Answer:
The motion of a transverse wave would be described as perpendicular to the wave direction.
Explanation:
The motion of a transverse wave is perpendicular to the wave propagation.
What is transverse wave?
A transverse wave is an oscillating wave in physics that advances in the opposite direction of its oscillations. A longitudinal wave, on the other hand, moves in the direction of its oscillations. Transverse waves include water waves.
The waves that can be made on a horizontal length of string by anchoring one end and moving the other end up and down provide a straightforward example. The waves that are produced on a drum's membrane serve as another illustration. Each point in the membrane moves up and down, perpendicular to the membrane plane, as the waves move in directions parallel to the membrane plane.
Another example of a transverse wave is light, which has electric and magnetic fields as oscillations.
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I really need help on this.
Earth's rotation is crucial to understanding the Coriolis effect. The Equator is where Earth rotates more quickly than the poles. There at Equator, Earth is larger.
Equatorial areas therefore move at a speed of around 1,600 km/h (1,000 mph) in a 24-hour period to complete a revolution. Earth rotates slowly towards to the poles, at 0.00008 km/h (0.00005 mi/h).
Low-pressure systems called cyclones draw air towards their "eye" or central region. Fluids representing high-pressure systems in the Northern Hemisphere pass low-pressure regions to the right.
Air masses are deflected when they're drawn inside cyclones from across all sides, giving the appearance that a hurricane is rotating clockwise. Trade winds refer to these air masses' recurrent circulation patterns.
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Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively. Where must a third charge be placed along the x-axis so that it does not experience any net force because of the other two charges? 50 cm 45.8 cm 9.12 cm 91.2 cm 4.58 cm
Answer:
45.8 cm
Explanation:
To solve this, we will use the formula
5 / x² = 7/(1 - x)²
5 / x² = 7 / (1 - 2x + x²)
5 / 7 = x² / (1 - 2x + x²)
x = 0.5 * (√(35) - 5) meters
x = 0.5 * (5.916 - 5)
x = 0.5 * (0.916)
x = 0.458 or x = 45.8
The position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges is 45.8 cm.
Given :
Two point charges of magnitudes +5.00 μC, and +7.00 μC are placed along the x-axis at x = 0 cm and x = 100 cm, respectively.
The following calculation can be used in order to determine the position where the third charge is placed along the x-axis so that it does not experience any net force because of the other two charges.
[tex]\rm \dfrac{5}{x^2}=\dfrac{7}{(1-x)^2}[/tex]
Simplify the above expression by cross multiplying.
[tex]5(x^2+1-2x)=7x^2[/tex]
[tex]\rm 5x^2 + 5 - 10x = 7x^2[/tex]
[tex]2x^2+2x-1=0[/tex]
Further, simplify the above expression in order to determine the value of x.
x = 0.458
x = 45.8 cm
Therefore, the correct option is b).
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How does Newton’s second law apply to golf
Answer: Newton's Second Law of Motion is proven through the way the golf ball flies through the air. Newton's law states that the net force of an object (Fnet) is equivalent to the object's mass (m) multiplied by the object's acceleration (a). In other words, Fnet = ma.
Explanation: Vote me brainliest ;D
What happens to the temperature of a substance while it is changing state?
Answer:
its temperature stays constant
Explanation:
If a drag racing car accelerated at 69 miles per second in 0.25 s, what is the acceleration of the car
Answer:
acceleration is : 276 mi/s^2
(276 miles per second squared)
Explanation:
We use the formula for acceleration (a) which is the change in velocity divided by the time it took to change it:
a = (vf - vi) / t
where "vf" stands for final velocity, "vi" for initial velocity, and "t" for the time it took for the velocity to change.
In our case:
a = (69 - 0) / 0.25 = 276 mi/s^2
(276 miles per second squared)
Dillon wants to go to the park to play basketball. To get to the park, he must travel 9 km East, and then 6 km South, then 9 Km West. Calculate the distance
Answer:
24 km
Explanation:
9 + 9 + 6 = 24
for which pair of objects would adding the same amount of eletrons to each object result in a decrease in a electrical force
Answer:
two positively charged objects
Explanation:
Which undergoes greater acceleration: an airplane that goes from 1000 km/h to 1005 km/h in 10 seconds or a skateboard that
goes from zero to 5 km/h in 1 second?
Answer:
Skateboard
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The airplane's acceleration is:
a = (1005 km/h − 1000 km/h) / 10 s
a = 0.5 km/h/s
The skateboard's acceleration is:
a = (5 km/h − 0 km/h) / 1 s
a = 5 km/h/s
Being a micro-manager is an example of using effective team building techniques
T or F
Answer:
TRUE
Explanation:
Answer:
True
Explanation:
The effect wind has on an airplane can be modeled by using a wind tunnel. What is one limitation of this model
Answer:
The limitations of this this model is the amount of wind being blown to effect the airplane.
Answer: Highly skilled workers are necessary to run the wind tunnel.
Explanation: I took the quiz on A pex.
A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Where [tex]g=9.8\ m/s^2[/tex], and t is the time.
Solving for t:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Using the value y=200:
[tex]\displaystyle t=\sqrt{\frac{2*200}{9.8}}[/tex]
t=6.39 sec
The penny will hit the ground at 6.39 seconds
A man starts walking at a steady speed of 1 m/s and 6s later his son sets off from the same point in pursuit of him, starting at rest and accelerating at 2/3 m/s/s. How far do they go before they are together?
Answer:
The father will walk 6 more meters and the son will walk 12 meters
Explanation:
Uniform Speed and Acceleration
This is a problem where two objects have different types of motion. The father walks at a constant speed and later, his son starts a constant acceleration motion in pursuit of him.
Let's start with the father, whose speed is v=1 m/s during t=6 seconds. He travels a distance:
[tex]x=vt=1*6=6\ m[/tex]
Now the son, starting from rest (vo=0) accelerates at a=2/3 m/s^2. His speed will increase and eventually, he will catch up with his father. Let's suppose it happens at a time t1.
The distance traveled by the son is given by:
[tex]\displaystyle xs=v_o.t_1+\frac{a.t_1^2}{2}[/tex]
Since vo=0:
[tex]\displaystyle xs=\frac{a.t_1^2}{2}[/tex]
The father will continue with constant speed and travels a distance of:
[tex]xf=v.t_1[/tex]
For them to catch up, the distance of the son must be 6 m more than the distance of the father, because of the leading distance he has already taken. Thus:
[tex]xs=xf+6[/tex]
Substituting the equations of each man:
[tex]\displaystyle \frac{a.t_1^2}{2}=v.t_1+6[/tex]
We know a=2/3, v=1:
[tex]\displaystyle \frac{2}{3}\cdot\frac{t_1^2}{2}=t_1+6[/tex]
Simplifying:
[tex]\displaystyle \frac{t_1^2}{3}=t_1+6[/tex]
Multiply by 3:
[tex]t_1^2=3t_1+18[/tex]
Rearranging:
[tex]t_1^2-3t_1-18=0[/tex]
Factoring:
[tex](t_1-6)(t_1+3)=0[/tex]
Solving:
[tex]t_1=6 , t_1=-3[/tex]
Since time cannot be negative, the only valid solution is
[tex]t_1=6\ s[/tex]
The distance traveled by the son in 6 seconds is:
[tex]\displaystyle xs=\frac{2/3\cdot 6^2}{2}[/tex]
[tex]xs=12\ m[/tex]
Note the father will travel
[tex]xf=1*6=6\ m[/tex]
This 6 m plus the 6 m he was ahead of the son, make them meet while walking at 6 seconds.
Answer: The father will walk 6 more meters and the son will walk 12 meters
A car travels 90 km/h. How long does it take for the car to travel
400 km?
b. 1.5x103 s
C. 1.5x104 s
a. 4x104 s.
d. 1.6x104s
Answer:
4.44 hr
Explanation:
distance= rate*time
400km/(90 km/hr)=time
time=4.44 hr
Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Answer:
[tex]B=1.61\times 10^{-4}\ T[/tex]
Explanation:
The attached figure shows the path followed by an electron in the semicircular path from A to B.
Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]
It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].
The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be [tex]B=1.61\times 10^-{4]\ T[/tex]
What is magnetic field?The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.
The attached figure shows the path followed by an electron in the semicircular path from A to B.
The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]
It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}[/tex]
[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]
[tex]B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]B=1.61\times 10^-{4]\ T[/tex]
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The gravitational constant G was first measured accurately by Henry Cavendish in 1798. He used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.27 m apart. One of the spheres had a mass of 188 kg, while the mass of the other sphere was 0.93 kg.
What was the ratio of the gravitational force between these spheres to the weight of the lighter sphere?
The gravitational force between the spheres is
[tex]F_{\rm g}=\dfrac{G(188\,\mathrm{kg})(0.93\,\mathrm{kg})}{(0.27\,\mathrm m)^2}\approx1.6\times10^{-7}\,\mathrm N[/tex]
where G = 6.674 x 10⁻¹¹ N m²/kg².
The weight of the lighter sphere is
[tex]F_{\rm w}=(0.93\,\mathrm{kg})g\approx9.1\,\mathrm N[/tex]
where g = 9.80 m/s².
The ratio between the two forces is then
[tex]\dfrac{F_{\rm g}}{F_{\rm w}}\approx1.8\times10^{-8}[/tex]
when are two magnets attracted?
Answer:
when the negative and positive energy is connected
Explanation:
ASAP PLEASE :)
How can we add kinetic energy to a baseball or football?
Answer:
Hitting it or throwing it with force.
The word photokinetic means “moving in response to light”. Why does this make sense based on the two main parts (morphemes) in this word?
Explanation:
photo means light in latin
kinetic means to move
To increase muscular strength the number of reputation should be?
A high
B light
C heavy
D low
increase muscular endurance the number of repetitions should be?
A high
B light
C heavy
D low
To increase muscular endurance the weight being lifted should be?
A high
B light
C heavy
D low
to increase muscular strength the weight being lifted should be?
A high
B light
C heavy
D low
Answer:
Explanation:
heavyy
I’ve been stuck on this question, what’s the answer to this question?
Explanation:
[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]
Where [tex]\sf{H_2CO_3 }[/tex] is Carbonic AcidWhere [tex]\sf{ NaOH }[/tex] is Sodium HydroxideReaction gives out [tex]\sf{ NA_2CO_3 + H_2O}[/tex]Where [tex]\sf{ NA_2CO_3 }[/tex] is Sodium HydroxideAnd [tex]\sf{ H_2O}[/tex] is water.So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.
Hope it helps :)
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Complete question:
A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Answer:
The elastic potential energy of the material is 0.036 J
Explanation:
Given;
Young's modulus, E = 2.0×10⁶ N/m²
Thickness of the abductin, l = 3.1 mm = 0.0031 m
compression of the abductin, x = 1.5 mm = 0.0015 m
area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²
Young's modulus for elastic material is given by;
[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]
The elastic potential energy of the material is given by;
U = ¹/₂kx²
U = ¹/₂(31,612.9)(0.0015)²
U = 0.036 J
Therefore, the elastic potential energy of the material is 0.036 J
explain which one would have a larger momentum a charging elephant or a buzzing bee
A train travels from Boston to New York. It travels at a speed of 180 km/h for two hours, speeds up to 200 km/h for the next four hours and then slows down to 120 km/h for the next six hours. What is the average speed of the train for this trip?
Answer:
156 2/3 km/hr
Explanation:
Average speed is found by dividing total distance by total time.
180 km/hr in 2 hrs is 360 miles
200 km/hr in 4 hrs is 800 miles
120 km/hr in 6 hrs is 720 miles
Total time is 12 hrs; Total distance 1880 hrs
Divide distance by time and you have 156 2/3 km/hr. This is your average speed.
How does energy from the sun travel to earth .
Answer:
through uv light
What is an antibody and what does it do?
an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
Explain why the interconnection is not valid. Explain why the interconnection is not valid. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in the same direction, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply different currents in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in opposite directions, which they do not. A valid interconnection would require the 3 AA and 4 AA sources to supply the same current in the same direction, which they do not.
Complete Question
The diagram for this question is shown on the first uploaded image
Explain why the interconnection is not valid.
i A valid interconnection would require the 3 A and 4 A sources to supply different currents in the same direction, which they do not.
ii A valid interconnection would require the 3 A and 4 A sources to supply different currents in opposite directions, which they do not.
iii A valid interconnection would require the 3 A and 4 A sources to supply the same current in opposite directions, which they do not.
iv A valid interconnection would require the 3 A and 4 A sources to supply the same current in the same direction, which they do not
Answer:
The correct option is iv
Explanation:
Looking at the diagram we see that the current source are connected in series, generally the current flowing through two source that are connected in series is suppose to be the same but in this case it is not so
i.e [tex]4A \ne 3 A[/tex] hence Kirchhoff's law is broken or not followed in this circuit which means the interconnection is not valid
also another reason why the interconnection is not valid is because the current are flowing in the different directions
A automotive test driver travels due north in a prototype hybrid vehicle at 30 mi/h
for 2 hours. She then reverses her direction and travels due south at 60 mi/h for 1 hour.
What is the average speed of the vehicle?
a) 40 mi/h
b) 50 mi/h
c) zero mi/h
d) 60 mi/h
e) 30 mi/h
Answer:
Option A. 40 mi/h
Explanation:
To obtain the average speed of the vehicle, we'll begin by calculating the distance travelled by the vehicle in each case. This is illustrated below:
Case 1:
Speed = 30 mi/h
Time = 2 h
Distance =...?
Speed = Distance /Time
30 = Distance /2
Cross multiply
Distance = 30 × 2
Distance = 60 mi
Case 2:
Speed = 60 mi/h
Time = 1 h
Distance =...?
Speed = Distance /Time
60 = Distance /1
Cross multiply
Distance = 60 × 1
Distance = 60 mi
Finally, we shall determine the average speed of the vehicle as follow:
Total distance travelled = 60 + 60
Total distance travelled = 120 mi
Total time = 2 + 1
Total time = 3 h
Average speed =..?
Average speed = Total Distance travelled /Total time
Average speed = 120/3
Average speed = 40 mi/h
Therefore, the average speed of the vehicle is 40 mi/h
Which is the correct answer? Please help.
Answer:
i believe it is c
Explanation:
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A man runs 400.0m around the track,
then another 400.0m around the track again.
As the track is 400.Om long, the man is back
where he started!
a) calculate distance travelled
b) calculate mans displacement
Answer:
Distance = 800 m, Displacement = 0
Explanation:
It is given that,
A man runs 400 m around the track, then another 400 m around the track again.
(a) Distance travelled by an object is the sum of total path covered.
In this case, he has covered total path of 400 m + 400 m i.e. 800 m. It means he travelled a distance of 800 m.
(b) Displacement covered by an object is the shortest path covered by it. In this problem, he reaches the point from where he has started. It means that his displacement is equal to 0.
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?