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In introductory physics, a typical cavendish balance for measuring the gravitational constant G use metal masses 2.39kg and 16g whose center are separated by 6.81cm calculate the gravitation force between these forces, treating each as a point mass located at the center of the sphere.

gravitational constant =6.67259 × 10⁻¹¹N·m²/kg²

Answers

Answer 1

Answer:

Explanation:

F = GMm/d²

F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²

F = 5.5019685...x 10⁻¹⁰ N

round as appropriate, probably no more than 3 significant figures.

Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹

Related Questions

What is the force exerted on a selectively permeable membrane because water has moved from an area of higher concentration to an area of lower concentration of water?
Diffusion
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Answers

Question

what is the force exerted on a selectively permeable membrane beacuse water has moved from an area of higher concentration to an area of Lower concentration of water?

Answer

OSMOSIS

Explanation

Osmosis: This is the hydrostatic force acting to equalize the concentration of water on both sides of the membrane that is impermeable to substances dissolved in that water. Water will move along its concentration gradient.

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If a wave is traveling at a constant speed, and the frequency decreases, what would happen to the wavelength?

A. It would increase.

B. It would decrease.

C. It would remain constant.

D. It would drop to zero.

Answers

It would decrease because the frequency is decreasing

an object is traveling with a constant velocity of 5m/s. How far will it have gone after 7s

Answers

Answer:

35m/s

Explanation:

Answer:

35m/s

Explanation:

Simply multiply 5 and 7.

You are standing 30 m due east of a 50 kg person who is running at a speed of 20 m/s due west. What is the magnitude of that person's angular momentum about you (in units of )

Answers

Hi there!

We can use the following equation for angular momentum:

[tex]\large\boxed{L = mrv}[/tex]

m = mass (kg)

r = distance from reference point (m)

v = velocity (m/s)

We can simply plug-and-chug the values provided in the question.

L = (50)(30)(20) = 30000 kgm²/s

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