Pls answer 9 Through 12

Answer:

They have different wavelengths.

They have different frequencies.

They propagate at different speeds through non-vacuum media depending on both their frequency and the material in which they travel.

Explanation:

The complete question is

Consider the following:

a) radio waves emitted by a weather radar system to detect raindrops and ice crystals in the atmosphere to study weather patterns;

b) microwaves used in communication satellite transmissions;

c) infrared waves that are perceived as heat when you turn on a burner on an electric stove;

d) the multicolor light in a rainbow;

e) the ultraviolet solar radiation that reaches the surface of the earth and causes unprotected skin to burn; and

f) X rays used in medicine for diagnostic imaging.

Which of the following statements correctly describe the various forms of EM radiation listed above?

check all that apply to the above

They have different wavelengths.

They have different frequencies.

They propagate at different speeds through a vacuum depending on their frequency.

They propagate at different speeds through non-vacuum media depending on both their frequency and the material in which they travel.

They require different media to propagate.

All the above phenomena are due the electromagnetic wave spectrum. Electromagnetic waves travel at a constant speed of 3 x 10^8 m/s in a vacuum. Within the spectrum, the different types of electromagnetic waves exists in different band range of frequencies and wavelengths unique to each of the waves, and the energy they carry. When these waves enter a non-vacuum medium, their speed change, depending on the nature of the material of the medium, and the frequency or the wavelength of the incoming wave.

Answer:

The mass of ball C is greater than the mass of ball A but less than the mass of ball B.

Explanation:

From Newton's second law, net force = mass × acceleration.

Using the data for ball B, the acceleration of gravity near the surface of the moon is:

∑F = ma

9.6 N = (6 kg) a

a = 1.6 m/s²

Therefore, the mass of ball C is:

∑F = ma

6.6 N = m (1.6 m/s²)

m = 4.1 kg

Answer:

The average force of wind on the building is 4.728 x 10¹² N

Explanation:

Given;

speed of the air wind, v = 124 km/h

dimension of the building, 42 m wide by 73 m high

density of the air, ρ = 1.3 kg/cm³ =

speed of the air in m/s = 124/3.6 = 34.44 m/s

Area of the building, A = 42 m x 73 m = 3066 m²

density of the air in (k.g/m³);

[tex]\rho = \frac{1.3 \ kg}{cm^3} *(\frac{100\ cm}{1 \ m} )^3\\\\\rho = \frac{1.3 \ kg}{cm^3} *\frac{10^6\ cm^3}{1 \ m^3} = \frac{1.3*10^6 \ kg}{m^3}[/tex]

The average force of wind on the building;

F = mass flow rate x velocity

F = (ρvA) x V

F = ρAv²

F = 1.3 x 10⁶ x 3066  x (34.44)²

F = 4.728 x 10¹² N

Therefore, the average force of wind on the building is 4.728 x 10¹² N

Answer:

True

Explanation:

J. Henry Alston was known as a famous African American psychologist. He was known through his thorough study of the sensations of heat and cold.

He thereby became the first African American to publish his research findings on the perception of heat and cold in a major US psychology journal and was an important figure in the field.

Answer:

0

Explanation:

Answer:

0.96 m

Explanation:

First, convert km/h to m/s.

162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s

Now find the time it takes to move 20 m horizontally.

Δx = v₀ t + ½ at²

20 m = (45.08 m/s) t + ½ (0 m/s²) t²

t = 0.4436 s

Finally, find how far the ball falls in that time.

Δy = v₀ t + ½ at²

Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²

Δy = -0.96 m

The ball will have fallen 0.96 meters.

Answer:

After the bullet emerges the block moves at 0.99 m/s

Explanation:

Given;

mass of bullet, m₁ = 22 g = 0.022 kg

initial speed of the bullet, u₁ = 240 m/s

final speed of the bullet, v₁ = 150 m/s

mass of block, m₂ = 2.0 kg

initial speed of the block, u₂ = 0

Let the final speed of the block = v₂

Apply principles of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.022 x 240 + 2 x 0 = 0.022 x 150 + 2v₂

5.28 = 3.3 + 2v₂

5.28 - 3.3 = 2v₂

1.98 = 2v₂

v₂ = 1.98 / 2

v₂ = 0.99 m/s

Therefore, after the bullet emerges the block moves at 0.99 m/s

The body moves at a speed of 2.61m/s after the bullet emerges.

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

Based on the law above;

[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]

v is the final velocity of the body after the collision

Substitute the given parameters into the formula as shown:

[tex]0.022(240) + 2(0) = (0.022+2)v\\ 5.28 = 2.022v\\v=\frac{5.28}{2.022}\\v= 2.611m/s[/tex]

This shows that the body moves at a speed of 2.61m/s after the bullet emerges.

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Answer:

The water is flowing at the rate of 28.04 m/s.

Explanation:

Given;

Height of sea water, z₁ = 10.5 m

gauge pressure, [tex]P_{gauge \ pressure}[/tex] = 2.95 atm

Atmospheric pressure, [tex]P_{atm}[/tex] = 101325 Pa

To determine the speed of the water, apply Bernoulli's equation;

[tex]P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2[/tex]

where;

P₁ = [tex]P_{gauge \ pressure} + P_{atm \ pressure}[/tex]

P₂ = [tex]P_{atm}[/tex]

v₁ = 0

z₂ = 0

Substitute in these values and the Bernoulli's equation will reduce to;

[tex]P_1 + \rho gz_1 + \frac{1}{2}\rho v_1^2 = P_2 + \rho gz_2 + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 + \frac{1}{2}\rho (0)^2 = P_2 + \rho g(0) + \frac{1}{2}\rho v_2^2\\\\P_1 + \rho gz_1 = P_2 + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + P_{atm} + \rho gz_1 = P_{atm} + \frac{1}{2}\rho v_2^2\\\\P_{gauge} + \rho gz_1 = \frac{1}{2}\rho v_2^2\\\\v_2^2 = \frac{2(P_{gauge} + \rho gz_1)}{\rho} \\\\v_2 = \sqrt{ \frac{2(P_{gauge} + \rho gz_1)}{\rho} }[/tex]

where;

[tex]\rho[/tex] is the density of seawater = 1030 kg/m³

[tex]v_2 = \sqrt{ \frac{2(2.95*101325 \ + \ 1030*9.8*10.5 )}{1030} }\\\\v_2 = 28.04 \ m/s[/tex]

Therefore, the water is flowing at the rate of 28.04 m/s.

Answer:

C. effusion because there is a movement of a gas through a small opening into a larger volume

Explanation:

Edge2020

Have a great day y'all :)

Answer:

The force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.

Explanation:

Given;

current though the two parallel wires, I₁ and I₂ = 5A

distance between the two wires, R = 1 m

The force per unit of the wires is calculated as;

[tex]\frac{F}{L} = \frac{\mu_o I_1I_2}{2\pi R}[/tex]

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

Substitute in the given values into the equation and determine the force per unit length (F/L).

[tex]\frac{F}{L} = \frac{\mu_o I_1I_2}{2\pi R} \\\\ \frac{F}{L} = \frac{4\pi *10^{-7}*5*5}{2\pi *1}\\\\ \frac{F}{L} = 5*10^{-6} \ N/m \ (repulsive)[/tex]

Therefore , the force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.

Answer:

Statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1

Explanation:

Both the velocity and kinetic energy of a gas molecule depends on its relative molecular mass according to Graham's law of diffusion in gases. Hence, the greater the relative molecular mass of the gas, the lesser its average velocity and kinetic energy.

Hence we can see that statement 2 vividly explains the postulation of statement 1 and makes the points more easily comprehensible.

Answer:

(a). V₁ = 10m/s (velocity inside the house), V₂ = 5m/s (velocity at ground level)

(b). P₂ = 236500 Pa

Explanation:

This is quite straight-forward so let us begin by defining the terms given.

Given that;

The cross-section area inside the student's house A₁ = 0.50 0.50 x 10-4m2.

Let us make the velocity of water inside the house be V₁

such that the Volume of water entering the per second is = A₁V₁

Therefore, in 90sec:

45 L =  90 A₁V₁

V₁ = 45 * 10⁻³m³ / 90*0.5*10⁻⁴

V₁ = 10m/s            (velocity of water inside the house)

From the continuity equation we have that;

A₁V₁ = A₂V₂

0.5*10⁻⁴ * 10 = 1*10⁻⁴ V₂

V₂ = 5m/s               (velocity at ground level)

(b). We are told to calculate the water pressure in the pipeline at the ground level.

Using Bernoulli's equation;

P₁ + pgh₁ + 1/2PV₁²  (inside)      =       P₂ + pgh₂ + 1/2PV₂²   (ground level)

1.01*10⁵ + 1000*9.8*10 + 1/2*1000*(10)² = P₂ + 0 + 1/2*1000*(5)²

P₂ (pressure) = 1.01*10⁵Pa

Therefore we have;

101000 + 98000 + 50000 = P₂ + 12500

P₂ = 236500 Pa

cheers I hope this helped !!

Answer:

f = 127.48 Hz ,  T = 7.844 1⁻³ s ,  Ф = 3.38 ,     λ = 12.49 m

Explanation:

The general equation for the motion of a wave in a string is

          y = A sin (kx -wt + fi)

the expression they give is

         y = ym sin (0.503x + 801 t + 3.38 )

the veloicda that accompanies time is

      w = 801   rad / s

angular velocity is related to frequency

      w = 2π f

      f = w / 2π

      f = 801 / 2π

      f = 127.48 Hz

The period is the inverse of the frequency

      T = 1 / f

       T = 1 / 127.48

      T = 7.844 10⁻³ s

the csntnate of phase fi is the independent term

      Ф = 3.38

the wave vector accompanies the position k = 0.503 cm

       ka = 2pi /λ

       λ = 2 π / k

       λ = 2 π / 0.503

       λ = 12.49 m

Answer:

1)  the two objects reach the floor at the same time.

2)the book reaches the floor much earlier than the foil

In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more

Explanation:

This interesting experiment has the following results

1) first case. Sheet on top of book

In this case the two objects reach the floor at the same time.

This shows that the acceleration in the two objects is the same and we call it the acceleration of gravity.

The speed of the body increases as it goes down linearly.

This occurs because the book that receives air resistance is much heavier, so the resistance has almost no effect on its movement, the sheet does not have the air resistance because it goes down next to the book.

2) second case. Book and sheet next to each other.

In this case the book reaches the floor much earlier than the foil.

This is because the resisting force of the air has almost no effect on the book and its movement is little affected by this force.

In the case of the blade, it has very little weight, therefore as its speed increases, the resistance force of the air rapidly equals the weight of the blade.

           W_sheet - fr = 0

so after this, since the acceleration is zero, it goes down at constant speed, this speed is called the terminal velocity.

In conclusion, the difference in motion between the two systems subjected to the same acceleration depends on the weight of the body and friction force, when the body has less weight, the friction of the air affects it more.

Answer :

(a). The speed of the block is 0.395 m/s.

(b). No

Explanation :

Given that,

Diameter = 20.0 cm

Power = 26.0 MW

Mass = 110 kg

diameter = 20.0 cm

Distance = 100 m

We need to calculate the pressure due to laser

Using formula of pressure

[tex]P_{r}=\dfrac{I}{c}[/tex]

[tex]P_{r}=\dfrac{P}{Ac}

Put the value into the formula

[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}[/tex]

[tex]P_{r}=2.75\ N/m^2[/tex]

We need to calculate the force

Using formula of force

[tex]F=P\times A[/tex]

[tex]F=P\times \pi r^2[/tex]

Put the value into the formula

[tex]F=2.75\times\pi (0.01)^2[/tex]

[tex]F=0.086\ N[/tex]

We need to calculate the acceleration

Using formula of force

[tex]F=ma[/tex]

Put the value into the formula

[tex]0.086=110\times a[/tex]

[tex]a=\dfrac{0.086}{110}[/tex]

[tex]a=0.000781\ m/s^2[/tex]

[tex]a=7.81\times10^{-4}\ m/s^2[/tex]

(a). We need to calculate speed of the block

Using equation of motion

[tex]v^2=u^2+2ad[/tex]

Put the value into the formula

[tex]v=\sqrt{2\times7.81\times10^{-4}\times100}[/tex]

[tex]v=0.395\ m/s[/tex]

(b). No because the velocity is very less.

Hence, (a). The speed of the block is 0.395 m/s.

(b). No

Answer:

10kg

Explanation:

Let PE=potential energy

PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

PE=m*g*(change in h)

196=m*9.8*2

m=10kg

Answer:

B. The maximum angle decreases

Explanation:

If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .

tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .

So the tan of angle of repose θ is proportional to coefficient of static friction.

If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie,  it at lower angle of inclination , the object will start slipping .

Answer:

Some protons align with the field and some align opposite to it.

Explanation:

Majority align to the field because these protons tend to act like small magnets under the effect of this external field

On account of external magnetic field, the protons will align with the magnetic field. Hence, option (a) is correct.

The given problem is based on the concept of magnetic field. The region where the magnetic force is experienced is known as magnetic field. Generally, the protons are the charged entities carrying the positive polarity and are one of the major constituents of modern atomic structure.

Thus, we can conclude that on account of external magnetic field, the protons will align with the field.

Learn more about the magnetic field here:

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Explanation:

A cheetahs force, velocity, and acceleration are related because velocity goes by seconds/mile per hour, force goes by strength and energy, and acceleration goes by how the velocity changes the speed.

Answer:

its B

Explanation:

Answer:

It's B

Explanation: hope it helps ^w^

Answer:

 n (a sin θ) =  m λ₀

n> 1, therefore the fringes move away from each other

Explanation:

The diffraction experiment the constructive interference fringes is described by

          a sin θ = m λ₀

in this equation it is assumed that the experiment emptied the air n = 1

When the same experiment is performed in water, the wavelength changes

           λₙ = λ₀ / n

execution for constructive interference

            a sin θ = m λₙ

we substitute

           a sin θ = m λ / n

           n (a sin θ) =  m λ₀

the refractive index of water is n = 1.33, so for the same wavelength the separation of the spectrum is multiplied by n> 1, therefore the fringes move away from each other

Answer:

1.3

Explanation:

it will taken to as in from of standard form

Answer:

1.3 * 10^-5

Explanation:

We are learning about scientific notation.

When a number becomes a decimal followed before with zeroes, we know that the value of that number is decreasing. So instead of usually doing a positive exponent, we will do a negative exponent indicating we are going back.

So let's not only count the amount of zeroes followed before 13, but the decimal.

0.000013

The original number "1.3" went back 5 spaces, therefore making our exponent 5.

1.3 * 10^-5

Answer:

The force of the radiation on the surface is  3.33 X 10⁻¹⁰ N

Explanation:

Given;

intensity of light, I = 1 kw/m²

area of the surface, A = 1 cm² = 1 x 10⁻⁴ m²

Power of the incident light, P = I x A

Power of the incident light, P = (1 kw/m²) x (1 x 10⁻⁴ m²)

Power of the incident light, P = 1 x 10⁻⁴ kW = 0.1 W

Power of the incident light is given by;

P = Fv

where;

F is the force of the radiation on the surface

v is the speed of light = 3 x 10⁸ m/s

F = P/ v

F = (0.1) / (3 x 10⁸)

F = 3.33 X 10⁻¹⁰ N

Therefore, the force of the radiation on the surface is  3.33 X 10⁻¹⁰ N

Answer:

GPS receivers provide location in latitude, longitude, and altitude. They also provide the accurate time. GPS includes 24 satellites that circle Earth in precise orbits.

Answer:

Density = 1.1839 kg/m³

Mass = 227.3088 kg

Specific Gravity = 0.00118746 kg/m³

Explanation:

Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³

Now, from tables, density of air at 25°C is 1.1839 kg/m³

Now formula for density is;

ρ = mass(m)/volume(v)

Plugging in the relevant values to give;

1.1839 = m/192

m = 227.3088 kg

Formula for specific gravity of air is;

S.G_air = density of air/density of water

From tables, density of water at 25°C is 997 kg/m³

S.G_air = 1.1839/997 = 0.00118746 kg/m³

Answer:

A static observer hears a sound whose frequency is appreciably different from actual frequency because here the change in frequency of the sound due to doppler effect.

Explanation:

Given that,

Frequency = f

We know that,

The sound source of frequency f moves with constant velocity through a medium that is at rest.

A static observer hears a sound whose frequency is significantly different from actual frequency due to doppler effect.

We know that,

The doppler effect is defined as

[tex]f=f_{0}(\dfrac{v+v_{0}}{v-v_{s}})[/tex]

Where, f₀ = actual frequency

f = observe frequency

v = speed of sound

[tex]v_{o}[/tex] = speed of observer

[tex]v_{s}[/tex] = speed of source

Hence, A static observer hears a sound whose frequency is significantly different from actual frequency because here the change in frequency of the sound due to doppler effect.

Answer:

is the equation for magnetic force on a length l of wire carrying a current I in a uniform magnetic field B, as shown in Figure 2. If we divide both sides of this expression by l, we find that the magnetic force per unit length of wire in a uniform field is F l=IBsinθ.

Explanation:

C.) Alpha Centauri

Explanation:

Due to it being the closest planetary system to earth.

About 4.367 light years away.

Answer: not enough information given

Explanation:

Answer:

The frequency changes by a factor of  0.27.

Explanation:

The frequency of an object with mass m attached to a spring is given as

[tex]f[/tex] = [tex]\frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]

where [tex]f[/tex] is the frequency

k is the spring constant of the spring

m is the mass of the substance on the spring.

If the mass of the system is increased by 14 means the new frequency becomes

[tex]f_{n}[/tex] = [tex]\frac{1}{2\pi } \sqrt{\frac{k}{14m} }[/tex]

simplifying, we have

[tex]f_{n}[/tex] = [tex]\frac{1}{2\pi \sqrt{14} } \sqrt{\frac{k}{m} }[/tex]

[tex]f_{n}[/tex] = [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex]

if we divide this final frequency by the original frequency, we'll have

==> [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex]  ÷  [tex]\frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]

==> [tex]\frac{1}{3.742*2\pi } \sqrt{\frac{k}{m} }[/tex]  x  [tex]2\pi \sqrt{\frac{m}{k} }[/tex]

==> 1/3.742 = 0.27

Answer:

400 N

Explanation:

Pressure is equal on both pistons.

P = P

F / A = F / A

F / (πd²/4) = F / (πd²/4)

F / d² = F / d²

1600 N / (8.0 cm)² = F / (4.0 cm)²

F = 400 N

The force that should be applied to the smaller piston is 400 N.

Given that,

Based on the above information, the calculation is as follows:

[tex]1600 N \div (8.0 cm)^2 = F \div (4.0 cm)^2[/tex]

F = 400 N

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