Answer:
1) P = 282m, A = 141m^2
2) P = 82.4in, A = 40in^2
3) P = 62.7m, A = 73.1m^2
Step-by-step explanation:
1) top:L=12m, W=3m, mid: l= 12m, w= 12-7 = 5m, bot: l=15m, w=3m
Perimeter= 2(lw)
P = 2(12x3) + 2(12x5) + 2(15x3)
P = 2(36) + 2(60) + 2(45)
P = 72 + 120 + 90
P = 282m
Area= lw
A = (12x3) + (12x5) + (15x3)
A = 36 + 60 + 45
A = 141m^2
2) Rectangle:l=7in, w=5in, Right Triangle:a=5-3=2in, b=12-7=5in
Perimeter= 2(lw) + (a+b+sqrt(a^2+b^2))
P = 2(7x5) + (2+5+sqrt(2^2+5^2))
P = 70 + 12.39
P = 82.4in
Area= lw + ((ab)/2)
A = (7x5) + ((2x5)/2)
A = 35 + 5
A = 40in^2
3) Semi-Circle: d=8m, r=8/2=4m, Right Triangle: a=8m, b=12m
Perimeter= pid + (a+b+sqrt(a^2+b^2))
P = 9pi + (8+12+sqrt(8^2+12^2))
P = 28.27 + 34.42
P = 62.7m
Area= (1/2)pir^2 + ((ab)/2)
A = (1/2)pir^2 + ((ab)/2)
A = (1/2)pi(4)^2 + ((8x12)/2)
A = 25.13 + 48
A = 73.1m^2
The college student senate is sponsoring a spring break Caribbean cruise raffle. The proceeds are to be donated to the Samaritan Center for the Homeless. A local travel agency donated the cruise, valued at $2000. The students sold 2357 raffle tickets at $5 per ticket.
Required:
a. Kevin bought ten tickets. What is the probability that Kevin will win the spring break cruise to the Caribbean?
b. Expected earnings can be found by multiplying the value of the cruise by the probability that Kevin will win. What are Kevin's expected earnings?
c. How much did Kevin effectively contriute to the Samaritan Center for the Homeless?
Answer:
A) The probability that Kevin will win the spring break cruise is 0.42%.
B) Kevin's expected earnings are $ 8.4.
C) Kevin effectively contributed with $ 50.
Step-by-step explanation:
Since the college student senate is sponsoring a spring break Caribbean cruise raffle, and the proceeds are to be donated to the Samaritan Center for the Homeless, ya local travel agency donated the cruise, valued at $ 2000, and the students sold 2357 raffle tickets at $ 5 per ticket, to determine A) if Kevin bought ten tickets, what is the probability that Kevin will win the spring break cruise to the Caribbean; B) Kevin's expected earnings and C) how much did Kevin effectively contribute to the Samaritan Center for the Homeless; the following calculation must be performed:
A) 10/2357 = 0.0042 x 100 = 0.42
Therefore, the probability that Kevin will win the spring break cruise is 0.42%.
B) 2000 x 0.0042 = 8.4
Therefore, Kevin's expected earnings are $ 8.4.
C) 5 x 10 = 50
Kevin effectively contributed with $ 50.
HELP MEEEEEEEEEEEE please
Answer:
X = 5
Step-by-step explanation:
Hope it's help you !!!!!!!!!
Answer:
X=5
Step-by-step explanation:
X=5
The other side is the same as X so it is 5. Also it the same as the bottom that = 5.
13. The pair of figures are congruent. Find the value of e.
37°
10 ft
8 ft
53°
6 ft
Answer:
No solution is possible from the provided information
Step-by-step explanation:
|-5| >3 true or false plssssss answer it’s important
Answer:
TRUE
Step-by-step explanation:
Those lines around the -5 mean the absolute value of the number, basically the value of the number without any negative signs. SO the absolute value of -5 is just 5.
5 IS GREATER than 3, so this is true
ur welcome :)
What are the values of A, B, C, and D?
A = 0; B = 1; C = -3; D = 3
A = 0; B = 1; C = 3; D = -3
A = 1; B = 0; C = -3; D = 3
A = 1; B = 0; C = 3; D = -3
Don’t know real answer
The values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
How to solve for A, B, C and D?From the question, we have:
x^3 + 8x - 3 = Ax^3 + 5Ax + Bx^2 + 5B + Cx + D
Collect like terms
x^3 + 8x - 3 = Ax^3 + Bx^2 + 5Ax + Cx + 5B + D
By comparing the coefficients, we have:
Ax^3 = x^3
Bx^2 = 0
5Ax + Cx = 8x
5B + D = -3
Remove the x factors
A = 1
B = 0
5A + C = 8
5B + D = -3
Substitute A = 1 in 5A + C = 8
5(1) + C = 8
Solve for C
C = 3
Substitute B = 0 in 5B + D = -3
5(0) + D = -3
Solve for B
D = -3
Hence, the values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
Read more about partial fractions at:https://brainly.com/question/18958301
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Stats question what are the main difference between frequenting and Bayesian
Answer:
The frequentist believes that probability represents long term frequencies of repeatable events (such a flipping a coin). Frequentists do not attach probabilities to hypotheses or unknown values. On the other hand, the Bayesian approach uses probabilities to represent the uncertainty in any event or hypothesis.HOPE IT HELPS
Evan wants to make an array of 32 miniature cars What are all the different ways Evan can place the cars?
Answer:
1 × 32, 2 × 16, 4 × 8, 8 × 4, 16 × 2, 32 × 1
Step-by-step explanation:
There are 6 different ways for Evan to create a array of 32 miniature cars.
What is the fundamental principle of multiplication?Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.
An array would constitute the shape of a parallelogram, in which you are essentially solving for s₁ and s₂.
Since there are 32 miniature cars in all, in which both sides, when multiplied, must result in said number:
32 x 1 = 32
2 x 16 = 32
4 x 8 = 32
8 x 4 = 32
16 x 2 = 32
1 x 32 = 32
Hence, There are 6 different ways for Evan to create a array of 32 miniature cars.
Learn more about multiplications;
https://brainly.com/question/14059007
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For the following right triangle find the side length x
Answer:
the answer should be 120 as the hypotenuse is obtained by √(a²+b²=c² )
Answer:
x = 17
Step-by-step explanation:
We're given a right triangle with the measures of two legs . We're also given as measures of hypotenuse as x .We need to find x.
Using Pythagorean theorem
a ² + b ² = c²
Where, a and b is the length of measures of legs and c is the measures of hypotenuse.Lebels the values , we get
( 15 ) ² + ( 8 )² = ( x ) ²
Expand the exponent
225 + 64 = x²
Add the numbers
289 = x²
Taking square root of both side
√289 = √x²
17 = x.
Hence, the length of side x is 17.
Find an equation for the line perpendicular to y= -4/3x+5 with y-intercept (0,-12). Write the answer in slope-intercept form
Answer:
y=3/4x−12.
Step-by-step explanation:
Slope of the perpendicular line is negative inverse: m=34.
The equation of the perpendicular line is y=3x4+a.
To find a, we use the fact that the line should pass through the given point: −12=(34)⋅(0)+a.
a=−12.
Therefore, the equation of the line is y=3x4−12.
If this helps you, please give bainliest!
I need help ASAP!!!!
Step-by-step explanation:
Kindly find 4 attached files
The proportionality is determined by the lines that only passes through the origin
And all the lines drawn are passing through the origin
So by either one of the 2 ways
By using rule of direct variation y=kx that has no y intercept
Or by finding the equation of straight line and find the slope with neglecting the y intercept since it's 0
The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an alphabetical list of all 4247 employees at the company and wants to conduct a systematic sample of size 40.
Required:
a. What is k?
b. Determine the individuals who will be administered the survey. Randomly select a number from 1 to k. Suppose that we randomly select 19. Starting with the first individual selected, the individuals in the survey will be: _________
Answer:
a). 106
b). See Explanation
Step-by-step explanation:
According to the Question,
Given, The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an alphabetical list of all 4247 employees at the company and wants to conduct a systematic sample of size 40.
a). Thus, the Required Value of K is 4247/40 = 106.175 ≈ 106
b). The individuals who will be administered the survey. Randomly select a number from 1 to k. Suppose that we randomly select 19. Starting with the first individual selected, the individuals in the survey will be
19(19+106) = 125(125+106) = 231337443549655761867973107911851291139715031609171518211927203321392245235124572563266927752881298730933199330534113517362337293835394140474153how much higher is -55 to -172?
Answer:
117 units higher
Step-by-step explanation:
|-172 + 55| = 172 - 55 = 117
117 units higher
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer:
30 more then 172
Step-by-step explanation:
12=x/5............................
Answer:
answer :
12 = x / 5
12 × 5 = x
60 = x
or
x = 60
312/132 (fraction simplified as a mixed number)
Answer:
2.3636363636 or 2 4/11
please answer the question first then explain
Answer:
Option A.
Step-by-step explanation:
If I have two variables b and c and a constant of 10. I can write that problem like this:
10b = c
For example, my factory today will make 20 books:
10×20 = c
$ 200 = c
What is the difference of the rational expressions blow 4x/9 - 2x/9
Step-by-step explanation:
answer in the photo above look
A five - question quiz is taken in which the first and second questions have four answer choices, the third and fourth questions have three answer choices,and the last question has five answer choices.If a student randomly marks an answer for each question, what is the expected number of questions he will answer correctly?
A: 0.96
B: 0.27
C: 1.37
D: 1.00
For the matrices below. Find all (real) eigenvalues.
A= [7 9]
[0 9]
Answer:
The answer is "9 and 7".
Step-by-step explanation:
Given:
[tex]A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right][/tex]
Using formula:
[tex]|A-\lambda \cdot I|= 0\\\\[/tex]
[tex]\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\[/tex]
[tex]\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\[/tex]
Which set of ordered pairs represent a function? O A {(1,0), (2,1), (2,3)} O B{(1,3), (1,4), (1,5)} O C{(1,5), (2,5), (3,5)} O D{(3, 1), (2, 2), (3, 3)}
Answer:
C
Step-by-step explanation:
C is the only answer that doesnt share x-values
An installation technician for a specialized communication system is dispatched to a city only when 3 or more orders have been placed. Suppose the orders follow a Poisson distribution with a mean of 0.25 per week for a city with a population of 100,000 and suppose your city contains 800,000.
a. What is the probability that a technician is required after a one-week period?
b. If you are the first one in the city to place an order, what is the probability that you have to wait more than two weeks from the time you place your order until a technician is dispatched?
Answer:
0.3233
0.09
Step-by-step explanation:
Given that :
Mean, λ = 0.25 for a 100,000 per week
For a population of 800,000 :
λ = 800,000 / 100,000 * 0.25 = 8 * 0.25 = 2 orders per week
Probability that technician is required after one week ;
After one week, order is beyond 2 ; hence, order, x ≥ 3
P(x ≥ 3) = 1 - [p(x=0) + p(x= 1) + p(x =2)]
P(x ≥ 3) = 1 - e^-λ(1 + 2¹/1! + 2²/2!)
P(x ≥ 3) = 1 - e^-2(1+2+2) = 1 - e^-2*5 = 1 - e^-10
P(x ≥ 3) = 1 - e^-2 * 10
P(x ≥ 3) = 1 - 0.6766764
P(x ≥ 3) = 0.3233
B.)
Mean, λ for more than 2 weeks = 2 * 2 = 4
P(x < 2) = p(x = 0) + p(x = 1)
P(x < 2) = e^-4(0 + 4^1/1!)
P(x < 2) = e^-4(0 + 4) = e^-4(5)
P(x < 2) = e^-4(5) = 0.0183156 * 5 = 0.0915
P(x < 2) = 0.09
Which of the following values are in the range of the function graphed below?
Check all that apply.
Answer:
D. -4
Step-by-step explanation:
the only graph I see is a red line in a coordinate grid.
this red line represents the function y = -4, for x in the interval [-1,4].
so, [-1,4] is the domain of the function, and [-4] is the range of the function.
when the question asks about what values are graphed below, and it mentions "range", I assume it means functional values (results of the function).
the only function I can see is the mentioned constant function y=-4, so that -4 is the only functional value (the only value in the range of the function) in this graphic.
please please please help!
Answer:
h=A-πr²÷2πr
Step-by-step explanation:
M making h subject
A=2πrh+πr²
A-πr²=2πrh
A-πr²÷2πr=h
h=A-πr²÷2πr
Translate the following sentence into an algebraic inequality: Three times a number, v, added to eight is greater than or equal to twenty-two. Question 7 options: A) 3v + 8 > 22 B) 3v + 8 ≥ 22 C) 3v + 8 ≤ 22 D) 3v + 8 < 22
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]3v + 8 \geq 22[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Breaking down the phrase...}}\\\\\text{Three times a number, v, added to eight is greater than or equal to twenty-two. }\\------------------\\\rightarrow \text{"Three times a number, v..."} - 3v \text{ This expresses the product of '3' and 'v'.}\\\\\rightarrow \text{"added to eight..."} - + 8 \text{ The product gets added to eight.}\\\\--------------\\\text{The First Part Is:}}\\\\3v + 8\\---------------\\\rightarrow \text{is greater than or equal to twenty-two. } - \geq 22[/tex]
[tex]\text{The value of '3v + 8' is greater than or equal to 22.}\\---------------\\\text{\underline{Putting it together, we would have:}}\\\\\boxed{3v + 8 \geq 22}}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Help please which option
Answer:
Step-by-step explanation:
-1<x<3. I hope it helpful!
What are the rational roots of f(d) = 5d - 6 + d-8?
Determine whether the following event is mutually exclusive or not mutually exclusive.
Choosing a student who is a mathematics major or a business major from a nearby university to participate in a research study. (Assume that each student only has one major.)
Answer:
The event is mutually exclusive.
Step-by-step explanation:
Mutually exclusive events are events that cannot exist simultaneously.
Thus, events that are not mutually exclusive can exist simultaneously.
Since each student only has one major, a single student cannot be both a mathematics major and a business major.
So, the event is mutually exclusive.
Which percentage is the best estimate for the shaded area under this normal curve?
=========================================================
Explanation:
It appears that -20 is the mean. It's not entirely clear however. If that assumption is correct, then the distance from -30 to -20 is 10 units. So the left endpoint is 1 standard deviation below the mean (because the standard deviation is 10 units).
Recall that through the empirical rule, roughly 68% of the distribution is within 1 standard deviation of the mean. This cuts in half to 34%. So the area from x = -30 to x = -20 is roughly 0.34
We'll use this value later so let A = 0.34
-------------------
The area under the curve from x = -20 to x = -10 is also 0.34
The area under the curve from x = -20 to x = 0 is 0.95/2 = 0.475
For the second part there, I'm using the idea that 95% of the normal distribution (roughly) is within 2 standard deviations of the mean.
So the area from x = -20 to x = -5 is somewhere between 0.34 and 0.475
Let B = 0.34 and C = 0.475
-------------------
The full shaded blue area is somewhere between A+B = 0.34+0.34 = 0.68 and A+C = 0.34+0.475 = 0.815
Based on that alone, the answer is between B and C.
-------------------
Unfortunately, we can't nail down an actual value unless we use a Z table or a calculator.
When I use a calculator, I'm getting 0.7745 (approximate) which rounds to 0.775 and converts to 77.5%
As for how to get this without a table or calculator, I'm not entirely sure what your teacher wanted you to do.
A knight wanted to visit a princess.
He had to arrive at exactly 17h00.
If he travelled at 15 km per hour, he would arrive one hour too early.
If he travelled at 10 km per hour, he would arrive one hour too late.
Questions : 1- At what time did he leave?
2- What distance did he travel?
3- At what speed did he travel?
Answer:
He had to arrive at 5:00pm
If he traveled at 15km per hour, he would arrive one hour too early
If he traveled at 10km per hour, he would arrive one hour too late.
At what time did he leave, what distance did he travel, and at what speed did he travel
:
Let d = distance traveled
:
Write an time equation; time = dist/speed
Travel time at 10 km/hr - travel time at 15 km/h = 2 hrs
d%2F10 - d%2F15 = 2
Multiply by 30
3d - 2d = 30(2)
d = 60 km is the distance
:
Find the travel time at 15 km/hr
60%2F15 = 4 hrs
:
let s = speed required to get there on time
:
required travel time - 15km/hr travel time = 1
60%2Fs - 4 = 1 hr
60 - 4s = 1s
60 = 1s + 4s
60 = 5s
s = 12 km/hr to arrive on time
:
Required travel time: 60%2F12 = 5 hrs
He would have to leave at noon
;
Summarize, depart at noon, travel for 5 hrs at 12 km/hr, a dist of 60 km
Step-by-step explanation:
the terminal side of 0 passes through the point (8,-7) what is the exact value of cos 0 in simplified form
Answer: [tex]\cos(\theta) = \frac{8\sqrt{113}}{113}\\\\[/tex]
=================================================
Work Shown:
x^2+y^2 = r^2
(8)^2+(-7)^2 = r^2
113 = r^2
r = sqrt(113)
The distance from (0,0) to (8,-7) is exactly sqrt(113) units.
This is the exact length of the hypotenuse of the right triangle.
Next, we do the following steps:
[tex]\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(\theta) = \frac{x}{r}\\\\\cos(\theta) = \frac{8}{\sqrt{113}}\\\\\cos(\theta) = \frac{8\sqrt{113}}{\sqrt{113}*\sqrt{113}}\\\\\cos(\theta) = \frac{8\sqrt{113}}{\sqrt{113*113}}\\\\\cos(\theta) = \frac{8\sqrt{113}}{\sqrt{113^2}}\\\\\cos(\theta) = \frac{8\sqrt{113}}{113}\\\\[/tex]
Side note: cosine is positive in quadrant Q4.
Find f(2) if f(x) = (x + 1).
Answer:
The awnser should be 3.
Step-by-step explanation:
if f(x) means the same thing as x + 1. Than that means f = 1. So if re write the question. 1 plus 2 equals 3.