The relative frequency distribution is:
Income ($) | Frequency Relative | Frequency200-300 | 51 | 18.82%301-400 | 58 | 21.40%401-500 | 74 | 27.30%501-600 | 69 | 25.46%More than 600 | 19 | 7.01%The correct option is A.
What is a relative frequency?A relative frequency is the proportion of the total number of outcomes to the number of times a certain value of the data happens in the set of all outcomes.
Relative frequency = frequency of given data/total frequency * 100%The relative frequency distribution of the given data is constructed below:
Total number of students = 51 + 58 + 74 + 69 + 19
Total number of students = 271
The relative frequency of each class interval will be:
200-300; 51/271 * 100% = 18.82%
301-400; 58/271 * 100% = 21.40%
401-500; 74/271 * 100% = 27.30%
501-600; 69/271 * 100% = 25.46%
More than 600; 19/271 * 100% = 7.02%
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Prove that
(secx+tanx)² =CSCx+1/CSC x-1
To prove that (secx+tanx)² = (cscx+1)/(cscx-1), we will start with the left-hand side (LHS) of the equation and simplify it step by step until it matches the right-hand side (RHS) of the equation.
LHS: (secx+tanx)²
Using the trigonometric identities secx = 1/cosx and tanx = sinx/cosx, we can rewrite the LHS as:
LHS: (1/cosx + sinx/cosx)²
Now, let's find a common denominator and simplify:
LHS: [(1+sinx)/cosx]²
Expanding the squared term, we get:
LHS: (1+sinx)² / cos²x
Next, we will simplify the denominator:
LHS: (1+sinx)² / (1 - sin²x)
Using the Pythagorean identity sin²x + cos²x = 1, we can replace 1 - sin²x with cos²x:
LHS: (1+sinx)² / cos²x
Now, let's simplify the numerator by expanding it:
LHS: (1+2sinx+sin²x) / cos²x
Next, we will simplify the denominator by using the reciprocal identity cos²x = 1/sin²x:
LHS: (1+2sinx+sin²x) / (1/sin²x)
Now, let's simplify further by multiplying the numerator and denominator by sin²x:
LHS: sin²x(1+2sinx+sin²x) / 1
Expanding the numerator, we get:
LHS: (sin²x + 2sin³x + sin⁴x) / 1
Now, let's simplify the numerator by factoring out sin²x:
LHS: sin²x(1 + 2sinx + sin²x) / 1
Using the fact that sin²x = 1 - cos²x, we can rewrite the numerator:
LHS: sin²x(1 + 2sinx + (1-cos²x)) / 1
Simplifying further, we get:
LHS: sin²x(2sinx + 2 - cos²x) / 1
Using the fact that cos²x = 1 - sin²x, we can rewrite the numerator again:
LHS: sin²x(2sinx + 2 - (1-sin²x)) / 1
Simplifying the numerator, we have:
LHS: sin²x(2sinx + 1 + sin²x) / 1
Now, let's simplify the numerator by expanding it:
LHS: (2sin³x + sin²x + sin²x) / 1
LHS: 2sin³x + 2sin²x / 1
Finally, combining like terms, we get:
LHS: 2sin²x(sin x + 1) / 1
Now, let's simplify the RHS of the equation and see if it matches the LHS:
RHS: (cscx+1) / (cscx-1)
Using the reciprocal identity cscx = 1/sinx, we can rewrite the RHS:
RHS: (1/sinx + 1) / (1/sinx - 1)
Multiplying the numerator and denominator by sinx to simplify, we get:
RHS: (1 + sinx) / (1 - sinx)
Now, we can see that the LHS and RHS are equal:
LHS: 2sin²x(sin x + 1) / 1
RHS: (1 + sinx) / (1 - sinx)
Therefore, we have proven that (secx+tanx)² = (cscx+1)/(cscx-1).
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Determine the equation of the circle graphed below.
-12-11-10-9-8-7 -5-4-3-2
11098765432-
hadis
-2
-9
-10
-11
123456
8 9 10 11 12
(8,-2)
Answer:
(x - 3)² + (y + 4)² = 29
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k ) are the coordinates of the centre and r is the radius
we have the coordinates of the centre but require to find the radius r
the radius is the distance from the centre to a point on the circle.
using the distance formula to find r
r = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (3, - 4 ) centre and (x₂, y₂ ) = (8, - 2) point on circle
r = [tex]\sqrt{(8-3)^2+(-2-(-4))^2}[/tex]
= [tex]\sqrt{5^2+(-2+4)^2}[/tex]
= [tex]\sqrt{25+2^2}[/tex]
= [tex]\sqrt{25+4}[/tex]
= [tex]\sqrt{29}[/tex]
then equation with centre (3, - 4 ) and r = [tex]\sqrt{29}[/tex] , is
(x - 3)² + (y - (- 4) )² = ([tex]\sqrt{29}[/tex] )² , that is
(x - 3)² + (y + 4)² = 29
Select the correct answer from each drop-down menu.
(0.1² +20+15, z < 10
0.25³ +k, z 210
f(x)==
a) =
If the left-hand limit of f(z) is equal to the right-hand limit of f (x) as x approaches 10, the limit of f (x) as x approaches 10 is
the value of k is
and
The limit of f(x) as x approaches 10 is -25, and the value of k is -25.
For the left-hand limit,
lim(x->10-) f(x)
= lim(x->10-) (0.1x² + 20x + 15)
For the right-hand limit,
lim(x->10+) f(x)
= lim(x->10+) (0.25x³ + k)
Since we want the left-hand limit to be equal to the right-hand limit
lim(x->10-) f(x) = lim(x->10+) f(x)
lim(x->10-) (0.1x² + 20x + 15)= lim(x->10+) (0.25x³ + k)
0.1(10)² + 20(10) + 15= 0.25(10)³ + k
10 + 200 + 15 = 0.25(1000) + k
225 = 250 + k
k = 225 - 250
k = -25
Therefore, the limit of f(x) as x approaches 10 is -25, and the value of k is -25.
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PLEASE HELP!!!!!!
it’s a division equation
Answer:
x+1
DOMAIN: x [tex]\neq[/tex] -5
Step-by-step explanation:
We can factor [tex]x^{2}[/tex]+6x+5 as (x+1)(x+5) since this expands to [tex]x^{2}[/tex]+5*x+1*x+5*1, which is [tex]x^{2}[/tex]+6x+5.
Now, we have:
[tex]\frac{(x+1)(x+5)}{(x+5)}[/tex]
We can cancel out x+5, because this expression is the same as (x+1)*[tex]\frac{x+5}{x+5}[/tex], which is (x+1).
HOWEVER, the denominator cannot be equal to zero because that will make the expression undefined (you can't divide by zero). So, since x+5[tex]\neq[/tex]0, x[tex]\neq[/tex]-5.
The bottom part says how many student tickets where brought? Can anyone pls help me PLSS
255 number of adults and 355 number of students bought ticket.
Here, we have,
Let the number of adults bought tickets are x and the number of students that bought tickets is (x + 100).
Since it is given that 100 more students brought tickets than adults.
Now, each adult ticket costs $5 and each student's ticket costs $3.5 and the total collected value of tickets is $2517.5.
So, 5x + 3.5(x + 100) = 2517.5
⇒ 8.5x + 350 = 2517.5
⇒ 8.5x = 2167.5
⇒ x = 255
So, 255 number of adults and (255 + 100) = 355 number of students bought ticket. (Answer)
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Solve the simultaneous equations using elimination method= x+2y-3z=0 3x+3y-z = 5 x-2y = 2z=1
Answer:
[1;1;1]
Step-by-step explanation:
try this option; all the details are in the attachment.
100 Points! Geometry question. Photo attached. Determine whether the pair of triangles is similar. If so, write a similarity statement. If not, what would be sufficient to prove the triangles similar? Explain your reasoning. Please show as much work as possible. Thank you!
The pair of triangles shown can be seen to be similar by SAS.
What is similarity of triangles by SAS?
When comparing two triangles, one way to tell if they are similar is to apply the SAS (Side-Angle-Side) similarity criterion. This criterion states that two triangles are comparable if they have two pairs of corresponding sides in proportion and congruent included angles between those sides.
Triangles must have an equal ratio of their matching sides' lengths. The respective sides' included angles must be equivalent.
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What is the greatest common factor of 6, 34, and 2?
Answer: 2
Step-by-step explanation:
List the factors(numbers that multiply to make that number for each number
6: 1, 2, 3, 6
34: 1, 2, 16, 34
2: 1, 2
Whichever is the factor that is the greatest that they all have in common is your greatest common factor.
2
BTS-2 has coordinates (-8,6) and the edge connecting vertices P and Q has the equation y = 4.
(b) Write down the coordinates of BTS-4.
a. Jason will receive the strongest signal from BTS-4 because he is located in the Voronoi cell of BTS-4.
b. The coordinates of BTS-4 are (−8,4).
How to explain the informationa. Jason will receive the strongest signal from BTS-4 because he is located in the Voronoi cell of BTS-4. A Voronoi cell is a region of space that is closer to a given point than any other point. In this case, the given point is BTS-4. The Voronoi diagram is a partitioning of the plane into Voronoi cells, one for each point.
b. The edge connecting vertices P and Q has the equation y=4, which means that it is a horizontal line that intersects the y-axis at 4. The coordinates of BTS-2 are (−8,6), which means that it is located 8 units to the left of the origin and 6 units above the origin. Therefore, BTS-4 must be located 8 units to the left of the origin and 4 units above the origin, which gives it the coordinates (−8,4).
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start time:9:55
End time:?
Elapsed time:27 minutes
Answer: 10:22
Step-by-step explanation:
9:55 + :05 = 10:00
10:00+ :22 = 10:22
100 Points! Algebra question. Photo attached. Please show as much work as possible. Thank you!
The equation is verified, and we have shown that E_0 = cos⁴θ is equivalent to E_0 = E_0 (1/2 + cos2θ/2)².
We have,
To verify the equation
E_θ = E_0 cos^4θ = E_0 (1/2 + cos2θ/2)², we can expand the right-hand side and simplify it.
Starting with the right-hand side of the equation:
E_0 (1/2 + cos2θ/2)²
Expanding the square using the binomial expansion:
E_0 [(1/2)² + 2(1/2)(cos2θ/2) + (cos2θ/2)²]
Simplifying:
E_0 [1/4 + cos2θ + (cos2θ)²/4]
Combining the terms:
E_0 [1/4 + 4cos²θ/4 + (cos²θ)²/4]
Simplifying further:
E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4]
Combining the terms again:
E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4] = E_0 [1/4 + 4cos²θ/4 + cos⁴θ/4]
Simplifying the expression yields:
E_0 cos⁴θ = E_0 cos⁴θ
Therefore,
The equation is verified, and we have shown that E_0 = cos⁴θ is equivalent to E_0 = E_0 (1/2 + cos2θ/2)².
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Elon sent a chain letter to his friends, asking them to forward the letter to more friends.
The relationship between the elapsed time,
�
tt, in days, since Elon sent the email, and the total number of people who receive the email,
�
(
�
)
P(t)P, left parenthesis, t, right parenthesis, is modeled by the following function:
P(t)=4⋅3t
Complete the following sentence about the daily rate of change in the number of people who receive the email.
Every day, the number of people who receive the email
by a factor of
.
Every day, the number of people who receive the email grows by a factor of 3.
What is an exponential function?In Mathematics and Geometry, an exponential function can be modeled by using this mathematical equation:
[tex]f(x) = a(b)^x[/tex]
Where:
a represents the initial value or y-intercept.x represents x-variable.b represents the rate of change, common ratio, decay rate, or growth rate.Based on the information provided above, an exponential function for the total number of people who received the email is given by;
[tex]P(t) = 4(3)^t[/tex]
By comparison, we have the following parameters;
Initial value, a = 4.
Growth rate, b = 3.
In conclusion, the number of people who receive the email from Elon every day grow by a factor of 3.
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Question one
Let F be a Boolean function defined by the following Boolean expression:
F = (¬A ∧ ¬B ∧ ¬C ∧ D) ∨ (¬A ∧ B ∧ C ∧ D) ∨ (A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ ¬B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ ¬D)
Where A, B, C, and D are Boolean variables.
a) Construct a truth table for F.
b) Find the minimal sum-of-products form of F using Quine-McCluskey method.
c) Using Boolean algebra, simplify the Boolean expression of F and state the simplified Boolean expression in terms of the three variables A, B, and C.
Answer:
a) The truth table for F is as follows:
A B C D F
0 0 0 0 1
0 0 0 1 0
0 0 1 0 0
0 0 1 1 1
0 1 0 0 0
0 1 0 1 1
0 1 1 0 1
0 1 1 1 0
1 0 0 0 0
1 0 0 1 1
1 0 1 0 1
1 0 1 1 0
1 1 0 0 1
1 1 0 1 0
1 1 1 0 0
1 1 1 1 1
b) Using the Quine-McCluskey method, we can find the minimal sum-of-products form of F:
F = ¬A ∧ ¬B ∧ D ∨ ¬A ∧ C ∧ D ∨ A ∧ B ∧ ¬C ∧ D ∨ A ∧ ¬B ∧ C ∧ D
c) Using Boolean algebra, we can simplify the Boolean expression of F as follows:
F = (¬A ∧ ¬B ∧ D) ∨ (¬A ∧ C ∧ D) ∨ (A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ ¬B ∧ C ∧ D)
= (¬A ∧ (¬B ∧ D ∨ C ∧ D)) ∨ (A ∧ (B ∧ ¬C ∧ D ∨ ¬B ∧ C ∧ D))
= (¬A ∧ (¬B ∨ C) ∧ D) ∨ (A ∧ ((B ∧ ¬C) ∨ (¬B ∧ C)) ∧ D)
= (¬A ∧ ¬B ∧ C ∧ D) ∨ (¬A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ D)
Therefore, the simplified Boolean expression of F in terms of the three variables A, B, and C is:
F = (¬A ∧ ¬B ∧ C ∧ D) ∨ (¬A ∧ B ∧ ¬C ∧ D) ∨ (A ∧ B ∧ C ∧ D) ∨ (A ∧ ¬B ∧ ¬C ∧ D)
Step-by-step explanation:
Need an answer quick!!
What is the volume of the shape on the next page?
Answer:
6 in³
Step-by-step explanation:
volume = width X length X height
= 3 X 1 X 2
= 6 in³
An art class has 63 minutes of painting for every 54 minutes of instruction. What is the basic ratio of minutes of painting to minutes of instruction
The basic ratio of minutes of painting to minutes of instruction is 7 : 6
What is the basic ratio of minutes of painting to minutes of instructionFrom the question, we have the following parameters that can be used in our computation:
Painting = 63 minutes
Instruction = 54 minutes
The ratio can be represented as
Ratio = Painting : Instruction
When the given values are substituted in the above equation, we have the following equation
Painting : Instruction = 63 : 54
Simplify
Painting : Instruction = 21 : 18
Simplify
Painting : Instruction = 7 : 6
This ratio cannot be simplified
Hence, the solution is 7 : 6
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Can someone please solve this for me
Answer:
1.3136363636363637
Step-by-step explanation:
Bc u times 17 times 17 devide by 220
Find the area of the given circle. Round your
answer to two decimal places. (Use pi = 3.14)
In this figure, we have been given a circle. The area of the circle is 314 sq ft.
The number of square units required to fill a circle is known as its area. The region occupied inside the boundaries of a round item or 2d figure is defined as the area in general. The measurement is done in square units, with square metres (m2) being the usual unit.
There are predefined formulas for calculating area for squares, rectangles, circles, triangles, and so on.
Area of a circle = πr²
We have been given r as 10 ft
and the value of π as 3.14, so we will just put it in the formula
Area of circle = 3.14 × 10²
= 3.14 × 100
314 sq ft.
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prove that
(z^a/z^b)^c * (z^b/z^c)^a * (z^c/z^a)^b =1
Step-by-step explanation:
remember, when we multiply the same base, we add the exponents, when we divide the same base we subtract the exponents.
when we have exponent of exponent, we multiply the exponents.
so,
the expression is
(z^ac / z^bc) × (z^ab / z^ac) × (z^bc / z^ab) = 1
we have in there the commutative and associative properties of multiplication : the sequence of operands do not matter at all.
and therefore we have in there the terms :
z^ac / z^ac
z^bc / z^bc
z^ab / z^ab
all three are 1
and so the main expression is
1 × 1 × 1 = 1
which is true, of course, and therefore the original equation is true.
(HELP ME BRAINLIEST OF THE BRAINLESTS!!!!!!)
A 1. Some square tiles measure 3 1/2 inches on each side. Seven Tiles are placed in a row. How long is the row of tiles?
The row would be _____ inches long
B 2. Suppose that 10 tiles like those problem 1 were placed in a row. How long would that row of tiles be
It would be ______ inches long
The row of tiles would be 24 1/2 inches long.
B:The row of 10 tiles would be 35 inches long.
What is the length of the row?A 1. To be able to know the length of the row of tiles, one need to multiply the length of one tile by the number of tiles in the said row.
So, all tile measures 3 1/2 inches on each side, Hence the length of one tile is 3 1/2 inches.
Based on the fact that there are 7 tiles in a row, we have to multiply the length of one tile by 7:
Length of the row = 3 1/2 inches/tile x 7 tiles
= 24 1/2 inches
So, the row of tiles is 24 1/2 inches long.
B 2. Also, to find the length of a row of 10 tiles, we need to multiply the length of one tile by 10.
Note that:
Length of one tile = 3 1/2 inches
Number of tiles in the row = 10
Hence:
Length of the row = 3 1/2 inches/tile x 10 tiles
= 35 inches
So, the row of 10 tiles is 35 inches long.
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Find x pls hurry lots of points
The area of the triangle in the shaded region is derived to be 29.75 square inches.
How to solve for the area of the triangleFor any triangle, the area is calculated as half the base multiplied by the height of the triangle, that is;
Area of triangle = 1/2 × base × height
For the triangle in the shaded region;
base = 8.5 inches
height = 7 inches
area of the triangle = 1/2 × 8.5 in × 8.5 in
area of the triangle = (59.5/2) in²
area of the triangle = 29.75 in²
Therefore, the area of the triangle in the shaded region is derived to be 29.75 square inches.
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Find the current balance for Jeff’s savings account if he had a balance of $396.80, made three $15 deposits, withdrew $125, and earned $1.04 interest.
The current balance for Jeff's savings account is $317.84.
To find the current balance for Jeff's savings account, we need to calculate the net effect of the deposits, withdrawals, and interest on his initial balance.
Initial balance: $396.80
Deposits: 3 × $15 = $45
Withdrawals: $125
Interest: $1.04
Adding the deposits and interest to the initial balance:
$396.80 + $45 + $1.04 = $442.84
Then, subtracting the withdrawal:
$442.84 - $125 = $317.84
Therefore, the current balance for Jeff's savings account is $317.84.
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pleaseeeeee helppppppp
The statements that complete the function transformations are left, up, stretch and stretch
Completing the function transformationsFrom the question, we have the following parameters that can be used in our computation:
f(x) = (x + 94)²
Also, we have
f(x) = x²
This implies that f(x) = (x + 94)² is obtained by shifting f(x) = x² left by 94 units
Next, we have
f(x) = x² + 94
This implies that f(x) = x² + 94² is obtained by shifting f(x) = x² up by 94 units
Next, we have
f(x) = 94√x from f(x) = √x
This implies that f(x) = 94√x can be obtained from vertically stretching f(x) = √x by a factor of 94
Also, the graph of f(x) = √94x can be obtained from horizontally stretching f(x) = √x by a factor of 1/94
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A boat travels with velocity vector (25, 25√3). What is the directional bearing of the boat?
ON 30° E
OE 30° S
OE 30° N
ON 30° W
In a case whereby a boat travels with velocity vector (25, 25√3) the directional bearing of the boat is ON 30° E.
How can the directional bearing of the boat be determined?The given velocity vector are; 25 and 25√3)
horizontal components =25
vertical components =25√3
Then the angle
Tan(θ) = {vertical component / horizontal component }
= 25√3 / 25
= √3 / 1
= √3
Tangent √3= 60 degrees, Then the directional bearing of angle 60 degrees is 30° E
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Identify the center and radius of a circle with equation (x-5)^2+(y+3)^2=25
The center and radius of the circle is (5, -3), and 5 respectively.
What is the center and radius of the circle?The standard form equation of a circle with center (h, k) and radius r is:
(x - h)² + (y - k)² = r²
Given the equation of the circle in the question:
( x - 5 )² + ( y + 3 )² = 25
To identify the center and the radius.
Comparing this equation ( x - 5 )² + ( y + 3 )² = 25 to the standard form of a circle equation, which is (x - h)² + (y - k)² = r², we can easily identify the center and radius of the circle.
( x - 5 )² + ( y + 3 )²
(x - h)² + (y - k)² = r²
The center of the circle is given by the values (h, k), which correspond to the opposite signs of the terms inside the parentheses.
In this case, the center of the circle is (5, -3), as we have (x - 5)² and (y + 3)².
The radius of the circle is the square root of the value on the right side of the equation.
In this case, the radius is √25, which simplifies to 5.
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Simplify. witch answer would it be A, B, C, OR D
Answer:
the answer is C
Step-by-step explanation:
any negative power is the reciprocal
so m^(-2) = 1/m^2
and so on
1/n^(-3) = n^(3)
The dot plots show the ages of people at two different movies at a school movie night. Which data set seems to have a greater variability? (find the MAD scores)
Answer:
Step-by-step explanation:
A lady paid 20% deposit $1100 the cost of a bicycle. How much does she have to pay to complete the price
Please help me with solving for x
Step-by-step explanation:
For some side x, we are given two angles so let use law of sines
We don't know the angle opposite of the x side so we using the triangle interior property
[tex]120 + 51 + x = 180[/tex]
[tex]x = 9[/tex]
So the missing angle is 9.
The law of sines formula is that
[tex] \frac{a}{ \sin( \alpha ) } = \frac{b}{ \sin( \beta ) } [/tex]
where a and b are side lengths.
And alpha, and Beta are angles that are OPPOSITE of the side lengths, a and b, respectively
Let a be 25,
therefore alpha is 120
Let b be x,
therefore beta is 9.
[tex] \frac{25}{ \sin(120) } = \frac{x}{ \sin(9) } [/tex]
Solving for x.
[tex]25 \times \frac{ \sin(9) }{ \sin(120) } = x[/tex]
[tex]x = 4.51587[/tex]
Round if needed so our answer is
[tex]x = 4.5[/tex]
will mark brainleist pls help me
we know that,
★ The sum of the angles in a triangle is always 180° ...
➺ 100° + 46° + x = 180°➺ 146° + x = 180°➺ x = 180°- 146° ➺ x = 34°__________________________________
Thus, the Value of x is 34°.
Answer:
34°Step-by-step explanation:
We know that,
Sum of three side of triangle is 180°
so,
100° + 46° + x = 180°
146° + x = 180°
x = 180° - 146°
x = 34°
[tex]\underline{\rule{190pt}{4pt}}[/tex]
50 Points! Multiple choice algebra question. Thank you!
The expression that is equivalent to the trigonometry ratio (sin²θ + cos²θ)/tan²θ is (a) cot²θ
How to determine the expression that is equivalent to the trigonometry ratioFrom the question, we have the following parameters that can be used in our computation:
The trigonometry ratio given as
(sin²θ + cos²θ)/tan²θ
In trigonometry,
sin²θ + cos²θ = 1
So, we have the following representation
(sin²θ + cos²θ)/tan²θ = 1/tan²θ
Evaluate the quotient
(sin²θ + cos²θ)/tan²θ = cot²θ
Hence, the expression that is equivalent to the trigonometry ratio is (a) cot²θ
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