Physics - Electricity and Magnetism

A ceiling fan operates at three speeds, using 120 V of electricity from the wall. At low speeds, it uses 0.25 A. Calculate the resistance needed to generate that current. Then in 1-2 sentences, describe how the resistance would change at medium and high speeds if larger currents are needed at those speeds. Your answer should include the calculated resistance and a sentence describing your reasoning.

Answers

Answer 1

Answer:

480 Ohms for the calculations

Explanation:

For the calculations:

V = 120 and I = 0.25

V = IR

R = V/I

R = 120/0.25

R = 480 Ohms

For the sentences, I am so sorry, I do not have them yet!

Answer 2

I. The resistance which is needed to generate a current of 0.25 Ampere in the ceiling fan is 480 Ohms.

II. Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

Given the following data:

Voltage = 120 VoltsCurrent = 0.25 Ampere

To calculate the resistance needed to generate that current, we would apply Ohm's law:

Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across the two terminals of the electrical circuit and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex]V=IR[/tex]

Where;

V is the voltage measured in Volts.I is the current measured in Ampere.R is the resistance measured in Ohms.

Making R the subject of formula, we have:

[tex]R =\frac{V}{I}[/tex]

Substituting the given parameters into the formula, we have;

[tex]R=\frac{120}{0.25}[/tex]

Resistance, R = 480 Ohms

Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.

In conclusion, the larger the current, the lower the resistance would be at both medium and high speeds.

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Have a nice day!

    I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Answers

I assume you mean an angle of θ, and not 0. I also assume the given components of the initial velocity are horizontal and vertical, respectively, so that

1. the initial velocity vector is

[tex]\boxed{\vec v_i = (7.5\,\vec\imath + 13\,\vec\jmath) \dfrac{\rm m}{\rm s}}[/tex]

which means the ball is thrown with an initial speed of

√((7.5 m/s)² + (13 m/s)²) ≈ 15 m/s,

and

2. the angle made by [tex]\vec v_i[/tex] with the positive horizontal axis is θ such that

[tex]\tan(\theta) = \dfrac{13}{7.5} \implies \theta \approx \arctan(1.7) \approx \boxed{60^\circ}[/tex]

3. At time t, the ball attains a height y and horizontal range x according to

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x = (7.5 m/s) t

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(13 m/s) t - g/2 t² = 0

13 m/s - g/2 t = 0

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Plugging this time into the x equation gives a horizontal range of

x = (7.5 m/s) (26 m/s)/g ≈ 20. m

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Answers

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Answers

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WILL GIVE BRAINLIST

Answers

The forces that push upward on an indoor skydiver are lift force and air resistance.

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plz help will mark brainliest ​

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Explanation:

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Anticlockwise moment = x × 2N

20 cm× 1.2N = 2N × x

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= 18 cm

Answer: 18 cm

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Heat rising in a hot-air balloon is an example of convection.

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they are converted into thermal and sound energy as well as the kinetic energy in the air

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I hope it helps.

How do energy transformations occur in a hydroelectric plant?


The potential energy of water is converted to mechanical energy by a turbine.


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The kinetic energy of water is converted by a generator into electric energy.


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Answer:

The answer is #3: The kinetic energy of water is converted by a generator into electric energy.

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HELP
How much heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C? The specific heat for water is 4.184 J/g°C. (Include your calculation to receive credit.)

Answers

Answer: 5.05 J

Explanation:

Qcalorimeter: m*c* ΔT  --> (37.5g)*(4.184J/g ° C)*(55.2 °C – 23.0 °C)    Qcalorimeter: 5.05 J

According to specific heat capacity, 5.052 kJ of heat energy is required to raise the temperature of 37.5 g of water from 23.0°C to 55.2°C.

What is specific heat capacity?

Specific heat capacity is defined as the amount of energy required to raise the temperature of one gram of substance by one degree Celsius. It has units of calories or joules per gram per degree Celsius.

It varies with temperature and is different for each state of matter. Water in the liquid form has the highest specific heat capacity among all common substances .Specific heat capacity of a substance is infinite as it undergoes phase transition ,it is highest for gases and can rise if the gas is allowed to expand.

It is given by the formula ,

Q=mcΔT

Substitution in above formula, givesQ= 37.5×4.184×32.2=5052.18 J or 5.052 kJ.

Thus , 5.052 kJ of  heat energy is required to raise the temperature of 37.5g of water from 23.0°C to 55.2°C.

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