Answer:
Explanation:
No, it is ludicrous and not possible to separate and detach a basic and neutral compound by 1M NaOH in DCM. This is due to the fact that neutral compounds don't respond and react with NaOH, and NaOH itself occurs to be a base. As a result, it can't respond and react with another base to produce salt. Consequently, we simply need a corrosive component i.e an acid
So; In DCM, we can't use 1M NaOH instead of 1M HCI for isolation and separation of neutral and basic compound mixtures.
Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 HCX2HX3OX2+NaOH⟶HX2O+NaCX2HX3OX2 If you require 33.98 mL of 0.1656 M N a O H NaOH solution to titrate 10.0 mL of H C 2 H 3 O 2 HCX2HX3OX2 solution, what is the molar concentration of acetic acid in the vinegar? Type answer:
Answer:
[tex]M_{acid}=0.563M[/tex]
Explanation:
Hello there!
In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:
[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]
Thus, we solve for the molarity of the acid to obtain:
[tex]M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M[/tex]
Regards!
A certain metal M forms a soluble nitrate salt M NO Suppose the left half cell of a galvanic cell apparatus is filled with a 3.00 mM solution of M(NO) and the right half cell with a 3.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C.
1. Which electrode will be positive? What voltage will the voltmeter show?
a. left
b. right
2. Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answer:
Explanation:
From the information given:
left half-cell = 3.00 mM M(NO)
right half-cell = 3.00 M M(NO)
Since the electrode are the same in both cells, then the concentration for the cell are also the same.
Negative electrode = Anode = lower concentration = 3.00 mM
Positive electrode = cathode = higher concentration = 3.00 M
Thus, right half cell will be postive electrode.
To determine the concentration cell:
[tex]Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)[/tex]
SInce [Cathode] > [anode],
[tex]R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol[/tex]
n = 3
[tex]Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}[/tex]
[tex]\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}[/tex]
Classify the following as either an element, compound, homogeneous mixture or
heterogeneous mixture:
sodium chloride
Sodium chloride is the chemical name for salt and is composed of sodium and chlorine, so it is a compound.
Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-pentene (d) (Z)-3-Hexene (e) (E)-2-Pentene (f) 3,3,3-Tribromopropene (g) (Z,4R)-4-Methyl-2-hexene (h) (E,4S )-4-Chloro-2-pentene (i) (Z)-1-Cyclopropyl-1-pentene (j) 5-Cyclobutyl-1-pentene (k) (R)-4-Chloro-2-pentyne (l) (E)-4-Methylhex-4-en-1-yne
Answer:
Attached below
Explanation:
(a) 3-Methylcyclobutene
(b) 1-Methylcyclopentene
(c) 2,3-Dimethyl-2-pentene
(d) (Z)-3-Hexene
(e) (E)-2-Pentene
(f) 3,3,3-Tribromopropene
(g) (Z,4R)-4-Methyl-2-hexene
(h) (E,4S )-4-Chloro-2-pentene
(i) (Z)-1-Cyclopropyl-1-pentene
(j) 5-Cyclobutyl-1-pentene
(k) (R)-4-Chloro-2-pentyne
(l) (E)-4-Methylhex-4-en-1-yne
The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.
how many atoms are in 0.5 mole of aluminum
According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.
Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.
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write a balanced equation between oxalic acid and potassium hydroxide
when are igneous rocks formed?
A. When layers of mud form inside Earth
B. When layers of mud are compressed
C. When melted rock solidifies
D. When solid rock melts
Answer:
C. When melted rock solidifies.
13. An aerosol spray can of deodorant with a volume of 0.410 L contains 3.0 g of propane gas (CH3) as propellant. What is the pressure in the can at 20°C? VRT 3. og festa
Answer: The pressure in the can is 4.0 atm
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = ?
V = Volume of gas = 0.410 L
n = number of moles = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{3.0g}{44.1g/mol}=0.068mol[/tex]
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]20^0C=(20+273)K=293K[/tex]
[tex]P=\frac{nRT}{V}[/tex]
[tex]P=\frac0.068mol\times 0.0820 L atm/K mol\times 293K}{0.410L}=4.0atm[/tex]
Thus the pressure in the can is 4.0 atm
Using the periodic table, choose the more reactive nonmetal.
Te or O
Answer:
answer is TE
Explanation:
Answer:
Tellurium is more reactive than Oxygen
3. How many joules are required to raise the temperature of a 29.352g sample of water by 52.0°C? (the specific heat of water is 4.184 J/g °C)
Answer:
6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
Q= ?c= 4.184 [tex]\frac{J}{g*C}[/tex]m= 29.352 gΔT= 52 CReplacing:
Q= 4.184 [tex]\frac{J}{g*C}[/tex] *29.352 g* 52 C
Solving you get:
Q= 6,386.05 J
6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.
Which general equation represents an endothermic reaction?
A. reactants - energy - products + energy
B. reactants
products + energy
C. reactants + products - energy
D. reactants + energy
products
Explanation:
The general equation for an endothermic reaction is: Reactants + Energy → Products.
Hope it helps :)❤
The equation represents an endothermic reaction is reactants + energy
products.
What is an endothermic reaction?
Endothermic reactions are chemical reactions in which the reactants soak up warm strength from the surroundings to form products.
net energy is not released.heat is not evolved with the product.heat is required to start the reaction.increase with the increase in temperature.decrease with a decrease in temperature.Learn more about the endothermic reaction here:-https://brainly.com/question/6506846
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im not sure if it is a molecule or an atom
Answer:
the first one
Explanation:
I looked it up:P
Only the 2nd answer is right, uncheck the 1st one
Explanation:
If we had a chemical formula like [tex]3(O_{2} )[/tex] the 3 means there are 3 molecules of [tex]O_{2}[/tex]. The 2 means there are two atoms of oxygen in each molecule.
What do scientists mean when they refer to population
population is the number of species living in a given area if this is regarding biology or earth studies :)
You have three containers each of which is connected to a fourth empty container. Three of the containers contain pure gases. In the first container oxygen is at 2 atm, nitrogen at 4 atm is in the second container, and argon at 1 atm is in the third. When you open the valve and mix the gases in the forth container, what is the pressure, PT, in the forth container
Answer: The total pressure is 7 atm
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.
[tex]p_{total}=p_A+p_B+p_C...[/tex]
Given : [tex]p_{total}[/tex] =total pressure of gases = ?
[tex]p_{O_2}[/tex] = partial pressure of oxygen = 2 atm
[tex]p_{N_2}[/tex] = partial pressure of nitrogen = 4 atm
[tex]p_{Ar}[/tex] = partial pressure of argon = 1 atm
putting in the values we get:
[tex]p_{total}=2atm+4atm+1atm[/tex]
[tex]p_{total}=7atm[/tex]
Thus the total pressure is 7 atm
Name the following straight-chain
alkane.
CH3CH2CH2CH3
Answer:
[tex]\huge\boxed{BUTANE}[/tex]
Explanation:
Since it is alkane, The suffix used will be "-ane".
Prefix for 4 carbons => "but-"
Hence, the name:
BUTANE
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807The
14. Use the graph to respond to the
question 14,
ga
ba
1
2
1
344 m/s
5000 m/s
1455 m/s
No sound
3
2
3
4
4
Answer:
21
Explanation:
definitely
During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D. 60 to 90
Answer:
b
Explanation:
During a running (dynamic) compression test at idle, a good engine should produce PSI between 60 to 90. The correct answer is option D.
A running compression test is a diagnostic test that measures the compression pressure of an engine while it is running.
The test is performed by connecting a compression gauge to the spark plug hole of each cylinder and then cranking the engine over to measure the compression pressure. The compression pressure of an engine is an important indicator of its overall health and performance. A low compression pressure can indicate a number of issues, such as worn piston rings, damaged valves, or a blown head gasket. On the other hand, a high compression pressure can indicate that the engine is in good condition and has strong compression.Therefore, in general, a good engine should produce compression pressure between 60 to 90 PSI during a running compression test at idle. Option D is the correct answer.
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Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.
Answer: An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction
Explanation:
Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.
Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.
If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?
Answer:
2.64 M
Explanation:
Use the dilution equation M1V1 = M2V2, where:
M1 = 12.0 M HCl
V1 = 220 mL HCl
M2 = ?
V2 = 1000 mL HCl
(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)
M2 = 2.64 M HCl
ionization of sodium dichromate
Explanation:
this is the answer of your question .
hope it helped you
anyone help with the percent yield questions?
Answer:
oof this is way to hard sry man
Explanation:
calculate the number of moles of chloride needed to form 14.0 moles of iron lll chloride. 2Fe+3Cl2=2FeCl3 ?
Explanation:
The reaction is
2Fe+3Cl2
→2FeCl3
So the mol ratio
Cl2÷FeCl3=3÷2
So for 14 mols of F
eCl3
we need 32×14=21
mols of Cl2
Calculate the molarity of a solution that contains 3.00x10-2 mol NH4Cl in exactly 450 cm3 of solution.
Answer:
0.06moles/litres
Explanation:
molarity = no of moles / volume in litres = 3.00*10^-2/(450/1000)=0.06 moles/litres
Answer:
0.07mol/dm^3
Explanation:
Please mark as brainliest
Pictures of every moon
Answer:
Where?
Explanation:
What are ALL full chemical reactions that ensue for each of the following disinfectants (may be more than one for each): (5 points) Cl2 (g) at pH 9
Answer:
The reactions that might ensue are
Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ---------- > HOCl + HCl
HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)
Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl
Explanation:
The Disinfectant Given is
CI2 (g) at PH 9
Determine the chemical reactions that might ensue
due to the High concentration of [tex]H^{+} (aq)[/tex] the formation of [tex]OCI^-[/tex](aq) will be better and this will decrease the power of the disinfectant.
Hence the chemical reactions that might ensue can be represented below as :
Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ---------- > HOCl + HCl
HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)
Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl
What is entropy?
A. Entropy is the measure of ability to do work.
B. Entropy is the measure of heat content.
C. Entropy is the measure of energy in molecules.
D. Entropy is the measure of randomness.
Answer:
D. Entropy is the measure of randomness
Explanation:
I got it right so I don't know if it's going to be right for you. All questions/answers are not the same but since I personally got it right then I wanted to help you out! I apologize if I'm late/wrong! God bless you guys!
Answer:
Entropy is a measure of randomness.
Explanation:
i just took the test on a pex.
An unknown concentration of sodium thiosulfate, Na2S2O3, is used to titrate a standardized solution of KIO3 with excess KI present. Suppose 15.65 mL of the Na2S2O3 solution is required to titrate the iodine formed from 21.55 mL of 0.0131 M KIO3. What is the molarity of the Na2S2O3 solution
Answer: The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M
Explanation:
[tex]KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2[/tex]
[tex]2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI[/tex]
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
[tex]\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol[/tex]
1 mole of [tex]KIO_3[/tex] produces = 3 moles of [tex]I_2[/tex]
[tex]2.8\times 10^{-4}[/tex] moles of [tex]KIO_3[/tex] produces = [tex]\frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex]
Now 1 mole of [tex]I_2[/tex] uses = 2 moles of [tex]Na_2S_2O_3[/tex]
[tex]8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex] uses = [tex]\frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}[/tex] moles of [tex]Na_2S_2O_3[/tex]
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M[/tex]
The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M
To prepare a buffer solution with a pH of 4.1, which acid should be used?
glycine: pka = 2.35
benzoic acid: pka = 4.19
hydrobromous: pKa = 8.7
Answer:
benzoic acid: pka = 4.19
Explanation:
If 0.000066 moles of 0.01 M solution of carbonic acid dissociates, then what is Ka of carbonic acid
Answer: 4.4 x 10^-7
Explanation:
0.000066 x 0.0000066 / 0.01
= 4.4 x 10^-7
is sublimation exothermic or endothermic
Answer:
endormic
Explanation:
It occurs at a temperature and pressures below a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid