Please help :[ Hold a flat piece of paper horizontally. Lift it high in front of you, and drop it. Then crumple a piece of paper into a tight ball, hold it high in front of you, and drop it from the same height. Compare the motion of the two pieces of paper.

Based on geographical analysis, the earthquakes affect the rise and progress of the civilization in America and the Pacific islands by causing slope failures, liquefaction, and tsunami.

The effect of earthquakes in America and the Pacific Islands has caused people displacement as buildings collapsed, and water from nearby oceans caused the destruction of physical properties.

For safety reasons, when a natural disaster like an earthquake occurs in your place, you are expected to stay away from buildings if you're outside.

Similarly, if you are in a car, you should stop and pull over.

If you are in bed during the earthquake, wrap your head and neck with a pillow while turning your head upside.

Also, avoid doorways or windows if you are inside.

Considering the three types of waves, the most destructive wave is known as surface waves.

Surface waves have the most potent vibrations and can travel through any earth surface, whether air or water.

Other types of waves include Transverse waves and Longitudinal waves.

Hence, in this case, it is concluded that the effect of earthquakes is negative on human society, and waves can be destructive.

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Answer:

ill go with B

Explanation:

inertia is the ability of a body to remain at rest or in a constant speed in a constant direction when no force is acting on it

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Answer: 4.44302176697 m/s^2

Explanation:

formula for acceleration is (final velocity - initial velocity)/time.   So in your case:

(34.7m/s - 0m/s)/ 7.81s  = 4.44302176697 m/s^2

Answer:

Explanation:

The common observable evidence are:

The big bang is the theory which explains that how the universe began. It says that the universe began with just a single point. It went on expanding and stretched to grow as large as possible. It is still now expanding.

The big bang consist of fully dark matter, interstellar gases or dust. The big bang is increasing just because in universe there is abundant of hydrogen and helium.

The radiations come from the big bang. These rays are also called as cosmic wave. This big bang is still on it way of expanding more.

Thus, the observational evidence are the measured abundances of element, the expansion of space and the cosmic wave background.

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The linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

We find the linear speed of a point on the 32nd parallel from v = rω where r = radius of 32nd parallel north = Rcos32° (since it is the radius of the small circle at the 32nd parallel) where R = radius of earth = 6,371,000 m and ω = angular speed of the earth = 2π/T where T = period of earth = 24h = 24 × 60 × 60 s = 86400 s.

So, v = rω

v = Rcos32° × 2π/T

v = 2πRcos32°/T

substituting the values of the variables into the equation, we have

v = 2πRcos32°/T

v = 2π × 6,371,000 m × cos32°/86400 s.

v = 2π × 6,371,000 m × 0.8480/86400 s.

v = 33947512.5035 m/86400 s

v = 392.91 m/s

So, the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

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Answer:its 3 and 5

Explanation:

j

Answer:

C.) decreases, stronger

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases; however, as the two objects are closer to each other, the force of the gravitational attraction between them also increases (stronger).

Answer:

The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.

Answer:

the acceleration of the rocket is: a=vemΔmΔt−g a = v e m Δ m Δ t − g .

Explanation:

I answered this before.

hope this helps! :)

Answer:

112 [kJ]

Explanation:

1) related formula is: A=F*S, where A - required work [J], F - force [N], S - distance [m].

2) according to the formula above: A=140*800=112000[J]=112 [kJ]

Answer:

112000 J

Explanation:

800N x 140m

The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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Answer:

refers to the bending of light

the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.

Answer:

Wavelength and speed both depend on the material of the medium.

Explanation:

Let [tex]f[/tex] denote the frequency of a wave. Let [tex]v[/tex] denote the speed of that wave in a given medium. Let [tex]\lambda[/tex] denote the wavelength of that wave in this medium.

The frequency [tex]f[/tex] of a wave stays the same regardless of the material of the media. However, the speed [tex]v[/tex] of a wave indeed depends on the material of the medium (density of the medium, etc.)

[tex]\lambda = v / f[/tex] and [tex]f[/tex] stays the same regardless of the medium. Thus, the wavelength [tex]\lambda[/tex] of this wave in a given medium would be proportional to the speed [tex]v[/tex] in that medium.

For example, the speed of sound in materials with a larger density (e.g., water) is generally larger than that in materials with lower density (e.g., air.)

When a sound wave travels from air into water, the frequency [tex]f[/tex] of this wave would stay the same. However, since the speed [tex]v[/tex] of the wave would increase, the wavelength [tex]\lambda[/tex] of this wave would also increase.

Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.

Explanation:

Answer:

radiation

Explanation:

Answer:

B is most likely forgive me if im wrong

Explanation:

The car accelerates 60 mph in 6.3 seconds. Thus, the acceleration is [tex]\frac{60}{6.3}[/tex]. [tex]f=ma[/tex], so [tex]4106 = m(\frac{60}{6.3})[/tex], so [tex]m=431.13[/tex].

The velocity and acceleration of the particle moving round the circle is;

Velocity = 162.12 m/s

Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²

We are given;

Radius of circle; 382400 km = 382400000 m

Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s

Now, formula for velocity is;

Velocity = distance/time

Thus;

I) velocity = 382400000/2358720

Velocity = 162.12 m/s

II) Acceleration is centripetal acceleration and is given by the formula;

a = v²/r

a = 162.12²/382400000

a = 6.873 × 10^(-5) m/s²

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Answer:

d/t = (230 km)/(3.25 h) = 70.8 km/h.

Explanation:

Answer:

15N

Explanation:

mass=w/g 150N/m×0.1m

Ans=15N

Answer:

Both springs have a constant of 25Nm and the block is motionless. If the bottom spring is compressed 0.4m past its equilibrium and the block has a mass of 3kg, how far is the top spring stretched past its equilibrium?

g=10ms2

Possible Answers:

1.0m

0.8m

0.2m

0.4m

0.6m

Correct answer:

0.8m

Explanation:

Since the block is motionless, we know that our forces will cancel out:

Fnet=0

There are three forces in play: one from each spring, as well as the force of gravity. If we assume that forces pointing up are positive, we can write:

Fspring,top+Fspring,bot−mg=0

Plugging in expressions for each spring force, we get:

kxtop+kxbot−mg=0

Rearring for the displacement of the top spring, we get:

xtop=mg−kxbotk=(3kg)(10ms2)−(25Nm)(0.4m)25Nm

xtop=30N−10N25Nm=0.8m

Answer:

It is unique among planets in our solar system for having water in its liquid form at the surface, in an amount conducive to life evolving. ... No one knows why Earth has the exact amount of water it does, which is relatively small considering that water molecules outnumber silicate molecules in the galaxy, he said. so no one actually found out who actually put water on the earth and why

Explanation:

Answer:

It is the only planet in our solar system that has water in its liquid state at the surface in sufficient quantities to support the evolution of life. Despite the fact that water molecules outnumber silicate molecules in the galaxy, no one understands why Earth has the precise quantity of water it has, which is a minuscule amount when compared to the rest of the galaxy.

Explanation:

Hope it helps:)

Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.

As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.

The higher energy orbital are always larger than the orbitals closer to the nucleus.

Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

Explanation:

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

The impulse experienced by the ball is calculated as follows;

[tex]Ft = \Delta P[/tex]

where;

[tex]Ft[/tex] is impulse

[tex]\Delta P[/tex] is change in momentum

The time of motion of the ball is calculated as follows;

[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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A.l and lll

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Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

The work needed to stop an 1100 kilograms car moving with a velocity of  59.0 km/hr would be  147.72 kilojoules.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour

the mass of the car = 1100 kilograms

the velocity of the car = 59 kilometers/hour

KE = 0.5mv²

     =0.5×1100×(59×1000/3600)²

     = 147.72 kilojoules

Thus, the work needed to stop an 1100 kilograms car would be  147.72 kilojoules

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Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.

When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.

Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.

Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.

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