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Which of the following inequalities contains (0, 0) in its shaded region?
3x + y < −5
x ≥ −y + 3
y − 7x > −4
3y > 2x

Answer:

160% is for 72 of 45

Answer: 45

Step-by-step explanation: 85/19=45

Answer:

Step-by-step explanation:

For a point to be a solution to a system of inequalities, the points must make the signs of the inequalities true.

For example, the points must give results like 2<3 or 0>-2, these are true solutions. If the points gives 1>2, then that point is not a solution.

Answer:

5

Step-by-step explanation:

Answer:

The final answer is [tex]x = 5[/tex], which would be the second choice.

Step-by-step explanation:

Solve the equation:

[tex]-16x = -80[/tex]

-Divide both sides by -16:

[tex]\frac{-16x}{-16} = \frac{-80}{-16}[/tex]

[tex]x = 5[/tex]

So, the final answer is [tex]x = 5[/tex] .

Answer:

h = 16

Step-by-step explanation:

By applying the Pythagorean Theorem, the slant height is given by the formula:

[tex]\sqrt{r^2+h^2}[/tex]

34 = [tex]\sqrt{30^2 + h^2}[/tex]

[tex]34^2 = 30^2 + h^2[/tex]

[tex]1156 = 900 + h^2[/tex]

[tex]256 = h^2[/tex]

[tex]h = \sqrt{256}[/tex]

[tex]h = 16[/tex]

Answer:

[tex]x = 6.6[/tex] and [tex]DE = 16.2[/tex]

Step-by-step explanation:

The question is incomplete as the attachment to solve segment DE is missing. However, see attached for complete question.

Given

[tex]\frac{5}{9}= \frac{9}{(2x+3)}[/tex]

Required

Find x

Length of DE

To find x, we need to first simplify the given equation

[tex]\frac{5}{9}= \frac{9}{(2x+3)}[/tex]

Multiply both sides by [tex]9(2x+3)[/tex]

[tex]\frac{5}{9} * 9(2x + 3) = \frac{9}{(2x+3)} * 9(2x + 3)[/tex]

[tex]5(2x + 3) = 9(9)[/tex]

[tex]10x + 15 = 81[/tex]

Subtract 15 from both sides

[tex]10x + 15 - 15 = 81 - 15[/tex]

[tex]10x = 66[/tex]

Divide both sides by 10

[tex]\frac{10x}{10} = \frac{66}{10}[/tex]

[tex]x = \frac{66}{10}[/tex]

[tex]x = 6.6[/tex]

From the attached;

[tex]DE = 2x + 3[/tex]

Substitute 6.6 for x

[tex]DE = 2(6.6) + 3[/tex]

[tex]DE = 13.2 + 3[/tex]

[tex]DE = 16.2[/tex]

Hence [tex]x = 6.6[/tex] and [tex]DE = 16.2[/tex]

Answer: 6.6 for the first x

Length of DE is 16.2

Also these are correct!

Step-by-step explanation:

I just put it in

Answer:

is this the right question

Answer:

1773

Step-by-step explanation:

because if you put the _ as - it mean to subtract so then you see how I got it

Answer:

[tex]yes \\ 1 : 3 = 3 : 9[/tex]

Step-by-step explanation:

yes.

[tex]1 : 3 = 3 : 9[/tex]

Let see how is it possible,

[tex]3 \times 1 : 3 \times 3 = 3 :9 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 3 : 9 = 3 : 9[/tex]

Also,

[tex]1 : 3= 3 \div 3 : 9 \div 3 \\ 1 : 3 = 1 : 3[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

L = f(J, K, F)

L = (JK²)/F

So, as the formula appears, the appropriate units will be option A.

Unit for number of laughs = (jokes*knowledge²) / familiarity

Just like the formula suggests.

Step-by-step explanation:

Complete Question

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: L = (JK²)/F

Select an appropriate unit for number of laughs:

A) (jokes*knowledge²) / familiarity

B) familiarity / (jokes*knowledge²)

C) familiarity² / (jokes*knowledge)

D) (jokes*knowledge) / familiarity²

Solution

L = f(J, K, F)

where

L = number of laughs

J = number of jokes

K = amount of knowledge about the joke material

F = familiarity with the jokes

Analysing how the dependent variable depends on each of the independent variables.

- Number of jokes

The number of laughs will increase with the number of jokes and vice versa. It can be stated that there is a direct variation between the number of laughs and number of jokes.

- Amount of knowledge about the joke material

The more one understands the joke material, the funnier the joke. In fact, the joke can be termed funnier when one understands the joke material deeply. The direct variation of number of laughs to knowledge about joke material isn't just enough, the number of laughs varying directly as the square of the knowledge of joke material seems more fitting.

- Familiarity with the joke

The more familiar one is with a joke, the less funny it is. Hence, it's an inverse relationship between number of laughs and the familiarity with the joke.

L = (JK²)/F

So, as the formula appears, the appropriate units will be

(jokes*knowledge²) / familiarity

Just like the formula suggests.

Hope this Helps!!!

The question is incomplete. Here is the complete question.

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: [tex]L = \frac{J.K^{2} }{F}[/tex].

Select an appropriate unit for number of laughs:

(jokes*knowledge²) / familiarity

familiarity / (jokes*knowledge²)

familiarity² / (jokes*knowledge)

(jokes*knowledge) / familiarity²

Answer: Unit for number of laughs is (jokes*knowledge²) / familiarity

Step-by-step explanation: Number of laughs (L) is related to jokes (J), knowledge (K) and familiarity (F) according to the proportion: [tex]L = \frac{J.K^{2} }{F}[/tex]

The unit for L will be: L = (jokes.knowledge²).familiarity⁻¹

or

L = [tex]\frac{jokes*knowledge^{2} }{familiarity}[/tex]

Answer:

9

Step-by-step explanation: