Please help me with math problems!
20 points for all questions plz

Answer:

Step-by-step explanation:

20 milligrams

Answer:

c. 0.6

Step-by-step explanation:

A student cannot receive an A or a B simultaneously, so [tex]P(A \cap B) = 0[/tex].

Grade of A equals .30 and the probability of receiving a grade of B equals .30.

This means that [tex]P(A) = P(B) = 0.3[/tex]

The probability that a randomly selected student from this class will receive either an A or a B equals:

This is:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.3 - 0 = 0.6[/tex]

So the probability is 0.6, and the correct answer is given by option c.

Answer:

1.84metres

Step-by-step explanation:

convert 76cm to metres

76/100=0.76m

convert 8cm to metres

8/100=0.08m

therefore we have,

1+0.76+0.08=1.84metres

Answer:

x = 18

Step-by-step explanation:

8 x 18 - 3 = 141

Step-by-step explanation:

3p + 7q = 55

7p + 7q = 91

(-)

-4p=-36

p=9

q=4

Answer:

p = 9 and q = 4

Step-by-step explanation:

3p + 7q = 55 -- (1)

7p + 7q = 91 -- (2)

(2) - (1) : 4p = 36

               p = 9 -- (3)

Substituting (3) into (1),

27 + 7q = 55

7q = 28

q = 4 -- (4)

Therefore, p = 9 and q = 4

If this helps you, please mark brainliest!

Have a nice day!

Answer:

[tex]y=-8x+14[/tex]

Step-by-step explanation:

Hi there!

What we need to know:

1) Determine the midpoint of the line segment

Midpoint: [tex](\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex] where the coordinates of the endpoints are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the endpoints (-24, -54) and (40, -46)

[tex](\frac{-24+40}{2} ,\frac{-54+(-46)}{2} )\\(\frac{-24+40}{2} ,\frac{-54-46}{2} )\\(\frac{16}{2} ,\frac{-100}{2} )\\(8 ,-50)[/tex]

Therefore, the midpoint of line AB is (8,-50).

2) Determine the slope of the line segment

This will help us find the equation of the perpendicular bisector.

slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

Plug in the endpoints (-24, -54) and (40, -46)

[tex]= \frac{-46-(-54)}{40-(-24)}\\= \frac{-46+54}{40+24}\\= \frac{8}{64}\\= \frac{1}{8}[/tex]

Therefore, the slope of line AB is [tex]\frac{1}{8}[/tex].

3) Determine the slope of the perpendicular bisector

Because perpendicular lines always have slopes that are negative reciprocals, the slope of the perpendicular bisector is -8 (the negative reciprocal of 1/8). Plug this slope into [tex]y=mx+b[/tex]:

[tex]y=-8x+b[/tex]

4) Determine the y-intercept (b) of the perpendicular bisector

[tex]y=-8x+b[/tex]

Recall that we found the midpoint of line AB, (8,-50). The perpendicular bisector passes through this point. Plug (8,-50) into [tex]y=-8x+b[/tex] and solve for b:

[tex]-50=-8(8)+b\\-50=-64+b[/tex]

Add 64 to both sides to isolate b

[tex]-50+64=-64+b+64\\14=b[/tex]

Therefore, the y-intercept of the line is 14. Plug this back into [tex]y=-8x+b[/tex]:

[tex]y=-8x+14[/tex]

I hope this helps!

Answer:

a) 64 b) 12

Step-by-step explanation:

32 + 32 = 64

2*3 = 6

6*2 = 12

Answer:

a) 64 b) 12

Step-by-step explanation:

The answer for a is simple the answer is 64 just multipy 32 with 2 and the second one first you have to solve he answer iin the bracket then the answer you get from the bracket you will have to multiply with the number outside the bracket which is 2 and the answer you get will be 12.

Answer:

a. 74.86%

b. 50%

c. 50%

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.

This means that [tex]\mu = 49, \sigma = 6[/tex]

a. Find the percentage of dogs of this breed that weigh less than 53 pounds.

The proportion is the p-value of Z when X = 53. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{53 - 49}{6}[/tex]

[tex]Z = 0.67[/tex]

[tex]Z = 0.67[/tex] has a p-value of 0.7486.

0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.

b. Find the percentage of dogs of this breed that weigh less than 49 pounds.

p-value of Z when X = 49, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{49 - 49}{6}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a p-value of 0.5

0.5 = 50% of dogs of this breed that weigh less than 49 pounds.

c. Find the percentage of dogs of this breed that weigh more than 49 pounds.

1 subtracted by the p-value of Z when X = 49, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{49 - 49}{6}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a p-value of 0.5.

1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.

Answer:

-2,0 0,-8 , 2,0 hope that helps

Answer:

10

solution

100-98 =2

96-94 = 2

92-90 = 2

8-6 = 2

4-2 =2

2+2+2+2+2=10✓

Answer:

[tex]1. \: \: \: 2x = 5 \\ x = \frac{5}{2} \\ 2. \: \: \: \: \: \: y + 1.8 = 14.7 \\ y = 14.7 - 1.8 \\ y = 12.9 \\ 3. \: \: \: \: \: 6 = \frac{1}{2} z \\ z = 6 \times 2 \\ z = 12 \\ 4. \: \: \: \: \: 3\frac{1}{4} = \frac{1}{2} + w \\ w = \frac{1}{2} - 3 \frac{1}{4} \\ w = \frac{12 + 2}{4} \\ w = \frac{14}{4} = \frac{7}{2} \\ please \: mark \: brainliest[/tex]

Answer:

a

Step-by-step explanation:

blue red blue red like this

Answer:

the ans of this question is 30cm².

Answer:

The new price is 48

Step-by-step explanation:

First find the markup

50% of 32

.5 * 32 = 16

Add the markup to the original price

16+32 = 48

The new price is 48

Answer:

$48

Step-by-step explanation:

32 * 0.50 = 16

32 + 16 = 48

Hope this is helpful

Answer:

45

Step-by-step explanation:

If 7/8 are relatives, 1/8 are not relatives

360 / 8 = 45

Answer:

no

22.25 minutes

Step-by-step explanation:

First determine how long it will take her to read the entire book

20 pages          47 pages

--------------  = ----------------

35 minutes         x minutes

Using cross products

20x = 35*47

20x=1645

Divide by 20

20x/20 = 1645/20

x =82.25 minutes

This is more than 1 hour ( 1 hour = 60 minutes)

82.25 minutes - 60 minutes = 22.25 minutes

She will need 22.25 more minutes

A quadratic function's graph being wide or narrow is determined or depended on a-term:

[tex] \large{y = a {x}^{2} + bx + c}[/tex]

If |a| has a lot of value, for example a = 2 or a = 100. The graph will get narrower if increasing the value of |a|. On the other hand, If |a| has small value, for example a = 1/2 or a = 1/10000. The graph would be wide.

Also it does not matter if a-term is negative or not since a-term being positive or negative determines if a parabola is upward or downward. Only |a| determines how narrow/wide the graph is.

From the question, it is clear that the parabola y = 2x^2 is the narrowest graph since it has the highest |a| value out of all choices.

Answer

Answer:

80

Step-by-step explanation:

more in math means add

if you multiply three by 26 is 78 + 2 would be 80  

PSA im not great in math

The side YZ=9 cm of the right angle

We have given that,

Triangle X Y Z is shown. Angle X Y Z is a right angle and angles Y Z X and Z X Y are 45 degrees. The length of side Y X is 9 centimeters.

The length of segment XY is 9 cm.

We have to determine the statements regarding triangle XYZ are correct.

A right triangle or right-angled triangle, or more formally an orthogonal triangle, formerly called a rectangle triangle, is a triangle in which one angle is a right angle or two sides are perpendicular.

The right angle with angles 45-45-90 has two side same.

Therefore the side YZ=9 cm bc of the right angle

To learn more about the right-angle triangle visit:

https://brainly.com/question/64787

#SPJ5

Answer:

10145

Step-by-step explanation:

5 times 950 equals 4750

and 6.5 times 830 equals 5395

add first and second value

4750 + 5395 equals 10145

there is no arguing

Answer:

10145 km

Step-by-step explanation:

Time x speed = Distance

5 x 950 = 4750

6.5 x 830 = 5395

add together = 10145

Answer:

y = -3x + 7

Step-by-step explanation:

If the line is parallel, it will have the same slope. So, this line will have a slope of -3.

Plug in the slope and given point into y = mx + b, and solve for b:

y = mx + b

4 = -3(1) + b

4 = -3 + b

7 = b

Plug in the slope and y intercept into y = mx + b

y = mx + b

y = -3x + 7

So, the equation is y = -3x + 7

Answer:

(1, 7)

Step-by-step explanation:

The number is n.

7 more than 3 times his

number is at least 10 and at most 28.

Thus;

10 ≤ 3n + 7 ≤ 28

Let's solve individually;

10 ≤ 3n + 7

10 - 7 ≤ 3n

n ≥ 3/3

n ≥ 1

Also,

3n + 7 ≤ 28

3n ≤ 28 - 7

3n ≤ 21

n ≤ 21/3

n ≤ 7

Thus, since n cannot be more than 7 or less than 1, it means in interval Notation, the answer is;

(1, 7)

Answer:

12.94 units

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

✔️Distance between A(1, 1) and B(3, 5):

[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] A(1, 1) = (x_1, y_1) [/tex]

[tex] B(3, 5) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(3 - 1)^2 + (5 - 1)^2} [/tex]

[tex] AB = \sqrt{(2)^2 + (4)^2} [/tex]

[tex] AB = \sqrt{4 + 16} [/tex]

[tex] AB = \sqrt{20} [/tex]

AB = 4.47 units

✔️Distance between B(3, 5) and C(5, 1)

[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] B(3, 5) = (x_1, y_1) [/tex]

[tex] C(5, 1) = (x_2, y_2) [/tex]

[tex] BC = \sqrt{(5 - 3)^2 + (1 - 5)^2} [/tex]

[tex] BC = \sqrt{(2)^2 + (-4)^2} [/tex]

[tex] BC = \sqrt{4 + 16} [/tex]

[tex] BC = \sqrt{20} [/tex]

BC = 4.47 units

✔️Distance between A(1, 1) and C(5, 1):

AC = |1 - 5| = 4 units

✅Perimeter of ∆ABC = 4.47 + 4.47 + 4 = 12.94 units

Answer:

28 days

Step-by-step explanation:

4 x 7 x 30= 840 total working hours

5 x 6 x n = 840

= n = 840 ÷ 30

= n = 28 days

The task will take approximately 1 day to complete with 5 people working for 6 hours per day.

Total work done in the first scenario = 4 × 7 × 30

= 840 work hours

Total work done in the second scenario = (5 × 6 × D)

= 4 × 7 × 30

Solving for D:

30D = (4 × 7 × 30) / (5 × 6)

D = (4 × 7) / (5 × 6)

D = 28 / 30

D ≈ 0.9333

Rounding up to the nearest whole day, D = 1

Therefore, the task will take approximately 1 day to complete with 5 people working for 6 hours per day.

Learn more on time calculation here https://brainly.com/question/26046491

Answer:

49.13

Step-by-step explanation:

1/2×6×8=24 3.14×4²/2=23.15

24+23.15=49.13

3.) If y varies directly as x and y = 24 when x = 6, find the variation constant and the equation of variation.

A. Express the statement “y varies directly as x”, as y = kx .

B. Solve for k by substituting the given values in the equation.

[tex]\sf\rightarrow{y = kx}[/tex]

[tex]\sf\rightarrow{24 = 6k}[/tex]

[tex]\sf\rightarrow{K = \frac{24}{6} }[/tex]

[tex]\sf\rightarrow{K={\color{magenta}{4}}}[/tex]

C. Form the equation of the variation by substituting 4 in the statement y = kx. Thus , y = 4 x.

[tex]{\large{—————————————————————}}[/tex]

#CarryOnMath⸙

Solution :

Given parametric equation for :

[tex]$x=1+2 \sqrt t$[/tex]

[tex]$y=t^3-t$[/tex]

[tex]z=t^3+t[/tex]

The point is (3, 0, 2)

The vector equation is equal to :

[tex]$r(t) = \left<1+2 \sqrt t, t^3 -t, t^3+t \right>$[/tex]

Solving for r'(t) by differentiating each of the components of r(t) w.r.t. to t,

[tex]$r'(t)= \left< \frac{1}{\sqrt t}, \ 3t^2-1, \ 3t^2+1 \right>$[/tex]

The parameter value corresponding to (3, 0, 2) is t = 1. Putting in t=1 into r'(t) to solve for r'(t), we get

[tex]$r'(1) = \left< \frac{1}{\sqrt 1}, \ 3(1)^2-1, \ 3(1)^2+1 \right>$[/tex]

We know that parametric equation for  line through the point [tex]$(x_0, y_0, z_0)$[/tex]  and parallel to the direction vector <a, b, c > are

[tex]$x=x_0+at$[/tex]

[tex]$y=y_0+bt$[/tex]

[tex]z=z_0+ct[/tex]

Now substituting the  [tex]$(x_0, y_0, z_0)$[/tex]   = (3, 0, 2) and  <a, b, c > into x, y and z, respectively to solve for the parametric equation of the tangent line to the curve, we get:

[tex]$x=3+(1)t$[/tex]

x  = 3 + t

y = (0) + (2)t

y = 2t

z = (2) + (4)t

z = 2 + 4t