pa help po
13.) given that " G " varies directly as " h " and g=64 when h=8 find the variation constant
can you plss answer no.# 13-15
wc in advance po
take note
nonsense answer= report
good answers will get brainlist and I'll follow you and I'll rate you
Answers
It would take 12 men 18 days to complete the job.
1) g ∝ h
g = kh; where k is the constant of variation.
g = 64, h = 8, hence:
64 = 8k
k = 8
g = 8h
2) j ∝ 1/h
j = k/h; where k is the constant of variation.
j = 190, h = 7, hence:
190 = k/7
k = 1330
j = 1330/h
When h = 70:
j = 1330/70
j = 19
3) y represent number of men and x represent the days
y ∝ 1/x
y = k/x
9 = k/24
k = 216
y = 216/x
For 18 days:
y = 216/18 = 12 men
Hence it would take 12 men 18 days to complete the job.
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4, 13, 5, 8, R, 5, 11
In the data set shown, R is an integer. If the median of the data set is 8 and R < 11, what is a possible value
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Answer:
Answers
Answers:
R can be either 8, 9 or 10
============================================================
Explanation:
Let's exclude the R value for now.
The set {4,13,5,8,5,11} sorts to {4,5,5,8,11,13}.
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So we've determined that 4 < R < 11. Because R is an integer, we can say it takes on the values from the set {5,6,7,8,9,10}
------------------------------
If R = 5, then {4,5,5,8,11,13} updates to {4,5,5,5,8,11,13} after adding in that R value. We can see the median is 5, so we can rule out the case that R = 5.
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So we've ruled out the cases that R = 5, R = 6 and R = 7.
If we tried R = 8, then {4,5,5,8,11,13} becomes {4,5,5,R,8,11,13} = {4,5,5,8,8,11,13}. This set has a median of 8 and R = 8 is one of the answers.
-------------------------------
Now let's consider the possibility that 8 < R < 11.
If for instance R = 9, then {4,5,5,8,11,13} becomes {4,5,5,8,9,11,13} to show that this set also has a median of 8. R = 9 is another answer.
The same idea happens when R = 10 as well because we get {4,5,5,8,10,11,13}. R = 10 is another answer.
-------------------------------
In short, R can be any of the following values: 8, 9, 10
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[tex] \frac{3}{4} \div \frac{3}{8} = \\ [/tex]
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