PLEASE HELP The mean life expectancy of a certain type of light bulb is 860 hours with a standard deviation of 22 hours.

What is the approximate standard deviation of the sampling distribution of the mean for all samples with n = 65?


0.34 h


0.75 h


2.73 h


2.95 h

Answer:

c) (1,-1)

Step-by-step explanation:

I hope this helps

Answer:

Step-by-step explanation:

it goes straight across 4 ( up and down)

Answer:

Step-by-step explanation:

Start with the standard form of an equation for a straight line:

y=mx+b,

where m is the slope and b is the y-intercept (the value of y when x = 0).

We are given the slope (4), so we have:

y = 4x + b

We can calculate b from the given point, (0,4).  Just enter the values for x and y and solve for b.  But in this case the given point already tells us the value of b since at x = 0, y = 4.  So we can enter it directly.

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For reference, if we went ahead and solved for b, this is what we'd get:

y = 4x + b

4 = 4*(0) + b

b = 4

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So the final equation of this line is y = 4x + 4

The graph is attached.

Answer:

Length is 35 width is 25

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

10.5 ÷ 3 = 3.5

3.5 × 6 = 21

Answer:

You look at the sign between y and 2x

Step-by-step explanation:

To find which way to shade, look at your symbol. The symbol you have is a less than or equal to, you shade to the left. Because it has the line underneath, you have a closed circle. (This is for line plots so I don't know if this completely helps)

Hopefully it does help though!!

Answer: D

Step-by-step explanation:

Answer:

i say go with D

Step-by-step explanation:

Answer:

153 adults and 168 children

Step-by-step explanation:

x - number of adults

y - number of children

[tex]\left \{ {{6x + 4y = 1590} \atop {x + y = 321}} \right.[/tex]

[tex]\left \{ {{6x+4y = 1590} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{6*(321 - y)+4y = 1590} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{1926 -6y+4y=1590} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{1926 -2y=1590} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{-2y=1590-1926} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{-2y=-336} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{y=168} \atop {x=321-y}} \right.[/tex]

[tex]\left \{ {{y=168} \atop {x=321-168}} \right.[/tex]

[tex]\left \{ {{y=168} \atop {x=153}} \right.[/tex]

Is it all clear?

Answer:

the answer is jesus asdlkfjsfs

Answer:

Step-by-step explanation:

If two triangles are congruent, then the corresponding sides and angles are congruent with each other.

Given:

The following are congruent parts:

Note Pay attention to order of vertices when comparing the congruent parts

[tex]\\ \sf\longmapsto <E\cong <U[/tex]

[tex]\\ \sf\longmapsto \overline{RE}=\overline{SU}[/tex]

[tex]\\ \sf\longmapsto ∆DRE=∆SUN[/tex]

[tex]\\ \sf\longmapsto <R\cong <S[/tex]

Hope it helps

Answer:

Divide both sides by -10

-10n+2=40

subtract 2 from both sides so

40-2=38

10n/10= 38/10

3.8 = n

Step-by-step explanation:

Given info:- [tex]\textsf{If (√3+√2)/(3√2-2√3) = x+y√6,} [/tex]

[tex]\textsf{then find the value of x and y?}[/tex]

Explanation:-

[tex]\textsf{Consider LHS=}\\[/tex]

[tex] \rm \: \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \\ [/tex]

[tex] \rm \: = \frac{ \sqrt{2 } + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ [/tex]

[tex] = \rm \: \frac{( \sqrt{2 } + \sqrt{3} )(3 \sqrt{2} + 2 \sqrt{3} )}{(3 \sqrt{2} - 2 \sqrt{3})(3 \sqrt{2} + 2 \sqrt{3}) } \\ [/tex]

[tex] \rm \: = \frac{3 \sqrt{2 \times 2} + 2 \sqrt{3 \times 2} + 3 \sqrt{2 \times 3} + 2 \sqrt{3 \times 3} }{(3 \sqrt{2} {)}^{2} - (2 \sqrt{3} {)}^{2} } \\ [/tex]

[tex] \rm = \frac{3 \times 2 + 2 \sqrt{6} + 3 \sqrt{6} + 2 \times 3}{18 - 12} \\ [/tex]

[tex] \rm \: = \frac{12 + 5 \sqrt{6} }{6} \\ [/tex]

[tex] \rm \: = 2 + \frac{5}{6} \sqrt{6} \\ [/tex]

[tex] \rm \therefore \: 2 + \frac{5}{6} \sqrt{6} = x + y \sqrt{6} \\ [/tex]

[tex]\textsf{On, comparing with RHS we notice that:}\\[/tex]

[tex]\textsf{the value of x = 2 and y = 5/6.}\\[/tex]

[tex]\bf{Read more:}[/tex]

[tex]\textsf{Similar questions}\\[/tex]

[tex] \sqrt{6} + \sqrt{11} \div \sqrt{5} + \sqrt{3} [/tex] A. [tex] \sqrt{30} + 3 \sqrt{2} + \sqrt{55} + \sqrt{33} \div 8[/tex] B. [tex] \sqrt{30} - 3 \sqrt{2} ...

https://brainly.com/question/8346905?referrer

Answer:

10. 45/6  

Step-by-step explanation:

Whatever you do to the top you have to do to the bottom. To get 2 from 6 in the denominator you would have had to divide by 3 so I multiplied 15 by 3 to give make the two fractions equal to each other. If you are not sure if your answers are correct just divide the numerator by the denominator on the calculator and if they are equal values then it's correct.

Answer:

990

Step-by-step explanation:

9900 * 10/100

= 990

Hello there!

First, divide by 100:

99

Now, multiply by 10:

990 is the answer.

Hope it helps!

~Just a determined gal

#CarryOnLearning

[tex]MysteriousNature[/tex]

Answer:

It would be 2 times the old perimeter.

Answer:

23x2x2

Step-by-step explanation:

Step-by-step explanation:

3/(4(x+2)) = x/(x+2)

the common denominator would have to be 4(x+2).

to get the right side to this denominator, we have to multiply numerator and denominator (top and bottom) by 4.

and then we get

3/(4(x+2)) = (4x)/(4(x+2))

and now as both sides are "standing" on the same denominator, we can simply compare only the top parts.

3 = 4x

and therefore we can solve

x = 3/4

and D is then the right answer choice.

Answer:

Lateral surface area = 154cm²

Step-by-step explanation:

h = 10cm

pi = 22/7

base area = 154cm²

2πrh = 154cm²

2 × 22/7 × r × 10 = 154

440/7 × r = 154

r = 154 ÷ 440/7 = 2.45

r = 2.45

LSA of right circular cylinder = 2πrh

2 × 22/7 × 2.45 × 10

44/7 × 24.5 = 1078/7

1078/7 = 154

Therefore, lateral surface area = 154cm²

Hope it helps:)

Answer:

r = 15

Step-by-step explanation:

Using Pythagoras' identity in the right triangle OAB

with OM and OB the radii r of the circle

OA² = OB² + AB²

(r + 10)² = r² + 20² ← expand left side using FOIL

r² + 20r + 100 = r² + 400 ( subtract r² from both sides )

20r + 100 = 400 ( subtract 100 from both sides )

20r = 300 ( divide both sides by 20 )

r = 15

Answer:

the answer is 12ft hope that helps

Answer:

3.5

Step-by-step explanation:

The tenths place would be 0.1

So in 3.468 the 4 is in the tenths place

Look at the number to the right of it, if it is greater than 5 you round up and if it is 4 or lower you stay the same.

For 3.468 you would round up

So you would have 3.5

Have A GREAT day man

Sincerly, lipor

Answer:

27 Chairs (See below)

Step-by-step explanation:

A: You will put 9 chairs in each row, and have 3 rows.

For a visual example I will use the symbol "O" for the number of chairs.

OOOOOOOOO

OOOOOOOOO

OOOOOOOOO

B: The multiplication problem, using the information 3 Rows, and 9 Chairs in each row, is 9x3

C: The factors are the numbers you are multiplying with, and the product, is your outcome when you multiply the two factors, 9, and 3.

So your answer is 27.

Hope this helps!

Answer:

A

Step-by-step explanation:

4×-12

Answer is letter A

hope it help^^

Answer:

78.5

Step-by-step explanation:

[tex]r^{2}[/tex]x3.14 (pie)

so then substitute.

5x5=25

25x3.14=78.5

The solution to the logarithmic equation [tex]\mathbf{log_2(x-6) = 4}[/tex] is x =24

The logarithmic equation is given as:

[tex]\mathbf{log_2(x-6) = 4}[/tex]

Apply exponential law of logarithm

[tex]\mathbf{(x-6) = 2^4}[/tex]

Remove the brackets

[tex]\mathbf{x-6 = 2^4}[/tex]

Add 6 to both sides

[tex]\mathbf{x-6 +6= 6+ 2^4}[/tex]

Express 2^4 as 16

[tex]\mathbf{x-6 +6= 6+ 16}[/tex]

Add -6 and 6

[tex]\mathbf{x= 6+ 16}[/tex]

Add 6 and 16

[tex]\mathbf{x= 24}[/tex]

Hence, the solution to the logarithmic equation [tex]\mathbf{log_2(x-6) = 4}[/tex] is x =24

Read more about logarithmic equation at:

https://brainly.com/question/3181916

Answer:

the bottom right

Step-by-step explanation:

Answer:

your friend is faster.

Step-by-step explanation:

2 km in 12 min means 3 km in 18 min.

you friend jogs those same 3 km in 16.5 min, so he or she is faster.

Step-by-step explanation:

I'm assuming your solving for [tex]x[/tex]

Picture 2.

For this one since the two sides are equal

[tex]2x-12=12\\2x=24\\x=12[/tex]

Picture 4.

We can use the Pythagorean theorem for this one, which is [tex]a^2+b^2=\sqrt{c}[/tex]

[tex]4\cdot4=16\\3\cdot3=9\\16+9=25\\\sqrt{25}=5[/tex]

[tex]x=5[/tex]

Picture 6.

We can use the Pythagorean theorem for this one, which is [tex]a^2+b^2=\sqrt{c}[/tex]

[tex]6\cdot6=36\\9\cdot9=81\\36+81=117\\[/tex]

[tex]\sqrt{117}=approximately[/tex] [tex]10.81[/tex]

Picture 8.

[tex]EG=6[/tex]

Since half of [tex]EG[/tex] is [tex]3[/tex]

[tex]3\cdot2=6[/tex]

[tex]EG=6[/tex]

Brainliest, please :)

Answer:

Step-by-step explanation: