Pls look at photos I’ll give 30 points

Using the grid model, the product of 3 and 13 is 39

Product refers to the result of multiplying two or more numbers or quantities together. It is a fundamental operation in arithmetic and algebra. When multiplying two numbers, the product is obtained by adding together a number of copies of one of the numbers, equal to the value of the other number.

Given, two numbers 3 and 9, and a grid.

To determine the product of 3 and 13 just count all the grids covered in 3 rows up to 13 columns or adding 3 for 13 times will result in 39.

Count the grids covered in a red box attached in the image below.

3+3+3+3+3+3+3+3+3+3+3+3+3=39

So, the product of 3 and 13 is 39.

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Answer:

5/7

Step-by-step explanation:

3/4-1/28

21/28-1/28

20/28

simplify

5/7

Using the binomial distribution, it is found that there is a 0.8202 = 82.02% probability that the shipment will make it through the control check.

For each article, there are only two possible outcomes, either it meets the specifications, or it does not. The probability of an article meeting the specifications is independent of any other article, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

In this problem:

The probability is:

[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)[/tex]

Then:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 8) = C_{10,8}.(0.85)^{8}.(0.15)^{2} = 0.2759[/tex]

[tex]P(X = 9) = C_{10,9}.(0.85)^{9}.(0.15)^{1} = 0.3474[/tex]

[tex]P(X = 10) = C_{10,10}.(0.85)^{10}.(0.15)^{0} = 0.1969[/tex]

[tex]P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.2759 + 0.3474 + 0.1969 =  0.8202[/tex]

0.8202 = 82.02% probability that the shipment will make it through the control check.

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Answer:

1  7/10

Step-by-step explanation:

= 17/6 ÷ 5/3

= 17 x 3

= 6 x 5

= 51/30

= 1 7/10

Answer:

[tex]4xy[/tex]

Step-by-step explanation:[tex](40/10) *(x^-^4/x^-^5) * (y^6/y^5) \\=4*x*y=4xy[/tex]

x=-1

3x-2x+8=10x+20-3

x+8=10x+17

-9x=9

x=-1

Answer:

[tex]x=-1[/tex]

Step-by-step explanation:

[tex]x-2\left(x-4\right)=5\left(2x+4\right)-3[/tex]

[tex]-2\left(x-4\right)\\\mathrm{Distribute}\\-2x+8[/tex]

[tex]3x-2x+8=5\left(2x+4\right)-3[/tex]

[tex]\mathrm{Combine\: like\: terms}[/tex]

[tex]x+8=5\left(2x+4\right)-3[/tex]

[tex]\left(2x+4\right)-3\\\mathrm{Distribute}\\10x+20-3\\10x+17[/tex]

[tex]x+8=10x+17[/tex]

[tex]\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}[/tex]

[tex]x+8-8=10x+17-8[/tex]

[tex]x=10x+9[/tex]

[tex]\mathrm{Subtract\:}10x\mathrm{\:from\:both\:sides}[/tex]

[tex]x-10x=10x+9-10x[/tex]

[tex]-9x=9[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9x}{-9}=\frac{9}{-9}[/tex]

[tex]\bold{x=-1}[/tex]

Answer:

91%

Step-by-step explanation:

hopes this helps

Answer:

185.71%

Step-by-step explanation:

130 / 70 = 1.857142857

(1.857142857)(100) = 185.71%

Answer:

(a) The particle is moving to the right in the interval  [tex](0 \ , \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2} \ , \ 2\pi)[/tex] , to the left in the interval [tex](\displaystyle\frac{\pi}{2}\ , \ \displaystyle\frac{3\pi}{2})[/tex], and stops when t = 0, [tex]\displaystyle\frac{\pi}{2}[/tex], [tex]\displaystyle\frac{3\pi}{2}[/tex] and [tex]2\pi[/tex].

(b) The equation of the particle's displacement is [tex]\mathrm{s(t)} \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex]; Final position of the particle [tex]\mathrm{s(2\pi)} \ = \ 3[/tex].

(c)  The total distance traveled by the particle is 9.67 (2 d.p.)

Step-by-step explanation:

(a) The particle is moving towards the right direction when v(t) > 0 and to the left direction when v(t) < 0. It stops when v(t) = 0 (no velocity).

Situation 1: When the particle stops.

[tex]\-\hspace{1.7cm} v(t) \ = \ 0 \\ \\ 5 \ \mathrm{sin^{2}(t)} \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.3cm} \mathrm{sin^{2}(t) \ cos(t)} \ = \ 0 \\ \\ \mathrm{sin^{2}(t)} \ = \ 0 \ \ \ \mathrm{or} \ \ \ \mathrm{cos(t)} \ = \ 0 \\ \\ \-\hspace{0.85cm} t \ = \ 0, \ \displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2} \ \ \mathrm{and} \ \ 2\pi[/tex].

Situation 2: When the particle moves to the right.

[tex]\-\hspace{1.67cm} v(t) \ > \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ > \ 0[/tex]

Since the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is positive in the first and third quadrant or when [tex]\mathrm{t} \ \epsilon \ (0, \ \displaystyle\frac{\pi}{2}) \ \cup \ (\displaystyle\frac{3\pi}{2}, \ 2\pi)[/tex] .  

*Note that parentheses are used to demonstrate the interval of t in which cos(t) is strictly positive, implying that the endpoints of the interval are non-inclusive for the set of values for t.

Situation 3: When the particle moves to the left.

[tex]\-\hspace{1.67cm} v(t) \ < \ 0 \\ \\ 5 \ \mathrm{sin^2(t) \ cos(t)} \ < \ 0[/tex]

Similarly, the term [tex]5 \ \mathrm{sin^{2}(t)}[/tex] is always positive for all value of t of the interval [tex]0 \ \leq \mathrm{t} \leq \ 2\pi[/tex], hence the determining factor is cos(t). Then, the question becomes of when is cos(t) positive? The term cos(t) is negative in the second and third quadrant or  [tex]\mathrm{t} \ \epsilon \ (\displaystyle\frac{\pi}{2}, \ \displaystyle\frac{3\pi}{2})[/tex].

(b) The equation of the particle's displacement can be evaluated by integrating the equation of the particle's velocity.

[tex]s(t) \ = \ \displaystyle\int\ {5 \ \mathrm{sin^{2}(t) \ cos(t)}} \, dx \ \\ \\ \-\hspace{0.69cm} = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx[/tex]

To integrate the expression [tex]\mathrm{sin^{2}(t) \ cos(t)}[/tex], u-substitution is performed where

[tex]u \ = \ \mathrm{sin(t)} \ , \ \ du \ = \ \mathrm{cos(t)} \, dx[/tex].

[tex]s(t) \ = \ 5 \ \displaystyle\int\ \mathrm{sin^{2}(t) \ cos(t)} \, dx \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ \mathrm{sin^{2}(t)} \, du \\ \\ \-\hspace{0.7cm} = \ 5 \ \displaystyle\int\ \ u^{2} \, du \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5u^{3}}{3} \ + \ C \\ \\ \-\hspace{0.7cm} = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ C \\ \\ s(0) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(0)} \ + \ C \\ \\ \-\hspace{0.48cm} 3 \ = \ 0 \ + \ C \\ \\ \-\hspace{0.4cm} C \ = \ 3.[/tex]

Therefore, [tex]s(t) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(t)} \ + \ 3[/tex].

The final position of the particle is [tex]s(2\pi) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(2\pi)} \ + \ 3 \ = \ 3[/tex].

(c)

[tex]s(\displaystyle\frac{\pi}{2}) \ = \ \displaystyle\frac{5}{3} \ \mathrm{sin^{3}(\frac{\pi}{2})} \ + \ 3 \\ \\ \-\hspace{0.85cm} \ = \ \displaystyle\frac{14}{3} \qquad (\mathrm{The \ distance \ traveled \ initially \ when \ moving \ to \ the \ right})[/tex]

[tex]|s(\displaystyle\frac{3\pi}{2}) - s(\displatstyle\frac{\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(\frac{3\pi}{2})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | (-1) \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{10}{3} \\ \\ (\mathrm{The \ distance \ traveled \ when \ moving \ to \ the \ left})[/tex]

[tex]|s(2\pi) - s(\displaystyle\frac{3\pi}{2})| \ = \ |\displaystyle\frac{5}{3} \ (\mathrm{sin^{3}(2\pi})} \ - \ \mathrm{sin^{3}(\displaystyle\frac{3\pi}{2})})| \ \\ \\ \-\hspace{2.28cm} \ = \ \displaystyle\frac{5}{3} | 0 \ - \ 1| \\ \\ \-\hspace{2.42cm} = \displaystyle\frac{5}{3} \\ \\ (\mathrm{The \ distance \ traveled \ finally \ when \ moving \ to \ the \ right})[/tex].

The total distance traveled by the particle in the given time interval is[tex]\displaystyle\frac{14}{3} \ + \ \displaystyle\frac{5}{3} \ + \ \displaystyle\frac{10}{3} \ = \ \displaystyle\frac{29}{3}[/tex].

Answer: z < -8

Step-by-step explanation:

Since z is negative, divide both sides by -1, which leaves you with z > -8.

Multiplying or dividing an inequality by a negative number flips the sign, thus the answer is z < 8.

Correct me if I am incorrect.

if we can assume the ball is being thrown from the ground upwards, then we can say that the inital height of it is 0, whilst its initial velocity is 80 ft/s, thus

[tex]~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&80\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&0\\ \qquad \textit{of the object}\\ h=\textit{object's height}\\ \qquad \textit{at "t" seconds} \end{cases} \\\\\\ h(t)=-16t^2+80t+0\implies h(t)=-16t^2+80t[/tex]

Answer:

3/8 bottle

Step-by-step explanation:

Fractions are just division.

Martin + 2sisters + 5bros

= 8 people

3bottles ÷ 8people

= 3/8 bottles per person

Martin is a person, so he gets 3/8 of a bottle, if they all share equally.

Using proportions, it is found that Martin will get 0.375 of a bottle.

The rule of three is:

1 person - x bottles

8 people - 3 bottles

Applying cross multiplication:

[tex]8x = 3[/tex]

[tex]x = \frac{3}{8}[/tex]

[tex]x = 0.375[/tex]

Martin will get 0.375 of a bottle.

To learn more about proportions, you can take a look at https://brainly.com/question/24372153

[tex]t = \sqrt \frac{ {2(x - ut)} }{a} \\ = > t = \sqrt{ \frac{2x - 2ut}{a} } \\ = > {t}^{2} = \frac{2x - 2ut}{a} \\ = > a {t}^{2} = 2x - 2ut \\ = > \frac{ { - at}^{2} }{2ut} = 2x \\ = > \frac{ - at}{2u} = 2x \\ = > \frac{ - at}{2u \times 2} = x \\ = > \frac{ - at}{4u} = x[/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

The last one

Step-by-step explanation:

A ratio table means that each number in the first column is multiplied by the same number to get the answer in the 2nd column

Answer:

9.3 centimeters

Step-by-step explanation:

Answer:

what is the question?

Step-by-step explanation:

Answer:

6.15

Step-by-step explanation:

10 gallons is 80/8

1 5/8= 13/8

80 divided by 13 is 6.15384615385 but rounded 6.15

6.15 hours

if its not that then keep rounding to 6.2 or 6hrs

Answer:

Please send a picture or explain properly

Answer:

B. [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

The whole beaker is 1. If you measure the beaker, you will notice you can fill up the beaker to the brim (whole, which is 1) if you use the current amount 4 times, and four times is [tex]\frac{1}{4}[/tex].

Answer:

1/2

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

We have two points on the line

(-1,3) and ( 1,4)

m = ( 4-3)/(1 - -1)

   = (4-3)/(1+1)

    = 1/2

Answer:

Start where the line meets a point. Then go up and over until it meets another.

The answer is 1/2

So go up one and over two. Then other problems such as this one should be pretty straight forward

Amount Lucy will be paying in interest will be $38,596.2  

Using the compound amount formula to get the amount after she will pay back after 20 years expressed as:

[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]

Substitute the parameters into the formula;

[tex]A=73,250(1+\frac{0.0315}{12} )^{20(12)}\\A= $73,250 (1.8761)\\A= \$137,421.49[/tex]

If Excel calculates the monthly payment to be $411.77, the amount paid for 20 years will be $411.77 * 240months = $98,824.8

Amount Lucy will be paying interest will be $137,421- $98,824.8 = $38,596.2  

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Answer:

D: {-2, 0, 2}

R: {-1, 1, 3

Answer:

i think 4x+3y = -24 is answer

Answer:

The bottom right is a linear equation.

Step-by-step explanation:

Answer:

right side down one

Step-by-step explanation:

as you know linear means supplementary having 180 °

========================================================

Explanation:

x = Jose's speed in mph

x+35 = Kayla's speed since she drives 35 mph faster than Jose

Jose gets a 2.1 hour head start and it takes Kayla 1.2 hours to reach him. So this means Jose has been driving for 2.1+1.2 = 3.3 hours when Kayla reaches him. The distance he travels is

distance = rate*time

d = r*t

d = x*3.3

d = 3.3x

while Kayla's distance equation is

d = r*t

d = (x+35)*1.2

d = 1.2x+42

Since Kayla meets up with Jose at the 1.2 hour mark, this means the two distances they travel is the same. Set their distance expressions equal to one another. Solve for x.

3.3x = 1.2x+42

3.3x-1.2x = 42

2.1x = 42

x = 42/(2.1)

x = 20

Jose's speed is 20 mph, while Kayla's speed is x+35 = 20+35 = 55 mph.

Jose's fairly slow speed is probably due to a number of factors such as heavy traffic, icy roads, or poor visibility. Kayla probably got a bit of a break with more favorable conditions.

Since Jose travels at 20 mph and does so for 3.3 hours, he travels d = r*t = 20*3.3 = 66 miles. Kayla travels d = r*t = 55*1.2 = 66 miles as well. We get the same number each time to help confirm the answer.

The exact area of triangle ABC is 93.51 cm².

The given parameters;

The base of the triangle is calculated by using trigonometry ratio as follows;

[tex]tan (30) = \frac{b}{18} \\\\[/tex]

where;

[tex]b = 18 \times tan(30)\\\\b = 10.39 \ cm[/tex]

The area of the triangle ABC  with the calculated base and given height is calculated as follows;

[tex]A = \frac{1}{2} \times base \times height\\\\A = \frac{1}{2} \times 10.39 \times 18\\\\A = 93.51 \ cm^2[/tex]

Thus, the exact area of triangle ABC is 93.51 cm².

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