PLEASE HELP! 50 POINTS! Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). Which of the following will give a 95% t confidence interval for the mean of the population from which the sample was drawn?

Answer:

Because 10 is twice as large as 5.

Step-by-step explanation:

Answer:

The answer is c on edge or f(x) = 1 sqt x + 6 -2

Step-by-step explanation:

From the given two options, none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

A function is a correspondence between input numbers (x-values) and output numbers (y-values). It is used to describe an equation.

Given that:

Suppose that x = c is a critical point of (x) then,

If f'(x) > 0 to the left of x = c and f'(x) < 0 to the right of x = c;

If f'(x) < 0 to the left of x = c and f'(x) > 0 to the right of x = c;

If f'(x) is the same sign on both sides of x = c;

From the given equation, the critical points: x = -3

If we put the point x = -3 into - |x+3|-2

We can therefore conclude that none of them has a function that has the same maximum value as f(x) = -|x+3|-2.

Learn more about the maximum and minimum of a function here:

https://brainly.com/question/6787214

#SPJ9

If Jack finish them all in 5 days, then he can solve m/5 math problem in just one day.

From the given question, jack can only solve m math problems in 5 days, this can be expressed as:

m problems = 5 days

The number of questions he can solve per day is expressed as:

x = 1 day

Take the ratio

m/x = 5/1

5x = m

x = m/5 math problems

This shows that jack can solve m/5 math problem in just one day

Learn more on ratio here: https://brainly.com/question/2328454

missing angle:

180° - 90° - 30°

180° - 120°

60°

missing sides:

(a)

[tex]\rightarrow \sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

[tex]\rightarrow \sf tan(30)= \dfrac{4}{adjacent}[/tex]

[tex]\rightarrow \sf adjacent= \dfrac{4}{tan(30)}[/tex]

[tex]\rightarrow \sf adjacent= 4\sqrt{3}[/tex]

[tex]\rightarrow \sf adjacent= 6.93 \ cm[/tex]

(b)

[tex]\sf \rightarrow sin(x)= \dfrac{opposite}{hypotensue}[/tex]

[tex]\sf \rightarrow sin(30)= \dfrac{4}{hypotensue}[/tex]

[tex]\sf \rightarrow hypotensue= \dfrac{4}{ sin(30)}[/tex]

[tex]\sf \rightarrow hypotensue= 8 \ cm[/tex]

Answer:

m∠X = 60°

BX = 8 cm

BM = 4√3 cm

Step-by-step explanation:

The sum of the interior angles of a triangle is 180°

Given:

⇒ m∠B + m∠M + m∠X = 180°

⇒ 30° + 90° + m∠X = 180°

⇒ 120° + m∠X = 180°

⇒  m∠X = 180° - 120°

⇒  m∠X = 60°

Using the sine rule to find the side lengths:

[tex]\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}[/tex]

(where A, B and C are the angles, and a, b and c are the sides opposites the angles)

Given:

[tex]\implies \dfrac{4}{\sin 30\textdegree}=\dfrac{BX}{\sin 90\textdegree}=\dfrac{BM}{\sin 60\textdegree}[/tex]

[tex]\implies BX=\sin 90\textdegree \cdot\dfrac{4}{\sin 30\textdegree}[/tex]

              [tex]=1 \cdot \dfrac{4}{\frac12}[/tex]

              [tex]=1 \cdot 4 \cdot 2[/tex]

              [tex]=8 \textsf{ cm}[/tex]

[tex]\implies BM=\sin 60\textdegree \cdot\dfrac{4}{\sin 30\textdegree}[/tex]

              [tex]=\dfrac{\sqrt{3}}{2}\cdot \dfrac{4}{\frac12}[/tex]

              [tex]=\dfrac{\sqrt{3}}{2}\cdot 4 \cdot 2[/tex]

              [tex]=4\sqrt{3} \textsf{ cm}[/tex]

16 + 32 = 16 x 1 + 16 x 2 = 16 x (1 + 2)

Answer:

A

Step-by-step explanation:

You can think about it as an equation without the inequality:

y = 5 - x        OR       y = -x + 5

Slope = -1

Y-intercept = 5

Graph B is a horizontal line with a slope of zero and y-intercept of 2. Graph A is the only one that fits the above parameters.

Hope this helps!

Answer:

a

Step-by-step explanation:

Answer: C

Step-by-step explanation:

Just look at a z-score table and multiply by 100.

-> (0.308538)(100) is about 30.85%

The sum we want is

[tex]\displaystyle \sum_{n=0}^\infty \frac{(-1)^{T_n}}{(2n+1)^2} = 1 - \frac1{3^2} - \frac1{5^2} + \frac1{7^2} + \cdots[/tex]

where [tex]T_n=\frac{n(n+1)}2[/tex] is the n-th triangular number, with a repeating sign pattern (+, -, -, +). We can rewrite this sum as

[tex]\displaystyle \sum_{k=0}^\infty \left(\frac1{(8k+1)^2} - \frac1{(8k+3)^2} - \frac1{(8k+7)^2} + \frac1{(8k+7)^2}\right)[/tex]

For convenience, I'll use the abbreviations

[tex]S_m = \displaystyle \sum_{k=0}^\infty \frac1{(8k+m)^2}[/tex]

[tex]{S_m}' = \displaystyle \sum_{k=0}^\infty \frac{(-1)^k}{(8k+m)^2}[/tex]

for m ∈ {1, 2, 3, …, 7}, as well as the well-known series

[tex]\displaystyle \sum_{k=1}^\infty \frac{(-1)^k}{k^2} = -\frac{\pi^2}{12}[/tex]

We want to find [tex]S_1-S_3-S_5+S_7[/tex].

Consider the periodic function [tex]f(x) = \left(x-\frac12\right)^2[/tex] on the interval [0, 1], which has the Fourier expansion

[tex]f(x) = \frac1{12} + \frac1{\pi^2} \sum_{n=1}^\infty \frac{\cos(2\pi nx)}{n^2}[/tex]

That is, since f(x) is even,

[tex]f(x) = a_0 + \displaystyle \sum_{n=1}^\infty a_n \cos(2\pi nx)[/tex]

where

[tex]a_0 = \displaystyle \int_0^1 f(x) \, dx = \frac1{12}[/tex]

[tex]a_n = \displaystyle 2 \int_0^1 f(x) \cos(2\pi nx) \, dx = \frac1{n^2\pi^2}[/tex]

(See attached for a plot of f(x) along with its Fourier expansion up to order n = 10.)

Expand the Fourier series to get sums resembling the [tex]S'[/tex]-s :

[tex]\displaystyle f(x) = \frac1{12} + \frac1{\pi^2} \left(\sum_{k=0}^\infty \frac{\cos(2\pi(8k+1) x)}{(8k+1)^2} + \sum_{k=0}^\infty \frac{\cos(2\pi(8k+2) x)}{(8k+2)^2} + \cdots \right. \\ \,\,\,\, \left. + \sum_{k=0}^\infty \frac{\cos(2\pi(8k+7) x)}{(8k+7)^2} + \sum_{k=1}^\infty \frac{\cos(2\pi(8k) x)}{(8k)^2}\right)[/tex]

which reduces to the identity

[tex]\pi^2\left(\left(x-\dfrac12\right)^2-\dfrac{21}{256}\right) = \\\\ \cos(2\pi x) {S_1}' + \cos(4\pi x) {S_2}' + \cos(6\pi x) {S_3}' + \cos(8\pi x) {S_4}' \\\\ \,\,\,\, + \cos(10\pi x) {S_5}' + \cos(12\pi x) {S_6}' + \cos(14\pi x) {S_7}'[/tex]

Evaluating both sides at x for x ∈ {1/8, 3/8, 5/8, 7/8} and solving the system of equations yields the dependent solution

[tex]\begin{cases}{S_4}' = \dfrac{\pi^2}{256} \\\\ {S_1}' - {S_3}' - {S_5}' + {S_7}' = \dfrac{\pi^2}{8\sqrt 2}\end{cases}[/tex]

It turns out that

[tex]{S_1}' - {S_3}' - {S_5}' + {S_7}' = S_1 - S_3 - S_5 + S_7[/tex]

so we're done, and the sum's value is [tex]\boxed{\dfrac{\pi^2}{8\sqrt2}}[/tex].

Fort nite battle pass is 8 dollars

Answer:

see explanation for detailed analysis

Answer:

The answer is {D}

Step-by-step explanation:

Digram:-

[tex] \\ [/tex]

[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}[/tex]

[tex] \\ [/tex]

STEP :-

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

{Linear pair}

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ} - {117}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt4q =64{}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{64}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times 4}{4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt \: q = \dfrac{16}{1}[/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf q = 16 \degree[/tex]

[tex] \\ \\ [/tex]

Verification:

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(4 \times 16- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt(64- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt63^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \tt180^{ \circ} = 18 {0}^{ \circ} [/tex]

[tex] \\ [/tex]

LHS = RHS

HENCE VERIFIED!

Answer:

Value of [tex]\sf\purple{q\: = \:16.}[/tex]

Step-by-step explanation:

[tex]\rightarrow[/tex]As we know that,

Sum all angles that lie on a straight line = [tex]\sf\blue{180°}[/tex]

So,

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)°+ 117°\: = \:180°}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:180-117}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:63}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{4q\: = \:63+1}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:\frac{64}{4}}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{q\: = \:16}[/tex]

Thus, [tex]\sf\purple{q\: = \:16.}[/tex]

_________________________________

Hope it helps you:)

[tex]\sqrt{7^{16}} = 7^n\\\\\implies \left(7^{16}\right)^{\tfrac 12} = 7^n\\\\\implies 7^{\left(\tfrac 12 \times 16\right)}=7^n\\\\\implies 7^8 = 7^n\\\\\implies \ln 7^8 = \ln 7^n\\\\\implies 8\ln 7 = n \ln 7\\\\\implies n =8[/tex]

Answer:

A) x would be 21 if i interpreted it right

Step-by-step explanation:

4x - 11 = 73

i think anyways

4x = 73 + 11

4x = 84

x = 21

i d k  what B means?

Answer:

B. (-3, 10)

Step-by-step explanation:

     I am going to graph the given equation. I then will see which of the points given are within the required area.

-> See attached.

-> I have explained in the image more in-depth as well.

At 1.00Pm the temperature was -13°C

So

The equation is

Answer:

$2821.50

Step-by-step explanation:

value = 2700 (deposit) x 0.003 (rate) x 15 (time) + 2700

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2700\\ r=rate\to 0.3\%\to \frac{0.3}{100}\dotfill &0.003\\ t=years\dotfill &15 \end{cases} \\\\\\ A=2700[1+(0.003)(15)]\implies A=2700(1.045)\implies A=2821.5[/tex]

Answer:

11

Step-by-step explanation:

Given:

8,14,22,7,2,11,25,7,5,9

Solve:

Put in order:

2, 5, 7, 7, 8, 9, 11, 14, 22, 25

Note:

Mean-

2+ 5+7+7+8+9+11+ 14+22+25=110

110/10 = 11

Hence, the mean of the data is 11.

[RevyBreeze]

Answer:

The mean of the data given is 11

What is mean?
The mean is the arithmetic average of a set of given numbers. The median is the middle score in a set of given numbers. The mode is the most frequently occurring score in a set of given numbers.

Step-by-step explanation:

Have a great rest of your day
#TheWizzer

(pls give the person who answered before me braineist)

Answer:

Answer:4 apples weigh 5/8 pound.

Step-by-step explanation:

Answer:

2(−5) − 10 = 2(0)

Step-by-step explanation:

If you substitute the values x = 0 and y = −5 into the second equation, you get a false statement

Answer: P=28 meters

Step-by-step explanation:

[tex]P=4[/tex] × a ⇒ a is the side length

[tex]P=4[/tex] × [tex]7[/tex]

[tex]P=28[/tex]

Answer:

28 m

Step-by-step explanation:

Given

Perimeter of a square

Answer:

17.0625

Step-by-step explanation:

Due to order of operations the division and multiplication get done first and the we add the 12

Answer:

2.89285714

Step-by-step explanation:

9x9/16+12

81/16+12

5.0625 + 12 = 17.0625

Hope this helps :)

Answer:

(0,-9) You have to substitute 0 for x and solve for y

Answer:

[tex]\frac{dx^{2} (x+1)S^{2} }{2(x^{2} +6x+3)^{2} }+ C[/tex]

Step-by-step explanation:

6 red face cards

->in favour:

6/52

= 3/26

-> against:

52-6= 46

46/52

=23/26

Answer:

72 square units

Step-by-step explanation:

H = 9 units

L = 8 units

A = H × L

A = 9 × 8

A = 72 square units

Answer:

4

Step-by-step explanation:

100 divided by 25 equals 4.