The specific Eastern Hero that I have selected and researched is given below
Who is the Eastern Hero?My selected Eastern Hero is the Chinese legendary figure, Sun Wukong, also known as the Monkey King. Sun Wukong is a central character in the classic Chinese novel, "Journey to the West." This novel was written by Wu Cheng'en during the Ming Dynasty and is considered one of the four great classical novels of Chinese literature.
The story of Sun Wukong revolves around his journey to the West to retrieve Buddhist scriptures. The novel follows Sun Wukong as he encounters various obstacles and battles demons along the way. Despite his mischievous and selfish nature, Sun Wukong is a powerful and skilled warrior who uses his wit and strength to protect his companions on their journey.
Therefore, I can relate to Sun Wukong as a hero because he represents the idea that even the flawed and imperfect can become great and compassionate. Like Sun Wukong, I believe that everyone has the potential to grow and improve, and that it is never too late to change. I also relate to Sun Wukong's mischievous and playful nature, as I too can be playful and enjoy causing mischief in my own way.
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A cylindrical container is filled with oil to a depth of 32cm. If the pressure exerted at the base is 2560pa , how much is the density of the oil?
The required density of the oil when pressure at the base and depth of the container are given is calculated to be 815.5 kg/m³.
We know the expression for pressure as, P = ρ g h
where,
ρ is density
g is acceleration due to gravity
h is height
Here, h is nothing but the depth of the cylindrical container.
h = 32 cm = 0.32 m
Pressure exerted is given as 2560 pa. P = 2560 pa
To find out density, make ρ as subject in the above equation.
ρ = P/(g h) = 2560/(9.8 × 0.32) = 815.5 kg/m³
Thus, the required density of the oil is calculated to be 815.5 kg/m³.
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A rock is dropped from a height of 2.7 m. How fast is it going when it hits the ground?
This is the Answer: 7.3 m/s.
Explanation:
You can use the equation from the conservation of mechanical energy, potential energy to kinetic energy.
1/2 [tex]mv^{2}[/tex] = mgh ……… factoring out the mass m and multiplying both sides by 2
[tex]v^{2}[/tex] = 2gh …. v is its velocity, g = 9.8 [tex]m/s^{2}[/tex] and h = 2.7 m
[tex]v^{2}[/tex] = 2 * 9.8 [tex]m/s^{2}[/tex] * 2.7 m ….. the unit becomes [tex]m^{2}[/tex]/[tex]s^{2}[/tex]
[tex]v^{2}[/tex] = 52.92 [tex]m^{2}/s^{2}[/tex]
v = √(52.92) m/s
v = 7.3 m/s
When the rock hits the ground its velocity is 7.3 m/s.
WHAT DOES MGH MEAN? MEANING DOWN BELOW!!
“m” is the symbol for mass. This would be measures in kilograms (kg) in SI Units.
“g” is the symbol for the acceleration due to gravity. This value is the only one of these three symbols that is a constant. This constant will change depending on what planet, where you are in the universe, and how far from the surface of the planet you are. For Earth, the value used for SI is 9.81 m/s^2, and this is accurate within 15 kilometers of the Earth’s surface.
“h” is the symbol for the vertical height or position. What is interesting here is this value actually can change because in physics, we can design whatever parameters we want to. So, if I wanted to know the height of a ball that is over a table, you must ask what are we calling the point of vertical height equal to zero. Because this value can be either defined from ball to table surface or ball to ground below the table. This value is measured in meters (m) under SI.
Together the product of m, g, and h gives us what is called the gravitational potential energy. This is the amount of an energy that a certain object possesses because the force of gravity will pull it towards the ground in order to achieve a lower mechanical energy.
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if astronauts land on the side of the moon facing the earth exactly at new moon, the side of the earth facing them would appear to be: group of answer choices half sunlit and half dark. in darkness. any fraction of the earth could appear sunlit depending on the direction from the earth to the sun. fully sunlit.
If astronauts land on the side of the moon facing the earth exactly at new moon, the side of the earth facing them would appear to be in darkness, without any visible sunlit areas.
If astronauts land on the side of the moon facing the earth exactly at new moon, the side of the earth facing them would appear to be in darkness.
At new moon, the moon is positioned directly between the sun and the earth, which means that the side of the earth facing the moon is not receiving any direct sunlight. The entire side of the earth visible to the astronauts would be in shadow, with no visible sunlit areas.
It's worth noting that while the side of the earth facing the moon would be in darkness, it would still be lit by indirect sunlight that has been scattered by the atmosphere. This scattered light would provide some illumination to the earth, but not enough to make any specific areas of the earth appear sunlit.
Additionally, even though the side of the earth facing the moon would be in darkness, other parts of the earth would still be fully sunlit, as the sun would be shining on the other half of the earth that is facing away from the moon.
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how much kinetic energy will an electron gain (in joules and ev) if it accelerates through a potential difference of ?
If the electron accelerates through a potential difference of 18500 V , then the electron will gain 2.96 × 10⁻¹⁵ Joules and 1.85 × 10⁴ eV .
The amount of Kinetic Energy that an electron gain which accelerates through a potential difference of 18500 V is calculated by using the equation: ΔK = eV ;
where ΔK is = change in kinetic energy,
⇒ e is = electron charge (approximately 1.60×10⁻¹⁹ C), and V is = potential difference.
Substituting in values, we get ;
⇒ ΔK = (1.60×10⁻¹⁹ C) × 18500 V
⇒ 2.96 × 10⁻¹⁵ Joules
In electron volts (eV), the energy is calculated as :
⇒ ΔK (eV) = ΔK/(1.60 × 10⁻¹⁹ J/eV)
⇒ ΔK (eV) = (2.96 × 10⁻¹⁵ Joules)/(1.60 × 10⁻¹⁹ J/eV) ;
⇒ 1.85 × 10⁴ eV
The given question is incomplete , the complete question is
How much Kinetic energy will an electron gain (in Joules and eV) if it accelerates through a potential difference of 18500 V ?
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suppose such a clock is calibrated correctly and then the temperature of the room in which it resides increases. does the clock run slow, fast, or correctly?
Warming causes the pendulum's length to lengthen, which lengthens the period. The clock will therefore run slowly.
What is a pendulum?
A weight that is suspended from a pivot so that it can swing freely is called a pendulum. A pendulum clock is a timepiece that keeps time by swinging a weight called a pendulum.
The length of time needed for a basic pendulum to complete one complete oscillation is known as its time period. The length of the pendulum also lengthens with temperature, lengthening the pendulum's period. As a result, it loses time as the temperature rises.
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an object is moving in a straight line. at one instant, the object is moving at 4 m/s. 2 seconds later it is moving in 10 m/s. what is the average acceleration during these 2 seconds?
Answer:
a=3m/s squared
Explanation:
a=v-u/t
where a=acceleration,v=final velocity,u=initial velocity,t=time taken
a=10-4/2-0
a=6/2
a=3m/s squared
the oscillation period of a simple pendulum (as described in section 13.5) is measured to be t, and then the length of the pendulum is increased by a factor of 4. (for example, increased from 10 cm to 40 cm or 1 m to 4 m.) which option best describes the new period of the pendulum? group of answer choices
The new time period of the pendulum will be 2 times the original period.
The period of a simple pendulum is given by the equation:
T = 2π√(l/g)
where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity.
If the length of the pendulum is increased by a factor of 4, the new period can be calculated as follows:
T' = 2π√(4l/g) = 2π√(4 × (l/g)) = 2π√4 × √(l/g) = 2 × 2π√(l/g) = 2T
Therefore, the new period of the pendulum will be 2 times the original period.
The period of oscillation of a pendulum is proportional to the square root of the length of the pendulum, so increasing the length of the pendulum by a factor of 4 will increase the period of oscillation by a factor of 2. This relationship can be shown mathematically by substituting the new length into the equation for the period of a pendulum.
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The oscillation period of a simple pendulum (as described in section 13.5) is measured to be t, and then the length of the pendulum is increased by a factor of 4. (for example, increased from 10 cm to 40 cm or 1 m to 4 m.) which option best describes the new period of the pendulum? group of answer choices
A. 2T
B. 4T
C. 8T
D. None of the above
A sphere has a charge of -6. 40 x 10-7 coulomb. Approximately how many electrons must be removed to make the sphere neutral?
a. 2. 50 x 10-13 c. 4. 00 x 1012
b. 1. 60 x 1012 d. 7. 03 x 1024
The number of electrons must be removed the charge on the sphere is 0, is [tex]4 \times 10^{12}[/tex]. Option c is correct choice.
A coulomb (C) is the standard unit of electric charge in the International System of Units (SI). It is the amount of electricity that a 1-ampere (A) current carries in one second (s). A quantity of 1 C is equal to the electrical charge of approximately 6.24 x 1018 electrons or protons.
Total charge on a electron is, [tex]-1.9 \times 10^{-19}[/tex] Coulombs.
The charge on Sphere is, [tex]-6.40 \times 10^{-7}[/tex] Coulombs.
The number of electrons required to be removed from sphere is, [tex]\dfrac{-6.40 \times 10^{-7}}{-1.9 \times 10^{-19}}[/tex],
[tex]4 \times 10^{12}[/tex].
Option c is correct.
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If the crest of one wave overlaps the crest of
another, and both waves have an amplitude
of 2 meters, what is the resulting amplitude
when they meet?
The resulting amplitude when they meet is 4 units.
What is Amplitude?Amplitude is a term used in various fields including physics, engineering, and audio technology, with different meanings in each context. In physics and engineering, amplitude refers to the maximum displacement or magnitude of a wave or oscillation from its rest position. For example, in a sound wave, the amplitude is the maximum displacement of the air molecules from their average position, and it determines the loudness of the sound. In light waves, amplitude refers to the maximum intensity of the light wave, which determines its brightness. In audio technology, amplitude refers to the strength or volume of a sound wave. In digital audio, amplitude is typically represented by a numerical value and is used to control the volume of a sound.
As both are amplitude and one overlaps each other, the amplitude formula doesn't apply, we can simply multiply the waves
2 × 2
= 4
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a tortoise can run with a speed of 0.15 m/s, and a hare can run 20 times as fast. in a race, they both start at the same time, but the hare stops to rest for 2.0 minutes. the tortoise wins by a shell (35 cm). (a) how long does the race take?
Race takes 14 seconds to complete.
We need to use the equation of motion:
d = vt
where d is the distance covered, v is the speed, and t is the time.
Let's assume that the hare covers a distance of x before it stops to rest, and the tortoise covers a distance of y in the same time. Since the hare is faster, it covers more distance than the tortoise before stopping to rest, so we can write:
[tex]x = 3.0 m/s * t[/tex]
[tex]y = 0.15 m/s * t[/tex]
After resting for 2.0 minutes or 120 seconds, the same as the distance the tortoise has to cover to win the race. Let's call this distance z.
We can write:
[tex]z = x - 0.35 m[/tex]
[tex]z = y[/tex]
[tex]3.0 m/s * t - 0.35 m = 0.15 m/s * t[/tex]
Solving for t, we get:
[tex]t = 14 s[/tex]
Therefore, the race takes 14 seconds to complete.
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explain how the balance of gravity versus thermal pressure predicts that a cloud should fragment into many stars.
Clouds are said to collapse when their self gravity exceeds the support provided by thermal pressure.
As gas pressure alone cannot overcome the gravitational pull a cloud exerts on itself, molecular clouds are prone to gravitationally collapse.
When self-gravity is greater than the support offered by thermal pressure, clouds collapse. Any cloud larger than a certain mass will collapse for any given density and temperature. The cloud gets denser and the balance mass gets smaller as it collapses.
So, the individual sub pieces of the cloud can collapse. The collapsing cloud fragments into many smaller collapsing pieces. Eventually, a cluster of low mass stars are formed rather than a single massive star.
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the car of prob. 3/50 is traveling at 25 mi/hr when the driver applies the brakes, and the car continues to move along the circular path. what is the maximum deceleration possible if the tires are limited to a total horizontal friction force of 2400 lb?
When the driver hits the brakes, the car of Approx. $3 / 61$ is moving around the circular road at a speed of $25 mathrm mi / mathrm hr.
What makes speed different from speed?
The distance traveled in a unit of time is called speed. It refers to a thing's rate of movement. The scalar quantity known as speed is the velocity vector's magnitude. It has no clear direction. An thing is travelling more quickly when its speed is higher. It is traveling more slowly when the speed is lower. It has zero pace if it isn't traveling at all.
What is an object's typical speed?
The relationship between average speed and velocity is Vav = st. While velocity indicates the how fast and in what direction an object is travelling, speed merely indicates how rapidly an object is moving. A car's speed has been mentioned if it is stated to be 60 km/h.
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if the diameter of the plunger is 1.5 cm and that of the needle 0.25 mm , with what force does the fluid leave the needle?
Force by which fluid leave needle is 0.00063N,if the diameter of the plunger is 1.5 cm
Pascal's law (likewise Pascal's principle) or the rule of transmission of liquid tension) is a standard in liquid mechanics given by Blaise Pascal that expresses that a strain change anytime in a bound incompressible liquid is sent all through the liquid to such an extent that a similar change happens everywhere.[4] The law was laid out by French mathematician Blaise Pascal in 1653 and distributed in 1663
Pascal's standard is characterized as
An adjustment of strain anytime in an encased liquid very still is sent undiminished to all places in the liquid.Pressure applied on a liquid in an encased holder is communicated similarly and undiminished to all pieces of the compartment and acts at right point to the encasing walls.The tension applied to any piece of the encased fluid will be communicated similarly this way and that through the fluid.
We need to use pascal law for finding the force,which is F₁/A₁ = F₂/A₂ where F₁ is the amount of force applied on area(A₁) and F₂ is the force applied on area(A₂)
Here,(A₁)=πd²/4=3.14×(1.5)²/4=1.766cm²
Similarly,(A₂)=πd²/4=3.14×(0.025)²/4=0.00049cm²
Also,F₁=2.29N
So,2.29/1.766=F₂/0.00049
=>F₂=(2.29ˣ0.00049)/1.766
=>F₂=0.00112/1.766
=>F₂=0.00063N.
Hence,force by which fluid leave is 0.00063N.
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(Complete question) is:
A 2.29N force is applied to the plunger of a hypodermicneedle.
If the diameter of the plunger is 1.5 cm and that ofthe needle is
0.25 mm, with what force does the fluid leave theneedle?
2. does this cross bedding indicate a steady flow of air or water, or does it indicate an oscillating (back and forth) flow?
Yes, it shows that there was a steady flow medium present in the depositional environment (typically water or wind).
Is cross-bedding a sign of growth?Examples include characteristics that can clearly identify the top or bottom of lava flows or sedimentary strata. Cross bedding, symmetric ripples, and graded bedding were some of the earliest sedimentary features to be used for way-up determination, with various sole marks only becoming relevant much later.
Which way do cross-beds slant?a sedimentary structure that develops in the lower flow regime, where sediment ridges align themselves with the flow direction, but inside the ridges, the sediment layers and dips in the direction of the flow.
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tthe planet Mars may be considered to be an isolated sphere of diameter of 6.79×10^6m with it's mass of 6.42×10^23 kg concentrated at its center. A rock of mass 1.40kg rests on the surface of Mars.
(assume that the dimensions of the rock are negligible compared to the radius of Mars)
(I) determine the weight of the rock on Mars
(ii) show that the gravitational potential energy of the rock is -1.77×10^7J
The weight of the rock on mars is 3.71 N
How to find the weight of rock on MarsI. To determine the weight of the rock on Mars, we need to calculate the force of gravity acting on the rock. The force of gravity can be calculated using the equation:
F = G * (m1 * m2) / r^2
where
F = force of gravity
G = gravitational constant (6.67 × 10^-11 N(m/kg)^2)
m1 = mass of Mars (6.42 × 10^23 kg)
m2 = mass of the rock (1.40 kg)
r = radius of Mars (3.39 × 10^6 m)
Plugging in the values, we get:
F = 6.67 × 10^-11 * (6.42 × 10^23 * 1.40) / (3.39 × 10^6)^2
F = 3.71 N
So the weight of the rock on Mars is 3.71 N.
II. The gravitational potential energy of the rock can be calculated using the equation:
U = - G * m1 * m2 / r
Plugging in the values, we get:
U = - 6.67 × 10^-11 * 6.42 × 10^23 * 1.40 / 3.39 × 10^6
U = -1.77 × 10^7 J
So the gravitational potential energy of the rock on Mars is -1.77 × 10^7 J.
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A car has a kinetic energy of 4.33 × 10^5 J when
traveling at a speed of 23 m/s.
What is its mass?
Answer:
Explanation:
The kinetic energy of a moving object is given by:
KE = (1/2)mv²
where KE is the kinetic energy, m is the mass of the object, and v is the velocity.
We can rearrange this equation to solve for the mass of the car:
m = 2KE / v²
Substituting the given values, we get:
m = 2(4.33 × 10^5 J) / (23 m/s)²
m = 2(4.33 × 10^5 J) / 529 m²/s²
m = 1.641 kg
Therefore, the mass of the car is approximately 1.641 kg.
a car of mass 1100 kg moves at 20 m/s. . a) what is its stopping distance? b) if the same car is moving at 40 m/s, what is its stopping distance?
A car of mass 1100 kg moves at 20 m/s the its stopping distance is 400m and 160 m.
Initial speed of the car is u.
Final speed of the car v = 0
Simply put, negative acceleration is a reverse acceleration. The velocity of the body may rise or fall. Acceleration is the term used to describe the change in velocity. The body experiences positive acceleration when its speed increases. Similar to this, as velocity falls, the acceleration turns negative and is known as negative acceleration.
Let the acceleration of the car be a.
Its stopping distance is 400m because s ∝ [tex]u^{2}[/tex] and s=400m by that form.
Using
[tex]v^{2} -u^{2}[/tex]= 2aS
0-u² = 2aS
s ∝ [tex]u^{2}[/tex] (for same a)
Now,
S = 40m u = 2u
[tex]\frac{S^{'} }{S} =\frac{u^{'2} }{u^{2} }[/tex]
[tex]\frac{S^{'} }{40} =4[/tex]
Then the distance will be,
S' = 160m
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what is the magnitude of the electric force on a protein with this charge in a 1700 n/c electric field?
The magnitude of the electric force on a protein with this charge in a 1700 n/c electric field is F = q * 1700 N/C
Coulomb's law may be used to calculate the amount of the electric force on a protein with a particular charge in an electric field. According to Coulomb's law, the force between two charged particles is equal to the product of their charges and inversely proportional to the square of their distance. The force on a charged particle in an electric field is expressed as follows:
F = q * E, where q is the charge on the protein and E is the intensity of the electric field. The strength of the electric field is specified as 1700 N/C. Coulombs are the unit of charge (C).
As a result, the size of the protein's electric force may be estimated as follows:
F = q * E
= q * 1700 N/C
The force will be directed in the direction of the electric field. If the protein's charge is positive, the force will be directed in the same direction as the electric field. If the protein has a negative charge, the force will be in the opposite direction as the electric field.
It's vital to remember that the electric force on a protein is affected by its size, shape, and charge. Other parameters, such as the dielectric constant of the surrounding medium, may impact the electric force on a protein in some situations.
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a speedboat has a constant acceleration of 3/0 m/s2. if the initial velocity of the boat is 8.0m/s, find the boats displacement after 10.0 seconds
The displacement of the speedboat after 10.0 seconds is 230.0 meters.
The displacement of an object with constant acceleration can be found using the formula:
d = vₒt + (1/2)at²
where d is the displacement, vₒ is the initial velocity, t is the time elapsed, and a is the acceleration.
Given the initial velocity of 8.0 m/s and acceleration of 3.0 m/s², and a time elapsed of 10.0 seconds, we can plug in the values into the formula to find the displacement:
d = 8.0 m/s × 10.0 s + (1/2) × 3.0 m/s² × (10.0 s)² = 80.0 m + 150.0 m = 230.0 m
So the displacement of the speedboat after 10.0 seconds is 230.0 meters. This means the boat has moved 230.0 meters from its original position due to the combined effect of its initial velocity and the acceleration.
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Of the following, which energy resource(s) can be extracted from marine sediments? Choose all Halite
that apply.
Petroleum
Manganese nodules
Phosphorites
Gas hydrates
Petroleum and gas hydrates are the principal energy sources linked to marine sediments.
Which four types of marine sediments are there?
Lithogenous, hydrogenous, biogenous, and cosmogenous are the four categories. Rivers, ice, wind, and other activities on land are how lithogenous sediments are transported. When planktonic creatures' exoskeletons degrade, they produce biogenous sediments. Chemical processes in the water produce hydrogenous sediments.
A fossil fuel is petroleum, sometimes referred to as crude oil. Petroleum was created from the remains of extinct marine animals like plants, algae, and bacteria, just like coal and natural gas. A crystalline solid made of water and gas is called a gas hydrate. It resembles ice in appearance and behavior but is actually very methane-rich and is known to exist on every continent.
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during a clear and pleasant night, you look up into the sky and recognize the planet mars near the center of the constellation of libra. if you look for mars the following night at around the same time, where are you most likely to find the planet?
Motion of Mars across the sky is not always predictable, but in general, Mars moves eastward relative to stars. This is because the Earth orbits the Sun faster than Mars, so the Earth moves in its orbit, it overtakes Mars, causing Mars to appear to move backwards (in retrograde motion) for a period of time before resuming its eastward motion.
However, the exact motion of Mars across the sky depends on many factors, including positions of Earth, Mars, and the Sun in their orbits. If you look for Mars the following night at around same time, you will need to locate it using star charts or astronomy apps that show the current position of Mars in the sky.
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Which statement best describes the motion of the box when the forces pull on the box
the required net force acting on the box is the difference between the two forces, which is 7 N to the left.
What is force?Force is a physical quantity that describes the interaction between two objects. It is a vector quantity, meaning it has both magnitude and direction.
The net force acting on the box is the difference between the two forces, which is 14 N - 7 N = 7 N to the left.
According to Newton's second law of motion, an object will move in the direction of the net force acting on it, so in this case, the box will move to the left. The magnitude of the acceleration of the box will be proportional to the magnitude of the net force, so the greater the net force, the greater the acceleration of the box.
Thus, the required net force acting on the box is the difference between the two forces, which is 7 N to the left.
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what do lightning and stars have in common? aboth have no electrical chargeincorrect answer bboth contain plasmaincorrect answer cboth have a fixed volumeincorrect answer dboth contain all three states of matter
Lightning and stars both contain plasma, which is a high-temperature ionized gas that contains free electrons and ions.
Plasma is a common state of matter in the universe and is found in stars, lightning, and other celestial bodies. Unlike solids and liquids, which have a fixed shape and volume, plasma has no fixed shape or volume and is highly influenced by electric and magnetic fields. In stars, the intense heat and pressure cause hydrogen and helium atoms to become ionized and form plasma, which sustains nuclear reactions that generate light and heat. In lightning, plasma is created by the ionization of air molecules due to the high-voltage discharge of electricity in a thunderstorm. Both lightning and stars have a significant impact on our lives and the universe around us.
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. where is the electric field the largest? where is it the smallest? how does the magnitude change as you move from one electrode to the other? on a dipole
The strength and direction of the electric field around a dipole are important in many areas of physics and engineering, such as in the design of antennas, electromagnetic radiation, and molecular interactions.
What is the electrode?
It is typically made of metal or a conductive material such as carbon, and is connected to a source of electrical current. The electrode is then placed in a circuit, allowing electricity to flow from the source to the nonmetallic part of the circuit.
In a dipole, the electric field is the strongest (largest) at the poles or tips of the dipole and the weakest (smallest) at the equator or midpoint between the poles. The direction of the electric field at any point on the dipole is always along the line joining the two charges.
As you move from one electrode to the other, the magnitude of the electric field decreases as you move away from the poles towards the equator. At the poles, the electric field is proportional to the magnitude of the charges and the distance between them. At the equator, the electric field is zero because the electric fields from the two charges cancel each other out.
It's important to note that the electric field around a dipole also varies with distance from the dipole. The magnitude of the electric field decreases as you move further away from the dipole, following an inverse square law.
The strength and direction of the electric field around a dipole are important in many areas of physics and engineering, such as in the design of antennas, electromagnetic radiation, and molecular interactions.
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if you were to stand up and sprint as fast as you could for about 10 seconds, what fuel sources would allow you to do this?
If you were to stand up and sprint as fast as you could for about 10 seconds, your body would primarily rely on stored carbohydrates (in the form of glycogen) as the main fuel source.
During high-intensity activities such as sprinting, the body's demand for energy increases rapidly. To meet this increased demand, the muscles break down glycogen into glucose, which is then converted into ATP (adenosine triphosphate), the primary energy currency of the cell.
In addition to glycogen, a small amount of fat may also be used as a fuel source during sprinting, but at such a high intensity, carbohydrates are the primary energy source.
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do the two cars ever have the same velocity at one instant of time? if so, between which two frames?
The two cars have the same position at seven seconds; yet they never have the same velocity at any instant in time.
The blue car starts ahead of" the red car. (The red car actually starts off the screen.) Since the red car is moving faster, it eventually catches up with and passes the blue car. The position-time plot of each car's motion is depicted by a diagonal line with a constant slope.
At the time that the cars are side by side, the lines intersect. That is, the two cars share the same position at that instant in time. The lines would not intersect for a velocity vs. time graph.
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A box with a mass of 25 kg is lifted to a height of 3 meters in 2 seconds. How much work was done?
Group of answer choices
735 J
958 J
245 J
75 J
Answer:
Explanation:
Work done = force x displacement
force = mass x acceleration (due to gravity)
work done =25 * 9.8 * 3 = 735J
Answer:
735 J
Explanation:
F (force) = ma = mg = 25kg × 9.81m/s² = 245.25N.
we are lifting, so the acceleration is going against Earth's gravity.
the work done to lift it up by 3 m is then
W = F×d = 245.25N×3 m = 735.75 J
the time (2 seconds) does not play a role here.
it would be needed to calculate the power needed to lift 25kg 3 m in 2 seconds :
power = W/t = 735.75/2 = 367.875 watts
10. Jared and Claire are climbing the stairs. Jared gets tired and stops halfway to the fourth floor. Claire makes it to the fourth floor without a problem. If Jared is twice as heavy as Claire, who has more gravitational potential energy? Explain your answer.
Answer:
They both have the same GPH
Explanation:
GPE = mgh
m = mass of Claire
2m = mass of Jared
h = height of Claire
h/2 = height of Jared
GPE-jared = (2m)(g)(h/2) = mgh
GPE-claire = mgh
They both have the same GPH
Consider two masses m1 and m2 connected by a thin string. Assume the following values: m1 = 4.2 kg and m2 = 1.0kg. Ignore friction and the mass of the string.
A: Find the acceleration of the two masses.
B: Changing the value of mass m1 while keeping mass m2 constant would change the acceleration of the two-mass system. What should be the value of mass m1 to get the largest possible value of acceleration of the two masses?
C: What would be the value of that maximum acceleration?
The acceleration of the masses are [tex]1.88 m/s^{2}[/tex]. The value of mass [tex]m_{1}[/tex] is zero to get maximum possible acceleration which is equal to [tex]9.8 m/s^{2}[/tex].
(A) The mass,[tex]m_{1} = 4.2 kg[/tex] and mass, [tex]m_{2} = 1.0 kg[/tex]
Let, the acceleration of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex] is [tex]a[/tex] as shown in the figure given below.
[tex]T = m_{1} a - (i)[/tex]
[tex]m_2 g -T = m_2 a -(ii)[/tex]
Put value of [tex]T[/tex] in equation [tex](ii)[/tex] from equation [tex](i)[/tex], we will get:
[tex]m_2 g - m_1 a = m_2 a[/tex]
[tex]m_2 g = m_1 a + m_2 a[/tex]
[tex]a = \frac{m_{1} }{m_{1} + m_{2} } g -(iii)[/tex]
[tex]a= \frac{9.8}{4.2 + 1}[/tex]
[tex]a = 1.88 m/s^{2}[/tex]
(B) For maximum acceleration, [tex]\frac{da }{dm_{1} } = 0[/tex]
[tex]\frac{d(\frac{m_{2} }{m_{1} +m_{2} }) }{dy} g = 0[/tex]
[tex]\frac{m_{1} }{(m_{1} +m_{2})^{2} } = 0[/tex]
[tex]m_{1} = 0[/tex]
(C) Put value of [tex]m_{1} = 0[/tex] in equation [tex](iii)[/tex]
[tex]a = \frac{m_{1} }{m_{1} + m_{2} } g[/tex]
[tex]a = g[/tex]
[tex]a = 9.8 m/s^{2}[/tex]
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What impulse must be applied to a 1.08 kg cart to cause a velocity change of 12.0 m/s
Answer:
Explanation:
Impulse of force =12.96 Ns
Explanation:
Impulse = force* time = change in momentum = mass* velocity
Given the following data;
mass = 1.08kg
Change in velocity = 12m/s
Impulse of force = 1.08* 12 = 12.96Ns