Please help i need quick answers

Answer:

1. 392 in², 2. 94.99 cm², 3. 145.2 ft², 4. 161.5 m², 5. 17 ft and 81 cm

Step-by-step explanation:

1. A = 16 x 19

A = 304

A = 1/2(11x16)
A = 1/2(176)
A = 88
304 + 88 = 392 in²

2. A = πr²
A = 3.14*5.5²
A = 3.14*30.25
A = 94.985
A = 94.99 cm²

3. A = 1/2(bh)
A = 1/2(11x26.4)
A = 1/2(290.4)
A = 145.2 ft²

4. A = bh
A = 9.5*17
A = 161.5 m²

5. part 1
A = (1/2) · (p + q) · h

112 = (1/2)(11+q)(8)
112 = 4(11+q)
112 = 44 + 4q
68 = 4q
17 = q

17 ft

5. part 2
A = lw
364.5 = 27w
13.5 = w
P = 2l + 2w
P = 2(27) + 2(13.5)
P = 54 + 27
P = 81
81 cm

Hope this helps :)

Answer:

I don't see any thing there

Step-by-step explanation:

u need to include the picture

Answer:

Step-by-step explanation:

What is the value of 6(2b-4) when b =5 2.  The value of is 36. Step-by-step explanation: Given expression: To find the value of at b= 5, we need to substitute the b=5 in the expression, we get.

can i have brainly please :) thanks bro

Answer: 36

Step-by-step explanation:

Answer:

Step-by-step explanation:

Identify the equation in slope-intercept form for the line containing the points

(3,5) and (2,-5)

Choices:

y = 3x − 15

y = 5x − 25

y = 10x − 25

y = 5x + 10

Pls help

Sooo let’s solve this….

Notice the x-axis

Slope Intercept form changes at a constant rate soooo… from (3,5) to (2,-5)

The axis goes left by 1

On A graph the more to the left the smaller number get.

The Y-axis goes down by 10 from the bigger point

But…..

It’s really not going left 1 and 10 down you always start with the smaller point so from

(2,-5) to (3,5) It goes Right 1 and 10 up

Knowing this

Slope Intercept form

Y=mx+b

Where m=slope

b= y-intercept where the line crosses x=0

Our Slope Is 10

Because from -5 to 5 you have to add 10 to get the other value

y=10x+b

But lets just figure out the y-intercept to be sure.

We want the X-axis to be 0 so we will be going left until we get to 0

So We get this point (2,-5)

Knowing that we go up 10 and right 1 to get to the higher value we will do the opposite.

We will go 1 to the left and 10 down

(2,-5)

(1,-15)

(0,-25) As you can see x=0 so the y-intercept will be -25

y=mx+b

m=slope

b= y-intercept

y=10x-25 The Third Option is the Answer….

SonicIsCoool, at your service if you need any help :)

Answer:

the correct answer is shown below

Step-by-step explanation:

hope this helps

have an awesome day -TJ

pls mark brainliest if this helps :)

Answer:

1 27/100

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

you cant see the picture

Step-by-step explanation:

Answer:

They felt it gave the commissioners too much power and was unfair to slaves by giving them a trail without injury

Answer:

The circumference (C) of a circle is found by the equation C = 2*[tex]\pi[/tex]*radius

There is a second relationship between [tex]\pi[/tex] and circles.  That of the area (A) of the circle which is found by the formula A = [tex]\pi*radius^{2}[/tex]

Step-by-step explanation:

Answer:

[tex]\frac{5}{36}[/tex]

Step-by-step explanation:

the total number of possible combinations of rolling two dice is 36 because a side has 6 sides and [tex]6^{2}=36[/tex]

and possible combinations that sum to 8 are

which are 5 possible combinations which gives [tex]\frac{5}{36}[/tex]

Answer:

⊕ y=2x+4

Step-by-step explanation:

1) all the answers are provided in slope-interception form, then

2) the slope of the required line is: (12-8)/(4-2)=2. The required line is like to y=2x+??;

3) if the points (2;8) and (4;12) belong to the line required, then the point (0;4) also belongs to this one. It means, the interception is 4;

4) finally, the line required is y=2x+4.

PS. note, the suggested solution is not the only way.

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

[tex]d=\sqrt{\frac{3h}{2} }[/tex]

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

[tex]d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)[/tex]

For Addison h=85(1/3)

[tex]d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)[/tex]

Subtracting both distances we get

[tex]8\sqrt{2}-6\sqrt{2} =2\sqrt{2}[/tex]

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

https://brainly.com/question/1392973

Answer:

2 root 2mi.

Step-by-step explanation:

Edge2020

Answer:

-12.

Step-by-step explanation:

a^2 - 5a - 6

When a = 2 we have

2^2 - 5(2) - 6

= 4 - 10 - 6

= -12.

Answer:

Step-by-step explanation:

a²- 5a - 6

Substitute a for 2

(2)² - 5(2) - 6

Solve.

4 - 10 - 6 = -12

If a = 2, a²- 5a - 6 equals -12

Answer:

The answer to your question would be -0.383

Step-by-step explanation:

I have no idea why it's deleting my answers, but that's the best choice.

=========================================================

Explanation:

The LCM of 3 and 5 is 3*5 = 15.

Every 15 days, the two people will swim together on the same day.

And so on.

Keep this process going of adding on 15 to find this sequence

1, 16, 31, 46, 61, 76, ...

We stop the sequence once we either reach 70 or go over it because there are 7*10 = 70 days in ten weeks. This assumes we use a 7 day week rather than a 5 day week.

As shown in bold, there are 5 items smaller than 70. So the two people swam together a total of 5 times

-----------------

Alternatively, you can solve 15n+1 = 70 for n to get n = 4.6 which rounds down to n = 4 to represent the set {0,1,2,3,4} which has 5 items in it to represent the five times total they swim together.

and so on until reaching n = 4 corresponding to day 15(4)+1 = 61.

Answer:

9/10.

Step-by-step explanation:

3 3/4 ÷ (1 2/3 + 2 1/2)​

= 3 3/4 / ( 5/3 + 5/2)

= 3 3/4 / ( 10/6 + 15/6)

= 3 3/4 / 25/6

= 15/ 4 / 25/6

= 15/4 * 6/25

= 90/100

= 9/10.

Step-by-step explanation:

a scale factor normally applies to lengths (one-dimensional sizes).

the perimeter of a triangle is calculated only by using lengths, so we can apply the scaling factor directly to the perimeter.

perimeter of the new triangle = 2 × perimeter of the old triangle = 2×8 = 16

[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ J^3=0.125\implies J^3=\cfrac{0125}{1000}\implies J^3=\cfrac{1}{8}\implies J^3=\cfrac{1}{2^3} \\\\\\ J^3=2^{-3}\implies J^3=(2^{-1})^3\implies J=2^{-1}\implies J=\cfrac{1}{2}[/tex]

Answer:

20320 minutes

Step-by-step explanation:

divided the minutes by 24 then get your answer

QUESTION -> {WHICH EQUATION DESCRIBES A LINEAR FUNCTION }.

ANSWER :

B .

y =(1 — 6 ) ×

or.

C .

y = (2) ×

HOPE IT HELPS .

Answer:

9

41/4

23/2

51/4

14

Step-by-step explanation:

The first term is the first term that is given. Just copy it.

Each next term is the previous term plus the common difference.

First term: a_1 = 9

Second term: a_2 = 9 + 5/4 = 36/4 + 5/4 = 41/4

Third term: a_3 = 41/4 + 5/4 = 46/4 = 23/2

Fourth term: a_4 = 46/4 + 5/4 = 51/4

Fifth term: a_5 = 51/4 + 5/4 = 56/4 = 14

Answer:

b) -b/a

Step-by-step explanation:

Slopes of perpendicular lines are negative reciprocals. That means to flip the fraction and change the sign. :-)

Answer:

a)0.012 kg

b)0.007kg

c)35.015kg

d)0.675kg

Step-by-step explanation:

please mark me as brainlest

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Derivative of tan(x) is sec²x

[tex]\qquad \sf  \dashrightarrow \: \therefore \dfrac{d}{dx} ( \tan(x)) = { \sec}^{2} (x)[/tex]

You can check the first principle method of derivation in attachment

[tex]\rightarrow \sf \dfrac{d}{dx} (tan(x))[/tex]

[tex]\rightarrow \sf \dfrac{d}{dx} ( \ \dfrac{sin(x)}{cos(x)} \ )[/tex]

use the quotient rule

[tex]\rightarrow \sf \dfrac{cos(x) * \dfrac{d}{dx} (sin(x)-sin(x)*\dfrac{d}{dx}(cos(x) }{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{cos(x) * cos(x)-sin(x)*(-sin(x) )}{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{cos(x)^2+sin(x)^2}{cos(x)^2}[/tex]

[tex]\rightarrow \sf \dfrac{1}{cos(x)^2}[/tex]

[tex]\rightarrow \sf sec(x)^2[/tex]

used formula's :

Using the combination formula, it is found that there are 84 ways to choose the three tiles.

The order in which the tiles are chosen is not important, hence the combination formula is used to solve this question.

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem, three tiles are chosen from a set of nine, hence:

[tex]C_{9,3} = \frac{9!}{3!6!} = 84[/tex]

There are 84 ways to choose the three tiles.

More can be learned about the combination formula at https://brainly.com/question/25821700

Answer:

x ^5/3 y ^1/3 (the second option listed)

Step-by-step explanation:

So without even solving the expression, you can find the correct option. If you're finding the cube root (or really any square root), you know it will be less than your original number (unless you are working with imaginary numbers, but you aren't).

So, if you are finding the cube root of an expression, you're finding the cube root of each number separately.

You wouldn't be cubing y, you would be finding the cube root. You wouldn't be leaving y the same, you are finding the cube root.

This means that without even solving (which I will explain),

the correct option is the second one on the screen.

Here's how to actually solve the equation:

So, if we are finding the cube root of a variable with an exponent, we can divide that exponent by 3 (because it is a cube root).

When we have a square root, you know that we are breaking down each number/variable into an even exponent to solve the expression. When taking the square root of an even exponent, such as 4, you would divide by 2.

This same strategy applies to cube roots. You are dividing the exponent of both variables by 3.

[remember: the exponent of a variable without an exponent is essentially an invisible exponent of 1.]