The simplified expressions for (A), (B) and (C) are:
(A) [tex]f(x+h) = 4x + 4h - 6[/tex]
(B) [tex]f(x+h) * f(x) = 16x^2 + 4xh - 24x + 4h^2 - 24h + 36[/tex]
(C) [tex]f(x+h) - f(x) / h = 4[/tex]
How to simplify the equation?To simplify we use the given method.
A)
[tex]f(x+h) = 4(x+h) - 6 = 4x + 4h - 6[/tex]
B) [tex]f(x+h) * f(x) = (4x + 4h - 6) * (4x - 6) = 16x^2 + 4xh - 24x + 4h^2 - 24h + 36[/tex]
C)
[tex]f(x+h) - f(x) / h = (4x + 4h - 6) - (4x - 6) / h = 4h / h = 4[/tex]
So the simplified expressions for (A), (B) and (C) are:
(A) [tex]f(x+h) = 4x + 4h - 6[/tex]
(B) [tex]f(x+h) * f(x) = 16x^2 + 4xh - 24x + 4h^2 - 24h + 36[/tex]
(C) [tex]f(x+h) - f(x) / h = 4[/tex]
Please note that in (C) the difference of the functions is divided by h, not multiplied.
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Assume that two fair dice are rolled. First compute P(F) and then P(FIE). Explain why one would expect the
probability of F to change as it did when the condition that E had occurred was added.
E: a three shows on at least one of the dice
F: the total is less than eight
...
The probability that a three shows on at least one of the dice is 11/36.
How to calculate the probability?It should be noted that of probability means the likelihood of the occurence of an event.
The probability that a three shows on at least one of the dice will be:
= 11/36
This can be seen from the table that is attached.
The probability that the total is less than 8 will be:
= 21/36
= 7/12
Here, there are 21 places where the total is less than 8.
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1. How much percent more than the cost price should a shopkeeper mark his goods so that after allowing a discount of 25% on the marked price, he gains 20% ?
2. When a bicycle is sold at marked price, a profit of 20% is earned by the seller. If a discount of 5% is allowed, the profit is only Rs. 180 earned by the seller. How much did the seller pay for the bicycle?
Answer:
1. 60%
2. He paid Rs. 1285.71
Step-by-step explanation:
1.
He buys an item for x.
He sells the item with a 25% of the marked price, and he still makes a 20% profit over his cost x.
He must sell for x + 20% of x which is the same as 1.2x.
Let the markup be y%.
Since he gives a 25% discount over the marked price, he sells for 75% of the marked price.
0.75(x + y% of x) = 1.2x
0.75(x + xy/100) = 1.2x
x + xy/100 = 1.6x
Divide both sides by x.
1 + y/100 = 1.6
Multiply both sides by 100.
100 + y = 160
y = 60
Remember that y is in percent, so the markup must be 60%.
Check:
He buys an item for $10.
He applies a markup of 60%. 1.6 × $10 = $16.
He has a price of $16 for this item.
Now he gives a 25% discount. That means the discounted price is 75% of the marked price.
75% of $16 = $12
He sells at a 25% discount for $12.
Compare the actual selling price after the 25% discount with this cost.
$12 compared to $10.
$12/$10 = 1.2 = 120%
Since he sells for 120% of the original price, the markup is 20% which is what he wanted.
2.
The cost to the seller is x.
If he sells it at a 20% profit, then he sells it for 1.2x
Now he gives a discount of 5%, so the final selling price after discount is
0.95(1.2x)
The profit is the difference between what he sold it for, 0.95(1.2x), and what he bought is for, x, and it is Rs. 180.
0.95(1.2x) - x = 180
1.14x - x = 180
0.14x = 180
x = 1285.71
Answer: He paid Rs. 1285.71
A rectangle has corners E, F, G, D, starting from top left and going clockwise. Point H is halfway between E and F. 2 lines are inscribed in the rectangle. One line goes from D to H and another goes from H to G. Angle E D H is (5 x) degrees and angle H D G is (4 x) degrees. Angles E D G and F G D are right angles. What is the measure of Angle EDH? 10° 40° 50° 90°
The measure of Angle EDH = 50°.
How to estimate the measure of Angle EDH?The angle EDH exists given as 5x° and the angle HDG exists given as 4x°. The angles EDG and FGD exist at right angles. That signifies both angles exist equivalent to 90°.
Angle EDH = 5x°
Angle HDG = 4x°
Angle EDG = 90°
5x + 4x = 90
9x = 90
Divide both sides by 9
x = 90/9
x = 10°
Angle EDH = 5x = 5 × 10 = 50°
The measure of Angle EDH = 50°.
Therefore, the correct answer is option c) 50°.
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Consider the following sample data set of 20 numbers.
24 30 4 42 40 26 23 36 12 45 29 21 34 16 47 28 32 54 19 9
1.
Create a relative frequency table and a frequency histogram with the bin width 8.
2.
Find the sample mean. (Round to the nearest hundredth.)
3.
Find the sample standard deviation
. (Round to the nearest hundredth.)
The mean = 28.55, while the standard deviation is 13.16
1. The histogram is an attachment
How to calculate for the mean of the data setWe have the following numbers
24 30 4 42 40 26 23 36 12 45 29 21 34 16 47 28 32 54 19 9
The sum of these numbers is given as
571
The total numbers = 20
The mean = 571/20
= 28.55
2 = How to find the standard deviation= (24 - 28.55)2 + ... + (9 - 28.55)/20 - 1
= 3292.95/19
= 173.31315789474
s = √173.31315789474
= 13.164845532506
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how to find n if sn=969 of A.p,a1=9 and d=6
Determine the number of solutions for the equation shown below.
4x+6= 4x+6
Ο Α. 0
OB. Infinitely many
* O C. 1
OD. 2
Question 2 of 5
Select the correct answer.
After buying a car, Sarah decides to get it appraised every few years. After owning the car for two years, its value is $5,000. After own
the car for five years, its value is $2,000.
What is the equation that models this inverse variation?
Oy=
O y = 2,500
O
O
5,000
y = 2,000
y =
10,000
Submit
Reset
The inverse proportional relationship that models this variation is given as follows:
[tex]y = \frac{10,000}{x}[/tex]
What is a proportional relationship?A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:
y = kx
In which k is the constant of proportionality.
An inverse proportional relationship is given as follows:
[tex]y = \frac{k}{x}[/tex]
In this problem, we have an inverse relation in which y(2) = 5000, hence the constant k is found as follows:
[tex]y = \frac{k}{x}[/tex]
[tex]5000 = \frac{k}{2}[/tex]
k = 10,000
Hence the relation is:
[tex]y = \frac{10,000}{x}[/tex]
As stated in the problem, when x = 5, y = 2,000, which we can verify replacing in the relation.
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Which inequality is true when x = 4?
A. X+5<_3
B.x/2<3
c.9x>36
D.18<_-8
Answer:
[tex] \sf{b. \frac{x}{2} <3}[/tex]
step by step explanation:
We will try one by one.
A. x + 5 < 3
Step 1. Subtitution Value of x
= 4 + 5 < 3
Step 2. Add by 4 with 5
= 9 < 5
A is wrong because 9 is bigger then 5
B. x/2 < 3
= 4/2 < 3
= 2 < 3
is true because 2 is smaller than 3
C. 9x > 36
9(4) > 36
36 > 36
is wrong, should 36 = 36
D. 18 < 8
is wrong because 18 is bigger than 8
I know question on central limit theorem has been asked numerous times
and I have searched around the website but still couldn't get what I wanted
to find out(probably most people who asked the question is stuck at
different parts of the theory).
Attached in my question is a lecture slide for the search for a
transformation of x that has a limiting distribution.I do not understand
why x and u is multiply by vn instead of n.Also,why when the statistic /n(x
-μ)is used,μbecomes zero?
Thank you in advance!
A nine year old girl did a science fair experiment in which she tested professional touch therapist to see if they could sense her energy field she flipped a coin to select either her right hand or her left hand and then she asked the therapist to identify the selected hand by placing their hand just under her hand without seeing it and without touching it among 285 trials the touch therapist were correct 116 times use a 0.01 significance level to test the claim that touch therapist use a message equivalent to random guesses to the results suggest that touch therapists are effective
The test statistic based on the probability illustrated is -3.22.
How to illustrate the probability?Based on the information, the test statistic will be:
= (0.4 - 0.5)/[✓0.5(1 - 0.5)/260]
= -3.22
The p value using the distribution table is 0.0012.
The conclusion is to reject the null hypothesis as there's sufficient evidence to warrant rejection.
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graph y=1/3x+5 PLS HELP ASAP
Answer:
Graph attached.
Step-by-step explanation:
Given equation:
[tex]y=\dfrac{1}{3}x+5[/tex]
The given equation is a linear equation in slope-intercept form, where 1/3 is the slope and 5 is the y-intercept.
To graph the equation, find and plot at least two points, then draw a straight line through them.
To find the points on the line, input values of x into the equation:
[tex]x = 0 \implies y=\dfrac{1}{3}(0)+5 \implies (0,5)[/tex]
[tex]x=3 \implies y=\dfrac{1}{3}(3)+5 \implies (3,6)[/tex]
[tex]x=6 \implies y=\dfrac{1}{3}(6)+5 \implies (6,7)[/tex]
See attachment for the graph of the given equation.
Find some points
x=0
y=5x=3
y=1+5=6x=-3
y=-1+5y=4Graph attached
IM IN A HURRY PLEASE HELP ME QUESTION IS DOWN BELOW WORTH 15 POINTS each
Answer:
a) ∠VUW
b) VY
c) XYV
d) 180°
e) 65°
Step-by-step explanation:
Part A:A central angle is an angle that creates an arc in a circle, while also having its vertex as the center of the circle.
Here the center is U. So, the vertex of the angle must include U.
This means that there are multiple answers to part a.
The answers can be:
∠VUW
∠WUX
∠XUV
Part B:A minor arc is any arc that doesn't exceed 180°.
The possible answers for part b, using this definition are:
WV
VY
XY
Part C:The answer you inputted here is incorrect.
The order of the letters matter.
A tip for you to never mess these up is to trace the letters you've chosen with your finger and see if that image you make with your finger matches up with the shape you wanted to make.
An arc that makes a semicircle is an arc that connects the endpoints of the diameter. The diameter in this case is VX.
This means that your answer must start with V and end with X, or the other way around. (Meaning you could start with x and end with v, but always make sure you keep the endpoints of the diameter as the endpoints of the arc.)
The possible answers for this part are either:
VYX or VWX
Part D:This arc intercepts the diameter, which is a straight line and a central angle.
The angle of a diameter is 180°.
The arc of an intercepted central angle has the same measure of the central angle itself.
So, the measure of VWX is 180°.
Part E:If an arc intercepts a central angle, then the arc has the same measure as the central angle.
This rule works the other way around, too.
So, the central angle has the same measure as the minor arc that it intercepts.
Measure of arc VUW is 65°, so m∠VUW is also 65°.
Which inequality is represented by the given graph?
C) y ≤ -3x+6
D) y ≥ 3x+6
Answer: c, y ≤ -3x+6
Step-by-step explanation:
for example we could use a point on the graph such as (-2, 0)
now we would insert the numbers into the inequality:
y ≤ -3x+6
= 0 ≤ -3(-2) +6
= 0 ≤ 6+6
= 0 ≤ 12
which is true! therefore it is y ≤ -3x+6
A stadium has 53,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A
equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,131,000 from each sold-out event. How many seats
does each section hold?
The number section A, section B and section C seats sold are 26500, 14200 and 12300 respectively.
How to use equation to find the total number of seat in each section?The stadium has 53,000 seats.
Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C.
The number of seats in Section A equals the total number of seats in Sections B and C.
Therefore,
a = b + c
a + b + c = 53000
b + c + b + c = 53000
2b + 2c = 53,000
25a + 20b + 15c = 1131000
25(b + c) + 20b + 15c = 1131000
25b + 25c + 20b + 15c = 1131000
45b + 40c = 1131000
Hence,
2b + 2c = 53000
45b + 40c = 1131000
40b + 40c = 1060000
45b + 40c = 1131000
-5b = - 71000
b = - 71000 / -5
b = 14,200
Therefore,
2(14,200) + 2c = 53000
2c = 53000 - 28400
2c = 24600
c = 24600 / 2
c = 12300
Hence,
a = b + c
a = 14200 + 12300
a = 26500
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Find sec, tan 0, and sin 0, where is the angle shown in the figure.
Give exact values, not decimal approximations.
0
4
5
The exact values of sec θ, tan θ and sin θ are 6.4/4, 5/4 and 5/ 6.4 respectively.
How to determine the trigonometric ratiosFrom the figure, we have the values of the sides to be;
opposite side = 5Adjacent side = 4Let's use Pythagorean theorem to find the hypotenuse(x)
Hypotebuse square = opposite side square + adjacent side square
Substitute the values deduced from the figures given
x² = 5² + 4²
x² = 25 + 16
x² = 41
x = [tex]\sqrt{41}[/tex]
x = 6. 4
sin θ = opposite/hypotenuse
Substitute the values
sin θ = 5/ 6. 4
tan θ = opposite/ adjacent
Substitute the values
tan θ = 5/ 4
sec θ = hypotenuse/ adjacent
substitute the values
sec θ = 6. 4/ 4
Thus, the exact values of sec θ, tan θ and sin θ are 6.4/4, 5/4 and 5/ 6.4 respectively.
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50 POINTS!!!!!!!!!!!!!!!!!!!!!!!! SOLVE THIS QUICKLY WITH AN EXPLANATION
Answer:
x = 22°
Step-by-step explanation:
Between two parallel lines, the opposite inside angles will be congruent. So, x is equal to angle V. The sum of the angles of any triangle will be 180°. Therefore, you can find the value of x by setting all the angles of the triangle SRV equal to 180°.
S = 5x + 4
R = 44
V = x
S + R + V = 180 <----- General equation
(5x + 4) + 44 + x = 180 <----- Insert values
5x + 48 + x = 180 <----- Add 4 and 44
6x + 48 = 180 <----- Add 5x and x
6x = 132 <----- Subtract 48 from both sides
x = 22 <----- Divide both sides by 6
16
3. A Ferris wheel with a radius of 25 m makes 2 rotations every minute.
a. State the period of the Ferris wheel.
b. Complete a tables of values showing the height above the ground for 2 rotations of the
Ferris wheel by assigning the correct variables
c. Graph 2 rotations of the Ferris wheel. (Hint: Time Vs Height above the platform)
d. State the amplitude of the Ferris wheel.
A) The Period is 30 seconds
D) The amplitude is 25 m
How to find the period and amplitude?
A) Since the Ferris wheel makes 2 rotations every minute, then we can say that the period is;
T = 1/2 = 0.5 minutes = 30 seconds
B) Let t be time in seconds and let h be height and as such, we have the formula; h = 25 - 25 cos ((2π/30)t)
Thus, the table is attached showing input values of t and their corresponding h values.
C) The graph of the table above is as attached below.
D) The amplitude is;
Amplitude = (Maximum Point - Minimum Point)/2
Amplitude = (50 - 0)/2
Amplitude = 25
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Please draw the number line and show me if possible:)
The solution to the given inequality expression is expressed as x ≥ 6
Solving inequalitiesGiven the inequality expression shown below;
5x-9/7≥3
Cross multiply
(5x -9)≥7(3)
Expand
5x-9≥21
Add 9 to both sides
5x ≥ 21 + 9
5x ≥ 30
x ≥6
The solution to the given inequality expression is expressed as x ≥ 6
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The diameter of an electric cable is normally distributed, with a mean of 0.9 inch and a standard deviation of 0.02 inch. What is the probability that the diameter will exceed 0.92 inch? (You may need to use the standard normal distribution table. Round your answer to three decimal places.)
The probability that the diameter of the electric cable that is normally distributed will exceed 0.92 inch is 0.841
What is probability?Probabilities are used to determine the chances, likelihood, possibilities of an event or collection of events
How to determine the probability?The given parameters are:
Mean = 0.9
Standard deviation = 0.2
Calculate the z-score at x = 0.92 using
[tex]z = \frac{x - \mu}{\sigma}[/tex]
This gives
z = (0.92 - 0.9)/0.02
Evaluate the numerator; subtract 0.9 from 0.92
z = 0.02/0.02
Divide 0.02 by 0.02. This gives
z = 1
The probability is then represented as:
P(x > 0.92) = P(z > 1)
Next, we look up the value of the z table of probabilities
From the z table of probabilities, we have:
P(x > 0.92) = 0.841
Hence, the probability that the diameter of the electric cable that is normally distributed will exceed 0.92 inch is 0.841
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A package of Toys Galore Cereal is marked "Net Wt. 13 oz." The actual weight is normally distributed, with a mean of 13 oz and a variance of 0.09.
(a) What percent of the packages will weigh less than 13 oz?
%
(b) What weight will be exceeded by 2.3% of the packages? (Round your answer to one decimal place.)
oz
The solution to the Questions are
P(z<0)=50%W=18.08ozWhat weight will be exceeded by 2.3% of the packages?where
u=13
n^2=0.16
[tex]\sigma=\sqrt{0.16}\\\\\sigma=0.4[/tex]
a)
Generally, the equation for is mathematically given as
[tex]X-N(u=13,\sigma=0.4)[/tex]
p(x<14)=P(z<\frac{13-13}{0.4})
P(z<0)
P=0.5
Therefore
P(z<0)=50%
b)
In conclusion
W=(u+2\sigma)
W=(13+2*0.4)
W=13+0.8
W=18.08oz
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How do you solve for m?
m= −(4+m)+2
Answer:
[tex]\bf m = - 1[/tex]
Step-by-step explanation:
[tex]\bf m= −(4+m)+2[/tex]
First of all, let's Rearrange the given terms :-
[tex]\bf m = - ( m +4) + 2[/tex]
Now, let's distribute:-
[tex]\bf m = - m - 4 + 2[/tex]
Add numbers -4 + 2 = -2
[tex]\bf m = - m - 2[/tex]
Add m to both sides, and combine like terms :-
[tex]\bf 2m = - 2[/tex]
Divide both sides by 2 :-
[tex]\bf m = - 1[/tex]
Does anyone know the answer to this?
Answer: equation: y=-4x+1
slope: -4
y intercept:1
What is the value of tan M?
15
15
17
L
∞ ∞01 200
8
17
8
15
15
K 8
8
M
Answer:
The value of tan M = 15/8
Step-by-step explanation:
[tex]tan \: m \: = \frac{p}{b} \\ tan \: m \: = \frac{15}{8} [/tex]
The sets L and J are defined as follows:
L = {d, e, g}
J = {b,c, h}
Find the intersection of L and J .
Answer:
The intersection of L and J or simply (L ∩ J)= ∅
or { }
Step-by-step explanation:
Hello!
The intersection operation is denoted by the symbol ∩. The set A ∩ B—read “A intersection B” or “the intersection of A and B”—is defined as the set composed of all elements that belong to both A and B.
Thus, at this situation there is no similar terms between the to set elements of L and J.
Estimate and classify the critical points for the graph of the function
Please show work
The critical points of the function graphed are given as follows:
x = -1.5: Local maximum.x = -1: Local minimum.What are the critical points of a function?The critical points of a function are the values of x for which:
[tex]f^{\prime}(x) = 0[/tex]
In a graph, they are turning points, and are classified as follows:
Local maximum, if the functions changes from increasing to decreasing.Local minimum, if the functions changes from decreasing to increasing.Looking at the graph, the turning points are approximately:
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lim 1 − cos(2x) /x x→0
The value of the limit of the function given when the value of x tends to zero is 0
What is a limit of a function?The limit of a function is a fundamental concept in calculus and analysis concerning the behavior of that function near a particular inputs.
Given the function limit below;
lim x→0 [1 − cos(2x) /x]
Substitute the value of x into the expression to have;
f(0) = 1-cos2(0)/0
f(0) = 1-1/0
f(0) = 0/0 (ind)
Apply the L'hospital rule to have:
lim x→0 [ − (-2sin2x)) /1]
Substitute the value of x into the result
f(0) = 2sin2(0)/1
f(0) = 2(0)
f(0) = 0
Hence the value of the limit of the function given when the value of x tends to zero is 0
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two vertices are 3x+10 and x+60 find x
The value of x such that the vertices 3x + 10 and x + 60 are equal is 25
What are vertices?Vertices are the endpoints or corners of a shape (such as triangle, square, rectangle and related shapes)
How to determine the value of x?The two vertices are given as:
3x + 10 and x + 60
The condition on the two vertices are not given.
So, we assume that the vertices are equal (as in the base angles of an isosceles triangle)
So, we have the following equation
3x + 10 = x + 60
Subtract x from both sides of the equation
2x + 10 = 60
Subtract 10 from both sides of the equation
2x = 50
Divide both sides of the equation by 2
x = 50/2
Evaluate the quotient
x = 25
Hence, the value of x such that the vertices 3x + 10 and x + 60 are equal is 25
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Solve the following system of equations algebraically:
y=x^2-x-22
y=x-7
The solution of the equations y=[tex]x^{2}[/tex]-x-22 and y=x-7 is that x=-3,5 and y=-10,-2.
Given equations y=[tex]x^{2} -x-22[/tex], y=x-7.
We are required to solve these equations for the value of x and y.
Equation is relationship between two or more variables expressed in equal to form.Equations of two variables look like ax+by=c.It may be a linear equation, quadratic equation and cubic equations.
The given equations are:
y=[tex]x^{2}[/tex]-x-22-----------1
y=x-7----------------2
Put the value of y from second equation in first equation.
x-7=[tex]x^{2}[/tex]-x-22
Solving
[tex]x^{2}[/tex]-x-x-22+7=0
[tex]x^{2}[/tex]-2x-15=0
[tex]x^{2}[/tex]-5x+3x-15=0
x(x-5)+3(x-5)=0
(x+3)(x-5)=0
x=-3,5
Put the values of x=-3 and 5 one by one to get the two values of y in second equation.
y=x-7
x=-3
y=-3-7
=-10
x=5
y=5-7
=-2
Values of y are -10 and -2.
Hence the values of x are-3 and 5 and values of y are -10,-2.
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Find the area of the smaller sector. Round to the nearest tenth. 130 8.02
Answer:
73.0 m²
Step-by-step explanation:
[tex] A = \dfrac{n}{360^\circ}\pi r^2 [/tex]
[tex] A = \dfrac{130^\circ}{360^\circ}\pi (8.02~m)^2 [/tex]
[tex] A = 73.0~m^2 [/tex]
Factor problems 1-4 by finding the GCF.
1. 4x3 – 12x2 + 4x
A. 4x(x2 – 3x + 1)
B. 4x(4x2 – 3x + 1)
C. 4x(4x2 – 3x - 1)
D. 4x(x2 – 6x + 1)
E. 2x(2x2 – 6x + 2)
F. This polynomial cannot be factored using the GCF method.
2. 9x4 + 4x3 - 27x2 + 12x
A. x(9x3 + 4x2 + 27x + 12)
B. x(9x3 + 4x2 - 27x + 12)
C. x(9x4 + 4x3 – 27x2 + 12x)
D. x4(9x3 + 4x2 + 27x + 12)
E. x(9x4 + 4x3 - 27x2 + 12x)
F. This polynomial cannot be factored using the GCF method.
3. x2 – 3x + 4
A. x(x – 3)
B. x(x + 3)
C. x(x – 1)
D. x(x – 7)
E. x(x + 7)
F. This polynomial cannot be factored using the GCF method.
4. 17x5 + 51x2 – 34
A. 17x5 + 3x2 + 2
B. 17(x3 + 3x2 + 2)
C. 17(x4 + 3x2 + 2)
D. 17(x5 + 3x2 – 2)
E. x5 + 3x2 – 2
F. This polynomial cannot be factored using the GCF method.
Factor problems 5 - 8 by grouping.
5. x2 – 2x + 1
A. (x – 1)(x – 1)
B. (x – 1)(x + 1)
C. (x + 1)(x – 1)
D. (x + 1)(x + 1)
E. (x + 2)(x – 1)
F. This polynomial cannot be factored by grouping.
6. x2 + 2x – 15
A. (x - 5)(x – 3)
B. (x + 5)(x + 3)
C. (x + 5)(x – 3)
D. (x - 5)(x + 3)
E. (x + 15)(x – 1)
F. This polynomial cannot be factored by grouping.
7. x2 – 3x – 18
A. (x + 3)(x + 6)
B. (x + 3)(x - 6)
C. (x - 3)(x - 6)
D. (x - 3)(x + 6)
E. (-x + 3)(x + 6)
F. This polynomial cannot be factored by grouping.
8. 8x2 + 47x + 28
A. This polynomial cannot be factored by grouping.
B. (3x + 7)(5x - 4)
C. (3x - 7)(5x - 4)
D. (3x + 7)(-5x + 4)
E. (-3x + 7)(-5x + 4)
F. (3x + 7)(5x + 4)
The factor of the polynomial expression 4x^3 – 12x^2 + 4x by using GCF method is 4x(x^2 - 3x + 1).
What is a factor of a number?The factors of a given number are those numbers that are divisible by the given number without a remainder.
By using the GCF method in an algebraic, i.e. the factors of the algebraic equation will be dependent on the greatest common factor.
From the given information, we are to factorize the following expression by using the GCF method as follows.
1.
4x^3 – 12x^2 + 4x
Here; the common expression in all the three variables is 4x. So, we have:
= 4x(x^2 - 3x + 1)
Option A is correct
2.
9x^4 + 4x^3 - 27x^2 + 12x
The common expression here is (x); So,
= x(9x^3 +4x^2 - 27x + 12)
Option B is correct
3.
x^2 - 3x + 4
This polynomial expression cannot be factored.
Option F is correct.
4.
17x^5 + 51x^2 - 34
= 17(x^5 + 3x^2 - 2)
Option D is correct.
The factorization of a quadratic equation (polynomial expression) in the form (ax^2 + bx + c) by grouping results into two factors that if multiplied together result back into the original equation.
Given that:
5.
x^2 – 2x + 1
Factors are two numbers that if the multiplied result in (ac) and if added it gives us (b)
By grouping, the polynomial expression is:
= (x - 1)(x - 1)
Option A is correct
6.
x^2 + 2x - 15
= (x + 5) (x - 3)
Option C is correct
7.
x^2 – 3x – 18
=(x + 3)(x - 6)
Option B is correct
8.
8x^2 + 47x + 28
= This polynomial expression cannot be factored in as it contains rational numbers.
Option A is correct.
Learn more about factors of polynomial expressions here:
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