Please answer & number. Thank you! <33

Answer:

The test statistics will be "-0.876",

Step-by-step explanation:

Given:

According to the question,

Level of significance will be:

= 0.05

Now,

The test statistics will be:

= [tex]\frac{\bar x-\mu}{\frac{s}{\sqrt{n} } }[/tex]

By substituting the values, we get

= [tex]\frac{18.6-19}{\frac{3.1}{\sqrt{46} } }[/tex]

= [tex]-\frac{2.713}{3.1}[/tex]

= [tex]-0.876[/tex]

Answer:

[tex]y= -x^{2} -2x+15[/tex]

Step-by-step explanation:

[tex]y= -x^{2} -2x+15[/tex]

total area =A1+A2+A3

A1=1/2b*h

A1=1/2*8mm*6mm

A1=24mmsquare

A2=1/2b*h

A2=1/2*8mm*6mm

A2=24mmsquare

A3=b*h

A3=8mm*6mm

A3=48mmsquare

Atotal=24mmsquare+24mmsquare+48mmsquare

Atotal=96mmsquare

Answer:

[tex]f(g(2)) = 2[/tex]

Step-by-step explanation:

Given

[tex]x \to f(x)[/tex]

[tex]-6 \to 1[/tex]

[tex]-3 \to 2[/tex]

[tex]g(x) = f^{-1}(x)[/tex] --- inverse

Required

[tex]f(g(2))[/tex]

For two functions f(x) and g(x) where f(x) and g(x)are inverse;

[tex]f(g(x)) = x[/tex]

So, by comparison:

[tex]f(g(2)) = 2[/tex]

591 Dollars 42 Cents (591 Dollars when rounded)

Answer:

The p-value is 0.2789 > 0.05, which means that the appropriate conclusion is that the students do not score differently.

Step-by-step explanation:

It is believed that students who begin studying for final exams a week before the test score differently than students who wait until the night before.

At the null hypothesis, we test if the two means are equal, that is, the subtraction of them is 0.

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

At the alternative hypothesis, we test if the two means are different, that is, the subtraction of them is different of 0. So

[tex]H_1: \mu_1 - \mu_2 \neq 0[/tex]

A hypothesis test for two independent samples is run based on your data and a p-value is calculated to be 0.2789.

Considering a standard significance level of 0.02789, the p-value is 0.2789 > 0.05, which means that the appropriate conclusion is that the students do not score differently.

Answer:

455 ways

Step-by-step explanation:

Given

[tex]n = 15[/tex] --- friends

[tex]r = 3[/tex] -- available postcard kinds

Required

Ways of sending the cards

The question is an illustration of combination and the formula is:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

So, we have:

[tex]^{15}C_3 = \frac{15!}{(15 - 3)!3!}[/tex]

[tex]^{15}C_3 = \frac{15!}{12!*3!}[/tex]

Expand

[tex]^{15}C_3 = \frac{15*14*13*12!}{12!*3*2*1}[/tex]

[tex]^{15}C_3 = \frac{15*14*13}{3*2*1}[/tex]

[tex]^{15}C_3 = \frac{2730}{6}[/tex]

[tex]^{15}C_3 = 455[/tex]

that alot of work shhheeshhh

Answer:

There are 2 x intercepts

Answer:

Iam going to do question 21

Step-by-step explanation:

1/7*x=2

1/7x=2

x=2:1/7

x=2*7/1

x=14

Answer:

The roots(Zeros) are

x=2.7913 and -1.7913

Answer:

If rounded to the nearest 10 bacteria, then it would be 500 bacteria.

Step-by-step explanation:

First multiply 150 by two in order to get 300, that leaves 4 hours to figure out. From there you can figure out the rest by seeing that 4 is 2/3 of 6. I converted it into the decimal number .66. Multiply 300 by .66 to get 198 and then add it to 300 to get 498. Then just round it up to the nearest 10 bacteria which leaves you with the final answer of 500 bacteria.

Answer:

2000*(1.08)^t where t is years after deposit

Step-by-step explanation:

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.

(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.

(c) Estimate the parameter using the data: phat = 27/212 = 0.127.

(d) Standard error (or SE).

(e) Compute the SE using phat = 0.127 in place of p:

SE ≈ √(phat(1−phat)/n) = 0.023.

(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.

(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).

Answer:

1) x = 2

Step-by-step explanation:

Hope it helps. I'll try to solve the second one too

9514 1404 393

Answer:

Step-by-step explanation:

1. Substitution can work for this.

  2x +3(4x -5) = 13

  14x = 28 . . . . . add 15

  x = 2 . . . . . . . divide by 14

__

2. The equation z=6 eliminates all but the 1st and 3rd choices. Using that value in the first equation gives ...

  x + y + 6 = 5

  x + y = -1

Only the 3rd choice satisfies this equation.

  (x, y, z) = (-5, 4, 6)

Answer:

[tex]3\frac{4}{5}[/tex]

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]3\frac{4}{5}[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the answer...}}\\\\8\frac{1}{5}-4 \frac{2}{5}\\-------------\\\text{Converting the mixed numbers into improper fractions...}\\\\\rightarrow 8\frac{1}{5} =\frac{41}{5}\\\\\rightarrow 4\frac{2}{5}=\frac{22}{5} \\-------------\\\frac{41}{5} -\frac{22}{5}\\\\\rightarrow\boxed{ \frac{19}{5}}\\-------------\\\\text{5 would go into 19 3 times with 4 as the remainder.}\\\\\frac{19}{5}=\boxed{3\frac{4}{5}}\\-------------\\\text{\textbf{Therefore:}}\\\\[/tex]

[tex]8\frac{1}{5}-4\frac{2}{5}=\boxed{3\frac{4}{5}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The mean number of miles between services is 4959 miles, with a standard deviation of 448 miles

This means that [tex]\mu = 4959, \sigma = 448[/tex]

Sample of 43:

This means that [tex]n = 43, s = \frac{448}{\sqrt{43}}[/tex]

What is the probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles?

p-value of Z when X = 4959 + 111 = 5070 subtracted by the p-value of Z when X = 4959 - 111 = 4848, that is, probability the sample mean is between these two values.

X = 5070

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{5070 - 4959}{\frac{448}{\sqrt{43}}}[/tex]

[tex]Z = 1.62[/tex]

[tex]Z = 1.62[/tex] has a p-value of 0.9474

X = 4848

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{4848 - 4959}{\frac{448}{\sqrt{43}}}[/tex]

[tex]Z = -1.62[/tex]

[tex]Z = -1.62[/tex] has a p-value of 0.0526

0.9474 - 0.0526 = 0.8948

0.8948 = 89.48% probability that the mean of a sample of 43 cars would differ from the population mean by less than 111 miles

[tex]x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]

Answer:

 B and D are polynomial

Step-by-step explanation:

An algebraic expression with non-zero coefficients and variables having non-negative integers as exponents is called a polynomial.

A)

If it is [tex]1 -\frac{5x^{2}}{x }=1-5x[/tex]   , then it is a polynomial.

But if it is [tex]\frac{1-5x^{2}}{x}[/tex] then it is not a polynomial

Answer:

0.0069

Step-by-step explanation:

According to the Question,

We have, μ=22 , σ= 5 , P(X<9.7)=Area to the left of 9.7.

Z = (x-μ)/σ

Z = (9.7-22) / 5 ⇒ -2.46

Thus,

Step-by-step explanation:

[tex]G(t) =\displaystyle \int (4 + t + t^2)dt[/tex]

[tex]\:\:\:\:\:\:\:=4t + \frac{1}{2}t^2 + \frac{1}{3}t^3 + C[/tex]

Check:

[tex]\dfrac{d}{dt}(4t + \frac{1}{2}t^2 + \frac{1}{3}t^3+C)= 4 + t + t^2 =g(t)[/tex]

Answer:

HL

Step-by-step explanation:

Since both triangles are right angle triangles that means one angle is 90°. other two sides are given congruent .

that means lengths of hypotenuse and the leg of the one right angle triangle is equal to the corresponding other hypotenuse and leg of other triangle.

This fulfills the condition of HL congruency.

9514 1404 393

Answer:

  see below

Step-by-step explanation:

Put the x-value in the equation and do the arithmetic.

For example, ...

  for x = -5,

  y = -10(-5) +3 = 50 +3 = 53

Answer: [tex]y=7\dfrac{1}{3}[/tex].

Step-by-step explanation:

[tex]\dfrac{y}{9} =\dfrac{44}{54} \\\\y \times 54=44 \times 9\\\\54y=396\\\\54y \div 54=396 \div 54\\\\y=7\dfrac{1}{3}[/tex]

Answer:

me too

Step-by-step explanation:

me too

Answer:

3x^2 + 10x

Step-by-step explanation:

If u wrote it correctly it would be ((x+4+2)+4)(x)

Answer:

should just be 4/6 or 2/3 simplified lol

Step-by-step explanation:

ratios and fractions are very similar, just pronounced differently. 4:6 is read as "four to fix" while 4/6 is read as "four sixths". only difference is the punctuation

To prove that: (2cosA+1) (2cosA-1) = 2cos2A+1

We try to solve one side of the equation to get the other side of the equation.

In this case, we'll solve the right hand side (2cos2A + 1) of the equation with the aim of getting the left hand side of the equation  (2cosA + 1)(2cosA - 1)

Solving the right hand side: 2cos2A + 1

i. We know that cos2A = cos(A+A) = cosAcosA - sinAsinA

Therefore;

cos2A = cos²A - sin²A

ii. We also know that: cos²A + sin²A = 1

Therefore;

sin²A = 1 - cos²A

iii. Now re-write the right hand side by substituting the value of cos2A as follows;

2cos2A + 1 = 2(cos²A - sin²A) + 1

iv. Expand the result in (iii)

2cos2A + 1 = 2cos²A - 2sin²A + 1

v. Now substitute the value of sin²A in (ii) into the result in (iv)

2cos2A + 1 = 2cos²A - 2(1 - cos²A) + 1

vi. Solve the result in (v)

2cos2A + 1 = 2cos²A - 2 + 2cos²A + 1

2cos2A + 1 = 4cos²A - 2 + 1

2cos2A + 1 = 4cos²A - 1

2cos2A + 1 = (2cosA)² - 1²

vii. Remember that the difference of the square of two numbers is the product of the sum and difference of the two numbers. i.e

a² - b² = (a+b)(a-b)

This means that if we put a = 2cosA and b = 1, the result from (vi) can be re-written as;

2cos2A + 1 = (2cosA)² - 1²

2cos2A + 1 = (2cosA + 1)(2cosA - 1)

Since, we have been able to arrive at the left hand side of the given equation, then we can conclude that;

(2cosA + 1)(2cosA - 1) = 2cos2A + 1

Answer:

[tex]\boxed{\sf LHS = RHS }[/tex]

Step-by-step explanation:

We need to prove that ,

[tex]\sf\implies (2 cosA +1)(2cosA-1) = 2cos2A+1[/tex]

We can start by taking RHS and will try to obtain the LHS . The RHS is ,

[tex]\sf\implies RHS= 2cos2A + 1 [/tex]

We know that , cos2A = 2cos²A - 1 ,

[tex]\sf\implies RHS= 2(2cos^2-1)-1 [/tex]

Simplify the bracket ,

[tex]\sf\implies RHS= 4cos^2A - 2 +1 [/tex]

Add the constants ,

[tex]\sf\implies RHS= 4cos^2-1 [/tex]

Write each term in form of square of a number ,

[tex]\sf\implies RHS= (2cos^2A)^2-1^2 [/tex]

Using (a+b)(a-b) = a² - b² , we have ,

[tex]\sf\implies RHS= (2cosA+1)(2cosA-1) [/tex]

This equals to LHS , therefore ,

[tex]\sf\implies \boxed{\pink{\textsf{\textbf{ RHS= LHS }}}} [/tex]

Hence Proved !

Answer:

ok so its is 5 dollars for a pencil and 420 dollars for a pen(dang)

a40+2100=2140

now

b6 pencil 462 pen

60+3696=3756

Hope This Helps!!!

(a) Afua paid ¢44,500.00 for 8 pencils and 5 pens.

(b) Afua will pay ¢71,400.00 for 10 pencils and 8 pens after the price increase.

(a) To find how much Afua paid altogether for 8 pencils and 5 pens, we need to calculate the total cost for each item and then add them together.

Given:

Cost of a pencil, [tex]Pencil_{cost}[/tex] = ¢500.00

Cost of a pen, [tex]Pen_{cost}[/tex] = ¢42,000.00

Number of pencils bought, [tex]n_{pencils}[/tex] = 8

Number of pens bought, [tex]n_{pens}[/tex] = 5

Total cost of pencils,

[tex]Total_{pencil}_{cost} = Pencil_{cost} * n_{pencils}[/tex]

                      = ¢500.00 × 8

                      = ¢4,000.00

Total cost of pens,

[tex]Total_{pen}_{cost} = Pen_{cost} * n_{pens}[/tex]

                   = ¢42,000.00 × 5

                   = ¢210,000.00

Altogether, [tex]Total_{cost} = Total_{pencil}_{cost} + Total_{pen}_{cost}[/tex]                                      

                                  = ¢4,000.00 + ¢210,000.00

                                  = ¢214,000.00.

Therefore, Afua paid ¢214,000.00 for 8 pencils and 5 pens.

(b) Now, let's calculate the new total cost after the price increase.

The price of a pencil increased by 20%, which means the new pencil cost is:

[tex]New_{pencil}_{cost}[/tex] = [tex]Pencil_{cost}[/tex]+ (20% × [tex]Pencil_{cost}[/tex])

                                  = ¢500.00 + (0.20 × ¢500.00)

                                  = ¢500.00 + ¢100.00

                                  = ¢600.00

Similarly, the price of a pen increased by 10%, which means the new pen cost is:

[tex]New_{pen}_{cost}[/tex] = [tex]Pen_{cost}[/tex] + (10% × [tex]Pen_{cost}[/tex])

                          = ¢42,000.00 + (0.10 × ¢42,000.00)

                          = ¢42,000.00 + ¢4,200.00

                          = ¢46,200.00

Now, we can find the total cost for 10 pencils and 8 pens with the increased prices:

Number of pencils to be bought, [tex]n_{pencils}_{new}[/tex] = 10

Number of pens to be bought, [tex]n_{pens}_{new}[/tex] = 8

Total cost of pencils with new prices,

[tex]Total_{pencil}_{cost}_{new}[/tex] =[tex]New_{pencil}_{cost}[/tex] × [tex]n_{pencils}_{new}[/tex]

                                        = ¢600.00 × 10

                                        = ¢6,000.00

Total cost of pens with new prices,

[tex]Total_{pen}_{cost}_{new}[/tex] = [tex]New_{pen}_{cost}[/tex] × [tex]n_{pens}_{new}[/tex]

                                    = ¢46,200.00 × 8

                                    = ¢369,600.00

Altogether, [tex]New_{total}_{cost}[/tex] = [tex]Total_{pencil}_{cost}_{new}[/tex] + [tex]Total_{pen}_{cost}_{new}[/tex]

                                               = ¢6,000.00 + ¢369,600.00

                                               = ¢375,600.00

Therefore, Afua will pay ¢375,600.00 for 10 pencils and 8 pens with the increased prices.

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