03 m

q = The charge of the inner sphere = 5.00 × 10⁻⁶ C

Q = The charge of the outer sphere = 15.00 × 10⁻⁶ C

k = 9 × 10⁹ N·m²/C²

Therefore, by plugging in the value of the variables, we have;

[tex]V_r - V_R = 9 \times 10^9 \times 5.00 \times 10^{-6} \times \left ( \dfrac{1}{0.03} - \dfrac{1}{0.06} \right) = 750,000[/tex]

The potential difference between the spheres, [tex]V_r - V_R[/tex] = 750,000 N·m/C = 750 kVA

(b) When the spheres are connected with a wire, the charge, 'q', on the smaller sphere will be added to the charge, 'Q', on the larger sphere which as follows;

[tex]Q_f[/tex] = Q + q = (5 + 15) × 10⁻⁶ C = 20 × 10⁻⁶ C

[tex]Q_f[/tex] = 20 × 10⁻⁶ C

From which we have;

Q₁/Q₂ = R/r

Where;

Q₁ = The new charge on the on the larger sphere

Q₂ = The new charge on the on the smaller sphere

[tex]Q_f[/tex] = 20 × 10⁻⁶ C = Q₁ + Q₂

∴ Q₁ = 20 × 10⁻⁶ C - Q₂ = 20 μC - Q₂

∴ (20 μC - Q₂)/Q₂ = 0.06/(0.03) = 2

20 μC - Q₂ = 2·Q₂

20 μC = 3·Q₂

Q₂ = 20 μC/3

The charge on the smaller sphere, Q₂ = 20 μC/3 = 6.[tex]\overline 6[/tex] μC

(c) Q₁ = 20 μC - Q₂ = 20 μC - 20 μC/3 = 40 μC/3

The charge on the smaller sphere, Q₁ = 40 μC/3 = 13.[tex]\overline 3[/tex] μC.

The potential difference is 7.5*10^5V and the charge on the smaller sphere is 6.67uC while the charge on the larger sphere is 13.34uC

Data;

for the inner sphere;

[tex]v_i = \frac{kq}{r} = \frac{(9*10^9)(5*10^-^6)}{0.03} \\v_i = 1.5*10^6V[/tex]

for the outer sphere;

[tex]v_o = \frac{KQ}{R} = \frac{(9*10^9)(15*10^-^6)}{0.06} = 2.25 * 10^6V[/tex]

The difference in potential is

[tex]\delta V = v_o - v_i = 2.25*10^6 - 1.5*10^6 = 7.5*10^5V[/tex]

[tex]q + Q = 5 + 15 = 20 \mu C = 20*10^-^6C ..eq(i)[/tex]

The sharing of charge continues till they attain a point of equal potential

[tex]v_i = v_o \\\frac{kq}{r} = \frac{kQ}{R} \\\frac{q}{0.03} = \frac{Q}{0.06} \\Q= 2q ...eq(ii)\\[/tex]

let's solve for equation (i) and equation (ii)

[tex]q+2q = 20\mu C\\q = 6.67 \mu C[/tex]

The charge on the smaller sphere is 6.67uC

The charge on the larger sphere is

[tex]Q = 2q\\q = 6.67 \mu C\\Q = 2 * 6.67 = 13.34 \mu C[/tex]

The charge on the larger sphere is 13.34uC

Learn more on potential difference on a charged particle here;

https://brainly.com/question/9383604

Answer: the first is incorrect the second is correct the third is correct

Explanation: the fourth is correct the fifth is incorrect

Answer:

1. The correct way a cell phone call goes out is;

The phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. Long wavelength

3. Microwave

Explanation:

1. When making a call through a cell phone, the speech made is digitized such that it is converted to electrical signals which are then converted into number strings that are transmitted out of the antenna of the phone as radio waves which are then picked up by the closest cellphone tower mast which then transmit the signal to the applicable central hub from where the signal is transmitted to the tower closest to the intended call receiver

Therefore, the correct option is that the phone call goes out, transmits through radio waves, then moves to the central hub. Then the signal go to the nearest tower to the receiver of the call

2. The property of AM frequencies that allow them to travel over long distances is long wavelength

The frequency of AM radio waves is between 540 kHz and 1600 kHz, which can be propagated as ground wave or by the ionosphere at night

3. Cell phones makes use of the subcategory of microwave which is the super high frequency (SHF) band which with a range of 3 GHz to 30 GHz

Answer:

.Cell phones convert sound waves into______waves.

-sound waves

.Electromagnetic waves used in cell phone communications are called?

-radio wave

.To send out a radio signal far and wide...it is called?

antenna

Explanation:

i might be wrong in ans c ok

Answer:

As the Sun ages it will enter another stage of stellar evolution where it's atmosphere begins to inflate.As the Sun heats up and expands, life on Earth will become increasingly difficult. Long before the Sun becomes a red giant some 4 or 5 billion years from now, our planet will be rendered uninhabitable.

~I HOPE IT HELPS♡

Answer: c

Explanation:

Sound waves cannot travel through a medium

Answer:

to have courage and show the strength of your character. ... A person with true grit has passion and perseverance. Goals are set and followed through.

Explanation:

for example: i had the passion and the courage to finish my school work and chores for i can go out with my friends and to get out of the house for a bit and have fun so i had the courage to finish chores from the house and do some schoolwork for i can finish ad hang out with some friends. so i had the strength to finish everything because i didn't want to be doing school work and chores any more so i had the passion to finish up quickly  

Answer:

A 50 kg ball traveling at 20 m/s would have 4 times more kinetic energy.

A 50 kg ball traveling at 5 m/s would have 4 times less kinetic energy.

A 50 kg person falling at 10 m/s would have the same kinetic energy.

Explanation:

hope this helps:)

Answer:

Cornea

Explanation:

The outer layer of the cornea is covered by epithelial cells that protect the surface. A corneal abrasion may result from dragging a piece of debris across the surface and scraping off the epithelial cells.

Answer:

C. Some waves

Explanation:

The answer is some waves because transverse waves are not the only types of waves we have on the earth. We also have longlitudal waves, which means only some waves can only be transverse. The answer to the question should be C. Some waves.