PLS HELP
Determine the dimensions for T if T = M V^2 A / L^3 where M is a mass, V is a velocity, A is an area, and L is a length.



L / T



No dimensions



M L / T^2



M



M / (L T^2)

Answers

Answer 1

Answer:

T=kg·m^2/s^2

Explanation:

T = kg (m^2/s^2) m^3 /m^3

Here I wrote down the unit for every dimension.

T=kg m^2 / s^2

m^3 is divided between m^3, this is equal to 1.

Result: T=kg·m^2/s^2

PD: I'm not sure if this is what you ask for. I hope it helps


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Exam Guidelines
Exam Instructions
Question 8 of 15 :
Select the best answer for the question.
8. You've been contracted to install hardwood flooring on a basketball court. The court
measures 125' x 70'. How many square feet of flooring do you need to order for the job?
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k
O A. 10,500 sq. ft.
O B.234 sq. ft.
O C. 100,500 sq. ft.
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Answers

Answer:

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Answer:

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Explanation:

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Answers

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Answers

Answer:

The answer of this question is 19.89142857

Answer:

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Read on to find the result of 222 divided by 11 in decimal notation, along with its properties.

Explanation:

Determine the dimensions for R if R = m V / (d^2 Q) where m is a mass, V is a velocity, d is a diameter, and the dimensions of Q are M/(LT).


No dimensions


M / (L T^2)


M L / T^2


M


L / T

Answers

Answer:

No dimension

Explanation:

The given equation is [tex]R = \dfrac{m \cdot V}{d^2 \cdot Q}[/tex], where;

m = Mass

V = Velocity

d = A diameter

The dimension of mass quantity = M

The dimension of the velocity quantity = L/T

The dimension of the dimeter quantity = L

The given dimension of Q = M/(L·T)

Therefore, we get;

[tex]The \ dimension \ of \ R = \dfrac{M \times L/T}{L^2 \times (M/LT)} = \dfrac{M \times L/T}{L \times M/T} = 1[/tex]

Therefore, R has no dimensions

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Answer:

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pls answer this thank you

Answers

Answer:

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Explanation:

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