please help will mark brainly!!!!! need done. PERSONAL FINANCE

Complete Question

A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. What is the numerical value of the sample mean?

Answer:

Sample Mean [tex]\=x=80[/tex]

Step-by-step explanation:

From the question we are told that:

Population Mean [tex]\mu=78[/tex]

Standard deviation [tex]\sigma=90[/tex]

Sample size [tex]n=120[/tex]

Sample Mean [tex]\=x=80[/tex]

Therefore

The numerical value of the sample mean is

Sample Mean [tex]\=x=80[/tex]

Answer:

b

Step-by-step explanation:

Answer:

3.82

Step-by-step explanation:

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Do not confirm the answer unless your equation looks like that?

[tex]\sqrt{(9+\sqrt{32}) }[/tex] Start by the [tex]\sqrt{32}[/tex]

[tex]\sqrt{(9+5.65) }[/tex] Now add (9 + 5.65)

[tex]\sqrt{14.65}[/tex]         Finally Simplify

[tex]3.82[/tex]              Final answer

Answer: 5%

Step-by-step explanation:

In 2006, there were 160 teachers in College A, and ¾ of them had their own vehicles, the number of people who had their own vehicles will be:

= 3/4 × 160

= 120

In 2007, 20 new teachers came to the school and 6 of them had own vehicles. This means the number if people with vehicles will be:

= 120 + 6

= 126

The percentage increase will be:

= Increase / Old vehicle owners × 100

= 6/120 × 100

= 1/20 × 100

= 5%

The Percentage increase is 5%.

Answer:

see down

Step-by-step explanation:

d is correct answer

Answer:

D

Step-by-step explanation:

Answer:

For the Broadway actors acting in their first role on Broadway, mean: 0.184, Standard Deviation: 0.063.

For the proportion of smokers, mean = 0.167, standard deviation = 0.068

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Suppose we took a survey of 38 Broadway actors and found that 18.4% of the actors we surveyed were first-timers.

This means that [tex]p = 0.184, n = 38[/tex]

What are the mean and standard deviation for the sampling distribution of p^?

Mean:

[tex]\mu = p = 0.184[/tex]

Standard deviation:

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.184*0.816}{38}} = 0.063[/tex]

Suppose you take a random sample of 30 smokers and find that the proportion of them who are current smokers is 16.7%.

This means that [tex]n = 30, p = 0.167[/tex]

What is the mean and the standard deviation of the sampling distribution of p^ ?

Mean:

[tex]\mu = p = 0.167[/tex]

Standard deviation:

[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.167*0.833}{30}} = 0.068[/tex]

Answer:

[tex]x=6\\y=4[/tex]

Step-by-step explanation:

Elimination method:

[tex]x+5y=26[/tex]

[tex]-x+7y=22[/tex]

Add these equations to eliminate x:

[tex]12y=48[/tex]

Then solve [tex]12y=48[/tex] for y:

[tex]12y=48[/tex]

[tex]y=48/12[/tex]

[tex]y=4[/tex]

Write down an original equation:

[tex]x+5y=26[/tex]

Substitute 4 for y in [tex]x+5y=26[/tex]:

[tex]x+5(4)=26[/tex]

[tex]x+20=26[/tex]

[tex]x=26-20[/tex]

[tex]x=6[/tex]

{ [tex]x=6[/tex] and [tex]y=4[/tex] }    ⇒ [tex](6,4)[/tex]

hope this helps...

Answer:

x = 6, y = 4

Step-by-step explanation:

x + 5y = 26

- x + 7y = 22

_________

0 + 12y = 48

12y = 48

y = 48 / 12

y = 4

Substitute y = 4 in eq. x + 5y = 26,

x + 5 ( 4 ) = 26

x + 20 = 26

x = 26 - 20

x = 6

Answer:

x = 20

Step-by-step explanation:

 3x -10 = 2x +10

x = 20

Answer:

Infinitely many solutions.

They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]x - 5y = 5[/tex]

[tex]-x + 5y = -5[/tex]

Required

The best description

Add both equations

[tex]x - x - 5y + 5y = 5 - 5[/tex]

[tex]0+0 =0[/tex]

[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.

Make y the subject in: [tex]-x + 5y = -5[/tex]

Add x to both sides

[tex]5y = x - 5[/tex]

Divide through by 5

[tex]y = \frac{1}{5}(x - 5)[/tex]

Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]

Answer:

I think no. D is the answer

Answer:

the larger number is 69

the smaller number is 16

Step-by-step explanation:

x is the smaller number

y is the larger number

x + y = 85

y - 4x = 5

y = 5 + 4x

x + 5 + 4x = 85

5x = 80

x = 16

y = 69

Answer:

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

Step-by-step explanation:

To solve these questions, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.

This means that [tex]\mu = 38.72, \sigma = 3.17[/tex]

Sample of 10:

This means that [tex]n = 10, s = \frac{3.17}{\sqrt{10}}[/tex]

Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

This is 1 subtracted by the p-value of Z when X = 40. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}[/tex]

[tex]Z = 1.28[/tex]

[tex]Z = 1.28[/tex] has a p-value of 0.8997

1 - 0.8997 = 0.1003

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

[tex]\mu = 266, \sigma = 16[/tex]

1. What is the probability a randomly selected pregnancy lasts less than 260 days?

This is the p-value of Z when X = 260. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{260 -  266}{16}[/tex]

[tex]Z = -0.375[/tex]

[tex]Z = -0.375[/tex] has a p-value of 0.3539.

0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?

Now [tex]n = 20[/tex], so:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}[/tex]

[tex]Z = -1.68[/tex]

[tex]Z = -1.68[/tex] has a p-value of 0.0465.

0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?

Now [tex]n = 50[/tex], so:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}[/tex]

[tex]Z = -2.65[/tex]

[tex]Z = -2.65[/tex] has a p-value of 0.0040.

0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?

Sample of size 15 means that [tex]n = 15[/tex]. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.

X = 276

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}[/tex]

[tex]Z = 2.42[/tex]

[tex]Z = 2.42[/tex] has a p-value of 0.9922.

X = 256

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}[/tex]

[tex]Z = -2.42[/tex]

[tex]Z = -2.42[/tex] has a p-value of 0.0078.

0.9922 - 0.0078 = 0.9844

0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

The correct answer will be option (B) Triangle A

An acute-angled triangle is a type of in which all the three internal angles of the triangle are acute, that is, they measure less than 90°

The steps are as follow:

So the triangle A is acute triangle

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the e-function stuff can be confusing sometimes, but notices that g(x) / the blue line, is just somewhat lower, rest is the same.

how much lower? look at the y-intercepts

f(0)= "about 5"

g(0)= "about -3"

with this y-intercept only option c can work

Answer:

5

Step-by-step explanation:

took the test

The coordinates of the point that divides the line segment from J to K into a ratio of 2:3 are P(-5,7), and the y-coordinate is 7, the correct option is D.

Ratio is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.

We are given that;

Ratio= 2:3

Now,

Let the point we are looking for be denoted as P(x,y), and let the ratio be 2:3, which means that the distance from J to P is 2/5 times the distance from J to K.

Using the distance formula, we can find the distance between J and K as:

d = sqrt((x2-x1)^2 + (y2-y1)^2)

= sqrt((-8 - (-3))^2 + (11 - 1)^2)

= sqrt(25 + 100)

= sqrt(125)

The distance from J to P is 2/5 of the total distance, which is:

(2/5)d = (2/5)sqrt(125) = 2sqrt(5)

Using the ratio formula, we get:

x = (3* (-3) + 2 * (-8)) / (3+2) = -5

y = (31 + 211) / (3+2) = 7

Therefore, by the given ratio answer will be 7.

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Answer:

yeah u forgot to add the picture ig

Answer:

Let be [tex]\vec A[/tex], [tex]\vec B[/tex] and [tex]\vec C[/tex] the vector of a triangle so that [tex]\vec C = \vec A + \vec B[/tex]. By definition of Dot Product:

[tex]\vec C \,\bullet\,\vec C = (\vec A + \vec B) \,\bullet \vec C[/tex]

[tex]\vec C \,\bullet \,\vec C = (\vec A\,\bullet \,\vec C) + (\vec B \,\bullet \,\vec C)[/tex]

[tex]\|\vec C\|^{2} = [\vec A \,\bullet \,(\vec A + \vec B)] + [\vec B\,\bullet \,(\vec A + \vec B)][/tex]

[tex]\|\vec C\|^{2} = \vec A \,\bullet \, \vec A + \vec B\,\bullet \vec B + 2\cdot (\vec A \,\bullet \, \vec B)[/tex]

[tex]\|\vec C\|^{2} = \|\vec A\|^{2} + \|\vec B\|^{2} + 2\cdot \|\vec A\|\cdot \|\vec B\|\cdot \cos\theta_{C}[/tex]

Step-by-step explanation:

Let be [tex]\vec A[/tex], [tex]\vec B[/tex] and [tex]\vec C[/tex] the vector of a triangle so that [tex]\vec C = \vec A + \vec B[/tex]. By definition of Dot Product:

[tex]\vec C \,\bullet\,\vec C = (\vec A + \vec B) \,\bullet \vec C[/tex]

[tex]\vec C \,\bullet \,\vec C = (\vec A\,\bullet \,\vec C) + (\vec B \,\bullet \,\vec C)[/tex]

[tex]\|\vec C\|^{2} = [\vec A \,\bullet \,(\vec A + \vec B)] + [\vec B\,\bullet \,(\vec A + \vec B)][/tex]

[tex]\|\vec C\|^{2} = \vec A \,\bullet \, \vec A + \vec B\,\bullet \vec B + 2\cdot (\vec A \,\bullet \, \vec B)[/tex]

[tex]\|\vec C\|^{2} = \|\vec A\|^{2} + \|\vec B\|^{2} + 2\cdot \|\vec A\|\cdot \|\vec B\|\cdot \cos\theta_{C}[/tex]

Answer:

243.125

Step-by-step explanation:

First do the integral part

11110011

1. From left to right, starting with a zero,

2. add the digit, double, move on to the next digit and repeat step 2 until digits are exhausted.

The successive results are

1

3

7

15

30

60

121

243

For the decimal part, we proceed similarly but

1. From the right-most digit proceed to the left, start with a zero.

2. Add the digit, halve, move on to the next digit and repeat step 2 until the decimal is reached.

Successive results are:

0.5

.25

.125

So the final result is 11110011.001 binary is 243.125 decimal

Answer:

A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day zero the population · Q: For this discussion, you will work in groups to find the area and answer questions.

Step-by-step explanation:

Answer:

A

Step-by-step explanation: just divide 71 into 2 which gives you 35.5 making a your answer.

Answer:

[tex] {f}^{ - 1} (x) = \frac{x}{3} + \frac{7}{3} [/tex]

hence option d is the correct option.

Answer:

Option C is answer.

Step-by-step explanation:

Hey there!

Given;

f(x) = (3-x) /7

Let f(x) be "y".

y = (3-x) /7

Interchanging "x" and "y".

x = (3-y)/7

7x = 3-y

y = 3-7x

Therefore, f'(x) = 3-7x.

Hope it helps!

Answer:

B

O 50° is the mZACB out of the options

↦ [tex]\huge\underline{ \underline{Answer:-}}[/tex]

[tex]5x = 3x + 12 \\ 5x - 3x = 12 \\ 2x = 12 \\ x = \frac{12}{2} \\ x = 6[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Step-by-step explanation:

hope it is h helpful to you

The expected payout is

2 × 0.5 + 4 × 0.2 + 6 × 0.15 + 8 × 0.1 + 10 × 0.05

= 1 + 0.8 + 0.9 + 0.8 + 0.5

= 4

The expected value of the winnings from this game is $3.90.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

Example:

The probability of getting a head in tossing a coin.

P(H) = 1/2

We have,

To find the expected value of the winnings, we multiply each possible payout by its probability and then sum these products.

So,

Expected Value = (2 x 0.5) + (4 x 0.2) + (6 x 0.15) + (8 x 0.1) + (10 x 0.05)

Expected Value = 1 + 0.8 + 0.9 + 0.8 + 0.5

Expected Value = 3.9

Therefore,

The expected value of the winnings from this game is $3.90.

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Answer:

y = 26.3x² - 116.9x + 109.6

Step-by-step explanation:

Given the data ;

Year Period Users (Millions)

2004 1 1

2005 2 5

2006 3 11

2007 4 58

2008 5 145

2009 6 359

2010 7 607

2011 8 846

A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :

y = Ax² + Bx + C

y = 26.3x² - 116.9x + 109.6

Answer:

80 seconds

Step-by-step explanation:

10/10 = 1

now it takes 1 seconds to count 1 sheet

80 x 1 = 80 seconds to count 80 sheets

Step-by-step explanation:

10sheets=10seconds

1sheet=1sheet÷10sheets x 10seconds

=1second

80sheets=80sheets÷1sheet x 1second

80seconds

hope this is helpful

Answer:

No, it is not possible.

Step-by-step explanation:

AB // CD and BC is transversal.

∠ABC = ∠BCD   ---> Alternate interior angles are equal.

Here, it is different which is not possible.

Answer:

x=5

y=3/2

Step-by-step explanation:

Take it or leave it, that's what the computer said.