PLEASE ITS AN Emergency IF ITS RIGHT I WILL GIVE BRAINLIEST

Protist:

Virus:

Fungus:

A) AIDS

B) Histoplasmosis

C) Amoebic dysentery

Answer:

Protist: C) Amoebic dysentery

Virus: A) AIDS

Fungus: B) Histoplasmosis

Hope that helps

Answer: Four times

Explanation:

Given

If Pressure and Volume is double

For ideal gas

PV=nRT

where P=Pressure

V=volume

n=no of moles

R=gas constant

T=temperature

Initially

PV=nRT......(i)

after doubling

(2P)(2V)=nRT'.......(ii)

divide (i) and (ii)

[tex]\frac{PV}{4PV}=\frac{nRT}{nRT'}\\T'=4T[/tex]

So, Temperature becomes 4 times

Answer:

Somatic I think

Explanation:

Answer:Sympathetic nervous system

Explanation:

Answer:

[tex]F_f=840N[/tex]

Explanation:

From the question we are told that

Weight of fireman [tex]W_f= 87.5kg[/tex]

Pole distance [tex]D=4.10m[/tex]

Final speed is [tex]V_f 1.75m/s[/tex]

Generally the equation for velocity is mathematically represented as

[tex]v^2 = v_0^2 + 2 a d[/tex]

Therefore Acceleration a

[tex]a'= v^2 / 2 d[/tex]

[tex]a'= 0.21m/s^2[/tex]

Generally the equation for Frictional force [tex]F_f[/tex] is mathematically given as

[tex]F_f=m*a[/tex]

[tex]F_f=m*(g-0.21)[/tex]

[tex]F_f=87.5*(9.81-0.21)[/tex]

Therefore

[tex]F_f=840N[/tex]

Answer:

The heat change of the system is 30 J.

Explanation:

Given;

increase in internal energy of a system, ΔU = 80 J

work done on the system, W = 50 J

The heat change of the system can be calculated from first law of Thermodynamics;

ΔU = Q - W

where;

Q is the heat absorbed by the system

W is the work done by the system (negative when work is done by the system and positive when work is done on the system)

Since work was done on the system the increase internal energy is given as;

ΔU = Q  + W

ΔU  - W = Q

80 J - 50 J = Q

30 J = Q

Therefore, the heat change of the system is 30 J.

Answer:

F = 1071.08 N

Explanation:

Given that,

The radius of the circular track, r = 3.23 m

Speed of the car, v = 3.72 m/s

The mass of the car, m = 250 kg

We need to find the net force acting on it. The centripetal force will act on it and it is given by the relation as follows :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{250\times (3.72)^2}{3.23}\\\\F=1071.08\ N[/tex]

So, the net force acting on the car is 1071.08 N.

Answer:the wave model

Explanation:

Answer:

60*12.0= 720 = v/60 * 12.0 squared which is 1,728

Explanation:

Horizontal velocity component: Vx = V * cos(α)

The horizontal velocity of the projectile is 6.0m/s

If a projectile is launched at an angle from the horizontal and at a velocity v, the horizontal velocity of the projectile is expressed as:

[tex]v_x =vcos \theta[/tex]

Given the following parameters

v = 12.0m/s

[tex]\theta=60^0[/tex]

Substitute the given parameters into the formula to have:

[tex]v_x=12.0cos60\\v_x=12.0(0.5)\\v_x=6.0m/s\\[/tex]

Hence the horizontal velocity of the projectile is 6.0m/s

Learn more here: https://brainly.com/question/23916021

Answer:

macule

Explanation:

its aa flat round areausually distingurished from its surroundung skin by its changed in color. smaller than 1cm  am small hemorrhage spot.

Answer:

The Potential Energy of the stretched spring is = 1.975 J

Explanation:

Recall that the potential energy of a spring of constant k stretched x\a distance x is given by the formula:

U = 1/2  k x^2

Therefore in our case, converting the stretch from cm of meters (0.05 m), this is

U = 1/2 * 79 * 0.05 J = 1.975 J

Answer:

The magnitude of each force is 66.67 N

Explanation:

Given that the magnitude of the tension forces are equal. Let the magnitude of the tension forces be represented by x, such that;

|OA| = |OB| = |OC| = x

Since their summation = 200 N, then;

|OA| + |OB| + |OC| = 200

This implies that;

x + x + x = 200

3x = 200

x = [tex]\frac{200}{3}[/tex]

    = 66.6667

x = 66.67 N

Therefore, the magnitude of each tension force is approximately 66.67 N

Answer:

D) See the explanation below.

Explanation:

Heat transfer is always given from a body of higher temperature to a lower temperature. In this way the heat from the boiling water is transferred to the ice bars and the energy of the phase change from solid to liquid from the ice is transferred to the environment

Answer:

95.7 degrees

Explanation:

The angle through which the particle rotate in radians is 1.667 rad.

Given the following data:

To determine the angle through which the particle rotate in radians:

Mathematically, the angular displacement or arc length in circular motion is given by the formula:

[tex]S=r\theta[/tex]

Where:

Making [tex]\theta[/tex] the subject of formula, we have:

[tex]\theta=\frac{S}{r}[/tex]

Substituting the given parameters into the formula, we have;

[tex]\theta = \frac{2.50}{1.50} \\\\\theta =1.667 \;rad[/tex]

Read more: https://brainly.com/question/8898885

Answer:

r2 = 1.25 × 10^(6) m

Explanation:

We are given;

Initial kinetic energy; K_1= 8.0 x 10^(7) J

Mass of planet zero; M = 4.0 x 10^(23) kg

Mass of space probe; m = 10 kg

Radius of planet zero; r1 = 2 × 10^(6) m

From conservation of energy, we can say that;

Initial potential energy + Initial kinetic energy = Final potential energy + Final kinetic energy

This is;

U1 + K1 = U2 + K2

Using formula for potential energy: U = GMm/r, we can write it as;

GMm/r1 + K1 = GMm/r2 + K2

Where Maximum distance = r2

At maximum distance from the center of Zero, K2 = 0.

Thus;

GMm/r1 + K1 = GMm/r2

Making r2 the subject, we have;

r2 = GMm/((GMm/r1)+ K1)

Where G is gravitational constant = 6.67 × 10^(-11) N/m²/kg2

Thus;

r2 = (6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/((6.67 × 10^(-11) × 4.0 x 10^(23) × 10)/(2 × 10^(6)) + (8.0 × 10^(7)))

r2 = 1.25 × 10^(6) m

Answer:

0.7432m²

1152in²

Explanation:

a) Usng the conversion

1ft² = 0.0929m²

8ft² = y

y = 8 × 0.0929

y = 0.7432m²

Hence 8ft² in m² is 0.7432m²

For ft² to in²

1ft² = 144in²

8ft² = x

X =8×144

x = 1152in²

Hence 8ft² expressed in in² is 1152in²

Answer:

The height (h) will be: [tex]\frac{3}{4}R =h[/tex]  

Explanation:

The scape speed equation is given by:

[tex]v_{scape}=\sqrt{\frac{2GM}{R}}[/tex]

Now, the speed of the missile is

[tex]v_{missile}=\frac{1}{2}v_{scape}[/tex]

[tex]v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}[/tex]

Using the conservation of energy, we can find the maximu height of the missile.

[tex]E_{i}=E_{f}[/tex]

[tex]\frac{1}{2}mv_{scape}^{2}-mgR =-mgh[/tex]

[tex]\frac{1}{2}\frac{2GM}{4R}-gR =-gh[/tex]

[tex]\frac{GM}{4R}-gR =gh[/tex]

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

[tex]\frac{1}{4}gR-gR =-gh[/tex]

[tex]\frac{1}{4}R-R =-h[/tex]    

Therefore the height (h) will be:

[tex]\frac{3}{4}R =h[/tex]    

I hope it helps you!

The five general principles from the APA are meant to: C. Guide and inspire good conduct.

Answer:

a) The tangential component of acceleration at the edge of the motor at  [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.

b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Explanation:

The angular aceleration of the electric motor ([tex]\alpha[/tex]), measured in radians per square second, as a function of time ([tex]t[/tex]), measured in seconds, is determined by the following formula:

[tex]\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right][/tex] (1)

The function for the angular velocity of the electric motor ([tex]\omega[/tex]), measured in radians per second, is found by integration:

[tex]\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right][/tex] (2)

Where [tex]\omega_{o}[/tex] is the initial angular velocity, measured in radians per second.

a) The tangential component of aceleration ([tex]a_{t}[/tex]), measured in meters per square second, is defined by the following formula:

[tex]a_{t} = R\cdot \alpha[/tex] (3)

Where [tex]R[/tex] is the radius of the electric motor, measured in meters.

If we know that [tex]R = 7.165\times 10^{-2}\,m[/tex], [tex]\alpha = 10\cdot t[/tex] and [tex]t = 1.5\,s[/tex], then the tangential component of the acceleration at the edge of the motor is:

[tex]a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)[/tex]

[tex]a_{t} = -1.075\, \frac{m}{s^{2}}[/tex]

The tangential component of acceleration at the edge of the motor at  [tex]t = 1.5\,s[/tex] is -1.075 meters per square second.

b) If we know that [tex]\omega_{o} = 104.720\,\frac{rad}{s}[/tex] and [tex]\omega = 26.180\,\frac{rad}{s}[/tex], then the time needed is:

[tex]26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}[/tex]

[tex]5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}[/tex]

[tex]t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5}[/tex]

[tex]t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s} }{5} }[/tex]

[tex]t \approx 3.963\,s[/tex]

The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Answer:

Length, gauge/size and composition

Explanation:

The longer the wire is the more resistance

The thinner the wire is more resistance

The difference in material effects the resistance ie. copper versus aluminium.

Answer:

A

Explanation:

Answer:

3.75 km away

Explanation:

From the law of moments, clockwise moments = anticlockwise moment

So WL = wl where W = weight of elephant = Mg and M = mass of elephant = 5000 kg, L = distance of elephant from axis of rotation = 0.75 m, and w = weight of mouse = mg where m= mass of mouse = 100 g = 0.1 kg and l =  distance of mouse from axis of rotation = unknown and g = acceleration due to gravity.

So, MgL = mgl

ML = ml

l = ML/m

= 5000 kg × 0.75 m/0.1 kg

= 3750 kgm/0.1 kg

= 37500 m

= 3.75 km away

Answer:

its true

Explanation:

i took it

Answer:

the powar produced is 0.7 watts

Answer:

19.6m/s

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 2s

Unknown:

Average velocity  = ?

Solution:

We can use the final velocity of the ball before landing to determines its average velocity ;

 Using;

              v  = u + gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

              v  = 0 + 9.8 x 2 = 19.6m/s

Answer:

summer

Explanation:

Answer:is there a 1 2 3 4 answer?

Explanation:

Answer:

speed  v = 0.148 m / s

velocity   v = 0

Explanation:

In this exercise we must be careful that the speed is a scalar and the speed is a vector, let's start by looking for the speed

           v = Δx /Δt

the distance traveled is x = 2d and the time taken is

           t = 7h 30 min

let's reduce to seconds

          t = 7 h 3600s / 1h + 30 min 60s / 1min = 27000 s

so the speed is

          v = 2d / 27000

to finish the calculation suppose a distance traveled d = 2000 m

          v = 2 2000/27000

          v = 0.148 m / s

this is the raides which is the speed module

Velocity is a vector,

          v = Dx / Dt

in this case the displacement is

           Dx = d -d

           Dx = 0

the total displacement is zero since it returns to the starting point, consequently the velocity is zero

          v = 0

bold is a vector

Answer:

14

Explanation:

21miles/3=7

7*2=14