plea help I will give brainiest

Answer:

Since x + y + z = 180° and z = 90°, y + z = 90°

Thus x + y = z  

Step-by-step explanation:

Answer:

2/7

Step-by-step explanation:

Since the denominators are the same, we need to add the numerators and place it over the common denominator

-4+6 = 2

so

-4/7 + 6/7 = 2/7

2/7

Answer:

B

Step-by-step explanation:

Step-by-step explanation:

if x-4 is a factor of 2x^3 + x^2- 26x - 40

then f(4) = 0

f(x) = 2x^3 + x^2- 26x - 40

f(4) = 2(4)^3 + (4)^2 - 26(4) - 40

f(4)= 2(64) + 16 - 104 - 40

f(4) = 128 + 16 - 104 - 40

f(4) = 0

hence factorize completely is the photo

Answer:

y < 2x -3

Step-by-step explanation:

Answer:

4-6x=y2

Step-by-step explanation:

Step-by-step explanation:

Say 21 divided by 3, which gives you 7

So mai has 7 books

Answer:

Mai has 7 books

Step-by-step explanation:

Tyler has 21 books and 3 times more than Mai

21/3 = 7

*see attachement for the diagram that is being referred to

Answer:

m<ACB = 50°

Step-by-step explanation:

From the diagram, <DCB is a right angle = 90°

Therefore:

m<DCA + m<ACB = 90° (complementary angles)

m<DCA = 40° (given)

Thus:

40° + m<ACB = 90° (Substitution)

m<ACB = 90° - 40° (Subtraction property of equality)

m<ACB = 50°

Answer:

Step-by-step explanation:

2 angles are added to result in = 180°

therefore

180 = 97 - 3x + 69 + 5x

180 = 166 + 2x

2x = 180 - 166

2x = 14

x = 14 ÷ 2

The value of x = 7

______________

#IndonesianPride

- kexcvi

Answer : b: How many push-ups can a sixth grade girl do? and d:What are the weights of the sixth grade boys?

Answer:

How much do sixth grade boys weigh?

 How many push-ups can a sixth grade girl do?

Step-by-step explanation:

A statistical question is one that has a variable answer.

Determine which questions are statistical questions and can be answered with the data gathered in the fitness test.

The questions "How many sixth grade students are there?" and "What is the shortest height of the sixth grade students?" can be answered with the data gathered in the fitness test. However, they do not have variable answers, so they are not statistical questions.

The questions "What are the heights of the eighth grade girls?" and "How many chin-ups can a sixth grade boy do?" do have variable answers, so they are statistical questions. However, these questions cannot be answered with the data gathered in the fitness test.

The questions "How much do sixth grade boys weigh?" and "How many push-ups can a sixth grade girl do?" do have variable answers, so they are also statistical questions. These questions can be answered with the data gathered in the fitness test.

Hope I helped.

Answer:

26

Step-by-step explanation:

You take the 65 plyers multiplied by the 40 % then you get 2600. You take that divided by 100 and get 26

Answer:

she brought 21 shirts and two pants

Step-by-step explanation:

shirt

21 × 14.50 = 304.50

357- 304.50 = 52.5

pants

52.5 ÷ 25 = 2.1

Answer:

Your answer is -11

Step-by-step explanation:

85-96=-11

Answer:

2

Step-by-step explanation:

Answer: 6*10^5 > 3*10^4

Step-by-step explanation:

6*10^5 = 600000

3*10^4 = 30000

Answer:

X - 3 = 5

Step-by-step explanation:

X decreased by 3 means X-3.

If X - 3 is 5, then it can be written as X - 3 = 5

Answer: 8

Step-by-step explanation: 8 decreased (subtracted) by 3 is 5.

Answer:

-√2

Step-by-step explanation:

C on Edg

Answer: - square root 2

Step-by-step explanation: c on edge

Answer:

y = 10x + 15

Step-by-step explanation:

y +25 = 10(x+4)

y = 10x + 40 - 25

y = 10x + 15

Answer:

Fraction: 10 and 5/8

Step-by-step explanation:

17 × 5/8

85/8

Answer:[tex]10\frac{5}{8}[/tex] or 10.625

Step-by-step explanation:

First of all, note that 17 is the same as 17/1 since 17 divided by 1 is 17. Therefore, start by setting up the problem like this:

[tex]\frac{17}{1} X \frac{5}{8}[/tex]

Multiply the numerators together (17 x 5 = 85) and multiply the denominators together (1 x 8 = 8) and make it into one fraction like so:

[tex]\frac{85}{8}[/tex]

Convert the improper fraction above to a mixed number to get the answer:

[tex]=10\frac{5}{8}[/tex]

Answer:

The answer is below

Step-by-step explanation:

Two triangles are similar if the ratio of their corresponding sides are in the same proportion.

1. ΔWXY is isosceles with legs WX and WY      (given)

2. ΔWVZ is isosceles with legs WV and WZ     (given)

3. WX =  WY, WV = WZ  (definition of an isosceles triangle)

4. [tex]\frac{WX}{WY}=1\\\\[/tex]

[tex]\frac{WX}{WY}=\frac{WZ}{WZ} \ \ \[/tex] (definition of ≅)

5. (WZ)(WX) = (WY)(WZ)       (multiplication property)

6. (WZ)(WX) = (WY)(WV)  (substitution property).

7. [tex]\frac{WY}{WZ}=\frac{WX}{WV}[/tex]      (property of proportion)

8. ∠W = ∠W (reflexive property)

9. ΔWXY ~ ΔWVZ (side - angle - side similarity postulate)

Answer:

♣:  

✔ WX = WY; WV = WZ

♦:  

✔ substitution property

♠:  

✔ SAS similarity theorem

Step-by-step explanation:

just took it :)

Answer:

A) y = 5

Step-by-step explanation:

30 / 6 = 5

y = 5

Hope this helps! Have a nice day! Plz mark as brainliest!!!

-XxDeathshotxX

Answer:

what do we have to do in this?????

Answer:

the answer is 5.25p=19.50

Answer:

The answer is 578.57

Step-by-step explanation:

your welcome

Answer:

[tex]\sin\,\theta =-\frac{\sqrt{21} }{5}[/tex]

[tex]\tan\,\theta =\frac{\sqrt{21} }{2}[/tex]

[tex]\sec\,\theta = \frac{-5}{2}[/tex]

[tex]cosec\,\theta =\frac{-5}{\sqrt{21} }[/tex]

[tex]\cot\,\theta =\frac{2}{\sqrt{21} }[/tex]

Step-by-step explanation:

[tex]\cos\theta =\frac{-2}{5}<0\\sin\theta <0[/tex]

As both [tex]sin\,\theta<0,\,\cos\,\theta <0[/tex],

[tex]\theta[/tex] lies in the third quadrant.

In the third quadrant,

[tex]\sin\theta<0,\,\cos\,\theta <0\,,\,\sec\,\theta<0,\,cosec\theta<0,\,tan\,\theta>0,\,cot\,\theta>0[/tex]

[tex]\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}[/tex]

[tex]\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}[/tex]

[tex]\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}[/tex]

[tex]\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }[/tex]

[tex]\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }[/tex]