Please help and answer.

9514 1404 393

Answer:

  g(f(x)) = x . . . so the functions are inverses

Step-by-step explanation:

Two functions f and g are inverses of each other if ...

  g(f(x)) = x   or   f(g(x)) = x

We are asked to evaluate g(f(x)). That will be x if the functions are inverses.

  g(f(x)) = g((x+1)/2) = 2((x +1)/2) -1 = (x +1) -1

  g(f(x)) = x . . . . the functions are inverses

Answer:

what is the quetion then i can answer it

Step-by-step explanation:

just remeber a penny is 1 cent a qurter is 25cents and so on

Answer:

fx=3x+7 gx=5x-8

Step-by-step explanation:

here i hope this helps im not 100% sure this is what you want but its what I think

Answer:

1.

Step-by-step explanation:

The line goes through positive 2

Answer:

2

Step-by-step explanation:

the slope has to intercept at y=2 and slope is rise over run so you would go up 1 and over 2.

Answer:

8

Step-by-step explanation:

since u first do six + 8 which is 14. Then u do 14 - 4 which is 10

Plz mark as brainliest

Answer:

x=2

Step-by-step explanation:

x = the number

x + 6 = 6x - 4

Solve for x and get

5x = 10

Given:

A linear function starting at point C at (3, –2) and ending at point D at (–2, 3).

To find:

The rate of change and the initial value.

Solution:

If a linear function passes through two points [tex](x_1,y_1)\text{ and }(x_2,y_2)[/tex], then the equation of linear function is

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The given linear function passes through (3,-2) and (-2,3). So, the equation is

[tex]y-(-2)=\dfrac{3-(-2)}{-2-3}(x-3)[/tex]

[tex]y+2=\dfrac{3+2}{-5}(x-3)[/tex]

[tex]y+2=\dfrac{5}{-5}(x-3)[/tex]

[tex]y+2=-(x-3)[/tex]

Subtracting 2 on both sides, we get

[tex]y=-x+3-2[/tex]

[tex]y=-x+1[/tex]

On comparing this equation with slope intercept form [tex]y=mx+b[/tex], where, m is slope and b is y-intercept, we get

[tex]m=-1[/tex] and [tex]b=1[/tex]

Therefore, the rate of change is -1 and the initial value is 1.

Answer:

15.13cm

Step-by-step explanation:

From that above question:

We are told that:

Lateral surface area of a right circular cone : πr√r² + h²

We are give the following parameters:

Lateral surface area = 236.64cm²

Radius = 4.75cm

We are to find the height

Making h the subject of the formula

h = √[(A/r)² - πr²]/π

h = √[(236.64/4.75)²- π ×4.75²]/π

h = 15.12975 cm

Approximately to the nearest hundredth = 15.13cm

Answer:

True

Step-by-step explanation:

ed 2020. I went back to check the answer so 100% right.

Answer:

tru

Step-by-step explanation:

Answer:

cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex]  ⇒ B

Step-by-step explanation:

Let us solve the question using one of the identities of trigonometry

∵ sin²Ф + cos²Ф = 1

∵ sinФ = [tex]\frac{3}{4}[/tex]

→ Substitute it in the rule above to find cos Ф

∴ ([tex]\frac{3}{4}[/tex])² + cosФ² = 1

∴ [tex]\frac{9}{16}[/tex] + cosФ² = 1

→ Subtract [tex]\frac{9}{16}[/tex]  from both sides

∴ cos²Ф = [tex]\frac{7}{16}[/tex]

→ Take √ for both sides

∴ cosФ = ± [tex]\frac{\sqrt{7}}{4}[/tex]

∵ Angle Ф lies on the second quadrant

∴ cosФ is a negative value

∴ cosФ = [tex]-\frac{\sqrt{7}}{4}[/tex]  

∴ cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex]  

Answer: 146n is the answer 100%

Answer:

k=8

Step-by-step explanation:

For 2 lines to be parallel, they must have the same slope. First, let's isolate y.

5y=2x+2

y=2/5x+2/5

Now, in our second equation, we must make it so that the slope is 2/5.

5(4)=20

2(4)=k

k=8

y=8/20x+10

If you simplify that, then the slope will be 2/5.

Answer:

The answer is 1.99

Step-by-step explanation:

23.88 divided by 12 =1.99 and There are 12 quarts in 3 gallons.Have a nice day❤

Answer:

Each piece weighed 1/10 of a pound.

Step-by-step explanation:

We have 3/5 of a pound and we want to divide it by 6 equal pieces for each student. 6 equal pieces is the same as 6/1.

In order to divide 3/5 by 6/1 we need to invert the 6/1 and multiply. So, it becomes 3/5 x 1/6. First, we multiply the numerators: 3x1=3 then we multiply the denominators: 5x6=30. The result is 3/30, which can be reduced by dividing both the numerator and denominator by 3. 3/3=1 and 30/3=10. So, the result is 1/10.

Answer:

$1

Step-by-step explanation:

Answer: -1/2

Step-by-step explanation: whenever a line is perpendicular you take the opposite reciprocal of the current slope.

Hello!

Perpendicular lines have slopes that are opposite reciprocals.

It means we take a number, flop it over and then make it negative.

So if we have 2, we flop it over:

[tex]\frac{1}{2}[/tex]

Then, we make it negative:

[tex]-\frac{1}{2}[/tex]

That is the slope. Hope it helps

If you have any query, please ask me! :)

~A forlorn girlie

[tex]MagicalNature[/tex]

Answer:

6 days

Step-by-step explanation:

Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.

The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.

This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days

Answer:

P-4,7

Q-1,4

R-4,4

S-1,1

Step-by-step explanation:

4,4- 1,4 theres a 3 unit distance. just subtract 3 from y and you'll get the answer

Answer:

y=-1x-6

Step-by-step explanation:

you can also use y=-x-6 but its your choice

Answer:

100/65 because 0.65 is a decimal number

Step-by-step explanation:

hope this helped

have a great day

Answer:

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Step-by-step explanation:

Given that we have;

[tex]x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }[/tex]

[tex]x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x^3 = \dfrac{9 \cdot x + 10}{3}[/tex]

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Answer:

d

Step-by-step explanation:

its right on khan

Answer:

D. All real numbers

Step-by-step explanation:

Answer:

Step-by-step explanation:

              Statements                        Reasons

1). UW bisects ∠VUX               1). Given

2). UW bisects ∠VWX             2). Given

3). ∠VUW ≅ ∠WUX                 3). Definition of angle bisector

4). ∠UWV ≅ ∠UWX                 4). Definition of angle bisector

5). UW ≅ UW                           5). Reflexive property

6). ΔUVW ≅ ΔUXW                 6). ASA postulate of congruence

Answer:

LP = 18

Step-by-step explanation:

Given that,

In ΔLPN,

LQ = 6, LM = 11 and MN = 22

We need to find the length of LP.

As QM ║PN, let QP = x

[tex]\dfrac{LQ}{LP}=\dfrac{LM}{LN}\\\\\dfrac{6}{6+x}=\dfrac{11}{11+22}\\\\\dfrac{6}{6+x}=\dfrac{11}{33}\\\\198=66+11x\\\\198-66=11x\\\\132=11x\\\\x=12[/tex]

LP = 6+x

= 6+ 12

= 18

Hence, the length of LP is 18.

Answer:

reflect over x axis

x+3  y+3

Step-by-step explanation:

Step-by-step explanation:

income income earned working 5 hours is $50