PLEASEEEE HELP ASAP
Solve for x. Round your answer to the nearest tenth.

The length of the missing side in the given triangle is equal to option c. 5.

Figure is attached.

In the attached figure of a right angle triangle,

Let the triangle be named as ABC.

AC is the hypotenuse of a triangle.

AB is the altitude of a triangle.

BC is the base of a triangle.

Form the attached figure

Length of altitude AB = 3

Length of base BC = 4

Using Pythagoras theorem we have,

Hypotenuse² = Altitude² + Base²

⇒ AC² = AB² + BC²

Substitute the value we get,

⇒ AC² = 4² + 3²

⇒AC = √ 16 + 9

⇒ AC = √25

⇒ AC = 5

Therefore, the length of the missing side in the given triangle is equal to option c . 5.

The above question is incomplete, the complete question is:

Find the length of the missing side. Leave your answer in simplest radical form.

The triangle is not drawn to scale.

A.) 25

B.) 144

C.) 5

D.) Square root of 5

Figure is attached .

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The scale factor for the dilation that maps △ABC to △DEF is 0.75.

A triangle is a geometric shape that consists of three line segments that connect to form three angles. These angles always add up to 180 degrees. A triangle has three sides and three vertices (corners). Triangles can have different shapes and sizes, and they are often classified based on the length of their sides or the size of their angles. Some common types of triangles include equilateral triangles (where all sides are equal in length and all angles are equal to 60 degrees), isosceles triangles (where two sides are equal in length), and right triangles (where one angle is a right angle, or 90 degrees). Triangles have many properties and are an important part of geometry and mathematics.

Here,

To determine the scale factor for the dilation that maps △ABC to △DEF, we need to find the ratio of the corresponding side lengths of the two triangles.

Since △ABC ∼ △DEF, we know that the corresponding angles of the two triangles are congruent. Therefore, angle B in △ABC corresponds to angle E in △DEF, and angle A in △ABC corresponds to angle D in △DEF.

Using the Pythagorean theorem, we can find the length of the missing side of △DEF:

DF² = DE² + EF²

6² =DE² + 4²

DE=√20

DE=2√5 units

3/4=2/2√5=√13/6=0.75

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The solution of system of equation  y= -2x-4 and  y=2/5x + 16/5 is (-3, 2).

Two or more expressions with an Equal sign is called as Equation.

The system of equations are  y= -2x-4

and y=2/5x + 16/5

By substitution method let us find the solution.

2/5x + 16/5=-2x-4

2/5x+2x=-4-16/5

12x/5=-20-16/5

12x=-36

Divide both sides by 12

x=-3

Now plug in x value in any of the equation

y=-2(-3)-4

y=6-4

y=2

Hence, the solution of system of equation  y= -2x-4 and  y=2/5x + 16/5 is (-3, 2).

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The probability of picking a factor of 10 is 1/4 or 0.25 as a decimal.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
To calculate the probability of picking a factor of 10, we need to count the number of cards that are factors of 10 and divide that by the total number of cards.

The factors of 10 are 1, 2, 5, and 10. Out of the given cards, only 2 is a factor of 10.

Therefore, the probability of picking a factor of 10 is 1/4 or 0.25 as a decimal.

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The attachment shows different types of polygons that have 3 more sides then the other.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Now depending on these we have following five possibilities:

Case 1: Triangle and hexagon

If first polygon is triangle with three angles, the second will have 6 angles and the second polygon will be hexagon.

Case 2: Quadrilateral and heptagon

If first polygon is quadrilateral with 4 angles, the second will have 4+3 =7 angles and the second polygon will be heptagon.

Case 3: Pentagon and Octagon

If first polygon is pentagon with 5 angles, the second will have 5+3=8 angles and the second polygon will be octagon.

Case 4: Hexagon and Nonagon

If first polygon is hexagon with 6 angles, the second will have 6+3=9 angles and the second polygon will be nonagon.

Case 5: Heptagon and Decagon

If first polygon is Heptagon with 7 angles, the second will have 7+3=10 angles and the second polygon will be decagon.

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The numbers that can be multiplied by each equation so that when the two equations are added together, the x term is eliminated is: A. –10 times the first equation and 3 times the second equation.

In order to determine the solutions to a system of two linear equations, we would have to evaluate and eliminate each of the variables one after the other, especially by selecting a pair of linear equations at each step and then applying the elimination method.

Given the following system of linear equations:

1/5(x) + 3y/4 = 9                .........equation 1.

2x/3 - 5y/6 = 8          .........equation 2.

In this scenario, the number that should be used to multiply first equation can be calculated by using the following ratio:

Ratio =  -(x-coefficient of second equation)/(x-coefficient of first equation)

Ratio = -(2/3)/(1/5)

Ratio = -10/3

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The measure of ∠U= 80°, ∠B=44°, ∠Q= 93° respectively which indicates the angle of each triangle.

First take the Triangle TUV:

⇒∠T+∠U+∠V=180°

⇒37°+∠U+63°=180°

⇒∠U+100°=180°

⇒∠U=80°

Now, take triangle ABC:

⇒∠A+∠B+∠C=180°

⇒46°+∠B+90°=180°

⇒∠B+136°=180°

⇒∠B=44°

Finally take triangle PQR:

⇒∠P+∠Q+∠R=180°

⇒51°+∠Q+36°=180°

⇒∠Q+87°=180°

⇒∠Q=93°

Therefore, measure of the indicated angle in each triangle are 80°, 44 and 93° respectively.

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The value of x is 11.3

The value of y is 11.3

Using the different trigonometric identities such as sine, cosine, tangent, secant, cosecant, cotangent.

To determine the value of x, we use the sine identity

sin θ = opposite/hypotenuse

sin 45 = x/16

Find the value

0.7071= x/16

cross multiply

x = 11.31

To determine the value of y, we get;

tan 45 = 11.3/y

Determine the value and cross mutiply

1 = 11.3/y

Then,

y = 11.3

Hence. the values are equivalent

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Answer:

x=9

Step-by-step explanation:

18/48=x/24

Cross multiply

48x=432

Divide

432/48=9

x=9

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From the given  information provided, by converting the units there are 0.001 milliliters in 1 microliter.

This means that if you have 1 microliter of liquid, it is equal to 0.001 milliliters of liquid.

The conversion factor between milliliters (mL) and microliters (μL) is:

1 mL = 1000 μL

Therefore, to convert microliters to milliliters, you divide the number of microliters by 1000.

For example, if you have 500 μL of liquid, you can convert it to milliliters by dividing 500 by 1000:

500 μL / 1000 = 0.5 mL

So, 500 microliters of liquid is equal to 0.5 milliliters of liquid.

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Answer:

[tex]117500[/tex]

Step-by-step explanation:

[tex]500 \times 235=100\times (5\times 235)=1175 \times 100=117500[/tex]

Answer: 117,500

Step-by-step explanation: 500 x 235 = 117,500

Answer:

1298/3 is the answer

Step-by-step explanation:

Answer:

1296

Step-by-step explanation:

Let the unknown number be x.

If 432 is the result of x being decreased by 66²/₃%, then 432 is 33¹/₃% of x since 100% - 66²/₃% = 33¹/₃%.

Therefore:

[tex]\implies 33\frac{1}{3}\%\;\textsf{of}\;x=432[/tex]

[tex]\implies \dfrac{33\frac{1}{3}}{100} \cdot x=432[/tex]

[tex]\implies \dfrac{33\frac{1}{3}x}{100} =432[/tex]

Multiply both sides of the equation by 100:

[tex]\implies 33\frac{1}{3}x =43200[/tex]

Rewrite 33¹/₃ as an improper fraction:

[tex]\implies \dfrac{100}{3}x =43200[/tex]

Multiply both sides by 3:

[tex]\implies 100x=129600[/tex]

Divide both sides by 100:

[tex]\implies x=1296[/tex]

Therefore, the number that when decreased by 66²/₃% is 432, is 1296.

Answer:

about 23,000 usd

Step-by-step explanation:

If you want a quick way to translate yen to usd, take the yen amount and take away two zeros. So 3 mil yen would be 30,000. This method is a bit off but is quick and easy.

1 us dollar is about 130 yen

The formula of the given exponential function whose graph passes through the points (3, 2.8) and (4, 5.6) is :

   y = 0.35* (2)ˣ

What is an exponential function?

When the input variable x appears as an exponent in the formula

f(x) = aˣ, an exponential function is indicated. The exponential curve is influenced by both the exponential function and the value of x. It is mostly used to determine exponential growth or decay.

When there is exponential growth, the quantity grows initially extremely slowly and subsequently quickly. Over time, the rate of change quickens. As time goes on, the rate of increase accelerates. In exponential decay, the quantity initially falls very quickly and then gradually. Over time, the rate of change slows. As time goes on, change happens at a slower rate.

The general formula of an exponential function is:

y = abˣ

It is said that points (3, 2.8) and (4, 5.6) are present on the graph of the given exponential function.

W can substitute these value values in the above formula.

2.8 = ab³

5.6 = ab⁴

Dividing the above equations,

2.8 /5.6 = b³/b⁴

1/2 = 1/b

b = 2

Now substituting this value in one of the equations to find the value of a.

2.8 = a. (2)³

a = 2.8/8 = 0.35

Therefore the formula of the given exponential function is :

   y = 0.35* (2)ˣ

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The correct answer is P and T directly varies with V and N, and P and N inversely varies with T and V respectively.

It is the mathematical relationship between two variables which can be expressed by an equation in which one variable is equal to a constant times the other.

Given that, the equation pT = kVN, where k is a constant.

pT = kVN

If we remove constant, then,

pT ∝ VN

or

p 1/∝ T

V 1/∝ N

Hence, the correct answer is P and T directly varies with V and N, and P and N inversely varies with T and V respectively.

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Answer:

Step-by-step explanation:  1133.5.

Z-scores can be either positive or negative, with a positive number signifying a score above the mean and a negative value signifying a score below the mean according to the z-score table.

The statistical measurement known as the Z-score describes the relationship between a value and the mean of a group of values. Z-score is quantified by the standard deviations from the mean. The mean score and the data point's score are equal when the Z-score is 0. The Z-score for a value that deviates by one standard deviation is 1.0. Z-scores are binary, with a positive value denoting a score above the mean and a negative value denoting a score below the mean.

Equation of the z-score: z = ( x - μ ) / σ

Get the value corresponding to one decimal place of the z-score by first looking at the left side column of the z-table.

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Algebra 1 covers a variety of topics in algebraic mathematics, including linear and quadratic equations, graphing, polynomials, exponents, factoring, rational expressions, inequalities, functions, and data analysis.

Algebra 1 is typically a high school level course that covers a variety of topics in algebraic mathematics. The specific topics covered can vary somewhat depending on the school or district, but some common topics in Algebra 1 include:

1. Linear equations: Solving for unknowns in linear equations and systems of linear equations.

2. Quadratic equations: Solving for unknowns in quadratic equations and understanding their properties.

3. Graphing: Graphing linear and quadratic functions, and understanding their properties such as slope and intercepts.

4. Polynomials: Understanding and manipulating polynomials of different degrees.

5. Exponents: Understanding and working with exponential functions and expressions.

6. Factoring: Factoring polynomials and other algebraic expressions.

7. Rational expressions: Simplifying and manipulating rational expressions, and solving equations involving them.

8. Inequalities: Solving and graphing inequalities, including absolute value inequalities.

9. Functions: Understanding the concept of a function, and working with linear and quadratic functions.

10. Data analysis: Using algebraic methods to analyze and interpret data, including creating and interpreting graphs and tables.

These are some of the main topics that are typically covered in Algebra 1, though the exact curriculum can vary depending on the specific school or district.

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A residual is the difference between an observed value and the predicted value from a regression line.

A negative residual indicates that the observed value lies below the regression line. This can be expressed mathematically using the formula [tex]y = mx + b[/tex], where y is the observed value, m is the slope, x is the independent value, and b is the y-intercept of the line.

For example, if the observed value is y = 3, the predicted value is y = 5, and the slope and intercept of the line are m = 2 and b = 1, respectively, then the residual can be calculated as [tex]y = 3 - (2*1 + 1) = -1.[/tex] Since the residual is negative, this indicates that the observed value lies below the regression line.

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The domain and range of the function for the given graph is -

The range of values which we're permitted to enter into our function is known also as domain of a function.

Thus, the domain and range of the function for the given graph is -

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[tex]\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{"y" varies inversely with }x^2}{y = \cfrac{k}{x^2}}\hspace{5em}\textit{we also know that} \begin{cases} x=4\\ y=\frac{11}{4} \end{cases} \\\\\\ \cfrac{11}{4}=\cfrac{k}{4^2}\implies \cfrac{11}{4}=\cfrac{k}{16}\implies \cfrac{(11)(16)}{4}=k\implies 44=k~\hfill \boxed{y=\cfrac{44}{x^2}} \\\\\\ \textit{when x=2, what's "y"?}\qquad y=\cfrac{44}{2^2}\implies y=\cfrac{44}{4}\implies y=11[/tex]

Answer:

y = 11 when x = 2

Step-by-step explanation:

This is indirect proportionality where:

y ∝ [tex]\frac{1}{x^{2}}[/tex]

This means:

[tex]y_{1} x_{1}^{2} = y_{2}x_{2}^{2}[/tex]

Substitute the following values in the above equation to solve for [tex]y_{2}[/tex]

[tex]y_{1} = \frac{11}{4}[/tex]

[tex]y_{2} = ?[/tex]

[tex]x_{1} = 4[/tex]

[tex]x_{2} = 2[/tex]

= [tex](\frac{11}{4})(4^{2}) = y_{2}(2^{2})[/tex]

= [tex](\frac{11}{4})(16) = y_{2}(4)[/tex]

= [tex]44 = 4y_{2}[/tex]

= [tex]y_{2} =\frac{44}{4}[/tex]

∴ y = 11

Answer:

SInce 2 is 2 less than 4, the value of x+2 is 4 less than 31. So x+2=29

Step-by-step explanation:

Answer:

Step-by-step explanation:

Since 2 is 2 less than 4, the value of x + 2 is 2 less than 31.

So, x + 2 = 29.

"Monica swam 9/16 of a mile on Tuesday. She swam 1 5/8 of a mile on Wednesday. She swam approximately 2 miles in all" is the true statement.

This a problem on addition and subtraction of fractions

Since Hope's dad gives her 7/8 of a chocolate bar one day and then gives her 6/12 of a chocolate bar the next day. Hope received approximately 1 chocolate bar. Total chocolate  received will be:

Total chocolate received = 7/8  + 6/12 = 1 3/8

This statement is not true

Since Dee has 10/12 of a cake and gives 4/8 to her neighbor. Dee has approximately 1 cakes left. The cakes left will be:

cakes left = 10/12 - 4/8 = 1/3

This statement is not true

Since Joe ran 8/15 of a mile on Thursday. He ran 4/5 of a mile on Friday. Joe ran approximately 1/2 mile in all. The total mile ran will be:

total mile ran =  8/15 + 1/2 = 2 1/10

This statement is not true

Monica swam 9/16 of a mile on Tuesday. She swam 1 5/8 of a mile on Wednesday. She swam approximately 2 miles in all.

mile swam =  9/16 +  1 5/8 = 2 3/16

This statement is true

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The solution is, the equation of the line that passes through the point (5,0) and has a slope of 6/5 is , y=6/5*x - 6

A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.

here, we have,

the line that passes through the point (5,0) and has a slope of 6/5

now, w know, the point slope form of straight line is,

y-y1=m(x-x1)

so, putting the values , we get,

y-0=6/5(x-(5))

y-0=6/5(x-5)

y=6/5*x- 30/5

y=6/5*x- 6

Hence, The solution is, the equation of the line that passes through the point (5,0) and has a slope of 6/5 is , y=6/5*x - 6

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For the given similar triangles, the length of the missing side in the second triangle is 20.

To solve for the length of the missing side in the pair of similar triangles, we can use the SSS similarity theorem. The theorem states that 'if all three pairs of corresponding sides of two triangles are proportional, then the two triangles are similar'. Since the triangles are similar, the ratio of their corresponding sides will be equal.

The given measurements of the first triangle are 12, 18, and 24, and the measurements of the second triangle are 10, 15, and x. To solve for x, you can use the ratio of corresponding sides of similar triangles. The ratio for the sides of the first triangle are 12:18:24 and for the second triangle are 10:15:x. The ratio of the corresponding sides is 10:12, 15:18, and x:24.

We can set up a proportion using the given dimensions and solve for x.

The proportion will look like this:

12/10 = 18/15 = 24/x

Cross-multiplying and simplifying, we get:

12x = 240

x = 20

Therefore, the length of the missing side in the second triangle is 20.

Note: The question is incomplete. The complete question probably is: Solve for length of the missing side in the pair of similar triangles. The dimensions of one triangle are 12, 18, and 24, and the dimensions of the second triangle is 10, 15, and x. (These are corresponding measurements).

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For the exponential function:

g(x) = 14*(2)^x

We can see that:

a = 14, and b = 2.

A general exponential function is written as:

y = a*(b)^x

Where a is the inital value of the exponential function and b is the base.

Here we have the exponential function:

g(x) = 14*(2)^x

Comparing that to the general one, we can see that the initial value is 14 and the base is 2.

Then:

a = 14

b = 2

The correct option is the second one.

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The next term is -25.

A number pattern is a pattern in a series of numbers that represents the common relationship between the numbers. In Maths, number patterns are the patterns in which a list number that follows a certain sequence. usaually, the patterns establish the relationship between two numbers. It is known as the sequences of series in numbers.

Given;

The pattern20,−10,5,___

Here, first term is 20, second is -10

Difference=20+10

=30

Now,

=5-30

=-25

Therefore, the answer of the given pattern will be -25.

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At (0.958, 0.287, 5) and (0.958, -0.287, -5) points, the helix r(t) = sin(t), cos(t), t intersect the sphere x^2 + y^2 + z^2 = 26.

The sphere x^2 + y^2 + z^2 = 26 is a sphere with center at the origin and radius sqrt(26).

The helix r(t) = sin(t), cos(t), t is parameterized by sine and cosine functions, which oscillate between -1 and 1.

To find the points at which the helix intersects the sphere, we need to find the values of t such that the distance between r(t) and the origin is equal to sqrt(26).

The distance between a point (x, y, z) and the origin is given by the formula:

d = sqrt(x^2 + y^2 + z^2)

So, substituting the values from r(t), we have:

d = sqrt(sin^2(t) + cos^2(t) + t^2)

Setting d equal to sqrt(26), we have:

sqrt(sin^2(t) + cos^2(t) + t^2) = sqrt(26)

Squaring both sides, we have:

sin^2(t) + cos^2(t) + t^2 = 26

Recall that sin^2(t) + cos^2(t) = 1, so we have:

1 + t^2 = 26

Subtracting 1 from both sides, we have:

t^2 = 25

Taking the square root of both sides, we have:

t = ±5

So, the two points of intersection are (sin(5), cos(5), 5) and (sin(-5), cos(-5), -5).

Rounding the results to three decimal places, we have:

(sin(5), cos(5), 5) = (0.958, 0.287, 5)

(sin(-5), cos(-5), -5) = (0.958, -0.287, -5)

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Translation: 2 units left and 1 unit down. Q(0,-1), D(-2,2), V (2,4), J(3,-3)

New coordinates are respectively, (-2, -2), (-4, 1), (0, 3), (1, -4)

A point is a location of an object by taking reference of origin, In general case we consider it at (0,0), At the origin value of both the coordinate position is considered as Zero, In simple words point indicates how much it is above or below from the coordinate axes.

Vertical distance from the x axis is known as y coordinate and horizontal distance from the y axis is known as x coordinate.

Given the points Q(0,-1), D(-2,2), V (2,4), and J(3,-3),

we can see that each point has been translated 2 units to the left and 1 unit down.

This is because each x-coordinate has decreased by 2 and each y-coordinate has decreased by 1.

So, the translation of 2 units left and 1 unit down has moved each point along the plane in the negative x-direction and the negative y-direction.

the points are respectively (-2, -2), (-4, 1), (0, 3), (1, -4)

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