please help Use the expression 8a + 16c.
Part A
Factor the expression using the GCF.
A. 2(4a + 8c)
B. 4(2a + 4c)
C. 8(a + 2c)
D. 16(12a + c)
Part B
What is the value of the expression when a = –5 and c = –1? Enter your answer in the box.

Answer:

24 tiles (none of the options given is correct)

Step-by-step explanation:

Number of tiles required to floor the room = area of the room/area of 1 tile

Area of the room = 36m * 24m = 864 m²

Area of 1 tile = 6² = 36 m²

Number of times required = 864/36 = 24 tiles

75 = 1 x 75, 3 x 25,

or

75 = 3 xx 5^(2)

Answer:

hasta no se pero nimodoa esta bien adiós baybau

Answer:

B. Isosceles right triangle.

Step-by-step explanation:

The triangle given has two sides that have equal lengths. It also has a right angle.

An Isosceles triangle has two equal side lengths.

Therefore, since the triangle above has a right angle and has two equal side lengths, based on the side lengths, it can can be classified as an isosceles right triangle.

Answer:

1. 6

2. 15

3. 11

Step-by-step explanation:

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

Female               |   31   |    42   |   46    |  16         135    

Totals                    54         77        122    62          315  

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

Answer:

3.8374326e+21

Step-by-step explanation:

id.k goo.gle said this

Yes 5.3 is greater than 5

5.3 > 5

Answer:

yes, it is.

Step-by-step explanation:

its a solution because in the graph below, 5.3 is in the shaded region. hope this helped!!

Answer:

Radius, Diameter and Circumference

The Radius is the distance from the center outwards. The Diameter goes straight across the circle, through the center. The Circumference is the distance once around the circle.

:)

Answer:

Radius = 8.7 cm

Step-by-step explanation:

The height and hypotenuse of the triangle is provided, so all we have to do is use the Pythagorean Theorem. [tex]\sqrt{15^{2}-12.2^{2}}[/tex] and this yields the answer.

Answer:

The answer to this question would be B.

Step-by-step explanation:

Tysm for the points! :D

Answer:

yup b

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

the answer is a because the rrow is pointing right so the symbol is > and the point starts at -5

Answer:

1)105°

2) 45°

3)63°

4)108°

5)68°

Step-by-step explanation:

Hope this helps! :)

Answer:

They saw 15 customers per hour.

Step-by-step explanation:

Answer:

254 R 6

Step-by-step explanation:

Answer:

256 7/16

Step-by-step explanation:

2308/9 = 256 7/16

Answer:

they retain 3/5 or 60% of their initial weight

Step-by-step explanation:

Answer:

9x3+5x2=37

8-(7-5)^2+8=12

10-3+5+5x4=32

ill solve rest in comments

9x3+5x2=37

8-(7-5)^2+8=12

10-3+5+5x4=32

Answer:

<A = 30°

The steps are given in the pic. Hope it will help :)

Answer:

6/8 or in simple terms, 3/4

Step-by-step explanation:

[tex] \frac{1}{2} + \frac{1}{4} \\ = ( \frac{1}{4} + \frac{1}{4} ) + \frac{1}{4} \\ = ( \frac{1}{8} + \frac{1}{8} ) + (\frac{1}{8} + \frac{1}{8} ) + (\frac{1}{8} + \frac{1}{8} ) \\ = ( \frac{2}{8} ) + ( \frac{2}{8} ) + ( \frac{2}{8} ) \\ = \frac{6}{8} \\ = \frac{2 \times 3}{2 \times 4} \\ = \frac{3}{4} [/tex]

The given operation of the two fractions can be found as 6/8. The correct option is (D).

A fraction is a number written in the form a / b, where a and b are integers and b ≠ 0.

The number a is called as the numerator and b is the denominator.

The given expression is 1/2 + 1/4.

It can be solved using the strip given as below,

The number of 1/8 sections under 1/2 in the strip is 4.

And, the number of 1/8 sections under 1/4 in the strip is 2.

Then, the addition of the two fractions is equivalent to the total number of 1/8 sections under both of them.

It can be written in mathematical form as,

⇒  1/2 + 1/4

⇒ 4 × 1/8 + 2 × 1/8

⇒ 6/8

Hence, the required sum of the given fractions can be evaluated as 6/8.

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Answer:

1/4 of a can

Step-by-step explanation:

He had 1/3 of a can.

He used 3/4 of the 1/3 of the can.

He used 3/4 * 1/3 of a can.

3/4 * 1/3 = 3/12 = 1/4

Answer: 1/4 of a can

Answer: It neither

Step-by-step explanation:

because x part is linear while y part is neither linear or exponential.

They both are supposed to have the same relationship since They are not then it’s neither linear or exponential.

Hope it help.

Answer:

$4.95

Step-by-step explanation:

Answer:

4.59

Step-by-step explanation:

0.59x5=$2.95

2.95+2=4.59

Answer:

y = 18

Step-by-step explanation:

[tex] \frac{21 + 7}{21} = \frac{y + 6}{y} [/tex]

[tex] \frac{28}{21} = \frac{y + 6}{y} [/tex]

Cross multiply

28*y = 21(y + 6)

28y = 21y + 126

28y - 21y = 126

7y = 126

y = 126/7

y = 18

Answer:

For s students, at least 6s liters of water will be needed. So, for 30 students, at least 6*30 = 180 liters of water will be needed.

Step-by-step explanation:

This question is solved by proportions, using rule of three.

I am going to say that:

s is the number of students.

l is the number of liters of water needed for s students.

I have found that with five students in the class at least 30 litres of water is needed.

This means that:

[tex]\frac{s}{l} = \frac{5}{30}[/tex]

[tex]5l = 30s[/tex]

[tex]l = \frac{30s}{5}[/tex]

[tex]l = 6s[/tex]

This means that for s students, at least 6s liters of water will be needed. So, for 30 students, at least 6*30 = 180 liters of water will be needed.

Answer:

The correct answer is A.

Step-by-step explanation:

From the picture you provided, you choose option A, f(x) = x^7 - x^3 - 3x^2 + 3 . Hope that helped :)

The functions that could have created this graph is f(x) = x⁷-x³-3x²+3

A function is an equation for which any x that can be put into the equation will produce exactly one output such as y out of the equation.

Given is a graph, we need to find its equation,

So, the graph is U-shaped, therefore, the leading coefficient is, a > 0

also, the graph does not have a zero at the origin,

The function which could possibly create the graph is the option; A.

F(x) = x⁷-x³-3x²+3

The leading coefficient is 1 > 0

The function has no factors of x = 0

The function has a linear factor.

Hence, the functions that could have created this graph is f(x) = x⁷-x³-3x²+3

Learn more about functions, click;

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Answer:

a) Since both np >= 5 and n(1-p) >= 5,  it is reasonable to approximate the sampling distribution of p^‚ using a normal distribution.

b) 0.5 = 50% probability of observing a sample proportion of at 0.658.

Step-by-step explanation:

a. Show that it is reasonable to approximate the sampling distribution of p̂ using a normal distribution.

We need that:

np >= 5

n(1-p) >= 5

Sample of 76, 50 of the children were born were right-handed.

So [tex]n = 76, p = \frac{50}{76} = 0.658[/tex]

np = 76*0.658 >= 5

n(1-p) = 76*0.342 >= 5

Since both np >= 5 and n(1-p) >= 5,  it is reasonable to approximate the sampling distribution of p^‚ using a normal distribution.

b. Assuming left- and right-handed children are equally likely from right-handed parents, what is the probability of observing a sample proportion of at least p̂ =0.658 ?

This is the mean, so 50% below and 50% above.

0.5 = 50% probability of observing a sample proportion of at 0.658.