Given:
The equation of a line is:
[tex]y=-\dfrac{5}{7}x+2[/tex]
A line passes through the point (-5,-3) and perpendicular to the given line.
To find:
The equation of the line.
Solution:
Slope intercept form of a line is:
[tex]y=mx+b[/tex] ...(i)
Where, m is the slope and b is the y-intercept.
We have,
[tex]y=-\dfrac{5}{7}x+2[/tex] ...(ii)
On comparing (i) and (ii), we get
[tex]m=-\dfrac{5}{7}[/tex]
We know that the product of slopes of two perpendicular lines is always -1.
[tex]m_1\times m_2=-1[/tex]
[tex]-\dfrac{5}{7}\times m_2=-1[/tex]
[tex]m_2=\dfrac{7}{5}[/tex]
Slope of the required line is [tex]\dfrac{7}{5}[/tex] and it passes through the point (-5,-3). So, the equation of the line is:
[tex]y-y_1=m_2(x-x_1)[/tex]
[tex]y-(-3)=\dfrac{7}{5}(x-(-5))[/tex]
[tex]y+3=\dfrac{7}{5}(x+5)[/tex]
Using distributive property, we get
[tex]y+3=\dfrac{7}{5}(x)+\dfrac{7}{5}(5)[/tex]
[tex]y+3=\dfrac{7}{5}x+7[/tex]
[tex]y=\dfrac{7}{5}x+7-3[/tex]
[tex]y=\dfrac{7}{5}x+4[/tex]
Therefore, the equation of the line is [tex]y=\dfrac{7}{5}x+4[/tex]. Hence, option A is correct.
help please asap just the answers
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]
[tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}[/tex]
8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]
[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
Type the correct answer in each box.
Find the volume of the irregular
figure
1 cm
3 cm
?] cm3
3 cm
1 cm
10 cm
5 cm
Answer:
Step-by-step explanation:
volume of reqd. figure=10×5×1+3×3×1=50+9=59 cm³
solve it : -
[tex] \sqrt{27 \times3 } [/tex]
_______
Answer:
9
Step-by-step explanation:
sqrt(27*3)
sqrt(81)
sqrt(9*9)
9
Answer:
9
Step-by-step explanation:
27 * 3 = 81
√81 = 9
Write the expanded form of the expression.
y(0.5+6)
y(0.5+ 6) =
(Simplify your answer. Use integers or decimals for any numbers in the expression.)
If (a,3) is the point lying on the graph of the equation 5x + 2y = -4, Then find a.
Answer:
I've attached the Answer
Answer:
a = - 2
Step-by-step explanation:
Given x = a, y = 3 lies on the equation. That is the values satisfies the equation when substituted.
Find a :
Equation : 5x + 2y = - 4
5 ( a ) + 2 ( 3) = - 4
5a + 6 = - 4
5a + 6 - 6 = - 4 - 6 [ subtracting both sides by 6 ]
5a + 0 = - 10
5a = - 10
a = - 2 [ dividing both sides by 5]
[ fact check : If (-2 , 3 ) lies on the equation : 5x + 2y = - 4
5(-2) + 2( 3 ) = - 4
- 10 + 6 = - 4
- 4 = - 4 ]
The exponent on b when b^3 is multiplied by b^3 is
A. 3
B. 6
C. 9
Answer:
B. 6
Step-by-step explanation:
3³ x 3³ = 3⁶
The answer is 6
Answer:
B) 6
Step-by-step explanation:
The reason for this is really awesome and is clearly seen when you expand it.
x^3= x times x times x
x^3= x times x times x
x^3 times x^3= x times x times x times x times x times x= x^6
Show your work on how you got the answer
please helppp
Answer:
250
Step-by-step explanation:
4/16 = 1/4 = .25
When dividing exponents, subtract the bottom from the top, so [tex]10^{5}[/tex]÷[tex]10^{2}[/tex] = [tex]10^{3}[/tex]
So, .25 * [tex]10^{3}[/tex] = 250
HELP PLEASEEEEE!!!!!!!
The scores from Dr. Wilhelm's students science fair project are shown below .
Dr wilhelm made a histogram for the data.
answer choices :
50
65
70
71
plsss help I appreciate it thank you so much
Answer:
See Explanation
Step-by-step explanation:
You posted an incomplete question with little and unclear details.
I will answer this question with a more complete version (see attachment)
Given that:
[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]
Required
The fraction that passed the test
Rearrange the score in ascending order:
[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
The total number of students is:
[tex]n =20[/tex]
Extract the students that passed (scored 70 and above)
[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]
Their numbers are:
[tex]Passed: 14[/tex]
So, the fraction of those that passed is:
[tex]Fraction = \frac{Passed}{n}[/tex]
[tex]Fraction = \frac{14}{20}[/tex]
Reduce fraction
[tex]Fraction = \frac{7}{10}[/tex]
You can solve a system of equations by translating it into a matrix,manipulating the matrix until it has eliminated terms,and then translating it back to equations
Answer:
True
Step-by-step explanation:
A system of equations can be solved by Translating the system of equations into a matrix by following theses steps
list all coefficients in a single matrix multiply the coefficient matrix with the variables matrixenter answers into a new matrixwrite out the resulting answer in form of equations.
Which of the following is an arithmetic sequence?
O A. 1,3,9,27,..
O B. 1,0,1,0,1,0,...
O C. 800, 200, 50,...
O D. 10.7.4 1.-2...
Answer:
a
Step-by-step explanation:
Answer:
The answer would be D.
Step-by-step explanation: Hope this helps and gl :)
Find the value of x that makes A || B.
A
N
B
5
5
22 = 3x – 10 and 23 = x + 30
x= [?]
I
Enter
Answer:
9
Step-by-step explanation:
A circle has a radius of 2 feet. What is the length of the arc subtended by a 15 degree central angle?
Answer:
Step-by-step explanation:
length = Pi.radius.15degree/180degree
= Pi.2.15/180 = about 0,5 feet
The length of the arc that is subtended by 15° is: 0.5 ft.
What is the Arc Length in a Circle?Formula for the arc length in a circle with a radius of r and a central angle of ∅ is, ∅/360 × 2πr.
Given the following:
r = 2 ft∅ = 15°Arc length = 15/360 × 2π(2)
Arc length = 0.5 ft.
Thus, the length of the arc that is subtended by 15° is: 0.5 ft.
Learn more about the arc length on:
https://brainly.com/question/17329757
10 points!!!!!! 16-20 please answer correctly and hurry please
Answer:
[tex] \large{ 16.}[/tex]
Two adjacent angles form a linear pair if the sum of those angles is 180°.[tex] \: \large{\tt{❃ \: m \: \angle \: 1 + m \: \angle \: 2 = 180 \degree \: ( \: SUM \: OF \: ANGLE \: IN \: LINEAR \: PAIR)}}[/tex]
[tex] \large{ \tt{⟶ \: 47 \degree + m \angle \: 2 = 180 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: m \angle \: 2 \: = 180 \degree - 47 \degree}}[/tex]
[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: 2 = 133 \degree}}}[/tex]
–––––––––––––
[tex] \large{17}.[/tex]
When two lines intersect , the Ames formed opposite to each other are called vertically opposite angles. Vertically opposite angles [ VOA ] are always equal to each other.[tex] \large{ \tt{↝ \: m \angle \: 6 = m \angle5 = \boxed{ 99.5\degree }\: ( \: BEING \: VOA)}}[/tex]
–––––––––––––
[tex] \large{18.}[/tex]
[tex] \large{ \tt{✻ \: m \angle \: JHL = m \angle \: JHK + m \: \angle \: KHL\: }}[/tex]
[tex] \large{ \tt{⤏ \: m \angle \: JHL= 60 \degree + 46 \degree}}[/tex]
[tex] \large{ \boxed{\tt{⤏ \: m \angle \: JHL = 106 \degree}}}[/tex]
Note that m ∠ KHL = 46° [ being vertically opposite angle ]–––––––––––––––
[tex] \large{ {19.}}[/tex]
Firstly , find out m ∠ JHP :[tex] \large{ \tt{❁ \: m \: \angle \: JHK + m \: \angle JHP+ m \: \angle PHN= 180 \degree \: ( \: sum \: of \: angle \: in \: straight \: line)}}[/tex]
[tex] \large{ \tt{↣ \: 60 \degree + m \angle \: JHP+ 46 \degree = 180 \degree}}[/tex]
[tex] \large{ \tt{↣ \: m \angle \: JHP = 74 \degree}}[/tex]
Now , find out m ∠ JHN :[tex] \large{ \tt{☂ \: m \angle \: JHN = m \angle \: JHP + m \angle \: PHN}}[/tex]
[tex] \large{ \tt{↦m \angle \: JHN = 74 \degree + 46 \degree}}[/tex]
[tex] \large{ \boxed{ \tt{ ↦m \angle \: JHN = 120 \degree}}}[/tex]
––––––––––––––––
[tex] \large{ 20.}[/tex]
[tex] \large{ \tt{✺ \: m \angle \: KHP = m \angle \: KHJ + m \angle \: JHP}}[/tex]
[tex] \large{ \tt{ ↬ \: \: m \angle \: KHP = 74 \degree + 60 \degree}}[/tex]
[tex] \large{ \boxed{\tt{↬ \: m \angle \: KHP = 134 \degree}}}[/tex]
And we're done! Yeyy :) . Also , Let me know if you have any questions regarding my answer !––––––––––––––––
[tex] \large{ \tt{ \# \: StayInAndExplore \: !}}[/tex]
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
A right triangle with the leg lengths of 7ft and 10ft. Using this information, find the length of the hypotenuse. Then round your answer to the nearest hundredth.
Answer:
12.21
Step-by-step explanation:
Explanation:
This is a right triangle, so the Pythagorean Theorem applies.
The Pythagorean Theorem states that the sum of the squared legs of a triangle is equal to the squared hypotenuse.
The legs of a triangle are the sides that form the right angle.
The hypotenuse of a triangle is the longest side.
Formula/solve:
[tex]a^2+b^2=c^2[/tex]
[tex]a,b-legs[/tex]
[tex]c-hypotenuse[/tex]
Here, I am solving for the hypotenuse.
[tex]7^2+10^2=c^2[/tex]
[tex]49+100=c^2[/tex]
[tex]149=c^2[/tex]
Conclude:
The last step is the cancel out c² by finding the square root of 149.
149 is not a perfect square, so I must round the square root to the nearest hundredth.
[tex]12.2065556157[/tex] ≈ [tex]12.21[/tex]
I, therefore, believe the length of the hypotenuse is 12.21 feet.
a.) If m 1 = 3x - 7, find x.
Answer:
x = 25
Step-by-step explanation:
Angle 1 and the angle opposite from Angle 1 (the angle that's 68°) are vertical angles.
What are vertical angles, you ask?
According to the Oxford dictionary, vertical angles are each of the pairs of opposite angles made by two intersecting lines.
For example, take the letter X. The letter X has two lines that intersect to form 4 angles. The top and bottom angles are a pair of vertical angles. So are the left and right angles.
Vertical angles are always congruent.
(This is VERY important to know! It will help you solve many types of geometry problems!)
m1 is 3x - 7. Because Angle 1 and the angle that's 68° are vertical angles, that means they are equal to each other.
Therefore: 3x - 7 = 68.
Now, you can solve for x to get x = 25.
Hope this helps!
If sally completed 6 laps around a circular track with the dimensions shown below, how many meters will she have run? Use 3.14 for up and round your answer to the nearest tenth
Answer/Step-by-step explanation:
The diagram of the circular track is missing, and so also its dimensions.
However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.
Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.
Circumference = πd
d = 20 m (we are assuming the diameter is 20 meters)
π = 3.14
Circumference of circular track = 3.14 × 20 = 62.8 m.
This means that 1 lap = 62.8 m that she would have to run.
Therefore,
6 laps would be = 6 × 62.8 = 376.8 m
Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.
Math tough, who agrees to this statement
Answer:
$1160
Step-by-step explanation:
And yes I agree to this statement
What are the values of x in the equation x2 - 6x + y =
A)x= -2 or x = 8
B)x= -1 or x = -11
C)x= 1 or x = 11
D)x = 2 or x = -8
a rule in quadratic equ states that
if summation of the roots should be -b/a of the equa
comparing the equ x² - 6x + y=0
with. ax² + bx +c =0
we see that in the equ, a= 1, b=-6
so the sum of the roots is -(-6)/1= +6
looking the the option the only one that agreed is option A
-2 + 8= 6
there fore the values of x are -2 or 8
can someone help me with this maths question? workings would be appreciated :]
Adrian, Ben and Charlie share some sweets in the ratio 8:5:10
Charlie got 20 more sweets than Adrian.
Work out the total amount of sweets.
Answer:
total amount of sweets=230
Step-by-step explanation:
ratio=8:5:10
total ratio=8+5+10
=23
Adrian=x
Charlie= x+20
Ben=1/2×(x+20)
Charlie's share
10/23×(x+20+x+(1/2×x+20))=x+20
10/23×(x+20+x+(x+20/2))=x+20
10/23×(x+20+x+x+20/2)=x+20
10/23×(2(x+20)+(2×x)+(x+20/2)/2=x+20
10/23×(2x+40+2x+x+20)/2=x+20
10/23×(2x+2x+x+40+20)/2=x+20
10/23×(5x+60)/2=x+20
50x+600/46=x+20
50x+600=46(x+20)
50x+600=46x+920
50x-46x=920-600
4x=320
4x/4=320/4
x=80
Total amount of sweet
x+x+20+1/2(x+20)
80+80+20+1/2(80+20)
180+1/2(100)
180+50
230
find the value x in the figure :
Answer:
[tex]{ \bf{perimeter = 2(length + width}} \\ \\ { \tt{28 = 2((x + 2) + (x + 6))}} \\ \\ 14 = 2x + 8 \\ 2x = 6 \\ { \tt{x = 3}}[/tex]
x = 3
step-by-step explanation:
Perimeter of rectangle = 2 ( l + b )
Where, we have
breadth is ( x + 6 ) cmlength is ( x + 2 ) cmPerimeter is 26 cm.substitute the values
28 cm = 2 ( ( x + 2) + ( x + 6 ))
28 cm = 2 ( x + 2 + x + 6 )combine like terms
28 cm = 2 ( 2 x + 8 )distributing 2 through parantheses
28 cm = 2 × 2x + 2 × 828 cm = 4x + 16subtract 16 from both side
28 cm - 16 = 4x + 16 - 1612 cm = 4xdivide both side by 4
12 cm / 4 = 4 x / 43 cm = x3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex][tex]\huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]
[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]
[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]
[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]
[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]
[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]
ฅ^•ﻌ•^ฅ
Michelle decides to ride her bike one day. First she rides her bike due south for 12 miles, then the direction of the bike trail changes and she rides in the new direction for a while longer. When she stops, Michelle is 2 miles south and 10 miles west from her starting point. Find the total distance that Michelle covered from her starting point.
Answer:
Total Distance Michelle Covered is 26.14 miles
Step-by-step explanation:
According To the Question, We Have
Michelle First Ride Her bike In 12 miles South, then Changed her Direction & Ride Bike For A long While, and when she stopped she find Herself 2 miles south and 10 miles west from starting point. that shows she change direction and start walking in South-West Direction.
(For Diagram, Please Find in attachment)
In Triangle ABC , Apply Phythagorus Theorem
AB² = BC² + AC²
AB² = 10² + 10²
AB² = 200
AB = √2×10 ⇔ 14.14 miles
Now The Total Distance Travelled by Michelle Would be
OA + AB = 26.14 miles
What is the remainder for the synthetic division problem?
Answer:
C. 54
Step-by-step explanation:
1. Drop down the 1
2. Multiply 1 by 3, put that answer, 3, underneath the 5
3. Add 3+5, then put that answer, 8, below.
4. Multiply 8 by 3, put the answer, 24, under the -8
5. Add 24 and -8 to get 16, drop 16 underneath
6. Multiply 16 by 3, put the answer, 48, under the 6
7. Add 48 and 6 to get 54. Drop 54 below.
Now there are no more coefficients to add the 54 to, so 54 is the remainder!
I hope this helped, the explanation without writing it down is kind of confusing. :))
If each dimension of the cylinder is doubled, how many
times larger will the volume of the cylinder be?
what is the opposite of 24? what is the reciprocal of 24? use a pencil and paper. Describe any similarities and differences between the opposite of a nonzero number and the reciprocal of that number.
the opposite of 24 is □
the reciprocal of 24 is □
Answer:
-24, [tex]\frac{1}{24}[/tex]
Step-by-step explanation:
An opposite number or additive inverse of any number (n) is a number which, if added to n, results in 0. The opposite number for n is written as −n.
For 24, this is -24.
A multiplicative inverse or reciprocal for a number n, is a number which when multiplied by n, their product is 1. To find the multiplicative inverse of a real number, just divide 1 by that number. The reciprocal for n is written as [tex]\frac{1}{n}[/tex] or [tex]n^{-1}[/tex].
For 24, this is [tex]\frac{1}{24}[/tex].
**This content involves opposite and reciprocal numbers, which you may wish to revise. I'm always happy to help!
A baseball is hit with an initial upward philosophy of 70 ft./s from a height of 4 feet above the ground. The equation h= -16x^2+70t+4 models the height in feet , t, seconds after it is hit. After the ball gets to its maximum height it comes down in his caught by another player at a height of 6 feet above the ground. About how long after it was hit does it get caught
Answer:
x=4.34 seconds
Step-by-step explanation:
-16x^2+70x-2=0
[tex]x=\frac{35+\sqrt{1193}}{16}[/tex]
x=4.34
A train travels a total of 38 km at a constant speed of 90 km/h. How long is its journey? Give your answer in minutes and seconds, to the nearest second.
I WILL GIVE BRAINLIEST TO BEST ANSWER
Answer:
3420 minutes 205,200 second.
Her result was x =-4.
A- What is the correct value of x? B- What was Samira’s error? Explain.