please help me out on this...




Only dogs
Only reptiles
Both cats and dogs
Both amphibians and reptiles

Answer:

is suppoesd to say after 20 yrs

Explanation:

Answer:

d = 513 m

Explanation:

Given that,

An echo returned in 3s.

We need to find the distance of the reflecting surface from the source, given that the speed of sound is 342 m/s.

The sound will cover 2d distance. The formula for the speed is given by :

v = d/t

So,

[tex]v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{342\times 3}{2}\\\\d=513\ m[/tex]

So, the required distance is 513 m.

Answer:

a car

A sled sliding across snow or ice.

a ball down a hill

mercury

Explanation:

Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

Answer:

walang kuwento

Explanation:

kasi ma answer ko

Answer: A pure substance is something that occurs in nature. An element is made up of one type of atom only and cannot be split further. A compound has the combined properties of the elements from which it is made. Atoms show the macro properties of an element.

Answer:Cricket !

The origins of cricket are very vague, and many theories have been put forward suggesting its origins, but it is, without doubt, very English. The first evidence of cricket being played was recorded in the year 1550, by the pupils of Royal Grammar School, Guildford.

Answer:

The velocity of the tuning fork sound is 317.4648 m/s

Explanation:

The given parameters are;

The frequency of the fork, f = 426.7 Hz

The length of the closed air column, L = 0.186 m

The diameter of the tube, d = 0.15 m

At the fundamental frequency in a closed tube, we have;

λ = 4·L

Where;

λ = The wavelength of the wave

L = The length of the tube

From the equation for the velocity of a wave, we have;

v = f·λ

Where;

v = The velocity of the (sound) wave

f = The frequency of the wave = 426.7 Hz

λ = 4·L = 4 × 0.186 m = 0.744 m

∴ v = 426.7 Hz × 0.744 m = 317.4648 m/s

Therefore, the velocity of the sound produced by the tuning fork, v = 317.4648 m/s

Answer:

B on EDGE

Explanation:

Answer:

A curve path downwards

Explanation:

When the ball is thrown, it curves downwards because the earth's core is pulling it out of the sky, and alse becasue the earth is round.

Answer:

H.  a curved path downwards

Explanation:

Answer:

2500 and kg its is very easy do with method

Answer:

208.33 W

Explanation:

Using,

P = W/t.......................... Equation 1

P = Average power output, W = total work, t = total time.

From the question,

Given: W = 6000000 J, t = 8 hours = (8×60×60) = 28800 s

Substitute these values into equation 1

P = 6000000/28800

P = 208.33 W.

Hence the average power output is 208.33 W

Answer:

7.7 m/s

Explanation:

Initial speed=2 m/s

mv=Ft

1*v=3*1.9

v=5.7 m/s

5.7+2=7.7

Answer:

The resultant velocity is 86.1 mi/h.    

Explanation:

The law of cosines is given by:

[tex] c^{2} = a^{2} + b^{2} - 2abcos(\theta) [/tex]

Where:

c: is the resultant velocity =?

a: is the velocity of the plane = 75.0 mi/h

b: is the velocity of the wind = 15.0 mi/h  

θ: is the angle between "a" and "b"                          

The angle between "a" and "b" can be found as follows:

[tex] \theta = 180.0 - 46.0 = 134.0 ^{\circ} [/tex]

Now, by using the law of cosines we have:

[tex] c^{2} = (75.0)^{2} + (15.0)^{2} - 2*75.0*15.0*cos(134.0) = 7413.0 [/tex]

[tex] c = 86.1 mi/h [/tex]    

Therefore, the resultant velocity is 86.1 mi/h.    

The law of sines is:

[tex] \frac{a}{sin(\gamma)} = \frac{b}{sin(\alpha)} = \frac{c}{sin(\theta)} [/tex]

Where:

γ: is the angle between "b" and "c"

α: is the angle between "a" and "c"

So, if we want to find "c" by using the law of sines, we need to know another angle besides θ (γ or α), and the statement does not give us.

I hope it helps you!        

Answer:

Neil Armstrong

Explanation:

Answer:

Neil Armstrong.

Explanation:

. PLEASE GIVE BRAINLIEST.

Yes it's true

compare a falling feather vs a falling rock

Answer:

It's true. Mass is directly proportional to force so more mass means more force applied which causes more damage.

Answer:

As atoms in the spoon vibrates about their equilibrium positions and transfer energy form one end to other end. This process is called conduction.

Answer:

Im pretty sure its 11 m/s east because it is 22 m/s hitting 11 m/s and the force is harder hitting

Explanation:

im not 100% sure becasue i did this stuff a while ago

Answer:

Finley, Xander and Max

Explanation:

v = Final velocity

t = Time

u = Initial velocity = 0

a = Acceleration

From kinematic equations we get

[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}=\dfrac{v-0}{t}\\\Rightarrow a=\dfrac{v}{t}[/tex]

Xander

v = 4.5 m/s, t = 3.5 s

[tex]a=\dfrac{4.5}{3.5}\\\Rightarrow a=1.29\ \text{m/s}^2[/tex]

Finley

v = 3.6 m/s, t = 4.2 s

[tex]a=\dfrac{3.6}{4.2}\\\Rightarrow a=0.86\ \text{m/s}^2[/tex]

Max

v = 7.3 m/s, t = 1.2 s

[tex]a=\dfrac{7.3}{1.2}\\\Rightarrow a=6.083\ \text{m/s}^2[/tex]

The required list is Finley, Xander and Max.

Answer:

Finley, Xander and Max

Explanation:

Answer:

1.42 seconds

Explanation:

T=2*pi*(sqrt length over gravity)

T=2*pi*(sqrt 0.5/9.8)

T=1.4189

Round to 3 significant digits

T=1.42 seconds

Answer:

The matter has mass and takes up space. The amount of space that matter takes up is called its : density

Answer:

Mass

Explanation:

Mass is the amount of matter occupied by an object.

Answer:

0.36 J

Explanation:

[tex]PE = \frac{1}{2} kx^{2} \\PE = \frac{1}{2} (200 N/m)(0.06 m)^{2} \\PE = 0.36 J[/tex]

Answer:

E = 2450 J

Explanation:

Given that,

Mass of Humpty Dumpty, m = 5 kg

He jumps from a 50 m high bridge.

Feeling nervous, he paces back and forth with a velocity of 2 m/s.

We need to find Humpty Dumpty's gravitational potential energy before jumping. The formula is given by :

[tex]E=mgh\\\\E=5\times 9.8\times 50\\\\E=2450\ J[/tex]

So, the required gravitaional potential energy is 2450 J.

Answer:

d

Explanation:

Answer:

The distance moved by the train is half the distance moved by the force

Explanation:

Given that the force applied to the smaller piston, F₂ = 4,000 N

The pressure in the area of the larger piston, A₁ = 2 × The pressure in the smaller piston, A₂

∴ A₁ = 2 × A₂

We have;

[tex]\dfrac{A_1}{A_2} = \dfrac{2\cdot A_2 }{A_2} =2 = \dfrac{F_1}{F_2}[/tex]

F₁ = 2·F₂ = 2 × 4,000 N = 8,000 N

F₁·d₁ = F₂·d₂

∴ 8,000 N ×d₁ = 4,000 N × d₂

d₁ = 1/2·d₂

∴ The distance moved by the train is half the distance moved by the force

When test charge is released, the charge will move towards the electron placed at point D.

The charge is the physical quantity that attracts or repels the other objects when comes into electric field.

The test charge is positive charge. The like charges repel each other and unlike charges attract each other.

So, when test charge is released, it gets attracted towards the opposite charge i.e. electron which is negatively charged.

Thus, the correct answer is D.

Learn more about charge.

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