Please need help ASAP, ASAP

The  average velocity of the airplane  between  Milwaukee and Chicago  is 1083.33 meter/second.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

The total distance between  Milwaukee and Chicago = 130 kilometer

= 1,300,000 meter.

Time interval = 20 minute = 20×60 second = 1200 second.

The  average velocity of the airplane = total distance/time interval

= 1,300,000 meter / 1,200 second.

= 1083.33 meter/second.

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True. The majority of space lawyers concur that the line dividing airspace from outer space is located halfway between the altitude at which airplanes fly and the orbital altitude of satellites.

They serve a variety of functions, including that of the Satellite Navigation System, amateur radio, television transmission, and weather forecasting. In order to conduct study and acquire data, they also employ telescopes to view outward somewhere at solar system.

Over 99% of Americans have access to satellite internet, along with most other (but certainly not all) rural residents. You do not need to have a home internet connection because the broadband signal is transmitted from satellites.

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Answer:

4.95 m

Explanation:

The rocket's initial kinetic energy is equal to the final gravitational potential energy, so we can set these equal to each other and solve for the additional height the rocket will rise:

KEinitial = KEfinal

1/2 * m * v^2 = m * g * h

Substituting the given values, we have:

1/2 * 9.5 kg * v^2 = 9.5 kg * 9.8 m/s^2 * h

Solving for h, we find that the additional height the rocket will rise is h = 2390 J / (9.5 kg * 9.8 m/s^2) = 4.95 m.

The coefficient of kinetic friction between the block and the rough surface is -0.6.

Kinetic friction is a type of friction that occurs when two objects are in contact and moving relative to each other. It is also known as sliding friction or dynamic friction. Kinetic friction is caused by the interaction of the two surfaces as they move against each other. The force of kinetic friction acts in the opposite direction of the motion of the two objects and is proportional to the normal force between them. The coefficient of kinetic friction is a measure of the amount of friction between two surfaces and is determined by the materials of the two surfaces.

The coefficient of kinetic friction can be found using the equation:
μk = (vf - vi) / (d * a)
where μk is the coefficient of kinetic friction, vf is the final velocity, vi is the initial velocity, d is the distance traveled, and a is the acceleration due to gravity (9.8 m/s2).
Plugging in the given values, we get:
μk = (6 - 18) / (30 * 9.8)
μk = -0.6
Therefore, the coefficient of kinetic friction between the block and the rough surface is -0.6.

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The shape of the coastlines and the slope of the ocean floor, as well as the gravitational pull of the Sun and Moon, all have an impact on the tides of the ocean.

Tides are extremely long-period waves that travel across the water as a result of the moon's and the sun's gravitational pull. The rise and fall of the sea's surface on a regular basis is what tides, which originate in the ocean, appear as as they move toward the coastlines.

High tide is when the wave's highest portion, or crest, reaches a specific area; low tide is when the wave's lowest portion, or trough, reaches that location. The term "tidal range" refers to the height difference between high tide and low tide.

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Answer:

70.56 J

Explanation:

Gravitational Potential Energy= mass×gravitational pull× height

= 6×9.8×1.2= 70.56 J

It is False that personnel in mission control spend roughly 75% of their time actively engaging with and managing running space missions, according to the evidence at hand.

The NASA Johnson Space Center has a designated center called Mission Control Center.

Only 10% of the time that the MCC staff devotes to mission control is actually spent actually managing missions; the other 80% is spent planning and organizing, and the remaining 15% is spent on training and education.

A facility that oversees space flights is known as a mission control center (MCC; sometimes known as a flight control center or operations center), often from the point of launch until landing or the mission's conclusion. It is a component of spacecraft operations on the ground.

Therefore, It is False that personnel in mission control spend roughly 75% of their time actively engaging with and managing running space missions, according to the evidence at hand.

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Answer:

0.15 m/s²

Explanation:

Acceleration is rate of change of velocity-time function. We can find acceleration by finding the slope. The slope of graph can be found by:

[tex] \displaystyle{a = \dfrac{ \Delta v}{ \Delta t} \: \to \: \dfrac{v_f - v_i}{t_f- t_i}}[/tex]

Substitute in:

[tex] \displaystyle{a = \dfrac{5 - 2}{40 - 20}} \\ \\ \displaystyle{a = \dfrac{3}{20}} \\ \\ \displaystyle{a = 0.15 \: \text{m/s}^{2} }[/tex]

Therefore, the acceleration is 0.15 m/s²

The net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

When a force acts on a body at rest or at uniform motion in a straight line, then it starts to accelerate.

Given that, the velocity is 5.0

Time is 2 sec

The given mass is 2.0 kg

First, we calculate the acceleration

Acceleration = v / t = 10 / 5.0 = 2

From Newton's second law, we know that

force = mass x acceleration

F = ma

F = 2.0 x 2 = 4.0 m/s

Therefore, the net work that is needed to accelerate a 2.0 kg mass from rest to velocity 2v is 4.0 m/s.

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The question is incomplete. Your most probably complete question is given below:

What net force is needed to accelerate a 2.0 kg mass from rest to a velocity of 10 m/s in 5.0 s?

The velocity of the experimental vehicle after 2 seconds is 14 m/s.

The displacement of the experimental vehicle after 2 seconds is 14 m.

The velocity of the experimental vehicle is the speed of the in a given direction starting from rest.

The velocity, v, of the experimental vehicle after 2 seconds is calculated using the formula below:

v = u + at

where;

u is the initial velocity = 0 m/s

a is the acceleration = 7 m/s²

t is time = 2 seconds

v = 0 + 7 * 2

v = 14 m/s

The displacement, s, of the vehicle is calculated below as follows:

v² = u² + 2as

14² = 0² + 2 * 7 * s

s = 196 / 14

s = 14 m

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Answer:

5/18 is used to convert km/hr into m/s

1 km = 1000 m

1 hr = 3600 sec

1 km/hr to m/s

1*1000/1*3600

1000/3600metre/sec

10/36metre/sec

5/18 metre/sec

Explanation:

srry if this is wrong!

Answer:

Δp=-18799.5kg*m/s

Explanation:

Δv=Vf-Vi

Δv=2.9m/s-18m/s

Δv=-15.1m/s

m*Δv=Δp

1245kg*(-15.1m/s)=Δp

Δp=-18799.5kg*m/s

Extra:

Deriving mΔv=Δp

Δp=Pf-Pi

Δp=m*Vf-m*Vi

Δp=m(Vf-Vi)

Vf-Vi=Δv

Δp=m(Δv) or Δp=mΔv

There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.

The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.

Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.

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(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.

(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.

The kinetic energy of the ball just before it hits the ground is calculated as follows;

K.E ( bottom) = P.E (top)

P.E (top) = mgh

where;

P.E (top) = 4 x 9.8 x 2

P.E (top) = 78.4 J

The change in the potential energy of the ball during its motion is calculated as follows;

ΔU = P.Ef - P.E i

where;

ΔU = 0 J - 78.4 J

ΔU = -78.4 J

The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;

K.E = -ΔU

K.E = -mg (hf - hi)

K.E = (4 x 9.8)(2m - 1.2 m)

K.E = 31.36 J

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The value of mA is the equation of conservation of linear momentum is determined as mA = [ mB (vBi - vBf) ] / [  (vAf - vAi ) ].

The principle of conservation of linear momentum states that in a closed or isolated system, the total momentum of the system is always conserved.

Mathematically, the formula for the principle of conservation of linear momentum is given as;

Pi = Pf

where;

mAvAi + mBvBi = mAvAf + mBvBf

where;

To find the value of mA, we will make mA the subject of the formula as follow;

mAvAf  - mAvAi = mBvBi - mBvBf

mA (vAf - vAi ) = mB (vBi - vBf)

mA = [ mB (vBi - vBf) ] / [  (vAf - vAi ) ]

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a. When a football is kicked and it moves from one location to another, it indicates that unbalanced troops are responding to it and b. If an object A applies a force to another object B, then the other object B.

The equilibrium of the forces is disturbed when an object's motion changes. Forces with opposite directions and equal sizes are said to be balanced forces. Motion remains constant when the forces are equal. In one of your scenarios from the previous section, you used the same amount of force on an object but pushed or pulled it in the opposite direction.

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The magnitude of the frictional force that must be overcome is 42.04 N.

The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for the frictional force is given as;

F = μmg

where;

The magnitude of the frictional force that must be overcome is calculated as;

F = 0.39 x 11 kg  x  9.8 m/s²

F = 42.04 N

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Springs are elastic devices used to absorb shock, store energy, and provide support in a variety of applications.

1- The distance the spring is stretched from its equilibrium position is x = 180 - 100 = 80 mm. This can be converted to meters by dividing by 1000, so x = 0.08 m.

2- The restoring force of the spring can be calculated using Hooke's law, which states that F = kx, where F is the restoring force, k is the spring constant, and x is the distance the spring is stretched from its equilibrium position. In this case, F = 50 N/m × 0.08 m = 4 N.

What is Hooke's law?

Hooke's law is a basic law of physics that states that the force applied to a spring is proportional to the amount of displacement (or stretching) of the spring. In other words, the more you stretch a spring, the more force is needed to keep it stretched. This law is expressed mathematically as F = -kx, where F is the force, k is a constant known as the spring constant, and x is the displacement.

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The speed at which a clock would have to be moving in order to run at half the rate of a clock at rest depends on the theory of relativity that you are using.

In special relativity, time dilation is the phenomenon where time appears to pass differently for objects in motion relative to an observer at rest.

According to the theory, time appears to slow down for an object as it approaches the speed of light. The rate at which time appears to pass for an object is given by the equation:

T' = T / [tex]\sqrt{(1 - (v^2 / c^2))}[/tex]

Where T is the time as measured by an observer at rest, T' is the time as measured by an observer moving relative to the object, v is the velocity of the object, and c is the speed of light.

In addition, this is a theoretical scenario, practically in order to measure time dilation in a laboratory, it is required a very high precision of measurements, that are currently not possible.

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The things that I will need to survive the layer of the earth called the mesosphere would be thick clothings.

The five(5) layers of the earth include the following such as:

The Mesosphere is one of the layers of the earth that is found directly above the stratosphere and then below the thermosphere.

The characteristics of the mesosphere is that the temperature rises due to reduced absorption of solar radiation and increased cooling by CO2 radiative emissions.

Therefore, for an individual to survive and live effectively at the Mesosphere layer of the earth, such needs thick clothings.

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Answer:

The power is 57.6 watts

Explanation:

We can use the Electric Power Equation to evaluate the power.

Electric Power Equation

[tex]P=IV[/tex]

[tex]P[/tex] is the power in watts

[tex]I[/tex] is the current in amps

[tex]V[/tex] is the voltage in volts

Our lightbulb has current of 0.480 A and a voltage of 120.0 V.

[tex]I=0.480\\V=120.0[/tex]

Now we can evaluate power.

Substitute our values in for the variables.

[tex]P=0.480*120[/tex]

[tex]P=57.6[/tex]

Answer:

Conduction

Explanation:

Conduction is a process whereby heat is transfer through solid state.

The overcoming force is equal to the friction. The train's mass is 15,560,880.5 Kg

Friction can simply be defined as a force that opposes the movement of an object in a plain surfaces.

Given that the heaviest train ever pulled by a single engine was over 2 km long. Suppose a force of 1.13 X 10^8 N is needed to overcome static friction in the train's wheels. If the coefficient of static friction is 0.741, what's the train's mass?

F = μN

Where

Substitute all the necessary parameters

1.13 X 10^8 = 0.741N

N = 1.13 X 10^8/0.741

N = 152496626.2 N

N = mg

152496626.2 = 9.8m

m = 152496626.2/9.8

m = 15,560,880.5 Kg

Therefore, the mass of the train is 15,560,880.5 Kg.

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If a longitudinal force exceeding 3000 N is applied. Young's modulus for that object equals DL = 0.0139m.

The greater the modulus, or the lesser elasticity strain that arises from the application of a given stress, the stronger that medium is. Young's modulus, sometimes referred to as mechanical performance, is a metric used to determine how stiff a material is. In other words, it is readily bent or stretched.

Young's modulus really measures a material's ability to withstand changes in length when compressed or under stress along its length. Divide the primary stresses by the strain to get Young's modulus, commonly known also as young's modulus.

Young's modulus Y= stress/strain

= (F/A) /(DL/L)

F=3000N,

A=0.54 cm²,

L=2.5cm,

Y=0.1 Gpa

0.1 * 10⁹ = (3000/(0.54* 10⁻⁴) (2.5 ⋆ 0.01/DL)

DL = 0.0139m

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Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.

The forces are balanced if the pullers are exerting equal force but going in the opposite direction on either side of the rope.

Forces that are balanced can cancel one another out. The thing stays in place whenever there is a balanced force.

To lift, turn, move, open, close, push, pull, and many other things requires forces. You apply force to a ball when you throw it in order for it to travel through the air. An object can be under the influence of multiple forces at once.

Therefore, Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.

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The work done to the mower is the product of force and the distance covered by the object which is equal to 40,811 Joules.

Work done can be defined as the product of external force and the distance over which the force is being applied. Work is done on an object when a force is applied to an object and the object is moved through a particular distance.

From this we can see that:

X-Component:

cos(θ) = x/F

Then,

X= F cos(θ).…..(1)

Now putting the values of F and θ in equation (1) we get,

X = 72 N × cos(40)

X = 72 N × 0.766

X= 55.15 N this is the x-component force

The work done to the mower is:

W = F × d

W = 55.15 × 740

W = 40,811 Joules

The work done to the mower is 40811 Joules.

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In (Figure 2), the wrong with panel B is: Field line can not cross each other the field lines should be parallel because of the sheers summoner.

In general, an electric field line is a curve drawn with each point's tangent pointing in the direction of that point's net field. To designate the direction of the electric field from the two potential directions provided by a tangent to the curve, an arrow on the curve is obviously required. A field line is a space curve, or a three-dimensional curve.

The wrong with panel B is: Field line can not cross each other.

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The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).

In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."

In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,

If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.

Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.

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It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:

Generally, The gravitational force between two objects is given by the equation:

force = G * (mass1 * mass2) / distance^2

Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.

The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.

The gravitational force between the Earth and the Moon is:

force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force

= 2.9 x 10^20 N

The gravitational force between the Earth and the Sun is:

force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force

= 3.5 x 10^22 N

To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.

Net force = 2.9 x 10^20 N + 3.5 x 10^22 N

= 3.5 x 10^22 N

When it is a Full Moon the distance is the same 384,400 km

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Yes, the skater is accelerating.

Acceleration is a change in speed OR direction OR both.  Since she's skating in a circle, her direction is constantly changing, so she is accelerating.

At A, her velocity points down.

At B, her velocity points right.

At C, her velocity points up.

At D, her velocity points left.