please help i guess on a

here you go it's too easy

Step-by-step explanation:

Explanation is in the attachment .

Hope it is helpful to you ❣️☪️❇️

Answer:

A is the equation in standard form

Step-by-step explanation:

Answer:

nr.herkyrsfdlufshfsyfs

Step-by-step explanation:

dsfsyfksutryrysyrslufzmfyzydzufmzmhfzl

hdhfuthfzhkrskyrsgj

Answer:

[tex]P(Negative | Yes) = 0.0486[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{} & {Yes} & {No} & {Positive} & {137} & {24} & {Negative} & {7} & {132} \ \end{array}[/tex]

Required

[tex]P(Negative | Yes)[/tex]

This is calculated as:

[tex]P(Negative | Yes) = \frac{n(Negative\ n\ Yes)}{n(Yes)}[/tex]

So, we have:

[tex]P(Negative | Yes) = \frac{7}{137+7}[/tex]

[tex]P(Negative | Yes) = \frac{7}{144}[/tex]

[tex]P(Negative | Yes) = 0.0486[/tex]

Answer:

0.1636 = 16.36% probability that Kobe makes his 10th free throw on his 14th shot

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either he makes it, or he misses. The probability of making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

He is able to make a free throw 70% of the time.

This means that [tex]p = 0.7[/tex]

What is the probability that Kobe makes his 10th free throw on his 14th shot?

9 of his first 13(P(X = 9) when n = 13), and then the 10th with 0.7 probability.

Thus

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 9) = C_{13,9}.(0.7)^{9}.(0.3)^{3} = 0.2337[/tex]

0.7*0.2337 = 0.1636

0.1636 = 16.36% probability that Kobe makes his 10th free throw on his 14th shot

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Explanation:

Your question covers a good bit of the material in an algebra course. The short answer is, "the same way you solve a numerical equation." The point of algebra is that literals can stand for numbers, and so be manipulated the same way numbers are.

Expressions are evaluated according to the Order of Operations. For equations involving a single variable, the equation specifies what operations are being performed on that variable. To find the vale of the variable (solve for that literal), you need to "undo" the operations that are performed on it. As with many problems that have layers, you work down through the layers from the outside in. Generally, that means working through the list of operations "backwards," undoing the last one first.

Simple example

  y = mx + b . . . . . . solve for x

In this equation, the operations performed on x are ...

In accordance with the above, the first thing we do is "undo" the addition of b. (Note that this could be a number or literal--or even a complicated expression--and the process would be exactly the same.) To "undo" addition, we add the opposite.

  y -b = mx +b -b   ⇒   y -b = mx

Next, we "undo" the multiplication by m. That is, we divide by m, or multiply by the reciprocal of m. Either is the same as the other.

  (y -b)(1/m) = (mx)(1/m)   ⇒   (y -b)/m = x

Now, we have solved this literal equation for x.

_____

Throughout this process you must adhere strictly to the properties of equality. That is, anything you do to one side of the equation must also be done to the other side.

The reason you study inverses and identity elements is so you understand that addition of an additive inverse produces the additive identity element:

  x + (-x) = 0

Similarly, multiplication by the multiplicative inverse (reciprocal) produces the multiplicative identity element.

  x · (1/x) = 1

When other operations are involved, such as raising to a power, trig functions, roots, logs, exponentiation, each of these has an associated inverse function that produces an identity:

  (x^a)^(1/a) = x^1 = x

  arcsin(sin(x)) = x

  (√x)^2 = x

  10^(log(x)) = x   or   log(10^x) = x

Some of these inverse functions have restricted domains, so care must be used when solving equations involving them.

When a variable of interest appears on both sides of the equal sign, then you must figure a way to rearrange the equation so the terms with the variable can be combined.

Example:

  ax + b = cx +d . . . . . solve for x

  ax -cx = d -b . . . . . . subtract (cx+b). (Of course, this is subtracted from both sides of the equation.)

  x(a -c) = d -b . . . . . combine x-terms

  x = (d -b)/(a -c) . . . . divide by the coefficient of x

Note that we had to divide the entire right-side expression by the x-coefficient, so had to enclose it in parentheses.

More Complicated Example:

A recent Brainly problem asked for the solution to ...

  T = 2π√(L/g) . . . . solve for L

Here, L is divided by g, a root taken, and that multiplied by 2π. Undoing these in reverse order, we first divide by 2π, square both sides to undo the root, then multiply by g to undo the division:

  [tex]T=2\pi\sqrt{\dfrac{L}{g}}\\\\\dfrac{T}{2\pi}=\sqrt{\dfrac{L}{g}}\\\\\left(\dfrac{T}{2\pi}\right)^2=\dfrac{L}{g}\\\\\boxed{L=g\left(\dfrac{T}{2\pi}\right)^2}[/tex]

The problem posted on Brainly had numbers where some of these variables are. That does not affect the solution method, except that sometimes numerical values can be combined where literal values cannot.

_____

Key Points

Answer:

y= (3/2)x - (5/2)

Step-by-step explanation:

Slope-intercept form is y=mx+b. So, 3x-2y=5 can be rearranged to slope-intercept form.

We need to isolate the y and get it by itself, so let's subtract the 3x from both sides.

-> -2y = 5 - 3x

Now we need to get rid of the -2 so that the y will be completely alone. So, divide the -2 from both sides of the equation.

-> y = (5/-2) (-3x/-2)

Now rearrange, and the negatives from the 3x and 2 cancel each other out and we are left with:

-> y = 3/2 x - 5/2

Answer:

m=5

n=-3

Step-by-step explanation:

3m+2m=9

3m-3n=24

3(5)+2(-3)=9

15-6=9 correct

Given :-

To Find :-

Solution :-

We know that the circumference of the Circle with radius r is given by ,

=> C = 2πr .

=> C = 2 × 3.14 × 50 cm

=> C = 314 cm .

Hence the required answer is 314 cm .

Answer:

Step-by-step explanation:

b 75

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Answer:

  (8a -a²)/(a +2)

Step-by-step explanation:

Cancel common factors from numerator and denominator.

  [tex]\dfrac{-56+15a-a^2}{a^2+2a}\div\dfrac{a-7}{a^2}=-\dfrac{(a-7)(a-8)(a^2)}{a(a+2)(a-7)}\\\\=-\dfrac{a(a-8)}{a+2}=\boxed{\dfrac{8a-a^2}{a+2}}[/tex]

Answer:

To create the graph of k(x) , the graph of f(x)   undergoes  a vertical stretching  by a factor of 9.

Step-by-step explanation:

We are given that

[tex]k(x)=9f(x)[/tex]

We have to Identify the transformation that occurs to create the graph of k(x).

To create the graph of k(x) we will multiply the function f(x) value by 9.

Let f(x) be any function

[tex]g(x)=a f(x)[/tex]

Where a>1

It means to obtain the graph  of g(x) the graph f(x)  has  undergone a vertical stretching  by a factor of a.

We have k=9>1

Therefore, to create the graph of k(x) , the graph of f(x) undergoes a vertical stretching  by a factor of 9.

Answer:

Correct option is

C

10

5

10P

5

Total ways in which one passenger can stop =10

Total ways in which 5 passengers can stop =10∗10∗10∗10∗10

=10

5

We will select 5 floors from 10 floors and assign each individual to each floor to keep everyone isolated from each other

No. of ways in which no two persons stop at the same floor =10C

5

∗5!

=10P

5

⇒P(E)=10P

5

/10

5

Answer:

7/30

Step-by-step explanation:

P = 1/15 + 1/6 = (2+5)/30 = 7/30

Answer:

B

Step-by-step explanation:

The coeffecients (I totally didn't spell that right) and variables match up.

Answer:

2

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Equivalent question: Find the slope of line going through points (1,-5) and (10,13).

Line points up vertically and subtract. Then put 2nd difference on top of first difference.

(1,-5)

(10,13)

---------'subtracting

-9, -18

So the slope of the line gong through point's (1,-5) and (10,13) is -18/-9=2.

The common difference of an arithmetic sequence whose first term is -5 and whose tenth term is 13 is 2.

Answer:

X⁴-7x²-8x-7

Step-by-step explanation:

Step-by-step explanation:

If the price is below the equilibrium level, then the quantity demanded will exceed the quantity supplied. Excess demand or a shortage will exist. If the price is above the equilibrium level, then the quantity supplied will exceed the quantity demanded. Excess supply or a surplus will exist.Whenever markets experience imbalances—creating disequilibrium prices, surpluses, and shortages—market forces drive prices toward equilibrium. A surplus exists when the price is above equilibrium, which encourages sellers to lower their prices to eliminate the surplus.

Answer: 5,987

Step-by-step explanation:

Answer:

 $10,000

Step-by-step explanation:

.05 x = 500

x = 500/.05

x = $10,000

Answer:

0.0106 = 1.06% probability that 2 or fewer will withdraw

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they withdraw, or they do not. The probability of an student withdrawing is independent of any other student, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

25% of its students withdraw without completing the introductory statistics course.

This means that [tex]p = 0.25[/tex]

Assume that 30 students registered for the course.

This means that [tex]n = 30[/tex]

Compute the probability that 2 or fewer will withdraw:

This is:

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{30,0}.(0.25)^{0}.(0.75)^{30} = 0.0002[/tex]

[tex]P(X = 1) = C_{30,1}.(0.25)^{1}.(0.75)^{29} = 0.0018[/tex]

[tex]P(X = 2) = C_{30,2}.(0.25)^{2}.(0.75)^{28} = 0.0086[/tex]

[tex]P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0002 + 0.0018 + 0.0086 = 0.0106[/tex]

0.0106 = 1.06% probability that 2 or fewer will withdraw

Answer:

[tex]P = (7, -\frac{3}{5})[/tex]

Step-by-step explanation:

Given

[tex]A = (-9,5)[/tex]

[tex]B = (11,-2)[/tex]

[tex]m : n = 4 : 1[/tex]

Required

Point P

This is calculated as:

[tex]P = (\frac{m * x_2 + n * x_1}{m + n}, \frac{m * y_2 + n * y_1}{m + n})[/tex]

So, we have:

[tex]P = (\frac{4 * 11 + 1 * -9}{4 + 1}, \frac{4 * -2 + 1 * 5}{4+1})[/tex]

[tex]P = (\frac{35}{5}, \frac{-3}{5})[/tex]

[tex]P = (7, -\frac{3}{5})[/tex]

Answer:

a) The reorder point necessary to provide a 95 percent service probability is 1557 units.

b) The Z value of 0.74 corresponds to 77% service probability.

Step-by-step explanation:  

Average weekly demand (d) = 315 units  

The standard deviation of weekly demand (\sigmad) = 90 units  

Lead time (L) = 4 weeks  

At 95% service level value of Z = 1.65  

Reorder point = d x L + safety stock  

[tex]= d \times L + (Z \times \sigma d \times \sqrt L)\\\\= 315 x 4 + (1.65 x 90 x \sqrt 4)\\\\= 1260 +(1.65 x 90 x 2)\\\\= 1260 + 297\\\\= 1557 units[/tex]

b) Earlier the safety stock was 297 units(calculated in part a)

Now the safety stock is reduced to 55%.so,55% of 297 = 163.35 units  

So the new safety stock = 297 - 163.35 = 133.65  

[tex]Safety stock = Z \times \sigma d \times \sqrt L\\133.65 = Z x 90 x 2\\133.65 = 180Z\\ Z = 133.65/180\\Z = 0.74[/tex]  

The Z value of 0.74 corresponds to 77% service probability.

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Answer:

  6.5 cm

Step-by-step explanation:

The length of the rhombus is the length of the long diagonal: 12 cm.

Perhaps you want the length of one side. We recognize the given lengths as the legs of a 5-12-13 right triangle. Since each side is the hypotenuse of a right triangle whose legs are half the diagonals, the side length of the rhombus will be half of 13 cm.

The side lengths of the rhombus are 6.5 cm.

Answer:

90

Step-by-step explanation:

360 ÷ 4 = 90

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Answer:

  x = -5  or  x = -2

Step-by-step explanation:

Factoring, we have ...

  ((x +3 +2)((x +3) -1)) = 0

  (x +5)(x +2) = 0

  x = -5  or  x = -2 . . . . . . . . values that make the factors zero

==========================================================

Explanation:

The graph of [tex]y \ge -\frac{1}{3}x+2[/tex] has the boundary y = (-1/3)x+2 which is a solid line. This line goes through (0,2) and (3,1). We shade above the boundary because of the "greater than" sign.

The graph of y < 2x+3 has a dashed boundary line of y = 2x+3, and we shade below the boundary because of the "less than" sign.

The two regions overlap in the upper right corner where it's shaded in the darkest color. The points (2,2), (3,1) and (4,2) are in this upper right corner region. If we plug the coordinates of each point into each inequality, then we'll get true statements.

For instance, let's try (x,y) = (2,2) into the first inequality

[tex]y \ge -\frac{1}{3}x+2\\\\2 \ge -\frac{1}{3}(2)+2\\\\2 \ge -\frac{2}{3}+2\\\\2 \ge -\frac{2}{3}+\frac{6}{3}\\\\2 \ge \frac{-2+6}{3}\\\\2 \ge \frac{4}{3}\\\\2 \ge 1.33\\\\[/tex]

Which is true since 2 is indeed larger than 1.33, so that confirms (2,2) is in the shaded region for [tex]y \ge -\frac{1}{3}x+2\\\\[/tex]

Let's check the other inequality as well

[tex]y < 2x+3\\\\2 < 2(2)+3\\\\2 < 4+3\\\\2 < 7\\\\[/tex]

That works too. So (2,2) is in BOTH shaded regions at the same time; hence, it's a solution to the system. You should find that (3,1) and (4,2) work for both inequalities also. This will confirm choice A is the answer.

--------------------------------

Extra info (optional section)

A point like (3,-1) does not work for the first inequality as shown below

[tex]y \ge -\frac{1}{3}x+2\\\\-1 \ge -\frac{1}{3}(3)+2\\\\-1 \ge -1+2\\\\-1 \ge 1\\\\[/tex]

Since -1 is neither equal to 1, nor is -1 larger than 1 either. The false statement at the end indicates (3,-1) is not a solution to that inequality.

Based on the graph, the point (3,-1) is not above the blue solid boundary line. All of this means we can rule out choice B.

You should find that (1,-2) is a similar story, so we can rule out choice C. Choice D can be ruled out because (2,0) is not a solution to the first inequality.