Peripherals are used to?

Answer:

The correct answer is "C. Qc > Kc, the reaction proceeds from right to left to reach equilibrium"

Explanation:

The reaction quotient Qc is a measure of the relative amount of products and reactants present in a reaction at a given time.

Being:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients of the balanced equation, the coefficient Q is calculated as:

[tex]Qc=\frac{[C]^{c}*[D]^{d} }{[A]^{a} *[B]^{b} }[/tex]

If Qc <Kc there is less concentration of products than in equilibrium, with which the reaction will evolve to the right to increase the concentration of products.  

If Qc> Kc, it is possible to affirm that the reaction will evolve to the left since in this case the direct reaction predominates and there will be more product present than what is obtained in equilibrium. Therefore, this product is used to promote the reverse reaction and achieve equilibrium. Then the system will evolve to the left to increase the concentration of reagents.

If Qc = Kc, it means that the reaction is in equilibrium.

In the case of the reaction:

2 SO₂ (g) + O₂ (g) ⇔ 2 SO₃(g)

the value of the constant Qc is calculated as:

[tex]Qc=\frac{[SO_{3} ]^{2} }{[SO_{2} ]^{2} *[O_{2} ]}[/tex]

Being:

and replacing:

[tex]Qc=\frac{10^{2} }{0.010^{2} *0.010}[/tex]

you get:

Qc=100,000,000=1*10⁸

Being Kc=4.3*10⁶, then Qc>Kc and the reaction proceeds from right to left to reach equilibrium.

So the correct answer is "C. Qc > Kc, the reaction proceeds from right to left to reach equilibrium"

The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

Effusion rate is inversely proportional to molar mass. NH3 will have a higher average molecule velocity, so it will diffuse faster and will reach the other side of the room more quickly.

The concentration gradient, or the rise or fall in concentration from one site to another, the amount of surface area available for diffusion, and the distance the gas particles must travel all affect the diffusion rate.

The effusion of gas molecules into a vacuum through a small hole, as a pinhole in a balloon, is a process that involves movement of gaseous species comparable to diffusion.

Therefore, The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

To learn more about Diffusion, refer to the link:

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Answer:

False

Explanation:

Temperature is the measure of the amount of kinetic energy in a substance.

It is commonly assumed that temperature measures the amount of heat, because it is commonly associated with the weather or checking for fevers.

However, temperature is truly a measure of the average kinetic energy of a substance.

Answer:

Temperature is the measure of average kinetic energy in a substance.but heat is also a form of kinetic energy so i think its also true to say that temperature is a measure of heat in a substance.

Explanation:

Answer:

The percent mass of HCl in the solution is 3.48  %

The percent mass of ethanol in the solution is 6.01  %

The molarity of silver nitrate in the solution is 3.46 M

Explanation:

Density always referrs to solution data.

1.02 g/mL = 100 g / volume of solution

Volume of solution = 98.04 mL

Molarity = moles of solute in 1L of solution (or mmoles of solute in 1mL)

M . 98.04 mL = mmoles of solute → 0.975 M . 98.04 mL = 95.59 mmoles

mmoles . PM (mg / mmol) = mg → 95.59 mmol . 36.45 mg/mmol = 3484 mg.

We convert data to g → 3484 mg . 1g/ 1000 mg = 3.48 g

The percent mass of HCl in the solution is 3.48  %

Density always referrs to solution data.

0.988 g/mL = 100 g / volume of solution

Volume of solution = 101.21 mL

Molarity = moles of solute in 1L of solution (or mmoles of solute in 1mL)

M . 101.21 mL = mmoles of solute → 1.29 M . 101.21 mL = 130.6 mmoles

mmoles . PM (mg / mmol) = mg → 130.6 mmol . 46.07 mg/mmol = 6015 mg.

We convert data to g → 6015 mg . 1g/ 1000 mg = 6.01 g

The percent mass of ethanol in the solution is 6.01  %

Density always referrs to solution data.

1.47 g/mL = 100 g / volume of solution

Volume of solution = 68.03 mL

Molarity = moles of solute in 1L of solution (or mmoles of solute in 1mL)

40 g = 40000 mg

mg / PM (mg / mmol) = mmol → 40000 mg / 169.87 mg/mmol

= 235.4 mmoles

mmoles / mL = Molarity  → 235.4 mmol / 68.03 mL = 3.46 M

Answer:

A practical pursuit of alchemy was the development of metallurgy practices.

Explanation:

As alchemists always tried to turn various metals into other things, metalworking techniques were developed even though their experiments were often unsuccessful.

Answer: developing metalworking techniques

Explanation:

trust it!!

Answer:

Decreasing pH decreases the solubility; increasing salinity increases the salinity.

Explanation:

Atmospheric carbon dioxide in seawater is involved in the following equilibria:

(i)   CO₂(g) ⇌ CO₂(aq)

(ii)  CO₂(aq) + H₂O ⇌ H₂CO₃(aq)  

(iii) H₂CO₃(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HCO₃⁻(aq)  

(iv) HCO₃⁻(aq)+ H₂O(l) ⇌ H₃O⁺(aq) + CO₃²⁻(aq)

1. Effect of pH  

Decreasing pH increases [H₃O⁺].

According to Le Châtelier's Principle, the position of equilibrium of (iv) will be pushed to the left.  

This, in turn, pushes the positions of equilibrium of (iii), (ii), and (i) to the left.

The net effect is that CO₂ is pushed out of the solution and back into the atmosphere.

Thus, decreasing the pH decreases the solubility of atmospheric CO₂.

2. Effect of salinity

Salinity includes the measurement of all ions in seawater, not just Na⁺ and Cl⁻.

An important ion that contributes to salinity is Ca²⁺.

Ca²⁺ ions are involved in the equilibrium  

Ca²⁺(aq) + CO₃²⁻(aq) ⇌ CaCO₃(s).

Thus, increasing the salinity ([Ca²⁺]) removes CO₃²⁻ from the solution and pulls the position of equilibrium of (iv) to the right.

The effect goes back through the chain of equilibria.

The net result is that more atmospheric CO₂(g) dissolves in the seawater to replace the CO₃²⁻ that has been removed.

Increasing the salinity increases the solubility of atmospheric CO₂.

Answer:

d) BaF2

Explanation:

The compound which is more soluble in an acidic solution than in a neutral solution is shown below:-

First we will compare acidic with Neutral

[tex]acidic \rightarrow H+ ions[/tex]

So,

[tex]PbBr2 \rightarrow Pb+2 + 2Br-[/tex]

[tex]BaF2 \rightarrow Ba+2 + 2F-[/tex]

[tex]AgI \rightarrow Ag+ + I-[/tex]

[tex]CuCl \rightarrow Cu+ + Cl-[/tex]

Now, when we add H+ ions, so it will be

[tex]BaF2 \rightarrow Ba+2 + 2F-[/tex]

[tex]F- + H2O <-> HF + OH-[/tex]

Then it will reduces F-, as BaF2 begin to form more aqueous ions, so, it will rises the solubility

Answer:

Ag+(aq) + Cl-(aq) —> AgCl(s)

Explanation:

2AgNO3(aq) + CaCl2(aq) —>2AgCl(s) + Ca(NO3)2(aq)

The balanced net ionic equation for the reaction above can be obtained as follow:

AgNO3(aq) and CaCl2(aq) will dissociate in solution as follow:

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

CaCl2(aq) —> Ca2+(aq) + 2Cl-(aq)

AgNO3(aq) + CaCl2(aq) –>

2Ag+(aq) + 2NO3-(aq) + Ca2+(aq) + 2Cl-(aq) —> 2AgCl(s) + Ca2+(aq) + 2NO3-(aq)

Cancel out the spectator ions i.e Ca2+(aq) and 2NO3- to obtain the net ionic equation.

2Ag+(aq) + 2Cl-(aq) —> 2AgCl(s)

Divide through by 2

Ag+(aq) + Cl-(aq) —> AgCl(s)

The, the net ionic equation is

Ag+(aq) + Cl-(aq) —> AgCl(s)

Answer:

d. To the left because Q > K_p

Explanation:

Hello,

In this case, for the given reaction:

[tex]CaCO_3(s) \rightarrow CaO(s) + CO_2(g)[/tex]

The pressure-based equilibrium expression is:

[tex]Kp=p_{CO_2}[/tex]

In such a way, since Kp is given we rather compute the reaction quotient at the specificed pressure of carbon dioxide as shown below:

[tex]Q=p_{CO2}=1.0[/tex]

Therefore, since Q>Kp we can see that there are more products than reactants, which means that the reaction must shift leftwards towards the reactants in order to reestablish equilibrium, thus, answer is d. To the left because Q > Kp.

Regards.

Answer:

[See Below]

Explanation:

13 cm.

Answer:

a) Insoluble

b) Soluble

c) Insoluble

d) Insoluble

e) Soluble

f) Soluble

Explanation:

Answer:

2.0 V

Explanation:

For the oxidation half cell;

Al(s) -------> Al^3+(aq) + 3e.

For reduction half cell;

Cu^2+(aq) +2e ------> Cu(s).

E°cell = E°cathode - E°anode

But;

E°cathode= 0.34 V

E°anode = -1.66 V

E°cell= 0.34 -(-1.66)

E°cell= 2.0 V

Answer: Well, the volume of the copper is (63.4 - 40.0) * mL = 23.4 * mL

Explanation:

Do you agree? The copper displaces the given volume of water.

Now  ρ Cu =  8.90  ⋅  g  ⋅  c m 3  OR  ρ Cu  =  8.90  ⋅  g  ⋅  m L − 1, i.e.  1 ⋅  m L  ≡  1  ⋅  c m 3

But by definition,  ρ  density  =  mass  volume

And thus  mass  =  ρ  ×  volume  =  8.90  ⋅  g  ⋅  m  L  −  1  ×  23.4  ⋅  m  L

= 208.3 * G

Answer:

Chloride (Cl⁻) and sodium (Na⁺) ions.

Explanation:

Hello,

In this case, since the aqueous species are actually dissociated when reacting and the solid species (ferric carbonate) remains undissolved, we can modify the given reaction as follows:

[tex]FeCl_2(aq) + Na_2CO_3(aq) \rightarrow FeCO_3(s) + 2NaCl(aq)[/tex]

In such a way, dissociating the aqueous species we obtain:

[tex]Fe^{2+}(aq)+2Cl^-(aq) + 2Na^+(aq)+CO_3^{2-}(aq) \rightarrow FeCO_3(s) + 2Na^+(aq)+2Cl^-(aq)[/tex]

It means that the net ionic equation is:

[tex]Fe^{2+}(aq)+CO_3^{2-}(aq) \rightarrow FeCO_3(s)[/tex]

Therefore, the spectator ions are those were cancelled out, chloride (Cl⁻) and sodium (Na⁺).

Best regards.

Answer:

8.2×10¯⁵ L

Explanation:

82 μL.

We can convert 82 μL to L by doing the following:

To convert from microlitre (μL) to litre(L), we need to know how many microlitre (μL) that makes up a litre (L)

Recall:

1 μL = 1×10¯⁶ L

Therefore,

82 μL = 82 μL × 1×10¯⁶ L/1 μL

82 μL = 8.2×10¯⁵ L

Therefore, 82 μL is equivalent to 8.2×10¯⁵ L

Answer:

option b is correct

Explanation:

when the temperature of liquid solid and gases increases the kinetic energy of their molecules increases but when the temperature of liquid solid or gases  decreases then kinetic energy of the molecule decreases

Answer:

B. Decreased kinetic energy of the molecules

Explanation:

The average kinetic energy of molecules determines the temperature of a substance.

Hotter objects

have faster-moving particles and higher temperatures

Temperature measures the averages because moving particles can absorb/release heat with each collision as heat is converted to kinetic energy and back.

Chemistry V22 flvs 6.01

Answer:

Al

Explanation:

4 Al  +  3 O₂  →  2 Al₂O₃

You need to figure out which one has the smaller mole ratio.  Convert both substances from grams to moles.

(10.0 g Al)/(26.98 g/mol) = 0.3706 mol Al

(19.0 g O₂)/(32.00 g/mol) = 0.5938 mol O₂

Now, use the mole ratios of reactant to product to see which substance produces the least amount of product.

(0.3706 mol Al) × (2 mol Al₂O₃/4 mol Al) = 0.1853 mol Al₂O₃

(0.5938 mol O₂) × (2 mol Al₂O₃/3 mol O₂) = 0.3958 mol Al₂O₃

Since aluminum produces the least amount of product, this is the limiting reagent.

Al is a limiting reagent. A further explanation is below.

Given equation,

So,

4 moles of Al reacts with 3 moles of O₂ to produce 2 moles of Al₂O₃.

then,

Number of moles of Al,

= [tex]\frac{10 \ g}{26.98 \ g/mol}[/tex]

= [tex]3.706\times 10^{-1} \ moles[/tex]

Now,

then,

Number of moles of O₂,

= [tex]\frac{19 \ g}{32 \ g/mol}[/tex]

= [tex]5.937\times 10^{-1} \ moles[/tex]

Now,

[tex]5.937\times 10^{-1} \ moles[/tex] of O₂ can react with,

= [tex]4\times \frac{5.937\times 10^{-1}}{3}[/tex]

= [tex]7.916\times 10^{-1} \ moles \ of \ Al[/tex]

But there is only [tex]3.706\times 10^{-1}[/tex] moles of Al available.

Thus the above approach is right.

Learn more:

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Answer:

333.6 atm

Explanation:

The following data were obtained from the question:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Next, we shall determine the total number of mole in the container.

This can be obtained as follow:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total mole =?

Total mole = nO2 + nN2 + nCO2

Total mole = 3.96 + 7.49 + 1.19

Total mole = 12.64 moles

Next, we shall determine the mole fraction of N2.

This can be obtained as follow:

Mole fraction = mole of substance/total mole

Mole of N2 (nN2) = 7.49 moles

Total mole = 12.64 moles

Mole fraction of N2 =?

Mole fraction of N2 = 7.49/12.64

Finally, we shall determine the partial pressure of N2.

This can be obtained as follow:

Mole fraction of N2 = 7.49/12.64

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Partial pressure = mole fraction x total pressure

Partial pressure of N2 = 7.49/12.64 x 563

Partial pressure of N2 = 333.6 atm

The, the partial pressure of nitrogen, N2 is 333.6 atm

Answer:

See the answer below

Explanation:

From the illustration;

1 chain = 20.1 meters

1 talent = 30.2 kg

The map says the treasure chest was buried 27 chains due west and 3 chains deep under the ground.

27 x 20.1 = 542.7 meters.

3 x 20.1 = 60.3 meters

This means that one would need to travel 542.7 meters due west from the US Capitol and dig 60.3 meters under the ground in order to locate the treasure chest.

The treasure chest has 50 talents of gold:

50 x 30.2 = 1,510 kg of gold.

Answer:

- In general, the salt that can make hydrolysis (both ions) is option c (ammonium nitrite).

- Salts that can make hydrolysis (one of the ions) are option a (potassium fluoride), option e (potassium cyanide), option f (sodium benzoate), option h (sodium carbonate) and option k (potassium formiate).

- Surely the neutrals salt are (salts that don't make hydrolysis) option b (sodium nitrate), option d (magnessium sulfate), option g (rubidium iodide) and option i (calcium chloride).

Explanation:

To determine the hydrolysis we have to dissociate the salts, and then we define the conjugate strong bases or acids, that can react to water.

a. KF → K⁺  +  F⁻

F⁻ comes from the HF, a weak acid so the anion is the conjugate strong base. F⁻ can make hydrolysis, but the K⁺, can not.

b. NaNO₃ → Na⁺  +  NO₃⁻

Boths are conjugate weak acid and base, this salt is neutral. So they cannot do hydrolysis.

c. NH₄NO₂  →  NH₄⁺  +  NO₂⁻

Both ions can make hydrolysis to water, because the are conjugate strong base and acid.

The ammonium gives ammonium again:

NH₄⁺  +  H₂O ⇄  NH₃  +  H₃O⁺      Ka

The nitrite gives nitrose acid, again

NO₂⁻ +  H₂O ⇄  HNO₂  +  OH⁻    Kb

d. MgSO₄ → Mg²⁺  +  SO₄⁻²

This is a neutral salt. Boths are conjugate weak acid and base, that's why they can not make hydrolysis.

e. KCN → K⁺  +  CN⁻

As K⁺ comes from a strong base, it can not do hydrolysis.

Then, the cyanide can make hydrolysis because it comes from the HCN (a weak acid), so the ion is the conjugate strong base.

CN⁻  +  H₂O  ⇄  HCN  +  OH⁻

f. C₆H₅COONa  → C₆H₅COO⁻  +  Na⁺

This salt is called sodium benzoate. As Na⁺ comes from a strong base, it can not do hydrolysis. Then, the C₆H₅COO⁻ can make hydrolysis because it comes from the benzoic acid, so the ion is the conjugate strong base.

C₆H₅COO⁻  + H₂O  ⇄  C₆H₅COOH  +  OH⁻         Kb

g. RbI  → Rb⁺  +  I⁻

This is a neutral salt. Similar case as NaCl. Both are conjugate weak acid and base, that's why they can not make hydrolysis.

h. Na₂CO₃ →  2Na⁺  +  CO₃⁻²

The one that can make hydrolysis in this case, is the carbonate anion.

CO₃⁻²  +  H₂O ⇄  HCO₃⁻  +  OH⁻

Carbonate comes from the carbonic acid, a dyprotic weak one.

i. CaCl₂ → Ca²⁺  + 2Cl⁻

This is a neutral salt. Similar case as NaCl. Both are conjugate weak acid and base, that's why they can not make hydrolysis.

j. HCOOK → HCOO⁻  + K⁺

This is the potassium formiate. K⁺ comes from KOH, a strong base. It don't make hydrolysis, while the HCOO⁻ can do the hydrolysis in water.

When the formiate react, we can produce formic acid. Formiate is the conjugate strong base, of a weak acid.

HCOO⁻  + H₂O  ⇄  HCOOH  +  OH⁻

Answer:

Explanation:

Diameter in the coin is the distance from side to side.

The numbers in the ruler are showing the centimeters. Each line is a subdivision in ten parts between centimeter and centimeter (Each line is equal to 1mm).

As you can see in the ruler, in the edge of the coin, the ruler is showing 3.8cm

As 1cm = 10mm:

3.8cm * (10mm / 1cm) =

38mm is the diameter of the coin to the nearest milimeter

Answer:

38m

Explanation:

Answer:

Yes.

Explanation:

Substances are made up of matter or matter are made up of tiny molecules or atoms that occur naturally or some are synthetic or man made.

All matter are made up of substances called elements and each elements have its own physical and chemical properties and cannot be broken easily by ordinary chemical reactions.

Of all the 118 elements only 92 occur naturally and 26 are man made or synthetic which are made in the laboratories.

Answer:

7.376 × 10^9 people

Explanation:

yes

Answer:

The correct answer is : 1.07 lbs

Explanation:

solution:

molar mass glucose (C6H12O6) = 180 g/mol

molar mass of oxygen molecule (O2) = 32 g/mol  (as we know molar mass of O = 16 g/mol)

the balanced reaction of conversion of water and oxygen to glucose is:

[tex]C_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O ...(A)[/tex]

1 mol of C6H12O6 = 6 mol of O2  (from reaction A)

so, 180 g C6H12O6 = 192 g O2

that is, 0.396 lb of C6H12O6 = 0.423 lb of O2  (  1 g = 0.00220462 lb )

so,

1 lb C6H12O6 =[tex]\frac{1(lb) \times 0.4233 (lb)}{0.3968 (lb)}[/tex] = 1.07 lb O2

therefore,  the correct answer is : 1.07 lbs

Answer:

D.A high temperature will make it spontaneous.

Explanation:

we know that

Δ G = Δ H - TΔS

For spontaneous reaction

Δ G should be negative . If Δ G = 0

Δ H =  TΔS

T =   Δ H / Δ S

At temperature above this T , Δ G becomes negative if Δ S and ΔH are  positive .

So at a  high temperature will make it spontaneous.

Answer:

D. A high temperature will make it spontaneous.

Explanation:

A P E X

Answer:

a number should be rounded up it is 5 or higher

Answer:

- Not balanced.

- Reactants: Zn  and HCI .

- Products: ZnCl₂ and  H₂.

- Substitution reaction.

Explanation:

Hello,

In this case, for the given reaction:

Zn  +  HCI  →  ZnCl₂ +  H₂

We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:

Zn  +  2HCI  →  ZnCl₂ +  H₂

And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:

Reactants: Zn  and HCI .

Products: ZnCl₂ and  H₂.

Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.

Best regards.

Answer:

The equation isn't balanced because there aren't equal numbers of hydrogen or chlorine atoms on both sides of the equation. To correct this, a coefficient of 2 must be placed in front of HCl on the left-hand side of the equation.

Explanation:

Answer:

four holes

Explanation:

A ball and stick model is a representation of a molecule that can show the number of bonds and sometimes, the stereochemistry of the molecule under study.

The number of holes on present in the ball and stick model for any atom corresponds to the number of bonds that particular atom can form without violating the octet rule.

Carbon is usually tetravalent, it forms four bonds to other atoms. Hence we expect carbon to have four holes.

Answer:

Explanation:

Carbon - Four-hole

Nitrogen - Three-hole

Oxygen - Two-hole

Hydrogyn - Two-hole

Answer:

pH after the addition of NaOH is 4.37

Explanation:

When the amount of the weak acid = Amount of the conjugate base (As in the problem) pH = pKa. That means pKa of benzoic buffer is 4.19.

Now, to solve the pH of the buffer we need to use H-H equation for benzoic buffer:

pH = pKa + log [Benzoate] / [Benzoic acid]

pH = 4.19+ log [Benzoate] / [Benzoic acid]

You can take [] concentrations as the moles of both species.

When you add NaOH to the buffer, it reacts with benzoic acid producing more sodium benzoate and water, thus:

NaOH + Benzoic Acid → Sodium benzoate + Water.

Before the reaction, moles of benzoic acid and sodium benzoate were:

500.0mL = 0.500L × (0.10mol / L) = 0.050 moles

After the reaction, 0.010 moles of Benzoic acid are consumed and the same 0.010 moles of sodium benzoate are produced. That means moles of both species after reaction are:

[Benzoate] = 0.050 moles + 0.010 moles = 0.060 moles

[Benzoic acid] = 0.050 moles - 0.010 moles = 0.040 moles

Replacing in H-H equation:

pH = 4.19+ log [Benzoate] / [Benzoic acid]

pH = 4.19+ log [0.060mol] / [0.040mol]

pH = 4.37