Answer: C
asdfasdasdasdfasdf
The appropriate method for the biologist to use for inference to the population is A) A one-sample t-interval for a population mean.
What occurs in one-sample t-interval?In this situation, the biologist wants to estimate the average weight of a population of dolphins living in a certain region of the ocean. The biologist will collect a random sample of dolphins and use the sample weights to create the estimate.
here, we have,
Therefore, the appropriate method for inference to the population is to use a one-sample t-interval for a population mean.
This method is used when we want to estimate the population mean using a sample mean and the standard deviation of the sample.
The t-interval takes into account the uncertainty of the estimate due to the random sampling process, which makes it an appropriate method for this situation.
Hence, The appropriate method for the biologist to use for inference to the population is A) A one-sample t-interval for a population mean.
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The correct question is:
A marine biologist wants to estimate the average weight of a population of dolphins living in a certain region of the ocean. The biologist will collect a random sample of dolphins and use the sample weights to create the estimate Which of the following is an appropriate method for the biologist to use for inference to the population?
A A one-sample t-interval for a population mean
B A one-sample t-interval for a sample mean
C A one-sample 2-interval for a population proportion
D A matched-pairs t-interval for a mean difference
E A two-sample t-interval for a difference between means
5) A medium radio wave band lies btw two wavelength 100 m and 1000m. Determine the corresponding frequency range (take the velocity of the wave to be 299.8X10^6m/s)
Answer: The frequency (f) of a wave is related to its wavelength (λ) and velocity (v) by the equation:
f = v/λ
Given the wavelength range of 100 m to 1000 m for the medium radio wave band, we can calculate the frequency range as follows:
For the lower wavelength of 100 m:
f = v/λ = 299.8 × 10^6 m/s / 100 m = 2.998 × 10^6 Hz
For the higher wavelength of 1000 m:
f = v/λ = 299.8 × 10^6 m/s / 1000 m = 299.8 × 10^3 Hz
Therefore, the frequency range for the medium radio wave band is approximately 2.998 × 10^6 Hz to 299.8 × 10^3 Hz.
Step-by-step explanation:
Quadrilateral ABCD has vertices A(-3,4), B(2,5), C(3,3), and D(-1,0).
AD is _____ to BC, and AB is _____ to DC. so the quadrilateral ABCD ______ a trapezoid. trapezoid ABCD _____ isosceles because AB ____ congruent to DC
The trapezoid ABCD not isosceles because AB is not congruent to DC.
What is a trapezoid?It is a polygon that has four sides. The sum of the internal angle is 360 degrees. In a trapezoid, one pair of opposite sides are parallel.
Quadrilateral ABCD has vertices A(-3,4), B(2,5), C(3,3), and D(-1,0).
The diagram is given below.
From the diagram, the line segment AD and BC are parallel to each other.
The length AB is given as,
AB² = (2 + 3)² + (4 - 5)²
AB = 5.1 units
The length CD is given as,
CD² = (3 + 1)² + (3 - 0)²
CD= 5 units
The trapezoid ABCD not isosceles because AB is not congruent to DC.
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for the phrase “x times the quantity 5 plus y,” what part goes in parentheses?
1. x(5)
2. y
3. x
4 5+y
5. 5
The part of the expression x(5 + y) that goes to the parentheses is 5 + y.
The correct option is 4.
What is an expression?One mathematical expression makes up a term. It might be a single variable (a letter), a single number (positive or negative), or a number of variables multiplied but never added or subtracted. Variables in certain words have a number in front of them. A coefficient is a number used before a phrase.
Given:
A phrase: “x times the quantity 5 plus y.”
5 plus y 5 + y
x times the quantity 5 plus y = x(5 + y)
The complete expression is,
x(5 + y).
Therefore, 5 + y is the required expression.
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set up, but do not evaluate, an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x , y = 0, x = 4; about x = 8
The integral for the volume of the solid is obtained by rotating the region bounded by the given curves about the specified axis is V = 2[tex]\int\limits^ π/3_[/tex][tex]_{0}[/tex] [tex]{x} tan(x) - x^{2} dx[/tex]
When we rotate a thin vertical strip, about the y-axis.
We get a cylindrical shell with an inner of radius an x and an outer of radius x + dx
The height of the cylinder shell is tan (x) - x
The volume of the cylindrical shell is
dV = π [tex](Outer Radius)^{2} (Height)[/tex] - π[tex](Inner Radius)^{2} (Height)[/tex]
dV = π [tex](x + dx )^{2} (tan(x) - x)[/tex] - π [tex](x )^{2} (tan(x) - x)[/tex]
dV = π[tex](x^{2} + 2 xdx + (dx)^{2} ) (tan(x) - x)[/tex] - π [tex](x)^{2} (tan(x) - x)[/tex]
assume [tex]dx^{2}[/tex]≈ 0
dV = π[tex](x^{2} + 2xdx + 0 - x^{2} ) (tan(x) - x)\\[/tex]
dV = 2πx (tan(x) - x) dx
V = 2[tex]\int\limits^ π/3_[/tex][tex]_{0}[/tex] [tex]{x} tan(x) - x^{2} dx[/tex]
Therefore, the integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis is
V = 2[tex]\int\limits^ π/3_[/tex][tex]_{0}[/tex] [tex]{x} tan(x) - x^{2} dx[/tex] .
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The correct question is:
Set up, but do not evaluate, an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=tanx,y=x,x=π/3; about the y-axis
A company must decide which of two delivery services they will contract with. During a
recent trial period they shipped numerous packages with each service, keeping track of how
often the deliveries did not arrive on time. Here are the data:
Delivery Service Type of Service Number of Deliveries Number of Late Packages
Pack Rats Regular 400 12
overnight 100 16
Boxes R Us Regular 100 2
Overnight 400 28
a) Compare the two service's overall (total) percentage of late deliveries. [5.6% for Pack
Rats; 6% for Boxes R Us]
b) Based on the results in part (a), the company has decided to hire Pack Rats. Do you
agree that they deliver on time more often? Why or why not? Be specific.
a) To compare the overall percentage of late deliveries for each delivery service, we need to calculate the total number of late packages and total number of deliveries for each service, and then divide the number of late packages by the total number of deliveries, and multiply by 100 to get the percentage.
For Pack Rats, the total number of deliveries is 400 + 100 = 500, and the total number of late packages is 12 + 16 = 28. Therefore, the percentage of late deliveries for Pack Rats is:
percentage of late deliveries for Pack Rats = (28/500) x 100 = 5.6%
percentage of late deliveries for Boxes R Us = (30/500) x 100 = 6%
Therefore, based on these calculations, Pack Rats has a lower overall percentage of late deliveries compared to Boxes R Us.
b) While Pack Rats has a lower overall percentage of late deliveries compared to Boxes R Us, it's important to note that this decision should not be based solely on this one comparison. It's possible that there are other factors that the company needs to consider, such as the cost of each delivery service or the quality of customer service provided by each company.
Furthermore, the sample size in this trial period may not be large enough to draw a definitive conclusion about the reliability of each service. Therefore, while Pack Rats may be a good choice based on the available data, the company should consider other factors and conduct further research before making a final decision.
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In a certain city, E Street, W Street, C Street, and D
Street are parallel streets that intersect K Street and
M Street. How long is K Street between C Street
and D Street?
600 ft
800 ft
540 ft
E St
W St
M St
C St
D St
1400 ft
K St
The length which lies from K Street between C Street and D Street is 337.5 ft.
Given that,
E Street, W Street, C Street, and D Street are parallel streets that cross K Street and M Street in a particular city. It is unknown how far K Street is from C Street and D Street.
Let the distance of street K between C and D be x,
Now,
Taking the equality of the proportionality expression of triangles,
600 / 400 = 600 + x / 400 + 250
6 / 4 = 600 + x / 625
3750/4 = 600 + x
937.5 = 600 + x
x = 337.5 ft
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-3(-3c+7)5(4+2c I need hekppppp
Answer:
90c^2 -30c - 420
Step-by-step explanation:
-3(-3c+7)5(4+2c)
(9c - 21) (20 + 10c)
180c + 90c^2 - 420 - 210c
90c^2 -30c - 420
Circle the two sets of lengths that DO NOT form a triangle.
A. 3 m, 5m, 7.3m
B. 12 yd, 25 yd, 13 yd
C. 5 ft, 9 ft, 16 ft
The two sets of lengths that do not form a triangle are the options B and C.
Which sets of lengths do not form a triangle?For a triangle with side lengths x, y, and z we know the triangular inequality, it says that the sum of any two sides must be larger than the other side, so we can write 3 inequalites:
x + y > z
x + z > y
z + y > x
So if for one of the given sets, one of these inequalities is false, then the set does not form a triangle.
For the second set:
12 yd, 25 yd, 13 yd
The inequality:
12 yd + 13yd > 25yd
25 yd> 25 yd
is false, so that set does not form a triangle.
And the last set:
5 ft, 9 ft, 16 ft
The inequality:
5ft + 9ft > 16ft
14ft > 16 ft
Is also false,
So B and C are the correct options.
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Shelly spent 45 minutes jogging and 30 minutes cycling and burned 1350 calories. The next day, Shelly swapped times, doing 30 minutes of jogging and 45 minutes of cycling and burned the same number of calories. How many calories were burned for each minute of jogging and how many for each minute of cycling?
Number of calories burned per minute =
The number of calories burned per minute be 23.33333.
What is meant by system of equations?Equations simultaneously, or a system of equations Several equations in algebra must be solved concurrently (i.e., the solution must satisfy all the equations in the system). There must be an equal number of equations and unknowns for a system to have a singular solution.
In order to locate the point where the lines intersect when the equations are graphed, systems of equations must be solved. The (x,y) ordered pair of this intersection point is regarded as the system's solution.
Let j be the number of calories burned by Shelly while running and c be the number of calories she burns while cycling.
The system of equations be
45j + 30c = 1350
30j + 45c = 1350
45j + 30(10)=1350
j = 23.33333
Therefore, the value j be 23.33333.
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a spam filer is designed by screening commonly occuring phrases in spam suppose that 60 of email is spam in 20 o the spam emails the phprase fee gift card is used
The probability that a newly arrived email which does mention "free gift card", is not spam is 0.0165.
Let S be the event that an email is spam, and let F be the event that an email mentions "free gift card". We want to find P(S' | F), the probability that the email is not spam given that it mentions "free gift card".
We can use Bayes' theorem to find P(S' | F):
P(S' | F) = P(F | S') P(S') / P(F)
We can calculate each of these probabilities as follows:
P(F | S') = the probability that a non-spam email mentions "free gift card". From the problem, we know that this probability is 0.005 (i.e., 99.5% of non-spam emails do not mention "free gift card").
P(S') = the probability that an email is not spam. From the problem, we know that this probability is 0.4 (i.e., 60% of emails are spam, so 40% are not spam).
P(F) = the probability that an email mentions "free gift card". This can be calculated using the law of total probability:
P(F) = P(F | S) P(S) + P(F | S') P(S')
= 0.20 × 0.60 + 0.005 × 0.40
= 0.121
In the first term, we use the given probability that 20% of spam emails mention "free gift card". In the second term, we use the probability that 0.5% of non-spam emails mention "free gift card".
Plugging these values into Bayes' theorem, we get:
P(S' | F) = 0.005 × 0.4 / 0.121 ≈ 0.0165
Therefore, the probability that a newly arrived email which does mention "free gift card" is not spam is approximately 0.0165 or 1.65%.
Correct Question :
A spam filer is designed by screening commonly occurring phrases in spam. Suppose that 60% of email is spam. In 20% of the spam emails, the phrase “free gift card” is used. In non-spam emails, 99.5% of them do not mention “free gift card”. What is the probability that a newly arrived email which does mention “free gift card”, is not spam?
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Select the correct answer. Consider triangle EFG. a right triangle EFG with base EG of 10, opposite EF of 8, and hypotenuse FG of 12. What is the approximate measure of angle G? A. 41,4 degree
b. 55,8 degree
c. 82,8 degree
d. 94,8 degree
The approximate measure of angle G.The correct answer is a. 41.4 degrees.
The measure of angle G in triangle EFG can be calculated using the Pythagorean Theorem. The Pythagorean Theorem states that the sum of the squares of the two legs of a right triangle is equal to the square of the hypotenuse. In right triangle EFG, the two legs are EF and EG and the hypotenuse is FG. This can be expressed mathematically as [tex]8^2 + 10^2 = 12^2.[/tex] Simplifying the expression, the equation becomes 64 + 100 = 144. Solving this equation yields 64 = 144, which is true. To calculate the measure of angle G, we will use the inverse tangent function, which is written as [tex]tan^-1[/tex]. In this function, the inverse tangent of the ratio of the opposite side to the adjacent side is equal to the angle. This can be expressed mathematically as [tex]tan^-1 (8/10)[/tex] = G. Using a calculator, the inverse tangent of 8/10 is approximately 41.4 degrees. Therefore, the correct answer is a. 41.4 degrees.
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Solve the formula for t V = 6pirt + 4pir2
Answer: Given the formula:
V = 6pirt + 4pir^2
To solve for t, we'll isolate t by rearranging the equation.
First, subtract 4pir^2 from both sides:
V - 4pir^2 = 6pirt
Next, divide both sides by 6pi:
(V - 4pir^2)/6pi = t
So, t = (V - 4pir^2)/6pi.
This gives us the value of t in terms of V and the radius of the cylinder, r.
Step-by-step explanation:
17 Answer:
Decide how many solutions this equation has:
x2 - 2x + 1 = 0
18 Answer:
Decide how many solutions this equation has:
x2 + 3 = 0
19 Answer:
The revenue from selling x units of a product is given by
y = -0.0002x2 + 20x. How many units must be sold in
order to have the greatest revenue? (Find the x-coordinate
of the vertex of the parabola.)
Given: Parallelogram LMNO; MO ⊥ LN
Prove: LMNO is a rhombus.
Parallelogram L M N O is shown. Diagonals are drawn from point L to point N and from point M to point O and intersect at point P. A square is drawn around point P. Sides L M and O N are parallel and sides L O and M N are parallel.
The proof of LMNO is a rhombus is shown below.
What is Rhombus?A parallelogram is a particular instance of a rhombus. The opposing sides and angles in a rhombus are parallel and equal. A rhombus also has equal-length sides on each side, and its diagonals meet at right angles to form its shape. The rhombus is also referred to as a diamond or rhombus.
Given:
|LO|=|MN| and |LM|=|ON|
Since Opposite sides of a parallelogram are equal.
Now, LN⊥OM
So, ∠LPO = ∠NPO = 90° ( by definition of perpendicular lines)
LPO ≅ ∠NPO (by definition of congruent angles)
|LP|=|PN| (diagonals of a parallelogram bisect each other)
Thus, LMNO is a rhombus
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Answer:
♣: ✔ All right angles are congruent.
♦: ✔ reflexive property
♠: ✔ Opposite sides of a parallelogram are congruent.
7x - 31 + 4y + 27 + 5x - 8 + 63
The solution is, 7x - 31 + 4y + 27 + 5x - 8 + 63 = 12x+4y+51.
What is simplification?Simplify simply means to make it simple. In mathematics, simply or simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.
here, we have,
now, we have to solve the given expression, using addition,
given that,
7x - 31 + 4y + 27 + 5x - 8 + 63
=12x+4y+51
here, we add the terms with x with each other, then add the terms with y, and, add the numbers & subtract them from given terms with minus sign.
Hence, The solution is, 7x - 31 + 4y + 27 + 5x - 8 + 63 = 12x+4y+51.
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If
f(x) = x + 2, what is ƒ(4)?
Answer:6
Step-by-step explanation:
ƒ(4)=4+2=6
 On Monday, Jack bought 2 burgers and 3 fries for $11.25. On Tuesday, he bought 7 burgers and 5 fries
for $32.50. Find the price of each item.
The price of burger is $3.75 and the fries cost $1.25
How to calculate the price of the burger and the fries?
On Monday, Jack bought 2 burgers and 3 fries for $11.25
On Tuesday he bought 7 burgers and 5 fries for $32.50
Let a represent the cost of the burger
Let b represent the cost of the fries
2a + 3b= 11.25..........equation 1
7a + 5b= 32.50..........equation 2
Solve by elimination method
Multiply equation 1 by 7 and multiply equation 2 by 2
14a + 21b= 78.75
14a + 10b= 65
11b= 13.75
b= 13.75/11
b = 1.25
Substitute 1.25 for b in equation 2
7a + 5(1.25)= 32.50
7a + 6.25= 32.50
7a= 32.50-6.25
7a= 26.25
a= 26.25/7
a= 3.75
Hence the price of burger is $3.75 and the price of fries is $1.25
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let be the solution to satisfying . (a) use euler's method with time step to approximate . -3 5.03421 5.03942 5.04269 5.04269 0.2(8e^(-5.04269)) (b) use separation of variables to find exactly.
Answer:
Step-by-step explanation:
c
A ring shaped region inner diameter is 14 cm and its outer diameter is 22 find the area shaded region
The region of the concealed district will be 226.08 square centimeters.
What is the area of the circle?It is the nearby bend of an equidistant point drawn from the middle. The sweep of a circle is the distance between the middle and the boundary.
Let d be the diameter of the circle. Then the area of the circle will be written as,
A = (π/4)d² square units
A ring-formed district's internal measurement is 14 cm and its external breadth is 22 cm. Then the region of the concealed district is given as,
A = (π / 4) (22² - 14²)
A = (3.14 / 4) (484 - 196)
A = 0.785 x 288
A = 226.08 square cm
The region of the concealed district will be 226.08 square centimeters.
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What is the probability of getting 3 heads in 4 coin tosses, given you get at least 2 heads?
The probability of getting 3 heads in 4 coin tosses, given that we get at least 2 heads, is 4/11 or 0.364.
To solve this problem, we can use the conditional probability formula. Let A be the event of getting 3 heads in 4 coin tosses, and let B be the event of getting at least 2 heads in 4 coin tosses. Then we want to find P(A|B), the probability of getting 3 heads in 4 coin tosses given that we get at least 2 heads.
By the definition of conditional probability, we have:
P(A|B) = P(A and B) / P(B)
To find P(B), the probability of getting at least 2 heads in 4 coin tosses, we can use the complement rule and find the probability of getting 0 or 1 heads:
P(B) = 1 - P(0 heads) - P(1 head)
To find P(0 heads), the probability of getting 0 heads in 4 coin tosses, we use the binomial probability formula:
P(0 heads) = (4 choose 0) * (0.5)^0 * (1-0.5)^(4-0) = 1/16
Similarly, we can find P(1 head):
P(1 head) = (4 choose 1) * (0.5)^1 * (1-0.5)^(4-1) = 4/16
So,
P(B) = 1 - P(0 heads) - P(1 head) = 11/16
To find P(A and B), the probability of getting 3 heads in 4 coin tosses and getting at least 2 heads, we can use the binomial probability formula again:
P(A and B) = (4 choose 3) * (0.5)^3 * (1-0.5)^(4-3) = 4/16
Therefore,
P(A|B) = P(A and B) / P(B) = (4/16) / (11/16) = 4/11
So the probability of getting 3 heads in 4 coin tosses, given that we get at least 2 heads, is 4/11 or approximately 0.364.
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Consider the following program statement consisting of a while loop
while ¬B do S
Assume that the Boolean expression B takes the value true with probability p and the value false with probability q. Assume that the successive test on B are independent.
1. Find the probability that the loop will be executed k times.
2. Find the expected number of times the loop will be executed.
3. Considering the same above assumptions, suppose the loop is now changed to "repeat S until B". What is the expected number of times that the repeat loop will be executed?
The probability is P(k) = (q^(k-1)) * p for k>=1, and P(0) = q. The expected number of times the loop will be executed is 1/p.The expected number of times that the repeat loop will be executed is 1/p.
To find the probability that the loop will be executed k times, we can consider the probability of the event that B is false k-1 times followed by B being true. This probability is q^(k-1) * p.
The event of the loop not being executed at all corresponds to B being true in the first trial, which has a probability of q. Therefore, the probability that the loop will be executed k times is P(k) = (q^(k-1)) * p for k>=1, and P(0) = q.
The expected number of times the loop will be executed is the sum of the probabilities of executing the loop k times, weighted by k, i.e., E = Sum(kP(k)) for k>=1, and E = 0 if P(0) = q.
By using the expression for P(k), we can simplify this to E = Sum(kq^(k-1)*p) for k>=1, and E = 0 if P(0) = q. By applying the formula for the sum of a geometric series, we get E = 1/p.
For the "repeat S until B" loop, the expected number of times that the loop will be executed is the expected number of trials in a Bernoulli process until the first success, where the success probability is p. By using the formula for the expected value of a geometric distribution, we get E = 1/p.
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7. suppose a student carrying a flu virus returns to an isolated college campus of 1000 students. determine a differential equation for the number of people x(t) who have contracted the flu if the rate at which the disease spreads is proportional to the number of interactions between the number of students who have the flu and the number of students who have not yet been exposed to it. (Use k > 0 for the constant of proportionality and x for x(t).)
Answer: If the rate at which the flu spreads is proportional to the number of interactions between students who have the flu and students who have not been exposed to it, we can write:
dx/dt = kx(1000 - x)
where x is the number of students who have contracted the flu, k is the constant of proportionality, and t is time. The term x(1000 - x) represents the number of interactions between the students who have the flu and the students who have not been exposed to it. The factor of 1000 - x represents the number of students who have not yet been exposed to the flu.
Thus, the differential equation models the spread of the flu on the isolated college campus as the number of people who have contracted the flu changes over time due to the number of interactions between the students who have the flu and the students who have not been exposed to it.
Step-by-step explanation:
Question
A tower made of wooden blocks measures114 feet high. Then a block is added that increases the height of the tower by 8 inches.
What is the final height of the block tower?
Answer:
The final height of the tower is 114 feet 8 inches.
To solve this problem, we need to convert the additional 8 inches into feet. 8 inches is equal to 0.67 feet, so the new height of the tower is equal to 114 feet + 0.67 feet which is equal to 114 feet 8 inches.
I'm not dead lol
I'm still here
Answer:
29
Step-by-step explanation:
trust
Answer: okay good!!!!!!
What number has 6 ten thousands, 2 fewer thousands than ten thousands, the same number of hundreds as ten thousands, 1 fewer ten than ten thousands and 5 more ones than thousands?
Therefore, the number that satisfies all the given conditions is 60,649.
What is equation?In mathematics, an equation is a statement that asserts the equality of two expressions, typically separated by an equals sign ("="). The expressions on either side of the equals sign are called the left-hand side and the right-hand side of the equation, respectively. The purpose of an equation is to describe a relationship between two or more variables or quantities, such as x + 3 = 7 or y = 2x - 5. Equations can be used to solve problems and answer questions in various fields of study, such as algebra, geometry, physics, chemistry, and engineering. Solving an equation typically involves finding the value or values of the variable(s) that make the equation true. Some equations may have a unique solution, while others may have multiple solutions or no solutions at all. The study of equations and their properties is a fundamental topic in mathematics.
Here,
Let's break down the clues given in the problem and use them to find the unknown number:
6 ten thousands: The number must start with 6.
2 fewer thousands than ten thousands: The number of thousands is 2 less than the number of ten thousands. Since there are 6 ten thousands, there are 4 thousands.
Same number of hundreds as ten thousands: The number of hundreds is the same as the number of ten thousands, which is 6.
1 fewer ten than ten thousands: The number of tens is 1 less than the number of ten thousands, which is 6-1=5.
5 more ones than thousands: The number of ones is 5 more than the number of thousands, which is 4+5=9.
Putting all of these clues together, we get the number: 60,649
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The probability distribution for the number of students in statistics classes at IRSC is given, but one value is
missing. Fill in the missing value, then answer the questions that follow. Round solutions to three decimal
places, if necessary.
The missing value is given as follows:
P(X = 28) = 0.31.
The mean and the standard deviation are given as follows:
Mean [tex]\mu = 27.17[/tex]Standard deviation [tex]\sigma = 1.289[/tex]How to obtain the measures?The sum of the probabilities of all the outcomes is of one, hence the missing value is obtained as follows:
0.14 + 0.18 + 0.21 + P(X = 28) + 0.16 = 1
0.69 + P(X = 28) = 1
P(X = 28) = 0.31.
The mean is given by the sum of all outcomes multiplied by their respective probabilities, hence:
E(X) = 25 x 0.14 + 26 x 0.18 + 27 x 0.21 + 28 x 0.31 + 29 x 0.16
E(X) = 27.17.
The standard deviation is given by the square root of the sum of the difference squared between each observation and the mean, multiplied by their respective probabilities, hence:
S(X) = sqrt((25-27.17)² x 0.14 + (26-27.17)² x 0.18 + (27-27.17)² x 0.21 + (28-27.17)² x 0.31 + (29-27.17)² x 0.16)
S(X) = 1.289.
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Using relational algebraa. list the flights that cost more than 800 - report their ID, airport code, destination code, and fareb. Report the airports city, code, and departure time for thr airports that have departing flights in the morningc. List the names and hometown of the passengers that do not have an airport in their hometownd. What airlines fly from Toronto, report the airline namee. what aurlines do not fly from toronto, report the airline namef. what airlines fly from toronto to vancouver? report the airline nameg. list the passangers flying to vancouver, report their name, origin, and destination airport codes, and arrival time
Using relational algebra:
a. flight ⋈ airport ⋈ ρ destination airport
b. flight ⋈ airport
c. passenger ⋈ airport
d. airline ⋈ airport ⋈ flight
e. airline ⋈ airport ⋈ flight
f. airline ⋈ airport ⋈ flight ⋈ ρ destination airport
g. flight ⋈ passenger ⋈ booking
QUESTION (a):
- using EQUI join (⋈) join relations "Flight, Airport and Airport as destination"
- and using select Operation (σ), relational operators (=, >) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "Flight.fID, Airport.code, destination.code, Flight.fare" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ flight . fid, airport . code, destination . code , flight.fare σ flight . airport = airport . code
AND flight . destination = destination . code (flight ⋈ airport ⋈ ρ destination airport)
QUESTION (b):
- using EQUI join (⋈) join relations "Flight, Airport"
- and using select Operation (σ), relational operators (=, >=, <=) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "airport . city, airport . code, flight . departure" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ airport . city, airport . code, flight . departure σ flight . airport = airport . code
AND (4 <= flight . departure AND flight . departure <= 10) (flight ⋈ airport)
QUESTION (c):
- using EQUI join (⋈) join relations "passenger, Airport"
- and using select Operation (σ), relational operators (<>) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "passenger . name, passenger . hometown" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ passenger . name, passenger . hometown σ passenger . hometown <> airport . city (passenger ⋈ airport)
QUESTION (d):
- using EQUI join (⋈) join relations "airline, airport, flight"
- and using select Operation (σ), relational operators (=) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "airline . name" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ airline . name σ airline . aid = flight . airline
AND flight . airport = airport . code
AND airport . city = "Toronto" (airline ⋈ airport ⋈ flight)
QUESTION (e):
- using EQUI join (⋈) join relations "airline, airport, flight"
- and using select Operation (σ), relational operators (<>, =) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "airline . name" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ airline . name σ airline . aid = flight . airline
AND flight . airport = airport . code
AND airport . city <> "Toronto" (airline ⋈ airport ⋈ flight)
QUESTION (f):
- using EQUI join (⋈) join relations "airline, airport, flight and airport as destination"
- and using select Operation (σ), relational operators (<>, =) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "airline . name" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ airline . name σ airline . aid = flight . airline
AND flight . airport = airport . code
AND flight . destination = destination . code
AND airport . city = "Toronto"
AND destination . city = "vancouver" (airline ⋈ airport ⋈ flight ⋈ ρ destination airport)
QUESTION (g):
- using EQUI join (⋈) join relations "flight, passenger, Booking"
- and using select Operation (σ), relational operators (=) and connector (and) select tuples from the joined relations
- Then using Project Operation (∏) projects columns "passenger . name, airport, destination" from the relation
- Below shows the SQL query, relation algebra query and relation algebra tree
RELATIONAL ALGEBRAπ passenger . name, airport, destination σ passenger . pid = booking . pid
AND booking . fid = flight . fid
AND destination . city = "vancouver" (flight ⋈ passenger ⋈ booking)
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Question correction:
See on the attached image.
If a coin is flipped 35 times and lands on heads 14 times, what is the relative
frequency of landing on heads?
OA. 0.35
OB. 0.14
OC. 0.5
OD. 0.4
The relative frequency of landing on heads is 0.4, then the correct option is D.
What is the relative frequency of landing on heads?When we have an experiment with some outcomes, and we perform the experiment N times, and in K of these N times we get a particular outcome, then the relative frequency for that outcome is K/N
In this case the coin is flipped 35 times and it lands on heasd 14 times, then the relative frequency of landing on heads is:
R = 14/35 = 0.4
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The speed of a molecule in a uniform gas at equilibrium is a random variable V whose pdf is given by f(v)={kv2e−bv2,v>00, else where,where k is an appropriate constant and b depends on the absolute temperature and mass of the molecule, m, but we will consider b to be known.(a) Calculate k so that f(v) forms a proper pdf.(b) Find the pdf of the kinetic energy of the molecule W, where W=mV2/2.
three different methods for assembling a product were proposed by an industrial engineer. to investigate the number of units assembled correctly with each method, employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by workers. the number of units assembled correctly was recorded, and the analysis of variance p
Since the p-value is less than .05, we reject the null hypothesis that the means of the three assembly methods are equal.
Therefore, we can conclude that there is a significant difference in the means of the three assembly methods.
Source Variation | Squares' Sum | Degrees of Freedom | Mean Square | F
Treatments 4560 2 2280 9.87
Error 6240 27 231.11
Total 10800 29
Using Alpha = .05 to test for any significant difference in the means for the three assembly methods.
The value of the test statistic is 9.87
The p-value is: less than .01
Conclusion not all means of the three assembly methods are equal.
Complete Question:
Three different methods for assembling a product were proposed by an industrial engineer. To investigate the number of units assembled correctly with each method, 30 employees were randomly selected and randomly assigned to the three proposed methods in such a way that each method was used by 10 workers. The number of units assembled correctly was recorded, and the analysis of variance procedure was applied to the resulting data set. The following results were obtained: SST = 10,800; SSTR = 4560.
Set up the ANOVA table for this problem (to 2 decimals, if necessary).