Please help I’m really lost!

Answer:

Step-by-step explanation: -3

Answer:

5x = x^2 - 6

Step-by-step explanation:

a number can be represented by x,

5 times a number can be represented as the product of 5 and x, 6 less than the square of that number tells us that this is equal to a number squared minus 6. is tells us that these two expressions are equal.

If you want a working number, just solve by completing the square once this is in standard form. This is then converted to vertex form.

x^2-5x-6 = (x-5/2)^2-49/4 = (x^2-5x+25/4) -49/4 = x^2-5x-6.

(x-5/2)^2-49/4=0

(x-5/2)^2=49/4

(x-5/2) = ±√49/4

(x-5/2) = ±7/2

x=5/2±7/2

x=(5±7)/2

x=12/2,-2/2

x=6,-1

Thus, the number can either be 6 or -1.

Answer:a

Step-by-step explanation:

Answer:

5000

Step-by-step explanation:

Let's start by evaluating what we are given. 50 times the sum of 64 and 36. Ok, so 50 times which is the way to write x (multiply) and the sum of 64 and 36 is another way to write 64 + 36.

Lets put this together now!

50 x ( 64 + 36 ) = 50 x ( 100 )

                         = 5000

Answer:

1/12

Step-by-step explanation:

3/4-2/3 = 9/12-8/12 = 1/12

Take a picture of the assignment and post it in your question.

Answer:

a

Step-by-step explanation:

did it on edge 2020

Answer:

deserts are 32.5%

appetizers are 42.5%

deserts are 25%

Step-by-step explanation:

let me know if i helped

Answer:

Any line with slope -1/(-1/3)=3.

Step-by-step explanation:

If a line l has slope m, any line perpendicular to l will have slope equal to -1/m.

Answer: line EF

Step-by-step explanation:

Did it in edg

Given parameters:

Equation of the line is y = -[tex]\frac{1}{2} x[/tex] + 8

Unknown:

Slope of line parallel to this line = ?

Slope of line perpendicular = ?

Solution:

A line parallel to this line will have the same slope with it.

A line perpendicular will have the negative inverse of this slope;

Slope of line  = - [tex]\frac{1}{2}[/tex]

Slope of line parallel to this line = [tex]-\frac{1}{2}[/tex]

Slope of line perpendicular = negative inverse = -( -([tex]\frac{1}{\frac{1}{2} }[/tex]))   = 2

So, the slope of line parallel to this line is - 1/2 and that perpendicular is 2

Answer:

5a+2b

Step-by-step explanation:

4a + 5b – 3b + a

Combine like terms

4a +a  + 5b-3b

5a+2b

Answer:

66%

Step-by-step explanation:

Use conditional probability.

P(full | holiday) = P(full AND holiday) / P(holiday)

P(full | holiday) = 0.19 / 0.29

P(full | holiday) ≈ 0.66

Answer:

I'm sure the answer is 15%

Step-by-step explanation:

Answer: y= 730+25x

Step-by-step explanation:

Given: Total pages she already read = 730

Pages read by her in 1 week = 25

Let x = number of days that she has followed her plan, and let y = the total number of pages read.

Then total pages she will read in x days = 25x

therefore , Total pages she read till now(y) =730 + 25x

Hence, the linear equations can Juliet use to model her plan and calculate the total number of pages read:

y= 730+25x

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Time taken to receive order = 2 minutes

Ingredient mixing and cake loading = 8 minutes

Baking time = 30 minutes

Number of cakes oven can hold at a time = 3

Cooling time = 1 hour = 60 minutes

Cake packing = 2 minutes

Billing customer = 3 minutes

a. What is the capacity of the process, and what is the bottleneck?

The capacity of the process:

Within an hour : two bakings can be done =(30 minutes * 2) = 60 minutes

Also oven can hold 3 cakes, so, 3 cakes can be baked at a time.

Hence, 3 cakes in 30 minutes ;

6 cakes in an hour;

Hence, capacity of the process is 6cakes per hour.

The bottleneck is the oven, because if the number of ovens were to be increased, the process capacity will increase, similarly, if one of the oven gets faulty, then the process capacity reduces further.

b. What is the throughput time for a typical cake?

The throughput time, is the summation of all the time taken to fully complete an order :

Receipt of order + mixing + baking + cooling + packing + billing

2 + 8 + 30 + 60 + 2 + 3 = 105 minutes

c. If on average five orders are taken per hour, how many cakes are there in the process (on average)?

(Throughput time / 60) * average number of order

(105/60) * 5

= 1.75 * 5

= 8.75

9514 1404 393

Answer:

  20 mm/min

Step-by-step explanation:

To find the rate in mm per minute, divide mm by minutes:

  (600 mm)/(30 min) = 20 mm/min . . . unit rate

[tex]\frac{35}{2} \: or \: 17 \frac{1}{2} [/tex]

Step-by-step explanation:

[tex]7 \times 2 \frac{1}{2} [/tex]

Convert mixed number to fraction

[tex]2 \frac{1}{2} = \frac{5}{2} \\ \\ 7 \times \frac{5}{2} [/tex]

Simplify

[tex] \frac{7}{1} \times \frac{5}{2} = \frac{35}{2} [/tex]

Convert to mixed number

[tex]17 \frac{1}{2} [/tex]

Answer:

53%

Step-by-step explanation:

Total voters = 5,800

5,800= 100%

3,074=X

X=3,074*100/5,800= 53%

Answer:

391.437

Step-by-step explanation:

Answer:

391.437

Step-by-step explanation:

6.1x3=18.3

18.3x6.9=126.27

126.27x3.1=391.437

Answer:

Where are the statements

Answer:

The answer is A

Step-by-step explanation:

Got this from edge

Answer:

(a) and (b) are not true in general. Refer to the explanations below for counterexamples.

It can be shown that (c) is indeed true.

Step-by-step explanation:

This explanation will use a lot of empty sets [tex]\phi[/tex] just to keep the counterexamples simple.

Note that [tex]A \cap B[/tex] can well be smaller than [tex]A[/tex]. It should be alarming that the question is claiming [tex]A\![/tex] to be a subset of something that can be smaller than [tex]\! A[/tex]. Here's a counterexample that dramatize this observation:

Consider:

The intersection of an empty set with another set should still be an empty set:

[tex]A \cap B = \left\lbrace 1\right\rbrace \cap \left\lbrace\right\rbrace = \left\lbrace\right\rbrace[/tex].

The union of two empty sets should also be an empty set:

[tex]((A \cap B) \cup C) = \left\lbrace\right\rbrace \cup \left\lbrace\right\rbrace = \left\lbrace\right\rbrace[/tex].

Apparently, the one-element set [tex]A = \left\lbrace 1 \right\rbrace[/tex] isn't a subset of an empty set. [tex]A \not \subseteq ((A\cap B) \cup C)[/tex]. Contradiction.

Consider the same counterexample

Left-hand side:

[tex](A \cup B) \cap C = \left(\left\lbrace 1 \right\rbrace \cup \left\lbrace \right\rbrace\right) \cap \left\lbrace 2 \right\rbrace\right = \left\lbrace 1 \right\rbrace \cap \left\lbrace 2 \right\rbrace = \left\lbrace \right\rbrace[/tex].

Right-hand side:

[tex](A \cap B) \cup C = \left(\left\lbrace 1 \right\rbrace \cap \left\lbrace \right\rbrace\right) \cup \left\lbrace 2 \right\rbrace\right = \left\lbrace \right\rbrace \cup \left\lbrace 2 \right\rbrace = \left\lbrace 2 \right\rbrace[/tex].

Apparently, the empty set on the left-hand side [tex]\left\lbrace \right\rbrace[/tex] is not the same as the [tex]\left\lbrace 2 \right\rbrace[/tex] on the right-hand side. Contradiction.

Part one: show that left-hand side is a subset of the right-hand side.

Let [tex]x[/tex] be a member of the set on the left-hand side.

[tex]x \in (A \backslash B) \cap C[/tex].

[tex]\implies x\in A \backslash B[/tex] and [tex]x \in C[/tex] (the right arrow here reads "implies".)

[tex]\implies x \in A[/tex] and [tex]x \not\in B[/tex] and [tex]x \in C[/tex].

[tex]\implies (x \in A\cap C)[/tex] and [tex]x \not\in B \cap C[/tex].

[tex]\implies x \in (A \cap C) \backslash (B \cap C)[/tex].

Note that [tex]x \in (A \backslash B) \cap C[/tex] (set on the left-hand side) implies that [tex]x \in (A \cap C) \backslash (B \cap C)[/tex] (set on the right-hand side.)

Therefore:

[tex](A \backslash B) \cap C \subseteq (A \cap C) \backslash (B \cap C)[/tex].

Part two: show that the right-hand side is a subset of the left-hand side. This part is slightly more involved than the first part.

Let [tex]x[/tex] be a member of the set on the right-hand side.

[tex]x \in (A \cap C) \backslash (B \cap C)[/tex].

[tex]\implies x \in A \cap C[/tex] and [tex]x \not\in B \cap C[/tex].

Note that [tex]x \not\in B \cap C[/tex] is equivalent to:

However, [tex]x \in A \cap C[/tex] implies that [tex]x \in A[/tex] AND [tex]x \in C[/tex].

The fact that [tex]x \in C[/tex] means that the only possibility that [tex]x \not\in B \cap C[/tex] is [tex]x \not \in B[/tex].

To reiterate: if [tex]x \not \in C[/tex], then the assumption that [tex]x \in A \cap C[/tex] would not be true any more. Therefore, the only possibility is that [tex]x \not \in B[/tex].

Therefore, [tex]x \in (A \backslash B)\cap C[/tex].

In other words, [tex]x \in (A \cap C) \backslash (B \cap C) \implies x \in (A \backslash B)\cap C[/tex].

[tex](A \cap C) \backslash (B \cap C) \subseteq (A \backslash B)\cap C[/tex].

Combine these two parts to obtain: [tex](A \backslash B) \cap C = (A \cap C) \backslash (B \cap C)[/tex].

Answer:

D

Step-by-step explanation:

Answer:

The scale factor is 2

Step-by-step explanation:

Answer:

45

90

135

180

225

Step-by-step explanation:

It represents a function because each element in the domain is matched with exactly one element in the range.

Answer:

See below

Step-by-step explanation:

[tex]3b-8=13 \implies 3b=21 \implies \boxed{b=7}[/tex]

[tex]-7 \text{ is not a solution for the equation}[/tex]

Answer:

yo its not that hard it just means that it can be any number