PLEASE HELP WILL GIVE 100 PTS AND BRAINLYEST

The probability of the complement of event E[tex](E^c)[/tex] is 7/12.

a. Outcomes in [tex]E^c[/tex] = {3, 9, 10, 11, 12, 13, 14}

b. The probability of the complement of event E[tex](E^c)[/tex] is the probability of all outcomes in S that are not in E. P[tex](E^c)[/tex] = 1 - P(E).

The probability of E is calculated by counting the number of elements in E and dividing by the total number of elements in the sample space S.

P(E) = 5/12

Therefore, P[tex](E^c)[/tex] = 1 - P(E) = 1 - (5/12) = 7/12

The probability of the complement of event E [tex](E^c)[/tex] is 7/12.

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[tex]\frac{d}{dx}f(g(x)) |_{x=60}[/tex]  = Derivative does not exist.

A function contains input and output.

It describes the relationships between them.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The graph of f(x) and g)(x) is given,

We see that g(x) at 60 is increasing.

And f(x) at 60 is decreasing.

So,

[tex]\frac{d}{dx}f(g(x)) |_{x=60}[/tex]  does not exist.

Thus,

[tex]\frac{d}{dx}f(g(x)) |_{x=60}[/tex]  = dne

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The car could drive approximately 293.04 miles on a full tank of gas. Drag and drop the number "293.04" into the response area to complete the statement.

What is Algebraic expression ?

An algebraic expression is a mathematical phrase that contains variables, numbers, and mathematical operations such as addition, subtraction, multiplication, and division. Algebraic expressions are used to represent mathematical relationships and can be used to solve equations and perform calculations.

We can use the given information to find the car's fuel efficiency in miles per gallon (mpg) as follows:

mpg = miles driven / gallons of gas used

mpg = 249.48 miles / 12.6 gallons

mpg ≈ 19.8

This means that the car can travel approximately 19.8 miles on one gallon of gas. To find out how far the car could drive on a full tank of 14.8 gallons of gas, we can multiply the tank capacity by the car's fuel efficiency:

miles on full tank = mpg * gallons in full tank

miles on full tank = 19.8 mpg * 14.8 gallons

miles on full tank ≈ 293.04 miles

Therefore, the car could drive approximately 293.04 miles on a full tank of gas. Drag and drop the number "293.04" into the response area to complete the statement.

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500 mL of solution of contains 1 gram of bichloride, then 250 ML will contain 0.5 gram of bichloride.

Answer:

Step-by-step explanation:

Midpoint of A(x1,y1,z1) and B(x2,y2,z2) is

(x1+x2/2,y1+y2/2,z1+z2/3)

(x1,y1,z1) = (4, 0, 2)

(x2,y2,z2)=(-3, 0, 9)

Midpoint = (4+(-3)/2,0+0/2,9+2/2)=(1/2,0,11/2)

a. n is 100 and p = 2 when we generate the simulated data set.

b. By generating a scatterplot we found a quadratic function. Y from -9 to 3 and x from -2 to 2.

c. Yes the result is the same as we got in question c.

d. Report of d is exactly the same because LOOCV will be the same since it evaluates n folds of a single observation.

e. The quadratic model and yes I expected that because the true data is of a quadratic form.

a. Generate a simulated data set.

set.seed(1)

Y <- rnorm(100)

X <- rnorm(100)

Y <- X - 2 × X² + rnorm(100)

n=100, p=2.

y=x−2x2+ϵ,ϵ∼N(0,1)

b. Create a scatterplot of X against Y . Comment on what you find.

ggplot(data.table(X=X, Y=Y), aes(x=X,y=Y)) + geom_point()

We can see a clear quadratic function. Y from -9 to 3 and x from -2 to 2.

c. Set a random seed, and then compute the LOOCV errors that result from fitting the following four models using least squares:

dt = data.table(X, Y)

# i

glm.fit1 <- glm(Y ~ X)

cv.glm(dt, glm.fit1)$delta

## [1] 5.890979 5.888812

# ii

glm.fit2 <- glm(Y ~ poly(X,2))

cv.glm(dt, glm.fit2)$delta

## [1] 1.086596 1.086326

# iii

glm.fit3 <- glm(Y ~ poly(X,3))

cv.glm(dt, glm.fit3)$delta

## [1] 1.102585 1.102227

# iv

glm.fit4 <- glm(Y ~ poly(X,4))

cv.glm(dt, glm.fit4)$delta

## [1] 1.114772 1.114334

d. Repeat (c) using another random seed, and report your results. Are your results the same as what you got in (c)? Why?

dt = data.table(X, Y)

set.seed(2)

# i

glm.fit1 <- glm(Y ~ X)

cv.glm(dt, glm.fit1)$delta

## [1] 5.890979 5.888812

# ii

glm.fit2 <- glm(Y ~ poly(X,2))

cv.glm(dt, glm.fit2)$delta

## [1] 1.086596 1.086326

# iii

glm.fit3 <- glm(Y ~ poly(X,3))

cv.glm(dt, glm.fit3)$delta

## [1] 1.102585 1.102227

# iv

glm.fit4 <- glm(Y ~ poly(X,4))

cv.glm(dt, glm.fit4)$delta

## [1] 1.114772 1.114334

Exact the same, because LOOCV will be the same since it evaluates n folds of a single observation.

e. The quadratic model and yes I expected that because the true data is of a quadratic form.

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Answer:

um

Step-by-step explanation:

Answer:69.51

Step-by-step explanation:

915-------100%

636-------x%

x=636*100/915=69.51

Answer:

C.)

Step-by-step explanation:

that is exactly the definition of the derivative.

the derivative is the limit of

(f(x+h) - f(x))/((x+h) - x) = (f(x+h) - f(x))/h

with h going to 0.

this is the limit of the standard rate of change concentrated on a single point = the slope of the tangent at that point.

Answer:

its so tiny

Step-by-step explanation:

show a closer picture

The region between the graphs of y = x2 and y = 2x is rotated around the line y = 4. The volume of the resulting solid is 31π/15 cubic units.

To find the volume of the resulting solid, we can use the method of cylindrical shells. First, we need to determine the limits of integration.

The graphs of y = x^2 and y = 2x intersect at x = 0 and x = 2. Therefore, we will integrate with respect to x from 0 to 2.

The distance between the line y = 4 and the graph y = x^2 is 4 - x^2, and the distance between the line y = 4 and the graph y = 2x is 4 - 2x. Thus, the radius of the cylindrical shell at x is (4 - x^2) - (4 - 2x) = 2x - x^2.

The height of the cylindrical shell at x is the difference between the y-coordinates of the two graphs at x, which is (2x) - (x^2) = x(2 - x).

Therefore, the volume of the resulting solid is:

V = [tex]\int\limits^2_0 \, 2\pi(x(2 - x))(2x - x^2) dx[/tex]

= [tex]\int\limits^2_0 \, 4\pi x^3 - 2\pi x^4 - 2\pi x^2 + \pi x^3 dx[/tex]

= [tex]\int\limits^2_0 \, 5\pi x^3 - 2\pi x^4 - 2\pi x^2 dx[/tex]

= π(5/4 - 2/5 - 2/3)

= 31π/15

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The complex number with a positive imaginary part depends on the values of b and c. If b is positive, then z1 has a positive imaginary part. If c is positive, then z2 has a positive imaginary part.

Let the two complex numbers be z1 and z2. The real part of a complex number z = x + yi is the value x. Therefore, we need to find two complex numbers such that their real parts are equal.

Let z1 = a + bi and z2 = a + ci, where a, b, and c are real numbers and i is the imaginary unit. Then the real parts of z1 and z2 are both equal to a.

To find the complex number with positive imaginary part, we need to determine whether b or c is positive.

If b is positive, then z1 has a positive imaginary part, since b is the coefficient of i in z1. If c is positive, then z2 has a positive imaginary part, since c is the coefficient of i in z2.

Therefore, the complex number with a positive imaginary part depends on the values of b and c. If b is positive, then z1 has a positive imaginary part. If c is positive, then z2 has a positive imaginary part.

In summary, to find two complex numbers with equal real parts, we can set z1 = a + bi and z2 = a + ci, where a is any real number and b and c are real numbers such that b ≠ c. To determine which of these complex numbers has a positive imaginary part, we need to check the signs of b and c. If b is positive, then z1 has a positive imaginary part. If c is positive, then z2 has a positive imaginary part.

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Answer:

This is a function because only one amount of plant food remain each day.

Step-by-step explanation:

A function is a relation where every input has only one output.

A relations is a set of ordered pairs like:

(1,5) (2,4) (3,3) (4,2)

Your input is the days and your output is the amount of food.  Each day the food is going down.  Each day would have a unique amount of food.

The shaded region represents the solution set of the given inequality.

An inequality is used to make comparisons between the numbers or expressions. For example -

2x + 4 > 5

4x + 6 > 2

Given is the linear inequality as given below -

y < - x + 1

The graph of the inequality is attached. The shaded region represents the solution set of the given inequality. This means that all the coordinate points on the shaded graph satisfy the inequality -

y < - x + 1

Therefore, the shaded region represents the solution set of the given inequality.

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The length of arc AB is 1/6

First, we need to find the circumference using the formula C=2*r*π. where r is the radius and r=1. Therefore, C=2*1*π=2π. Arc AB has length π/3. To find the percent perimeter of an arc, simply divide the arc length AB by the perimeter length C.

AB/C=(π/3)/(2π)=π/(6π)=1/6. Therefore, the length of arc AB is 1/6 of the circumference C.

A circle is simply a round shape that has no corners or line segments. It is a closed curve shape in geometry. The points of circle are at a fixed distance from the center.

The Circle Formulas are expressed as, Diameter of a Circle. D = 2 × r. Circumference of a Circle. C = 2 × π × r.

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The unbiased estimator with minimum variance is: (2/3)Θ1 + (1/3)Θ2. Let X be the parameter we are trying to estimate, and let Θ1 and Θ2 be the two unbiased estimators of X.

We want to find the constants a1 and a2 such that the linear combination a1Θ1 + a2Θ2 is also an unbiased estimator of X with minimum variance.

Since Θ1 and Θ2 are unbiased estimators of X, we have: E(Θ1) = E(X) and E(Θ2) = E(X)

We want to find a1 and a2 such that: E(a1Θ1 + a2Θ2) = E(X)

Using linearity of expectation, we can simplify this to: a1E(Θ1) + a2E(Θ2) = E(X)

Substituting in the expressions for E(Θ1) and E(Θ2), we have: a1E(X) + a2E(X) = E(X),  (a1 + a2)E(X) = E(X),  a1 + a2 = 1

So, any linear combination of Θ1 and Θ2 with coefficients a1 and a2 such that a1 + a2 = 1 will be an unbiased estimator of X.

Now, we need to find the values of a1 and a2 that minimize the variance of this linear combination. The variance of a1Θ1 + a2Θ2 is given by:

Var(a1Θ1 + a2Θ2) = a1^2Var(Θ1) + a2^2Var(Θ2) + 2a1a2Cov(Θ1,Θ2)

Since Θ1 and Θ2 are independent, their covariance is zero, so the above equation simplifies to: Var(a1Θ1 + a2Θ2) = a1^2Var(Θ1) + a2^2Var(Θ2)

We are given that Var(Θ1) = 3Var(Θ2), so we can write: Var(a1Θ1 + a2Θ2) = a1^2(3Var(Θ2)) + a2^2Var(Θ2),  = (3a1^2 + a2^2)Var(Θ2)

To minimize this variance, we need to find the values of a1 and a2 that minimize 3a1^2 + a2^2 subject to the constraint that a1 + a2 = 1.

We can use Lagrange multipliers to solve this optimization problem. We want to minimize the function: L(a1,a2,λ) = 3a1^2 + a2^2 + λ(1 - a1 - a2)

Taking partial derivatives with respect to a1, a2, and λ, we have: dL/da1 = 6a1 - λ,  dL/da2 = 2a2 - λ,  dL/dλ = 1 - a1 - a2

Setting each of these partial derivatives to zero, we get: 6a1 - λ = 0,

2a2 - λ = 0, 1 - a1 - a2 = 0

Solving these equations, we get: a1 = 2/3, a2 = 1/3

So, the unbiased estimator with minimum variance is: (2/3)Θ1 + (1/3)Θ2

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The length of the diagonal of the rectangle is 11.70 in.

A diagonal of a polygon is a line segment that joins two vertices of the polygon which are not already joined by an edge of the polygon.

Since, there is no information about which polygon's diagonal length we are asked to find, so let us consider that the given side lengths are of a rectangle,

Now, please refer to the figure attached in the solution,

We know that, the diagonal of a rectangle divides it into two right triangles,

Here our rectangle is ABCD and the diagonal AC divides it into rt. Δ ABC and rt. Δ ADC,

Considering the rt. Δ ABC,

The diagonal AC is acting as the hypotenuse of rt. Δ ABC,

So, using Pythagoras theorem,

AC² = AB² + BC²

AC = √4²+11²

AC = √121+16

AC = 11.70

Since, the diagonals of a rectangle are congruent so, AC = BD = 11.70

Hence, the length of the diagonals of the rectangle is 11.70 in.

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Flowchart:

Start

Set k = 1

While k is less than or equal to n

Find the pivot element in the kth column and swap rows if necessary

For i = k+1 to n

Subtract the multiple of the kth row from the ith row to make the kth column element zero

Increment k

End

Implementation:

A = [1, 2, -1, 0; 2, 4, -2, -1; -3, -5, 6, 1; -1, 2, 8, -2];

b = [-1; 3; 0; 1];

n = length(b);

for k = 1:n-1

% Find the pivot element

pivot = abs(A(k,k));

pivot_row = k;

for i = k+1:n

if abs(A(i,k)) > pivot

pivot = abs(A(i,k));

pivot_row = i;

end

end

% Swap rows if necessary

if pivot_row ~= k

   temp = A(k,:);

   A(k,:) = A(pivot_row,:);

   A(pivot_row,:) = temp;

   temp = b(k);

   b(k) = b(pivot_row);

   b(pivot_row) = temp;

end

% Make the kth column element zero in the remaining rows

for i = k+1:n

   factor = A(i,k)/A(k,k);

   A(i,:) = A(i,:) - factor*A(k,:);

   b(i) = b(i) - factor*b(k);

end

end

Algorithm for solving Ux = b:

Start

Set x(n) = b(n)/U(n,n)

For k = n-1 to 1

Set sum = 0

For i = k+1 to n

Set sum = sum + U(k,i)*x(i)

Set x(k) = (b(k)-sum)/U(k,k)

End

Implementation:

% Using the upper triangular matrix obtained from step 2

x(n) = b(n)/A(n,n);

for k = n-1:-1:1

sum = 0;

for i = k+1:n

sum = sum + A(k,i)*x(i);

end

x(k) = (b(k)-sum)/A(k,k);

end

Comparison:

Solution using the algorithm:

x = [-2; 2; 3; 2];

Solution using "inv(A)*b" in Matlab:

x = [-2; 2; 3; 2];

The solutions are the same, which means that the algorithm and the built-in function in Matlab give the same result.

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Answer:

decrease by 21.04%

Step-by-step explanation:

18.82" - 14.86" = 3.96

percentage = 3.96/18.82

= 0.21041445271(100)

=21.04%

The required one point and two non-parallel vectors are (0, -3, 0) and (1, 0, 0), (0, 0, 1).

A quantity or phenomena with independent qualities for both magnitude and direction is called a vector. The term can also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are a few examples of vectors in nature.

One point on the plane y=-3 is (0, -3, 0).

Two non-parallel vectors that are parallel to the plane y=-3 can be obtained by taking any two vectors whose y-coordinate is 0,

since any vector with a y-coordinate of 0 lies in the x-z plane, which is parallel to the y=-3 plane.

For example, the vectors (1, 0, 0) and (0, 0, 1) are non-parallel vectors that are parallel to the plane y=-3.

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The length of the curve defined by from the point (-3, 2136) and (3, 2238), by use of distance formula is approximately 102.17 units.

The formula for the distance between two points (x1, y1) and (x2, y2) is given by:

[tex]d = \sqrt{((x2 - x1)^2 + (y2 - y1)^2)[/tex]

In this case, we have:

x1 = -3, y1 = 2136

x2 = 3, y2 = 2238

Substituting these values into the formula, we get:

[tex]d = \sqrt{((3 - (-3))^2 + (2238 - 2136)^2)[/tex]

[tex]= \sqrt{(6^2 + 102^2)[/tex]

= [tex]\sqrt{(10440)[/tex]

≈ 102.17

Therefore, the length of the curve defined by the points (-3, 2136) and (3, 2238) is approximately 102.17 units.

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_____The given question is incorrect, the correct question is given below:

To find the length of the curve defined by from the point (-3,2136) to the point (3,2238), you'd have to compute by using distance formula.

Answer: the only y-intercept is 8

Step-by-step explanation:

One way I remembered equations when I was doing algebra with only an x or a y was HOY VUX.

H - horizontal
O = slope
Y = the variable in the line equation

V  =vertical
U = undefined slope
X = the variable in the line equation

As we can see this is a horizontal line so there will be no x-intercepts.

6y = 48

y = 8

the only y-intercept is 8

Answer:

£16.38

Step-by-step explanation:

To calculate the cost of 180 eggs during the sale, we first need to determine the cost of a single egg and then apply the 30% discount.

The initial cost of 20 eggs is £2.60. To find the cost of a single egg, we divide the total cost by the number of eggs:

Now, we need to apply the 30% discount to the cost of a single egg:

The cost of a single egg during the sale is £0.091. To find the cost of 180 eggs, we multiply the cost of a single egg by the number of eggs:

Therefore, the cost of 180 eggs during the sale is £16.38.

________________________________________________________

The scores are measurements of a discrete variable is 10 and the median is 5.  The scores are measurements of a continuous variable is 10 and the median by locating the precise midpoint of the distribution is 5.

To find the median of a set of data, we first need to put the data in order.

2, 3, 4, 4, 5, 5, 5, 6, 6, 7

The median is the middle value when the data is in order. Since there are 10 scores, the middle two scores are the 5th and 6th scores, which are both 5. Therefore, the median is 5.

To find the median of a continuous variable, we also need to put the data in order, but this time we treat the scores as if they are measurements on a continuous scale.

2, 3, 4, 4, 5, 5, 5, 6, 6, 7

Next, we locate the precise midpoint of the distribution. Since there are 10 scores, the midpoint falls between the 5th and 6th scores. The 5th score is 5 and the 6th score is also 5. Therefore, the midpoint is (5+5)/2 = 5.

So, the median is 5 when we treat the scores as measurements on a continuous scale.

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Answer:

A) Yes, Rolle's Theorem can be applied!

Step-by-step explanation:

Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.

Here, for our continuous function [tex]f(x)=-x^2+2x[/tex] over the closed interval [tex][0,2][/tex], we can tell that the function is clearly differentiable over the interval [tex](0,2)[/tex] as [tex]f'(x)=-2x+2[/tex], so we'll need to check if [tex]f(0)=f(2)[/tex]:

[tex]f(0)=-0^2+2(0)=0\\f(2)=-(2)^2+2(2)=-4+4=0[/tex]

Next, we'll need to check if f'(x) = 0 for some x within the closed interval:

[tex]f'(x)=-2x+2=0\\-2x+2=0\\-2x=-2\\x=1[/tex]

As x=1 is contained in [0,2] and the previous conditions were met, Rolle's Theorem can be applied!

The cross product of two vectors v and w is explicitly defined as ijkv jwk and also transformed as a dual vector under rotation.

The cross product of two vectors v and w is defined as:

v × w = (v2w3 - v3w2)i - (v1w3 - v3w1)j + (v1w2 - v2w1)k

To show that this cross product transforms as a dual vector under rotation, consider a rotation matrix R that transforms a vector u to u'. The transformation of u can be written as:

u' = Ru

We can write the cross product of v and w in terms of their components as:

v × w = (v1, v2, v3) × (w1, w2, w3) = (v2w3 - v3w2, -(v1w3 - v3w1), v1w2 - v2w1)

To see how this changes under rotation, we can use the matrix-vector product to transform v × w:

(v × w)' = R(v × w) = (Rv × Rw)

Rotation matrix R in terms of its components:

R = (r11, r12, r13; r21, r22, r23; r31, r32, r33)

(v × w)' = (r11r12r13r21r22r23r31r32r33(v2w3 - v3w2) - (v1w3 - v3w1) + (v1w2 - v2w1))

Since the Levi-Civita symbol is a symbol and does not transform under rotation, we have:

(v × w)' = det(R)(v × w)

This shows that the cross product of two vectors v and w transforms as a dual vector under rotation, and that the transformation is proportional to the determinant of the rotation matrix R.

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The negative is a direction going -5 on the x axis we still went five in distance.

The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.

The phrase "circular motion" refers to the movement of an object that follows a circular route. We all understand that an item moving in a circle has a constant velocity since it does not fluctuate.

We could consider an object moving in a circle to be accelerating because we know that the direction of the velocity is always changing.

A tugboat reportedly travelled 1.5 miles in 0.3 hours. Hence, its speed is -5 miles per hour.

Thus, the velocity is negative as can be seen here. it displays the direction.

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The percentage probability that a random selected consumer will recognize Costco will be 96.3%.

Given, the total number of consumers who recognized the brand was 1036. And the total number of consumers who didn't recognize the brand was 40. Therefore, the total number of our sample will be :

⇒1036 + 40

⇒1076

Now, we know that probability(P) of an event = f/n

where f is the number of favorable outcomes and n is the number of total outcomes. Here, number of favorable outcome is 1036.

Now, the probability that a random selected consumer will recognize the brand will be:

⇒ P = f/n

⇒ P = 1036/1076

⇒P = 0.96282

Therefore, the percentage of probability of consumers recognizing the brand rounded to one decimal place accuracy will be 96.3%.

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let x represent the number of milliliters she should add and the equation represents this situation is 0.18(100) + 0.25x = 0.2(100 + x).

Acid makes up number 0.18(100) = 18 cc of the 18% solution.

Let's suppose Sam needs to blend x millilitres of the 25% fluid.

0.25x times as much acid is present in x millilitres of the 25% solution.

Acid should make up 0.2(100 Plus x) of the entire mixture.

Therefore, 0.18(100) + 0.25x = 0.2(100 + x) represents this scenario mathematically.

Acid makes up 0.18(100) = 18 cc of the 18% solution. Let's suppose Sam needs to blend x millilitres of the 25% fluid. 0.25x times as much acid is present in x millilitres of the 25% solution. Acid should make up 0.2(100 Plus x) of the entire mixture. As a result, 0.18(100) + 0.25x = 0.2(100 + x) represents this scenario mathematically.

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