Answer: False!
This equation is in slope - intercept form, where y = mx + b. B is the y - intercept and m is the slope. They got the location of the y - intercept right, but they forgot to add the negative. It's actually -8.
Hope this helps!
The y-intercept is -8 as the minus always stays with the number to the right of it
[tex] \int \sec(x) dx[/tex]
Evaluate the integral above
[tex] 👋 [/tex] Hello ! ☺️
Step-by-step explanation:
∫sec(x)dx =
∫ [tex]\frac{sec(x).(secx + tanx)}{secx + tanx}dx[/tex]
∫ [tex] \frac{sec {}^{2} (x) + secxtanx}{secx + tanx}dx [/tex]
u = secx + tanx
[tex] du = secx tanx + sec {}^{2}x \: dx[/tex]
[tex] ∫\frac{1}{u}du [/tex]
∫sec(x)dx= ln |u|
[tex]\boxed{\color{gold}{∫sec(x)dx= ln |secx +tanx| + C}} [/tex]
[tex]<marquee direction="left" scrollamount="2" height="100" width="150">💘Mynea04</marquee>[/tex]
Answer:
[tex] = \ln( | \sec(x) + \tan(x) | ) + C[/tex]
Step-by-step explanation:
[tex] \int \sec(x) dx[/tex]
multiply and divide by sec x + tan x
[tex] = \int \frac{ \sec(x) ( \sec(x) + \tan(x) ) }{ \sec(x) + \tan(x) } dx[/tex]
let u = sec x + tan x
du = (sec x)(sec x + tan x) dx
[tex] = \int \frac{1}{u} du[/tex]
[tex] = \ln( |u| ) + C[/tex]
[tex] = \boxed{\color{green}{ \ln( | \sec(x) + \tan(x) | ) + C}}[/tex]
Find the product. √5(2+√7) A)2√5+√35 B)√45 C)2√5+2√7 D)√10+√35
Answer:
[tex]\huge \boxed{2\sqrt{5} +\sqrt{35}}[/tex]
Step-by-step explanation:
[tex]\sqrt{5} (2+\sqrt{7} )[/tex]
Expand brackets.
[tex]\sqrt{5} (2)+\sqrt{5}(\sqrt{7} )[/tex]
[tex]2\sqrt{5} +\sqrt{5} \sqrt{7}[/tex]
Apply radical rule : [tex]\sqrt{a} \sqrt{b} =\sqrt{ab}[/tex]
[tex]2\sqrt{5} +\sqrt{5 \times 7}[/tex]
[tex]2\sqrt{5} +\sqrt{35}[/tex]
Answer:
[tex] \boxed{ \boxed{ \bold{ \blue{2 \sqrt{5} + \sqrt{35} }}}}[/tex]Option A is the correct option.
Step-by-step explanation:
[tex] \sf{ \sqrt{5} \: (2 + \sqrt{7} )}[/tex]
Distribute √5 through the parentheses
⇒[tex] \sf{ \sqrt{5} \times 2 + \sqrt{5} \times \sqrt{7} }[/tex]
Calculate the product
⇒[tex] \sf{2 \sqrt{5} + \sqrt{5 \times 7} }[/tex]
⇒[tex] \sf{2 \sqrt{5} + \sqrt{35} }[/tex]
Hope I helped!
Best regards!
Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.
Explain how you know that Rectangle C is not a scaled copy of Rectangle B.
Answer:
Step-by-step explanation:
The length is x2 while the width is x1.5
Therefore it cannot be a scaled copy
Answer: It is not scale copy (given)
Step-by-step explanation:
Rectangle B: 15 by 10
Rectangle C: 30 by 15
-------------------------------------
First way: Compare the ratio among themselves
Rectangle B: 15:10=3:2
Rectangle C: 30:15=2:1
Apparently, the two side ratios are not the same, thus it is not scale copy
--------------------------------------
Second way: Compare the ratio between the two.
Length: Rectangle B:Rectangle C=15:30=1:2
Width: Rectangle B:Rectangle C=10:15=2:3
1:2≠2:3
Thus, Rectangle C is not a scaled copy of Rectangle B
Through 5 games in April, Lebron James has scored 112 points. At this rate, how many points will he score in his next 12 games? Round to the nearest point. _______ points
Answer:
269points
Step-by-step explanation:
112/5=22.4
22.4x12=268.8
268.8≈269
Two variable equation
Simplify 3+2-16x9
Simplify : 4-3+7(12-2)
Answer:
[tex]3+2-16x9[/tex] is [tex]5-16x^9[/tex] [tex]4-3+7(12-2)[/tex] is [tex]71[/tex]
Step-by-step explanation:
calculate the values of the expression below 5 - 2 * 3 + 6 (3^2+1)
Answer:
= 59
Step-by-step explanation:
5 - 2 * 3 + 6 (3² + 1)
= 5 - 2 * 3 + 6 * 10
= 5 - 6 + 6 * 10
= 5 - 6 + 60
= 59
Answer:
59Step-by-step explanation:
[tex]5-2\times \:3+6\left(3^2+1\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3^2+1\right)\::\quad 10\\\\=5-2\times \:3+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times \:3\::\quad 6\\=5-6+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\times \:10\::\quad 60\\\\=5-6+60\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5-6+60\:\\\\:\quad 59[/tex]
Write an equation in slope-intercept form for each line described. Slope = 8, passes through (-7,5)
Answer:
Equation of given line: y=8x+61
See graph below for a visual of given straight line equation.
+graph%28+300%2C+300%2C+-10%2C+10%2C+-100%2C+100%2C+8x%2B61%29+
Vertical and passes through (-4,-2)
vertical slope means that the equation becomes: x=-4, (y does not matter)
hope it helps
(20pts) Prove that the product of any two odd numbers is always odd. Make sure to explain your proof
Answer:
See below (I hope this helps!)
Step-by-step explanation:
Because odd numbers are always 1 greater than even numbers, we can call the two odd numbers x + 1 and y + 1 where x and y are even integers. Multiplying the two gives us:
(x + 1) * (y + 1)
= x * y + x * 1 + 1 * y + 1 * 1
= xy + x + y + 1
We know that x * y will be even because x and y are also even and the sum of two even numbers will be even, and we also know that x and y are even and that 1 is odd. Since the sum of even and odd numbers is always odd, the product of any two numbers is always odd.
*NOTE: I put a limitation on x and y in my proof (the limitation was that x and y must be EVEN integers) but you don't have to do that, you could make the odd integers 2x + 1 and 2y + 1 where x and y could be any integer from the set Z like mirai123 did. I simply gave this proof because it was the first thing that came to mind. While mirai123's proof and mine are different, they are still both correct.
Answer:
Prove that the product of any two odd numbers is always odd.
Examples:
[tex]3 \cdot 7 = 21 \text{ } \boxed{\text{odd}}\\5 \cdot 9 = 45 \text{ } \boxed{\text{odd}}\\83 \cdot 3 = 249 \text{ } \boxed{\text{odd}}[/tex]
Defining an odd number as:
[tex]u= 2k+1, k \in \mathbb{Z}[/tex]
[tex]u \cdot u = (2k+1)(2k+1)= 4k^2+4k+1[/tex]
[tex]\text{Is } \boxed{4k^2+4k+1} \text{ odd?}[/tex]
Yes, it is, because [tex]4k^2 \text{ and } 4k \text{ will always be even considering } k \in \mathbb{Z}[/tex]
An even number plus one is an odd number.
work out 2 ¼÷ ½ as a single fraction
Show all your working.
Answer:
Step-by-step explanation:
[tex]2\frac{1}{4}[/tex] ÷[tex]\frac{1}{2}[/tex] = [tex]\frac{9}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex]
[tex]=\frac{9}{4}*\frac{2}{1}\\\\\\=\frac{9}{2}\\\\\\=4\frac{1}{2}[/tex]
two variable equation
LET x=0 x-2y=4 what is the value of y?
Solve for the missing variable: LET y=0: x-2y=4 what is the value of x?
Step-by-step explanation:
(i) Let x = 0 and x-2y=4
Put x = 0 in x-2y=4
0-2y=4
-2y=4
y=-2
If x = 0, the value of y is -2.
(ii) Let y=0 and x-2y=4
Put y = 0 in x-2y=4
x-2(0)=4
x=4
If y = 0, the value of x is 4.
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks
Complete question :
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.
Answer:
575 - 12t
Step-by-step explanation:
Given the following :
Total number of fireworks = 575
Number of shots per minute = 12
To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.
In algebraic terms
[total number of fireworks on display - (number of shots per minute × t)]
575 - 12t
Which equation has exactly one solution?
A. x+7= x-2
B. 2(x-6)=2x-12
C. 3(x+2) = 2x-5
D. 7x+13= 13+7x
Answer:
a and c
Step-by-step explanation:
a. 9=x
b.2x-12=2x-12 ims
c.3x+6=2x-5
3x+11=2x
11=-1x
-11=x
d. ims
Simplify -6/3 divided by 2/-9
How many different outfits can be made
if Jessica chooses 1 each from 11 skirts, 9 blouses,
3 belts, and 7 pairs of shoes?
Answer: 2079
Step-by-step explanation: 11 x 9 x 3 x 7 = 2079, there are 2079 possible combinations of outfits
Using the Fundamental Counting Theorem, it is found that 2079 different outfits can be made.
What is the Fundamental Counting Theorem?It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
In this problem, considering the options, we have that [tex]n_1 = 11, n_2 = 9, n_3 = 3, n_4 = 7[/tex].
Hence, the total number of options is given by:
N = 11 x 9 x 3 x 7 = 2079.
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866
#SPJ2
What are the whole numbers between 3 to 10?
4, 5, 6, 7, 8 and 9 are the whole numbers between 3 to 10.
What are whole numbers?Whole numbers are a set of numbers including all natural numbers and 0. They are a part of real numbers that do not include fractions, decimals, or negative numbers. Counting numbers are also considered as whole numbers.
Two given whole numbers are 3 and 10.
The number of whole numbers between 3 to 10 is
(10-3)-1=6
The whole numbers between 3 to 10 are 4, 5, 6, 7, 8, 9.
Therefore, 4, 5, 6, 7, 8 and 9 are the whole numbers between 3 to 10.
Learn more about the whole numbers here:
https://brainly.com/question/29766862.
#SPJ2
26 points with brainiest and 5 stars and thanks, please help! :[
Answer:
[tex]\Huge \boxed{{9}}[/tex]
Step-by-step explanation:
Let the age of Darrell be x.
Let the age of Bryce be y.
x = y + 8
xy = 153
Substitute x = y + 8 in the second equation.
(y+8)y = 153
Solve for y.
y² + 8y = 153
Subtract 153 from both sides.
y² + 8y - 153 = 0
Factor left side.
(y-9)(y+17) = 0
Set factors equal to 0.
y - 9 = 0, y = 9
y + 17 = 0, y = -17
The value of y has to be positive, so y = 9.
Substitute y = 9 in the first equation.
x = 9 + 8
x = 17
Darrell is 17 years old.
Bryce is 9 years old.
Answer:
[tex]\huge\boxed{9\ years}[/tex]
Step-by-step explanation:
Let Darrel's Age be x and Bryce's Age be y
Condition 1:
x = 8 + y
Condition 2:
xy = 153
Put the 1st equation in the second one
(8+y)y = 153
y²+8y-153 = 0
y²+17y-9y-153 = 0
y(y+17)-9(y+17) = 0
(y-9)(y+17) = 0
Either,
y-9 = 0 OR y+17 = 0
y = 9 OR y = -17 [Contrary to be given, Age can never be negative]
So, y = 9
And
Bryce's Age = 9 years
If y = 1/2(d + 1), find y when d = 7
Answer:
4
Step-by-step explanation:
Plug in 7 for d:
y= 1/2(7+1)
y=1/2(8) .... Adding what's in the parenthesis (PEMDAS)
y=4 ..... Multiply 1/2 by 8
Hope this helps:)
Answer:
[tex] \boxed{ \boxed{ \bold{ \purple{y = 4}}}}[/tex]Step-by-step explanation:
[tex] \sf{Given}[/tex]
[tex] \sf{d = 7}[/tex]
Let's find the value of y:
[tex] \sf{y = \frac{1}{2} (d + 1)}[/tex]
plug the value of d
[tex] \sf{ = \frac{1}{2} (7 + 1)}[/tex]
Add the numbers
[tex] \sf{= \frac{1}{2} \times 8}[/tex]
Calculate
[tex] \sf{ = 4}[/tex]
Hope I helped!
Best regards!
After a snowstorm in the town of Golden Glen, the morning temperature was – 10°F. But by the afternoon, the temperature had risen by 17°F. What was the afternoon temperature?
Answer:
7°F
Step-by-step explanation:
We have the following information from the question;
Morning temperature = -10°F
Increase in temperate = 17°F
Afternoon temperature = the unknown
Since;
Increase in temperature = Afternoon temperature - morning temperature
Then;
Afternoon temperature = increase in temperature + morning temperature
Afternoon temperature = 17°F + (-10°F)
Afternoon temperature= 7°F
Answer:
7
Step-by-step explanation:
Your welcome!
kinyua spent 1/4 of his net january salary on school fees .he spent 1/4 of the remainder on electricity,he spent 1/9 of what remained on transport,if he finally had sh 3400,calculate his net january salary
Answer:
1-1/4 = 3/4.
3/4-1/4 = 2/4 = 1/2.
1/2-1/9 = 9/18-2/18 = 7/18.
7x/18 = 8400
X = $21,600 = Net Jan. salary.
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
Find y' if x = cos(y).
1. Solve for y (complex solution)
y=−iln(x2−1+x)+2πn1, n1∈Z
y=−iln(−x2−1+x)+2πn2, n2∈Z
2. Solve for y (Easier)
y=−arccos(x)+2πn1, n1∈Z
y=arccos(x)+2πn2, n2∈Z, ∣x∣≤1
Can The intersection of two planes can be a ray.
Answer: Either the plane and the ray perfectly coincide in which case there is an infinity of solutions or the ray is away from the plane in which case there is no intersection. Generally in a C++ implementation, when the denominator is lower than a very small value, we simply return false (no intersection was found).
Step-by-step explanation:
Find the value of a/b when a = 2/3 and b= 7/9
Answer:
6/7
Step-by-step explanation:
2/3X9/7
simplify 9 by 3
which equals:
2/1X3/7
=6/7
What is the inverse function of y = -5/3x - 8?
Answer:
You can't graph inverse function on graphing calculator
Step-by-step explanation:
step 1 rewrite function f(x) --> y
step 2 change x and y's position
step 3 solve for y
step 4 replace Y with f-1(up to f) and (x)
A triangle has vertices at (-4,-6),(3,3), (7,2). Rounded to two decimal places, which of the following is the closest approximation of
the perimeter of the triangle?
A. 19.34
B. 12.36
C. 15.52
D. 29.12
Answer:
Hey there!
The perimeter of the triangle is the distance around it.
We can find the distance of two points using the distance formula, and add up all the distances to find the total distance.
-4, -6 to 3, 3 is 2
3, 3 to 7, 2 is 5
7, 2 to -4, -6 is about 5.4
2+5+5.39=12.4, which is closest to 12.36.
Let me know if this helps :)
(4,0) (3,-1) (6,3) (2,-4) which are solutions to y=x-4
Answer:
None of them are
(4,-4)
Step-by-step explanation:
To find the value of x make y =0 then substitute into the formula. Therefore 0 = x-4 then make x the subject by adding 4 to the other side 4+0=x.
Then to find the value of y make x=0 then substitute it into the formula y=0-4 which is equal to - 4
I hope this helps
can you please solve this for me asap?
Hi there! :)
Answer:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
Use the Pythagorean theorem to solve for the side-length of DC. Let "s" represent the side-lengths:
s² + s² = 26
2s² = 26
Divide both sides by 2 to simplify:
s² = 13
Take the square root of both sides:
s = √13 ≈ 3.61 cm.
------------------------------------------------------------------------------------------
Calculate the shaded region by subtracting the area of the arc from the area of the square. DC represents the radius of the circle that the arc is apart of. Therefore:
Area of arc AC = 1/4 (πr²)
Solve for the area:
AC = 1/4 (π · (3.61)²)
AC = 1/4 (40.92)
AC = 10.23 cm²
Subtract this area from the area of the square (A = s²)
A = (√13)²
A = 13 cm²
13 - 10.23 = 2.77 cm²
Therefore, the solutions are:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
which value of x makes the equation 2.75(2x - 14)= 5.55
Answer:
x=881/110 =8^1/110 =8.009
Step-by-step explanation:
2.75(2x−14)=5.55
Divide both sides by 2.75.
2x-14=5.55/2.75
Expand 5.55/2.75 by multiplying both numerator and the denominator by 100.
2x−14= 555/275
Reduce the fraction 555/275 to lowest terms by extracting and canceling out 5.
2x−14= 111/5
Convert 14 to fraction 770/55 = 14
2x=111/55+770/55
Since 111/55 and 770/55 have the same denominator, add them by adding their numerators.
2x=111+770/5
Add 111 and 770 to get 881.
2x=881/55
Divide both sides by 2.
x= 881/55/2
Express 881/55/2 as a single fraction.
x= 881/55 x 2
Multiply 55 and 2 to get 110.
x = 881/110
Mike is catering a party. He plans on having 4 trays of 5 appetizers each on the buffet at the beginning of the party and will rotate in new trays as those become empty. To ensure that he does not run out of appetizers during the party, he is going to make 2 appetizers per person in addition to the initial number put out on the buffet. Which of the following represents A, the amount of appetizers Mike needs to make, in terms of p, the amount of people attending the party?
A.
A = 20p + 2
B.
A = 20 + 2p
C.
A = 2 - 20p
D.
A = 2p - 20
Answer:
B
Step-by-step explanation:
Since he needs to make 2 appetizers per person, the variable "p" needs to go with the "2".
Also, since he is making 20 ( 4 trays, 5 apps each) extra appetizers for the beginning, we will need to add 20 to that number.
x=3y+6
how do I solve for y?
Answer: y=2X-3
Step-by-step explanation:
1st u need to subtract the 6 on each side so your left with, -6+X=3y, then u divide the 3 on each side and your left with, -3+2X=y.
HW: Solve for the
1) 5(2- b) = 0
Plz help ASAP???
Answer:
[tex]\huge \boxed{b=2}[/tex]
Step-by-step explanation:
[tex]5(2- b) = 0[/tex]
[tex]\sf Divide \ both \ sides \ by \ 5.[/tex]
[tex]2-b=0[/tex]
[tex]\sf Subtract \ 2 \ from \ both \ sides.[/tex]
[tex]-b=-2[/tex]
[tex]\sf Cancel \ negative \ signs.[/tex]
[tex]b=2[/tex]
Answer:
b = 2
Step-by-step explanation:
5(2-b) = 0
=> 5 x 2 - 5 x b = 0
=> 10 - 5b = 0
=> -5b = -10
=> -b = -10/5
=> -b = -2
=> b = 2
Let's check whether our answer is correct:
=> 5(2-2) = 0
=> 5 (0) = 0
=> 0 = 0