PLS HELP please give an explanation if you don’t have one pls still give answer

Answer:

0.0783

Step-by-step explanation:

The probability of getting the first success on xtg trial ; this is a geometric distribution :

P(x) = p(1−p)^x−1

The probability of being a universal donor , p = 0.15

The probability of obtaining someone who is a universal donor on 5th trial will be :

P(5) = 0.15(1 - 0.15)^(5 - 1)

P(5) = 0.15(0.85)^4

P(5) = 0.15(0.52200625)

P(5) = 0.0783009375

P(5) = 0.0783

Least to greatest: 20,564 22,755 2,3805

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Explanation:

The phrasing "no less than" means the same as "at least".

Saying "at least 37" means 37 is the lowest we can go.

If x is the number of disconnected calls, then [tex]x \ge 37[/tex] and we want to find the probability of this happening (the max being 295).

We could use the binomial distribution to find the answer, but that would require adding 295-37+1 = 259 different values which could get tedious. So we could use the normal approximation to make things relatively straight forward.

Assuming this binomial meets the requirements of the normal approximation, then we'd look under the normal curve for the area to the right of 36.5; which is why the answer is choice A.

Why 36.5 and not 37? This has to do with the continuity correction factor when translating from a discrete distribution (binomial) to a continuous one (normal).

If we used 37, then we'd be missing out on the edge case. So we go a bit beyond 37 to capture 36.5 instead. It's like a fail safe to ensure we do account for that endpoint of 37. It's like adding a buffer or padding.

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Side notes:

Answer:

The obove picture the rule is SSA

Answer:

The sampling distribution of the sample mean is approximately normal with mean 72 and standard deviation 1.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Normally distributed with mean 72 and standard deviation 6.

This means that [tex]\mu = 72, \sigma = 6[/tex]

A random sample of size 36

This means that [tex]n = 36, s = \frac{6}{\sqrt{36}} = 1[/tex]

The sampling distribution of the sample mean is

By the Central Limit Theorem, it is approximately normal with mean 72 and standard deviation 1.

Answer:

Step-by-step explanation:

A.

[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]

which equation has the steepest graph ?

[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]

[tex]y = mx + c[/tex]

[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]

[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]

[tex] \blue{A.T.Q}[/tex]

PART A:-

[tex]y = mx + c \sim y= -14x+1 [/tex]

[tex] \orange{SO}[/tex]

m= (-14)

which is equal to the slope of the equation .

PART B:-

[tex]y = mx + c \sim y= ¾x-9 [/tex]

[tex] \orange{SO}[/tex]

m= (¾)

PART C:-

[tex]y = mx + c \sim y= 10x-5[/tex]

[tex] \orange{SO}[/tex]

m= (10)

PART D:-

[tex]y = mx + c \sim y= 2x+8[/tex]

[tex] \orange{SO}[/tex]

m= (2)

Negative shows Slope is in negative direction.

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

Answer:

The probability that in a sample of 400 registered voters at least 290 voted in their most recent local elections is:

= 72.5%

Step-by-step explanation:

Sample of registered voters = 400

Sample of voters that actually voted = 290

Probability = 290/400 * 100

= 72.5%

b) This result above gives the statistic that for every 100 registered voters, 72.5 voters voted.  Probability measures the chance of an event occurring given other events.  Therefore, one can conclude that the voting was at least 72.5%.  Inversely, 27.5% of the registered voters did not participate or cast their ballots in the local elections.

Answer:

[tex]{ \tt{ \frac{819}{13} = \frac{441}{h} }} \\ { \tt{h = \frac{(441 \times 13)}{819} }} \\ h = 7 \: hours[/tex]

Answer:

Step-by-step explanation:

i think if its -10 degrees i think the fahrenheit would be 50 degrees

Answer:

The insurance company should charge $1,873.5.

Step-by-step explanation:

Expected earnings:

1 - 0.99813 = 0.00187 probability of the company losing $1 million(if the client dies).

0.99813 probability of the company earning x(price of the insurance).

What premium would an insurance company charge to break even on a one-year $1 million term life insurance policy?

Break even means that the earnings are 0, so:

[tex]0.99813x - 0.00187(1000000) = 0[/tex]

[tex]0.99813x = 0.00187(1000000)[/tex]

[tex]x = \frac{0.00187(1000000)}{0.99813}[/tex]

[tex]x = 1873.5[/tex]

The insurance company should charge $1,873.5.

Hey there!

2 1/4

= 2 * 4 + 1 / 4

= 8 + 1 / 4

= 9 / 4

= 9 ÷ 4

= 2.25

Therefore, your answer is: 2.25

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

- Bar Gaps should be the same

Y-axis up in units of 5 would help out

Step-by-step explanation:

Answer:

x<-12

Step-by-step explanation: hope this helps!

Answer:

A) P(Type I error) = 0.045

B) P(Type II) error = 0.1

Step-by-step explanation:

We are told that the reliability of the test is 90% reliable.

Also, we are told that the probability that the test erroneously detects a lie even when the individual is actually telling the truth is 0.045.

Thus;

A) To calculate the probability of type I error:

From statistics, in this question we can say that the probability of a type I error is the probability that the test will erroneously detect a lie even though the individual is actually telling the truth. Thus;

Probability of (type I error) = P(rejecting true null) = 0.045

B) For probability of type II error, it is defined as the error where we accept a null hypothesis that is false. We can say that it produces a false negative and the formula is;

P(Type II) error = 1 - reliability

Reliability in the question is 0.90

Thus;

P(Type II) error = 1 - 0.9

P(Type II) error = 0.1

Answer:

Given Two equations :-

[tex]3x {}^{2} - 2 {y}^{2} = 57 .\: .\: .\: . \:(i) \\ - 2 {x}^{2} + 3 {y}^{2} = -23.\: .\: .\: . \:(ii)[/tex]

[tex](3x {}^{2} - 2 {y}^{2} = 57 ) \times 2 .\: .\: .\: . \:(i) \\ ( - 2 {x}^{2} + 3{y}^{2} = - 23) \times 3.\: .\: .\: . \:(ii)[/tex]

[tex]6x {}^{2} - 4 {y}^{2} =114 .\: .\: .\: . \:(i) \\ - 6 {x}^{2} + 9 {y}^{2} = - 69.\: .\: .\: . \:(ii)[/tex]

[tex]0 + 5 {y}^{2} = 45 \\ 5y {}^{2} = 45 [/tex]

[tex] {y}^{2} = 9[/tex]

[tex]y = + - 3[/tex]

3x²- 2×9 = 57

3x² - 18 = 57

3x² = 57 + 18

3x²= 75

x² = 25

x = ± 5

Answer:

see the attachment

Step-by-step explanation:

Hope it helps you

Answer:

9ab+3a

Step-by-step explanation:

(2a+a)(3b+1)=(3a)(3b+1)

3a(3b+1)

=(3a×3b)+3a×1

=9ab+3a

Answer:

L = 0.16 yd, W = 0.22 yd

Step-by-step explanation:

Dimensions of play ground 23/147 yd x 3/14 yd

reducing factor 2/147

Let the original length is L.

[tex]L - \frac{2L}{147} = \frac{23}{147}\\\\L\frac{143}{147} = \frac{23}{147}\\\\L=\frac{23}{143} yd[/tex]

L = 0.16 yd

Let the width is W.

[tex]W - \frac{2W}{147} = \frac{3}{14}\\\\W\frac{143}{147} = \frac{3}{14}\\\\W=0.22 yd[/tex]

The amount of water released from the sprinkler for 80 minutes is 200 L

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the amount of water from the sprinkler for 80 minutes be = A

Now , the value of A is given by the equation

A sprinkler releases water st a rate of 150 liters per hour

So , 60 minutes = 150 Liters of water

80 minutes = 1/60 hours

80 minutes = 1.333 hours

The amount of water released for 1.333 hours A = 150 x 1.333

On simplifying the equation , we get

The amount of water released for 1.333 hours A = 200 L

Therefore , the value of A is 200 L

To learn more about equations click :

https://brainly.com/question/19297665

#SPJ2

Answer:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Step-by-step explanation:

for person A, we know that earns $40, then we can write the equation:

-4*z + 3*x + 3*y = $40

For person B, we know that earns $50, then:

1*z + 2*x - 3*y = $50

For person C, we know that earns $130, then:

6*z - 1*x + 4*y = $130

Then we have a system of equations:

-4*z + 3*x + 3*y = $40

1*z + 2*x - 3*y = $50

6*z - 1*x + 4*y = $130

To solve the system, we need to isolate one of the variables in one of the equations.

Let's isolate z in the second equation:

z = $50 - 2*x + 3*y

now we can replace this in the other two equations:

-4*z + 3*x + 3*y = $40

6*z - 1*x + 4*y = $130

So we get:

-4*($50 - 2*x + 3*y) + 3*x + 3*y = $40

6*($50 - 2*x + 3*y) - 1*x + 4*y = $130

Now we need to simplify both of these, so we get:

-$200 + 11x - 9y = $40

$350 - 13*x + 28*y = $130

Now again, we need to isolate one of the variables in one of the equations.

Let's isolate x in the first one:

-$200 + 11x - 9y = $40

11x - 9y = $40 + $200 = $240

11x = $240 + 9y

x = ($240 + 9y)/11

Now we can replace this in the other equation:

$350 - 13*x + 28*y = $130

$350 - 13*($240 + 9y)/11 + 28*y = $130

Now we can solve this for y.

- 13*($240 + 9y)/11 + 28*y  = $130 - $350 = -$220

-13*$240  - (13/11)*9y + 28y = - $220

y*(28 - (9*13/1) ) = -$220 + (13/11)*$240

y = ( (13/11)*$240 - $220)/(28 - (9*13/1) ) = $3.66

We know that:

x = ($240 + 9y)/11

Replacing the value of y, we get:

x = ($240 + 9*$3.66)/11  = $24.81

And the equation of z is:

z = $50 - 2*x + 3*y = $50 - 2* $24.81 + 3*$3.66 = $11.36

Then:

Price of X is $24.81

Price of Y is $3.66

Price of Z is $11.36

Answer:

7sin

2

x+3cos

2

x=4

4sin

2

x+3sin

2

x+3cos

2

x=4

4sin

2

x+3=4

4sin

2

x=1

sin

2

x=

4

1

sinx=

2

1

or sinx=−

2

1

Step-by-step explanation:

TAKING THE POSITIVE ROOT x=

6

π

tan(

6

π

)=

3

1

Answer:

100-70=30 so

55*0.3=16.5

Hope This Helps!!!

Answer:

Answer :

70% less than 55 is

16.5

Answer:

Tommy's age is 9 years old.

Timmy's age is 14 years old.

Step-by-step explanation:

Take Tommy's age to be x and Timmy's age to be x+5

x+x+5=23

2x+5=23

2x=23-5=18

x=18÷2=9

x+5=9+5=14

Answer:

If you buy per dozen, each buns costs about 91 cents.

You will save $4.11 if you buy per dozen.

Step-by-step explanation:

1.25 * 12= $15

10.89/12= .9075 = .91 cents

15-10.89= $4.11

Hello my dear friend of USA !!!

DB/AD = BE/EC

=> 6/4 = x+1/x

=> 6x = 4x + 4

=> 2x = 4

=> x = 2

So x = 2

I am from INDIA.

Lots of love ❤️!!!

Have a great day ahead!

Answer:

x = 2

Step-by-step explanation:

[tex]\frac{6}{4} = \frac{x+1}{x}[/tex]

6x = 4x + 4

2x = 4

x = 2

Answer:

I will say 2,000 yes so that is what I am putting

Answer:

[tex]F = 39.47[/tex]

Step-by-step explanation:

Given

[tex]n = 30[/tex] --- observations

[tex]p = 1[/tex] -- variables

[tex]SSR = 1,297[/tex]

[tex]SSE= 920[/tex]

Required

The F statistic

This is calculated using:

[tex]F = \frac{SSR}{p} \div \frac{SSE}{n - p -1}[/tex]

[tex]F = \frac{1297}{1} \div \frac{920}{30 - 1 -1}[/tex]

[tex]F = \frac{1297}{1} \div \frac{920}{28}[/tex]

[tex]F = 1297 \div \frac{920}{28}[/tex]

Rewrite as:

[tex]F = 1297 * \frac{28}{920}[/tex]

[tex]F = \frac{1297 *28}{920}[/tex]

[tex]F = \frac{36316}{920}[/tex]

[tex]F = 39.47[/tex]

Answer:

True

Step-by-step explanation:

Each f(x) value increases by 5 so therefore this function would be linear

Hope you understand :)

Answer:

La suma de las dos matrices cuadradas de dimensión 2 es [tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex].

Step-by-step explanation:

Considerando que se tratan de dos matrices de igual dimensión y cuyos elementos son números reales, conocemos que la adición entre dos matrices consiste en las sumas de los elementos de igual posición, esto es, los elementos que están localizados en las mismas filas y columnas, entonces, la suma es:

[tex]\vec A = \left[\begin{array}{cc}1&2\\-1&0\end{array} \right][/tex], [tex]\vec B = \left[\begin{array}{cc}-2&9\\3&5\end{array}\right][/tex]

[tex]\vec U = \vec A + \vec B = \left[\begin{array}{cc}1 + (-2)&2+9\\-1 + 3&0 + 5\end{array}\right][/tex]

[tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex]

La suma de las dos matrices cuadradas de dimensión 2 es [tex]\vec U = \left[\begin{array}{cc}-1&11\\2&5\end{array}\right][/tex].