please explain me answer a b c d

Answer:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

Explanation:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

Answer:

in contrast, peru and Bolivia entered the war hindered by numerous domestic fractures and by an economic and insititutional backwardness that nearly prevented the two countries from fighting the war at all

Answer:

There are four elements that are found in all living animals, that are:

Oxygen (O)

Carbon (C)

Hydrogen (H)

Nitrogen (N).

Answer:

bromine

Explanation:

Answer:

beta to Kr-80 or Se-80

Explanation:

sorry if wrong

Answer:

good job ;0

Explanation:

Answer:

1. molecule, cell, tissue, organ, organ system, organism, population, community, ecosystem, biosphere

2. A

3. D

4. C

5. C

6. C

7. C

8. B

9. Sorry I don't know :(

10. B

11. A

12. C

13. Sorry :((

14. C

15. a

16. d

Sorry I don't know the rest.. I hope this helps though!!

Answer:

the bond is ionic

Explanation:

Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

Answer:

It depends on their melting and/or their boiling points, because the heat provides the particles with kinetic energy to break the electrosatic bonds in the substances, which can differ in strength

Explanation:

Answer:

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

Here is the atomic model in the picture.

Answer:

Hey mate....

Explanation:

This is ur answer....

Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose. Starch is stored in seeds and other plant parts as a food source.

Hope it helps!

Brainliest pls!

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Answer:

Plants use photosynthesis to convert sun light into their own food to consume. Green plants use this light energy to change water and carbon dioxide into oxygen and nutrients called sugars. The plants use some of the sugars and store the rest. The oxygen is released into the air.

Answer:

The primary producer uses some of that energy. Because we lose energy each time we move up a trophic level, we have more producers than consumers, more herbivores than carnivores, more primary consumers than secondary consumers. See this Socratic answer for more detail.

Explanation:

Answer:

Producers produce food energy for themselves and all the other levels

Explanation:

The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :

(i) The molecular formula of sulphur dioxide is [tex]SO_{2}[/tex]

So, [tex]1[/tex]  mole of [tex]SO_{2}[/tex] = [tex]Mass[/tex] [tex]of[/tex] [tex]2'O'[/tex]

[tex]=32+2*16[/tex]

[tex]= 64[/tex] grams

Now, [tex]64g[/tex] of sulphur dioxide [tex]= 1[/tex] mole

So, [tex]1g[/tex] of sulphur dioxide = [tex]\frac{1}{64}[/tex] mole

Thus, we have [tex]\frac{1}{64}[/tex] mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, [tex]\frac{1}{64}[/tex] mole of methane will also contain x molecules of methane.

(ii) Molecular formula of methan is [tex]CH_{4}[/tex]

So, 1 mole of [tex]CH_{4}[/tex]  = Mass of C + Mass of 4 H

[tex]=12+4*12[/tex]

Now, 16g of methane = 1 mole

So, 1 g of mathane = [tex]\frac{1}{16}[/tex] mole

We know that:

[tex]\frac{1}{64}[/tex] mole of methane contains = x molecules

So, [tex]\frac{1}{16}[/tex]  mole of contains will contain =[tex]\frac{x*64}{16}[/tex] molecules

=[tex]4x[/tex] molecules

Answer:

Q= ms∆T

Where, m is mass of substance

S is specific heat

∆T is temperature change

As in question , m=8.21 ,s=0.13 ,∆T =6.2

So, Q = 8.21×0.13×6.2=6.61 J

Answer:

A13+

Explanation:

I took a test that had this question.

Answer:

resultant

Explanation:

Answer:

i the answer to your question should be C

Explanation:

Hope this helps!

The atomic mass of an element related to a mole in grams, is the mass of one mole of atoms. Therefore, option C is correct.

An atom's mass is its atomic mass. Although the kilogramme is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.

A mass that is one-twelfth the mass of an atom of carbon-12 is known as an atomic mass unit. Any isotope of any element's mass is represented in terms of the carbon-12 reference standard.

The size of an atom is indicated by its atomic mass. Technically speaking, an atom's mass is the total weight of its protons, neutrons, and electrons.

Thus, option C is correct.

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Answer:

His kinetic energy is converted into potential energy.

Explanation:

Answer:

0.354 molal

Explanation:

The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).

Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( [tex]10^{-3}[/tex] ) and kilo- denotes a factor of one thousand ( [tex]{10}^3[/tex] ),

[tex]1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}[/tex].

To calculate the corresponding molality of the solution, the formula

[tex]Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)}[/tex] is used.

Therefore,

[tex]Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)[/tex]

It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.

We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;

t1 = time taken for Rn to equilibrate = 4.0 s

t2 = time taken for Ne to equilibrate = ?

M1 = molar mass of Rn = 222g/mol

M2 = molar mass of Ne = 20 g/mol

Using

t1/t2 = √M1/M2

4/t2 = √222/20

4/t2 = 3.33

t2 = 4/3.33

t2 = 1.2 seconds

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This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:

N₂(g) + O₂(g) ⇄ 2 NO(g)

Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:

There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:

[tex]\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)[/tex]

Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:

[tex]\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K[/tex]

Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:

[tex]\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol[/tex]

And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:

[tex]K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}[/tex]

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The elements in the lanthanide series are similar to gadolinium.

The periodic table is arranged in groups and periods. Elements in the same group have similar properties. At the bottom row of the periodic table lies a group of elements that have unique properties called the lanthanides. This is where Gadolinium belongs.

The elements in the lanthanide series such as europium and terbium are similar to gadolinium. The lanthanides are similar in chemical reactivity and appearance. However, the density of the metals differ because it increases with increase in atomic number.

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Answer:

A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.

Explanation:

The molar volume (Vm) is the volume occupied by one mole of a chemical element or chemical compound at standard temperature and pressure (STP). The molar volume of Cl₂ is 35.10 cm³/mol.

One mole of any gas has a defined volume when it is at a particular temperature and pressure. The relationship between molar mass and molar volume is direct and inverse, respectively.

Two gases have equal molecules if their volumes are the same at a given temperature and pressure. A gas's volume is directly proportional to the number of moles it contains. One mole of any gas takes up 22.4 L of space at STP.

The expression used to calculate molar volume is:

Molar volume = Molar mass / Density

The molar mass of Cl₂ = 70.906 g/mol

Molar volume = 70.906 / 2.02

Molar volume = 35.10 cm³/mol

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Answer:

273.15 Kelvins

Explanation: