PLEASE HELP ME!!!!!!!

Answer:

25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

Answer: 25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

This [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

It is given that the  [tex]\rm P(Z\geq 1.7)[/tex]

It is required to find which statement is equivalent to [tex]\rm P(Z\geq 1.7)[/tex]

The statements are:

[tex]a) \ \rm P(Z\geq -1.7)\\b) \ \rm 1-P(Z\geq -1.7)\\c) \ \rm P(Z\leq 1.7)\\d) \ \rm 1-P(Z\leq 1.7)[/tex]

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

We have the [tex]\rm P(Z\geq 1.7)[/tex]

We know that:

[tex]\rm P(Z\leq a)=P(Z\geq -a)\\\rm P(Z\geq a)=P(Z\leq -a)[/tex]

If we compare statement (a) and statement (c), we will see these options are not equivalent to  [tex]\rm P(Z\geq 1.7)[/tex]

For statement (b) if we plot the graph for the given statement we will get the negative area of the bell curve hence it is also incorrect.

For statement (d) if we plot the graph for the given statement we will get the positive area which is equivalent to the [tex]\rm P(Z\geq 1.7)[/tex]

Thus, the [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

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#1

First the rectangle

Area

For semicircle

Area

Total area

#2

Area:-

Answer:

2/5 > 1/4

Step-by-step explanation:

First convert the denominators to the LCM which will be 20

2/5 will convert to 8/20 because 5 x 4 = 20 so 2 x 4 = 8 and 1/4 will convert to 5/20 because 4 x 5 = 20 so 1 x 5 = 5

Answer:

9.09

Step-by-step explanation:

[tex]\frac{0.81}{0.09} + \frac{0.81}{9}[/tex]

= 9 + [tex]\frac{0.81}{9}[/tex]

= 9+ 0.09

= 9.09

I hope this helped!! If so please rate and mark brainliest <3!!

Answer:

tan ¤ = opp/adj

tan ¤ = 20/50

since opposite of the angle is 20, height of the tree is 20 feet.

Ans : D

Answer:

Explanation:

[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

[tex]\hookrightarrow \sf tan(x)= \dfrac{20}{50}[/tex]

The cosine function for the ferris wheel ride is an illustration of a sinusoidial function

The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195

A cosine function is represented as:

y = Acos(Bt - C) + D

From the complete question, the diameter of the ferris wheel is 380 feet.

The amplitude represents the radius, and this is calculated as:

A = 380/2

A = 190

The function becomes:

y = 190cos(Bt - C) + D

The period of the function is:

T = 2π / B

From the complete question, one full rotation is completed in 4 minutes.

Convert the time to seconds

T = 4 * 60

T = 240.

So, we have:

240 = 2π / B

Divide both sides by 2

120 = π / B

Make B the subject

B = π / 120

The function becomes

y = 190cos(π / 120 t - C) + D

From the question, the ferris wheel is 195 feet above the ground.

This represents the vertical shift.

So, we have:

D = 195

The function becomes

y = 190cos(π / 120 t - C) + 195

Also, we have:

The lowest point is at t = 0 and the function is a negative cosine function

So, we have:

C = 0

The function becomes

y = -190cos(π / 120 t) + 195

Hence, the cosine function is y = -190cos(π / 120 t) + 195

Read more about cosine functions at:

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Answer:

The answer is 15

Step-by-step explanation:

Answer:

nsgs6

68÷9

02_3

73929

Step-by-step explanation:

8282×627=628373

Answer:

i hope this helps you!

Step-by-step explanation:

The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios

Triangle 1

The value of x is calculated using the following tangent ratio

tan(25) = 10/x

Make x the subject

x = 10/tan(25)

Evaluate

x = 21.4

Triangle 2

The value of x is calculated using the following tangent ratio

tan(x) = 8/5

Evaluate the quotient

tan(x) = 1.6

Take the arc tan of both sides

x = arctan(1.6)

Evaluate

x = 58

Triangle 3

The value of x is calculated using the following tangent ratio

tan(x) = 0.34/0.15

Evaluate the quotient

tan(x) = 2.27

Take the arc tan of both sides

x = arctan(2.27)

Evaluate

x = 66

The lengths of the diagonals are:

L1 = 2 in

L2 = 5 in

Represent the angles with x and y.

The measures of the angles are calculated using the following tangent ratios

tan(0.5x) = 2/5 and y = 90 - x

Evaluate the quotient

tan(0.5x) = 0.4

Take the arc tan of both sides

0.5x = arctan(0.4)

Evaluate

0.5x = 22

Divide by 0.5

x = 44

Recall that:

y = 90 - x

This gives

y = 90 - 44

Evaluate

y = 46

Hence, the angles in the rhombus are 44 and 46 degrees, respectively

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Answer:

A

Step-by-step explanation:

the rock lands when it reaches height 0.

so, for what t is h(t) = 0 ?

16t² - 100 = 0

16t² = 100

now we pull the square root on both sides (we can ignore the negative solutions, as negative seconds don't make any sense in our scenario)

4t = 10

t = 10/4 = 5/2 = 2.5 seconds

so, A is correct.

Answer:

y = x + 9

Step-by-step explanation:

Since each x input can be added by 9 to get the y outputs, the equation is y=x+9
Hope this helps :)

Answer:

v = 118.333333333

Step-by-step explanation:

formula: V=a^2h/3

The area is the base edge (so 5)

The height is the line going up the triangle (14.2)

Fill in:

v = 5^2(14.2/3)

Solve:

exponent first: 5^2 = 25

v = 25 (14.2/3)

divide/find out fraction: 14.2/3 = 4.73333333333

v = 23 x 4.73333333333

multiply: 23 x 4.73333333333 = 118.333333333

v = 118.333333333

you can also write as v = 118.3 with a line like “-“ over 3 to show the 3 is repeating:)

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}}\implies \cfrac{6}{3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{4})\implies y = 2x-8[/tex]

Answer:

[tex]x=\pm\frac{1}{2}[/tex]

Step-by-step explanation:

On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively

Answer:

483

Step-by-step explanation:

I really really pray and hope this helpss.

Answer:

X=3(7+23)

Step-by-step explanation:

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Answer:

The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.

Step-by-step explanation:

I Hope This Helps You!

-Justin:)

[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &7\\ t=\textit{elapsed time}\dotfill &127\\ h=\textit{half-life}\dotfill &64.8 \end{cases} \\\\\\ A=7\left( \frac{1}{2} \right)^{\frac{127}{64.8}}\implies A=7\left( \frac{1}{2} \right)^{\frac{635}{324}}\implies A\approx 1.80[/tex]

The half-life of sr-85, which may be used in bone scans, is 64.8 days. 1.80 milligrams of a 7 mg sample will be left after 127 days.

Half-life is defined as the time required for a quantity to reduce to half of its initial value.

The half-life of sr-85, which may be used in bone scans, is 64. 8 days.

We need to find how many milligrams of a 7 mg sample will be left after 127 days.

[tex]\rm A = P\frac{1}{2} ^{t/h}[/tex]

here A = current amount

P = inital amount

t = time

h = half life

So,

[tex]\rm A = 7\frac{1}{2} ^{127/64.8}[/tex]

[tex]\rm A = 7\frac{1}{2} ^{635/324}\\A = 1.80[/tex]

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#SPJ4

Using the midline property;

[tex]2wy = vz[/tex]

[tex]2(p - 21) = p - 7[/tex]

[tex]2p - 42 = p - 7[/tex]

[tex]2p - p = - 7 + 42[/tex]

[tex]p = 35[/tex]

Answer:

App. 83.33 kg

Step-by-step explanation:

10/60=0.167 kg/minute

0.167/3=0.056 kg/minute/person

0.056 x 25 x 60= 83.33...6

Answer:

Below

Step-by-step explanation:

According to a website, ebra

Solve for

N

by cross multiplying.

N

=

5

Tap to view steps...

Solve for s

Isolate the variable by dividing each side by factors that don't contain the variable.

s

=

8

r

−

5

t

Tap to view steps...

Solve for x

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

x

>

−

6

Interval Notation:

(

−

6

,

∞

)

Tap to view steps...

Solve by Substitution

Move all terms that don't contain

x

to the right side and solve.

x

=

9

2

−

y

2

Tap to view steps...

3/31/2022 4:07 PM

How can I help you?

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Find the Function

Find the function by taking the integral of the derivative.

G

(

x

)

=

5

2

x

2

−

x

+

C

Tap to view steps...

How was this solution?

Tap to rate...

Find the Function

I am unable to solve this problem.

Tap for examples...

Tired of typing? Download the app to take a picture of your problems!

Find the Function Rule

The chosen topic is not meant for use with this type of problem. Try the examples below.

x

q

(

x

)

1

1

2

2

3

3

4

4

x

q

(

x

)

1

3

2

6

3

11

4

18

x

q

(

x

)

1

2

9

162

2

8

8

128

3

18

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

Let y represent the amount of dirt on the floor after x passes.

The floor initially has 550 ml of dirt, hence a = 550.

During each pass, 24% of the dirt is removed. Hence b = 100% - 24% = 76% = 0.76

The equation is given by:

y = 550(0.76)ˣ

After 10 passes:

y = 550(0.76)¹⁰ = 35.36 ml

The function is given by y = 550(0.76)ˣ, after 10 passes, the number of dirts is about 35.36 ml

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Answer:

1

by looking only 1 is missing

Answer: 0.27

Population density of the species in water:

Population density of a species in the water is given by the expression,

       Density =Given in the question,

Number of goldfish in the tank = 12

Volume of the tank = 45 cubic feet

Substitute these values in the expression,

Density =

            = 0.267

            ≈ 0.27 goldfish per cubic feet

      Therefore, density of the tank will be 0.27 goldfish per cubic feet.

Answer:

4 ways

Step-by-step explanation:

Given

Possible combinations

The standard form of a circle shows the center and the radius

The equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

The standard equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2

Where:

Center= (a,b)

Radius = r

Assume that:

(a,b) = (-5,3)

r = [tex]\sqrt{[/tex]57

The equation of the circle would be:

(x + 5)^2 + (y - 4)^2 = ([tex]\sqrt{57[/tex])^2

Evaluate the exponent

(x + 5)^2 + (y - 4)^2 = 57

Hence, the equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

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