Place each object on the measurement tray, one at a time. Which objects have a mass greater
than 300 grams?
How do you know?

Answer:

the independent variable is the beakers

Explanation:

Answer:

will i think the 21.0cm

[tex]0.68 \: moles \: calcium \times \frac{6.02 \times {10}^{23} \: calcium \: atoms }{1 \: mole \: calcium} \\ [/tex]

The (( mole calcium ))s are simplified so the answer is based on the number of calcium atoms.

[tex]0.68 \times 6.02 \times {10}^{23} = 68 \times {10}^{ - 2} \times 602 \times {10}^{ - 2} \times {10}^{23} \\ [/tex]

[tex] = 68 \times 602 \times {10}^{ - 4} \times {10}^{23} = 40936 \times {10}^{19} \\ [/tex]

[tex] calcium \: atoms = 40936 \times {10}^{19} \\ [/tex]

_________________________________

And we're done.

Thanks for watching buddy good luck.

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Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia. ... If that velocity is zero, then the object remains at rest.

Explanation:

Answer:

Before Galileo and Newton, many people thought that objects lost speed because they had a built-in natural tendency to do so. But those people weren't taking into account the multiple forces here on Earth - for example, friction, gravity, and air resistance - that cause objects to change their speed. If we could see the motion of an object in deep interstellar space, we would be able to observe the natural tendencies of an object that is free from any external influence. In deep interstellar space we would observe that if an object had a speed, it would continue to move with that speed until there was some force causing a change in its motion. Likewise, if an object were at rest in interstellar space, it would remain at rest until there was a force causing a change in its motion.

Explanation:

Hope it helped you =)

Answer:

They both have two valence electrons

Answer:

I am guessing because they are both metals

Answer:

D. Atom, Electron, and Proton

Explanation:

Because Atoms are the smallest and they make up everything.

because  the Proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.

Answer:

C

Explanation:

Electrons are the smallest part of matter. Protons are bigger than electrons. And the whole atom is bigger than everything inside it.

Answer:

(i) Final pressure and temperature are 25.119 bar and 753.566 K, (ii) Final pressure and temperature are 66.289 bar and 994.336 K.

Explanation:

This system experiments an adiabatic compression, as such compression happens with no heat interaction between the piston-cylinder device and surroundings. This is a particular case of polytropic process, in which there is no entropy generation according to the Second Law of Thermodynamics.

The compression process is represented by the following formulas:

[tex]\frac{p_{2}}{p_{1}} = \left(\frac{V_{1}}{V_{2}} \right) ^{\gamma}[/tex] (Eq. 1)

[tex]\frac{T_{2}}{T_{1}} = \left(\frac{V_{1}}{V_{2}} \right)^{\gamma - 1}[/tex] (Eq. 2)

Where:

[tex]p_{1}[/tex], [tex]p_{2}[/tex] - Initial and final pressures, measured in bar.

[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures, measured in Kelvins.

[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Initial and final volumes, measured in cubic meters.

[tex]\gamma[/tex] - Specific heat ratio of air, dimensionless.

From Theory of Diesel and Otto Cycles we know that compression ratio is defined as:

[tex]r_{c} = \frac{V_{1}}{V_{2}}[/tex] (Eq. 3)

And (Eqs. 1, 2) can be rewritten as follows:

[tex]\frac{p_{2}}{p_{1}} = r_{c}^{\gamma}[/tex] (Eq. 1b)

[tex]\frac{T_{2}}{T_{1}} = r_{c}^{\gamma - 1}[/tex] (Eq. 2b)

Then, we clear final pressure and pressure in each expression and calculate them for each case:

[tex]p_{2} = p_{1}\cdot r_{c}^{\gamma}[/tex]

[tex]T_{2} = T_{1}\cdot r_{c}^{\gamma-1}[/tex]

(i) [tex]r_{c} = 10[/tex], [tex]p_{1} = 1\,bar[/tex], [tex]T_{1} = 300\,K[/tex], [tex]\gamma = 1.4[/tex]

[tex]p_{2} = (1\,bar)\cdot 10^{1.4}[/tex]

[tex]p_{2} = 25.119\,bar[/tex]

[tex]T_{2} = (300\,K)\cdot 10^{0.4}[/tex]

[tex]T_{2} = 753.566\,K[/tex]

Final pressure and temperature are 25.119 bar and 753.566 K.

(ii) [tex]r_{c} = 20[/tex], [tex]p_{1} = 1\,bar[/tex], [tex]T_{1} = 300\,K[/tex], [tex]\gamma = 1.4[/tex]

[tex]p_{2} = (1\,bar)\cdot 20^{1.4}[/tex]

[tex]p_{2} = 66.289\,bar[/tex]

[tex]T_{2} = (300\,K)\cdot 20^{0.4}[/tex]

[tex]T_{2} = 994.336\,K[/tex]

Final pressure and temperature are 66.289 bar and 994.336 K.

In the redox reaction involving the permanganate ion in acidic solution, permanganate ion is reduced to manganese (ii) ion while iron (ii) ion is oxidized to iron(iii) ion.

A redox reaction is a reaction in which reduction and oxidation occurs at the same time and to the same extent.

An example of a redox reaction is the reaction involving the permanganate ion and tetraoxosulphate (vi) ion in acidic solution.

The equation of the reaction is given below:

[tex]MnO_{4}^{ - } (aq) + 5Fe^{2+}(aq) + 8H^{+} \rightarrow Mn^{2+}(aq)+ 5Fe^{3+}(aq) +4H_{2}O(l) \\ [/tex]

Therefore, in the redox reaction involving the permanganate ion in acidic solution, permanganate ion is reduced to manganese (ii) ion while iron (ii) ion is oxidized to iron(iii) ion.

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Answer:

Volume of solution is 0.88 L.

Explanation:

Given data:

Molarity of solution = 0.750 M

Mass of KNO₃ = 67.0 g

Volume of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 67.0 g/ 101.1 g/mol

Number of moles = 0.66 mol

Now we will put the values in molarity formula.

0.750 M = 0.66 mol / L of solution

L of solution  = 0.66 mol / 0.750 M

L of solution  = 0.88 L

Volume of solution is 0.88 L.

Answer:

equilateral (B)

Explanation:

it is the only word which relates to triangles and their shape - plus, its logical and makes sense.

Answer:

its b

Explanation:

Answer:

DE

Explanation:

BC has a constant speed of 0, and DE does not have a consistent slope, therefore the speed is changing

The speed is defined as the rate of change of distance with respect to time.

In interval DE , speed of the object is changing.

Since, speed is defined as the rate of change of distance with respect to time.

   [tex]v=\frac{dx}{dt}[/tex]  , where x represent distance.

Slope of given graph represent distance, In interval BC slope is constant.

In interval, DE slope is always changing at each point.

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Please do mark me as Brainiest. I would be so happy!!! Here's your answer....

Answer:

D.)

Explanation:

Compact fluorescent lamps, or CFLs, use 75 percent less energy than a traditional incandescent bulb, but they never quite caught on for home use.

Have a great rest of your day!

Answer:

The given metal sample is not aluminum because its density is 3.0 g/cm³ while density of aluminum is  2.7 g/cm³.

Explanation:

Given data:

Density of aluminum = 2.7 g/cm³

Mass of metal sample = 52.0 g

Volume of metal sample = 17.1 cm³

which sample is that = ?

Solution:

The given problem will be solve through density formula.

d = m/v

d = density

m = mass

v= volume

Now we will put the values in formula.

d = 52.0 g/ 17.1 cm³

d = 3.0 g/cm³

It is given in question the density of aluminum is 2.7 g/cm³. The given metal sample is not aluminum because its density is 3.0 g/cm³.

Answer:

They are called subshells

electron configuration

Explanation:

C option i think but I didn't know

Answer: the particles in the water heats up and the hotter to gets the faster it moves. When there is no where for the heat to go it builds up and pushes its way out and turns to steam when it hits cool air

Explanation:

Answer:

O nome "transição" vem da posição dos elementos na tabela, representando a transição do grupo 2 ao 13, pela sucessiva adição de elétrons ao orbital d. Elementos de transição externa (ou somente elementos de transição):

Answer:

Because the sugar flour and eggs can no longer be separated. The properties of the materials have changed so it's a chemical change

Sugar, flour, and eggs cannot be separated. The materials' properties have changed, resulting in a chemical change.Therefore, crumbling a cookie is not a physical change.

Physical changes affect a chemical substance's form but not its chemical composition. Physical changes can be used to separate mixtures into their component compounds, but not to separate compounds into chemical elements or simpler compounds.

A chemical change is the transformation of one material into another, the formation of new materials with different properties, and the formation of one or more new substances. It occurs when one substance reacts with another to form a new substance.

A physical change is characterized by a change in physical properties. Melting, transition to a gas, change in strength, change in durability, changes in crystal form, textural change, shape, size, colour, volume, and density are all examples of physical properties.

Thus, crumbling a cookie is not a physical change.

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Answer:

112.5

Explanation:

I think so because in one unit has 4 oxygen atoms.

Answer:

EL Niño  had hurricanes and so many damages in nature. :)

Explanation:

it creates warm weather, there is low pressure towards canada

Numerous health issues, such as disease outbreaks, malnutrition, heat stress, and respiratory illnesses are being brought on by the severe drought and associated food insecurity, flooding, precipitation, and temperature increases brought on by El Nino.

The exceptional warming of surface waters in the eastern tropical Pacific Ocean is referred to as El Nino, a climate pattern. El Nino is a bigger phenomena known as the El Nino-Southern oscillation, and it is its warm phase.

Climate change brought on by El Nino can be severe and extensive. Increased precipitation results from convection over warmer surface waters. In Ecuador and northern Peru, rainfall rises dramatically, causing coastal erosion and flooding.

Homes, businesses, schools, and hospitals may be destroyed by heavy rains and flooding. They hinder transportation and obliterate crops. As reservoirs dry up and rivers carry less water, the droughts pose a threat to the area's water resources. Agriculture is in danger since it depends on water for irrigation.

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Answer:

30

Explanation:

25.0 + 5.0  = 30

Answer:

30

Explanation:

Group 17 elements called halogens . All halogens have the same number of valence

electrons

Answer:

False

Explanation:

Answer:

what? what's the full question?

Answer:

-56.1kJ/mol

Explanation:

The reaction between HCl and NaOH is:

NaOH + HCl → NaCl + H₂O + ΔH

Where ΔH is heat change in  the reaction.

As the temperature of the solution increases, the heat is released and ΔH < 0

The heat released in the reaction is obtained using coffe-cup calorimeter equation:

Q = C×m×ΔT

Where Q is heat

C is specific heat of the solution (4.184J/g°C)

m is mass of solution: Assuming density = 1g/mL, 100mL of solution = 100g

And ΔT is change in temperature (13.4°C)

Replacing:

Q = C×m×ΔT

Q = -4.184J/g°C×100g×13.4

Q = -5606.6J

Now, in the reaction you have:

Moles HCl:

0.050L * (2.2mol/L) = 0.11 moles

Moles NaOH:

0.050L * (2.0mol/L) = 0.1 moles

That means the moles of reaction are 0.1 moles, and heat change in the chemical reaction is:

5606.6J / 0.1 mol = 56066J =

Answer:

Time = 8.12 h = 0.34 day

Explanation:

First we find speed of water flow:

Speed = u = (3160 tons/s)(907.185 kg/1 ton)

u = 2866704.6 kg/s

also,

Density = (1 g/mL)(1 mL/1 x 10⁻⁶ m³)(1 x 10⁻³ kg/1 g)

Density = 1000 kg/m³

Now,

Volume Flow Rate = Speed/Density

Volume Flow Rate = (2866704.6 kg/s)/(1000 kg/m³)

Volume Flow Rate = 2866.7 m³/s

Now, we find volume of cylinder:

Volume = (Area)(Length)

Volume = (πd²/4)(L)

Volume = [(π)(0.53 m)²/4][236000 mi][1609.36 m/1 mi]

Volume = 83,792,823.82 m³

Now,

Time = Volume/Volume Flow Rate

Time = (83,792,823.82 m³)/(2866.7 m³/s)

Time = (29299.71 s)(1 h/3600 s)

Time = 8.12 h = 0.34 day

Answer:

a

[tex]\Delta H^o _{rxn} = -2568.9 \  kJ [/tex]

b

[tex]H  = 350 JK^{-1}[/tex]

c

[tex]T_{max}  = 32.4 ^o C[/tex]

Explanation:

From the question we are told that

 The reaction of cyclobutane and oxygen is

         [tex]C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}[/tex]

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

      [tex]\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ][/tex]

=>  [tex]\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0][/tex]

=>  [tex]\Delta H^o _{rxn} = -2568.9 \  kJ [/tex]

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is  mathematically represented as

     [tex]H  = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}][/tex]

=>  [tex]H  = [ 4 * 37.1 + 6* 33.6 ][/tex]

=>   [tex]H  = 350 JK^{-1}[/tex]

From the question the initial temperature of reactant is  [tex]T_i  =  25^oC[/tex]

Generally the enthalpy change([tex]\Delta H^o _{rxn}[/tex]) of the reaction is mathematically represented as

 [tex]|\Delta H^o _{rxn} |=  H  * (T_{max} -T_i)[/tex]

  [tex]  2568.9 =   350  * (T_{max} -25)[/tex]  

=> [tex]\frac{2568.9 }{350}  =  T_{max} - 25[/tex]

=> [tex]T_{max}  = 32.4 ^o C[/tex]

Answer:

13.3 L

Explanation:

Step 1: Given data

Step 2: Convert P₁ to atm

We will use the conversion factor 1 atm = 1.01325 bar.

3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm

Step 3: Calculate V₂

We will use the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

V₂ = P₁ × V₁ × T₂/T₁ × P₂

V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm

V₂ = 13.3 L