PLLLzzzzzzzz helpppp Which is correct lab safety? A) Rodney wafted the fumes produced during the reaction toward his nose. B) Andrew heated the test tube towards himself in order to better observe the reaction. Eliminate C) Kadie was aware of the lab procedures that day so she began the lab before the rest of the class to be sure she would finish. D) Suzanne did not use all of the sulfuric acid she poured out for the experiment, so she returned the remainder to the stock bottle.

Answer:

3

Explanation:

Answer:

3.5 mol

Explanation:

Step 1: Given data

Moles of HCl: 7.0 mol

Step 2: Write the balanced equation

Fe(s) + 2 HCl(aq) ⇒ FeCl₂(aq) + H₂(g)

Step 3: Calculate the moles of H₂ gas produced from 7.0 moles of HCl

According to the balanced equation, the molar ratio of HCl to H₂ is 2:1.

7.0 mol HCl × 1 mol H₂/2 mol HCl = 3.5 mol H₂

Answer:

They agree to ethical standards when they are licensed.

Explanation:

Answer:

C) They agree to ethical standards when they are licensed

Explanation:

Answer:

it is 25%

Explanation:

Answering so you can give the other person brainliest :D have a good day

based on the law of conservation of energy its it atoms hold by strong chemical bonds

Answer:

a. 6 moles of O₂

b. 4.06×10²⁴ molecules of O₂

c. 3.04 g of KCl

Explanation:

Reaction of decomposition is:

2KClO₃  →  2KCl  +  3O₂

a. See stoichiometry value

2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3

If 2 moles of KClO₃ can decompose to 3 moles of O₂

Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂

b. In this case, the stoichiometry is the same.

Per 2 moles of KClO₃, I produce 2 moles of KCl

Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃

We apply, the last relation:

(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.

How many molecules are in 6.75 moles?

6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂

c. First of all, we convert the mass to moles:

5g . 1mol /122.55g = 0.0408 moles of salt

As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl

We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g

Answer:

See explanation

Explanation:

When the complex ion Co(H2O)6 2+(aq) is placed in solution and chloride ions are added, the following equilobrium is set up;

  Co(H2O)62+(aq) + 4 Cl-(aq) <=> CoCl42-(aq) + 6 H2O(g)

Co(H2O)6 2+(aq) solution  is pink in colour while CoCl42-(aq) solution is blue in colour.

Since the solubility of CoCl42-(aq) is endothermic, heating the solution will move the equilibrium position towards the right (more CoCl42-(aq) is formed and the solution is blue in colour).

When the solution is cooled, more Co(H2O)62+(aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in colour.

When the solution is cooled, more [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.

When the complex ion [tex]Co(H_2O)_6^{2+}[/tex] (aq) is placed in solution and [tex]CoCl_4^{2-}[/tex] are added, the following equilibrium is set up;

[tex]Co(H_2O)_6^{2+}(aq) + 4 Cl^-(aq) < = > CoCl_4^{2-}(aq) + 6 H_2O(g)[/tex]

[tex]Co(H_2O)_6^{2+}[/tex] (aq) solution  is pink in color while [tex]CoCl_4^{2-}[/tex](aq) solution is blue in color. Since the solubility of [tex]CoCl_4^{2-}[/tex](aq) is endothermic, heating the solution will move the equilibrium position towards the right (more [tex]CoCl_4^{2-}[/tex] (aq) is formed and the solution is blue in color). When the solution is cooled, more  [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.

Find  more information about Equilibrium here:

brainly.com/question/517289

Answer:

B. To make a guess in order to prove a hypothesis.

Explanation:

Answer:

C. 21%oxygen

Explanation:

Dry air contains 78.09% nitrogen, 20.95%oxygen, 0.93% argon, 0.04% carbon dioxide, and small amounts of other gases.

Answer and Explanation:

V1/n1 = V2/n2

450.0 mL / 0.0184 mol = 200.0 mL / n2

n2 = 8.17X10^-3 mol

moles removed = 0.0184-8.17X10^-3 = 0.0102 mols removed, I think I'm right but I'm not 100% sure..

According to Avogadro's law, 0.008 moles of gas must be removed to shrink balloon to 200 ml.

Avogadro's law is a gas law which states that the total number of atoms or molecules has a direct proportion to the volume occupied by a gas at a constant temperature and pressure.

It is closely related to ideal gas equation as it links temperature, pressure, volume and the amount of substance.It is given as, V∝n,

The straight line graph of volume versus moles is a straight line passing through the origin which implies that zero moles of gas occupy zero volume.

Here, the number of moles is calculated as, V₁/n₁=V₂/n₂

Therefore on substitution, n₂=0.0184×200/450=0.008 moles.

Thus,0.008 moles are required to shrink  the balloon to 200 ml.

Learn more about Avogadro's law,here:

https://brainly.com/question/6534668

#SPJ3

Answer:

percent=69.94%

Answer:

Budding, in biology, a form of asexual reproduction in which a new individual develops from some generative anatomical point of the parent organism. ... The initial protuberance of proliferating cytoplasm or cells, the bud, eventually develops into an organism duplicating the parent.

Explanation: im not sure if this will help because you didnt give any statements.

Answer: Cell division with mitosis causes new individuals to develop on a parent.

Explanation: did the test A.P.E.X. hope this helps <3

Answer:

mass of CO 2 = M r x number of moles of CO 2 = 44.0 × 0.010 = 0.44 g

Explanation:

Answer:

The answer is 28.68 moles

Explanation:

Hope this helped Mark BRAINLEST!!!

Answer:

hope this helps

Explanation:

72

Answer:

e. oxygen is a reactant in combustion and pure oxygen increases the reactant concentration

Explanation:

The reaction of a burning match is combustion. In this combustion, the organic components of the match (such as cellulose, C₆H₁₀O₅) react with oxygen, producing water and carbon dioxide:

Seeing as oxygen is a reactant and not a catalyst nor product, and that nitrogen plays no part in the reaction, the only correct answer is option e.

Answer:

they can carry cold arctic air, producing snow and freezing weather.

Explanation:

-w- hope it helps

Answer:

b

Explanation:

Answer:

electrons are transferred from the clouds to the grounf

Explanation:

Answer:

the answer is circle 3 hope it helps

Answer:

1. The two gases making the highest relative contribution to the greenhouse gases are: "CO2 and CH4."

2. The effect of increasing amount of greenhouse gasses is: "All of the above"

3. Which one of the following is a wrong statement?: "Eutrophication is a natural phenomenon in freshwater bodies"

4. The major contributors to the greenhouse gases are: "All of the above"

Explanation:

CO2 is carbon dioxide, and CH4 is methane. Also, the greenhouse gas effect is natural, except, the amount of greenhouse gases is not.

Answer:

The particles' kinetic energy is increased, allowing the gas to expand. When a gas is heated the volume will increase when gas is increased....

Answer:

1 and the element is hydrogen (there is an exception for the octet rule for the element hydrogen) hope this helps

Explanation:

Answer:

0.62 N

Explanation:

first of all: 3.0 s = 0.05 m

Let ? be the work that brakes do at 3.0s

24 m ----> 299 N

0.05 m ---->?

? = (0.05 m x 299 N)/ 24

? = (14.95)/ 24

? = 0.622 N

Answer:

The Florian predict the metamorphic rocks because it changes when subjected to heat and pressure.

Explanation:

i hope this helps

Answer:

Nitrogen

Explanation:

Answer:

Yes, its nitrogen. I wrote my answer earlier in the wrong spot.

Explanation:

The atmosphere contains many gases, most in small amounts, including some pollutants and greenhouse gases. The most abundant gas in the atmosphere is nitrogen, with oxygen second. Argon, an inert gas, is the third most abundant gas in the atmosphere.