Answer:
[tex]P(A\cup B \cup C)=89[/tex]
Step-by-step explanation:
From the question we are told that:
Believed in UFO's [tex]A=42[/tex]
Believed in Ghosts [tex]B=45[/tex]
Believed in Bigfoot [tex]C=21[/tex]
Believed in UFO's & Ghosts [tex]A&B=11[/tex]
Believed in Ghosts & Bigfoot [tex]B&C=6[/tex]
Believed in UFO's & Bigfoot [tex]A&B=4[/tex]
Believed in ALL [tex]A&B&C=2[/tex]
Generally with a well detailed Set diagram of the Number of People that that believed in at least one of them is mathematically given by
[tex]P(A\cup B \cup C)=n(A\cap C)-n(B\cap C) +n(A\cap B \cap C)[/tex]
[tex]P(A\cup B \cup C)=42+45+21-11-6-4+2[/tex]
[tex]P(A\cup B \cup C)=89[/tex]
A's salary is 50% more than B's. How
much percent is B's salary less than A's?
a. 33(1/4)% b. 33(1/3)% c. 33(1/2)% d. 33%
Answer:
The correct answer is B. 33 1/3%.
Step-by-step explanation:
Given that A's salary is 50% more than B's, to determine how much percent is B's salary less than A's, the following calculation must be performed:
Salary A = B + 50
Salary B = 100
Salary A = 100 + 50 = 150
150 = 100
100 = X
100 x 100/150 = X
10,000 / 150 = X
66.666 = X
100 - 66,666 = 33,333
Answer:
B. 33 1/3%.
Step-by-step explanation:
Hope this helps
PLEASE HELP ASAP! What is the value of x in the inequality start fraction seven plus two x over five end fraction minus three less than x ?
A. x greater than negative start fraction eight over three end fraction
B. x less than negative start fraction eight over three end fraction
C. x greater than start fraction eight over three end fraction
D. x less than negative start fraction three over eight end fraction
Answer:
A
Step-by-step explanation:
the first one in the picture
The marked price of a bicycle is Rs 2000. If the shopkeeper allows some discount and a customer
bought it for Rs 1921 including 13% VAT, how much amount was given as the discount?
Answer:
Discount amount = $328.73
Step-by-step explanation:
Below is the calculation for the discount amount:
The marked price of bicycle = 2000
Purchase price = Rs 1921
VAT = 13%
First find the purchase price excluding VAT = 1921 - (13% of 1921) = 1671.27
Discount amount = 2000 - 1671.27
Discount amount = $328.73
Convert the following 11110011.001 to decimal
Answer:
243.125
Step-by-step explanation:
First do the integral part
11110011
1. From left to right, starting with a zero,
2. add the digit, double, move on to the next digit and repeat step 2 until digits are exhausted.
The successive results are
1
3
7
15
30
60
121
243
For the decimal part, we proceed similarly but
1. From the right-most digit proceed to the left, start with a zero.
2. Add the digit, halve, move on to the next digit and repeat step 2 until the decimal is reached.
Successive results are:
0.5
.25
.125
So the final result is 11110011.001 binary is 243.125 decimal
Need help please I don’t get it
the e-function stuff can be confusing sometimes, but notices that g(x) / the blue line, is just somewhat lower, rest is the same.
how much lower? look at the y-intercepts
f(0)= "about 5"
g(0)= "about -3"
with this y-intercept only option c can work
An urn contains 2 small pink balls, 7 small purple balls, and 6 small white balls.
Three balls are selected, one after the other, without replacement.
Find the probability that all three balls are purple
Express your answer as a decimal, rounded to the nearest hundredth.
Answer:
The probability is P = 0.08
Step-by-step explanation:
We have:
2 pink balls
7 purple balls
6 white balls
So the total number of balls is just:
2 + 7 + 6 = 15
We want to find the probability of randomly picking 3 purple balls (without replacement).
For the first pick:
Here all the balls have the same probability of being drawn from the urn, so the probability of getting a purple one is equal to the quotient between the number of purple balls (7) and the total number of balls (15)
p₁ = 7/15
Second:
Same as before, notice that because the balls are not replaced, now there are 6 purple balls in the urn, and a total of 14 balls, so in this case the probability is:
p₂ = 6/14
third:
Same as before, this time there are 5 purple balls in the urn and 13 balls in total, so here the probability is:
p₃ = 5/13
The joint probability (the probability of these 3 events happening) is equal to the product between the individual probabilities, so we have:
P = p₁*p₂*p₃ = (7/15)*(6/14)*(5/13) = 0.08
14 Calculate the mode from the following data: 7,8, 6, 5, 10, 11, 4, 5,2 b. 5: а. 3.' 4 6 с. d: 6
MODE IS THE NUMBER THAT IS REPEATED THE HIGHEST TIME..
HERE, IN YOUR QUESTION 5CAME 2 TIMES i.e. it is repeated highest time .so mode=5....
A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. Select the correct description of the population in this study.
Complete Question
A few years ago, people tended to have relatively large CD collections. For students at a large university in the midwest, the mean number of CDs owned was 78 with a standard deviation of 90. To confirm these numbers, a random sample of 120 students from this university was collected and the size of their CD collections recorded. These particular 120 students had a mean CD collection size of 80 CDs. What is the numerical value of the sample mean?
Answer:
Sample Mean [tex]\=x=80[/tex]
Step-by-step explanation:
From the question we are told that:
Population Mean [tex]\mu=78[/tex]
Standard deviation [tex]\sigma=90[/tex]
Sample size [tex]n=120[/tex]
Sample Mean [tex]\=x=80[/tex]
Therefore
The numerical value of the sample mean is
Sample Mean [tex]\=x=80[/tex]
Juan and Lizette rented a car for one week to drive from Phoenix to Boise. The car rental rate was $250 per week and $0.20 per mile. By the most direct route, the drive is 926 miles. How much did they spend on the rental car?
( solution at pic)
This Bar Chart shows the number of DVDs sold at a local music store during one week.
Which measure(s) of central tendency can be used to determine the average number of DVDs sold each day?
A. the median
B. the mean
C. the mean and the median
D. the mode
Answer:
B. the mean
Step-by-step explanation:
According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.
Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.
This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.
Answer:
The Mean
Step-by-step explanation:
I took the test
Find the quotient of the following
Answer:
you simply have to do ide the coefficients and subtract the power
which of these statements is true for f(x) =3x2x
Step-by-step explanation:
which of these statements is true for f(x) =3x2xsorry i think u got yr question incomplete ...stay safe healthy and happy........help me please ineed your help
Some number times 7 is equal to the number increased by 9
Answer:
.
Step-by-step explanation:
.
The quadratic function f(x) = -x2 - 6x - 8 is graphed.
What are the solutions of the quadratic equation 0 =
x2 - 6x - 8?
Ту
2
O 2 and 4
0-2 and 4
0-2 and 4
O: 2 and 4
6 5 A
-3
-1
X
-2
ون
Answer:
-2 and -4
Step-by-step explanation:
When the quadratic equation equals 0, that means when y = 0.
By looking at the graph, whenever y = 0 is when the graph crosses the x-axis.
The graph crosses the x-axis at only two points:
(-4, 0) and (-2, 0)
So the solutions to the graph when -x^2 - 6x - 8 equals 0 is -2 & -4.
Hope it helps (●'◡'●)
Answer:
-2 and -4
Step-by-step explanation:
if you'll notice the function goes through the x axis at -2 and -4
Find the expected value of the winnings
from a game that has the following
payout probability distribution:
Payout($) 2 46 8 10
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]
The expected payout is
2 × 0.5 + 4 × 0.2 + 6 × 0.15 + 8 × 0.1 + 10 × 0.05
= 1 + 0.8 + 0.9 + 0.8 + 0.5
= 4
The expected value of the winnings from this game is $3.90.
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
Example:
The probability of getting a head in tossing a coin.
P(H) = 1/2
We have,
To find the expected value of the winnings, we multiply each possible payout by its probability and then sum these products.
So,
Expected Value = (2 x 0.5) + (4 x 0.2) + (6 x 0.15) + (8 x 0.1) + (10 x 0.05)
Expected Value = 1 + 0.8 + 0.9 + 0.8 + 0.5
Expected Value = 3.9
Therefore,
The expected value of the winnings from this game is $3.90.
Learn more about probability here:
https://brainly.com/question/14099682
#SPJ7
Which of the following is not true?
Answer:
C. m<c = 140°
Step-by-step explanation:
Let's analyse each of the given options:
A. m<a = 140° is TRUE
Rationale: angle a and 140° are vertical angles. Vertical angles are congruent.
B. m<b = 140° is TRUE.
Rationale: angle a and 140° are alternate interior angles. Alternate interior angles are congruent.
C. m<c = 140° is NOT TRUE.
Rationale: angle c and 140° are same side interior angles. Same side interior angles are supplementary.
D. m<d = 140° is TRUE.
Rationale: angle d and 140° are corresponding angles. Corresponding angles are congruent.
The number of users of a certain website (in millions) from 2004 through 2011 follows:
Year Period Users (Millions)
2004 1 1
2005 2 5
2006 3 11
2007 4 58
2008 5 145
2009 6 359
2010 7 607
2011 8 846
Using Minitab or Excel, develop a quadratic trend equation that can be used to forecast users (in millions). (Round your numerical values to one decimal place.)
Answer:
y = 26.3x² - 116.9x + 109.6
Step-by-step explanation:
Given the data ;
Year Period Users (Millions)
2004 1 1
2005 2 5
2006 3 11
2007 4 58
2008 5 145
2009 6 359
2010 7 607
2011 8 846
A quadratic regression model can be obtained using a quadratic regression calculator ; The quadratic regression modeled obtained is in the form :
y = Ax² + Bx + C
y = 26.3x² - 116.9x + 109.6
Which division problem does the diagram below best illustrate?
A diagram with 8 ovals containing 4 squares each.
O 16 divided by 4 = 4
O 32 divided by 4 = 8
O 36 divided by 4 = 9
O 8 divided by 2 = 4
Answer:
The answer is 32 divided by 4
Step-by-step explanation:
Because in each box there is 4. There are 8 ovals all together. So 8×4, you get 32 and divide it by the number of squares in an oval which is 4
Answer:
the answer is 32 divided by 4=8
Step-by-step explanation:
because when you look at the ovals there's eight ovals and in side there's four squares..
HOPE THIS HELPS!!!!!
12. A professor creates a boxplot of test scores for 26 students in a statistics course. What percentage of students scored above 81
Answer:
25%
Step-by-step explanation:
Based on the boxplot given ;
The boxplot can be summarized as follows :
Lower quartile, Q1 = 50 (starting point of the box)
Median (Q2), 50th percentile = 70 (vertical line in between the box)
The upper quartile marks the 75th percentile, Q3 = 81 (end point of the box)
The total distribution is 100% and hence, the percentage above the score 81 will be :
100% - 75% = 25%
A cardboard box without a lid is to have a volume of 4,000 cm3. Find the dimensions that minimize the amount of cardboard used. (Let x, y, and z be the dimensions of the cardboard box.)
The principal P is borrowed at a simple interest rate are for a period of time T. Find the loans future value A, or the total amount due at time T
Answer:
The total amount due after five years is $57,000.
Step-by-step explanation:
Recall that simple interest is given by the formula:
[tex]\displaystyle A=P(1+rt)[/tex]
Where A is the final amount, P is the principal amount, r is the rate, and t is the time (in years).
Since we are investing a principal amount of $38,000 at a rate of 10.0% for five years, P = 38000, r = 0.1, and t = 5. Substitute:
[tex]\displaystyle A=38000(1+(0.1)(5))[/tex]
Evaluate. Hence:
[tex]\displaystyle A=\$ 57,000[/tex]
The total amount due after five years is $57,000.
Why is underfind the square root of a negative number?
Answer:
The square root of a negative number is undefined, because anything times itself will give a positive (or zero) result. Note: Zero has only one square root (itself). Zero is considered neither positive nor negative
Answer:
sjshzhshshdhdgdgdhdhdgshshshshshwywhwhw
Find a formula for the general term an of the sequence, assuming that the pattern of the first few terms continues. text({)1, 1/4, 1/16, 1/64, 1/256, ... text(})
Answer:
[tex]T_n = \frac{1}{4^{n-1}}[/tex]
Step-by-step explanation:
Given
[tex]({)1, 1/4, 1/16, 1/64, 1/256, ... (})[/tex]
Required
The general term
The given sequence is geometric.
So first, we calculate the common ratio (r)
[tex]r = T_2/T_1[/tex]
So, we have:
[tex]r = 1/4 \div 1[/tex]
[tex]r = 1/4[/tex]
The function is then calculated using:
[tex]T_n =T_1 * r^{n-1}[/tex]
This gives
[tex]T_n =1 * 1/4^{n-1}[/tex]
[tex]T_n = \frac{1}{4^{n-1}}[/tex]
A sports company has the following production function for a certain product, where p is the number of units produced with x units of labor and y units of capital.
p(x,y)=2500x1/5y1/5
Find:
1. Number of units produced with 26 units of labor and 1333 units of capital.
2. Marginal productivities.
3. Evaluate the marginal productivities at x=25, and y=1333
Answer:
(a) 20226 units
(b) Marginal productivities
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
(c) Evaluation of the marginal productivities
[tex]P_x =803[/tex]
[tex]P_y = 15[/tex]
Step-by-step explanation:
Given
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex]
Solving (a): P(x,y) when x = 26 and y = 1333
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P(26,1333) = 2500*26^\frac{1}{5}*1333^\frac{1}{5}[/tex]
[tex]P(26,1333) = 20226[/tex] --- approximated
Solving (b): The marginal productivities
To do this, we simply calculate Px and Py
Differentiate x to give Px, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * x^{\frac{1}{5}-1} & y^\frac{1}{5}[/tex]
[tex]P_x =2500 * x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]
Differentiate y to give Py, so we have:
[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes
[tex]P_y =2500 * x^\frac{1}{5} & y^{\frac{1}{5}-1}[/tex]
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]
Solving (c): Px and Py when x = 25 and y = 1333
[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex] becomes
[tex]P_x =2500 * 25^{-\frac{4}{5}} * 1333^\frac{1}{5}[/tex]
[tex]P_x =803[/tex] --- approximated
[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex] becomes
[tex]P_y =2500 * 25^\frac{1}{5} * 1333^\frac{-4}{5}[/tex]
[tex]P_y = 15[/tex]
i’ll give brainliest to right answer please hurry
Answer:
Scientific notation uses exponential notation. When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.
Answer:
Look at the exponitial factor. If it is like 10^2 or like 10^10 the number is very big because it is raised to a very big power. Oppisitely, when it is rasied to a negative number, the number producted will have many decimal places. For example 10^-1 is literaly 0.1.
Step-by-step explanation:
Yes I got u
There are 100 sheets of paper on table. It takes 10 seconds to count 10 sheets. How many seconds will you need to count 80 sheets?
Answer:
80 seconds
Step-by-step explanation:
10/10 = 1
now it takes 1 seconds to count 1 sheet
80 x 1 = 80 seconds to count 80 sheets
Step-by-step explanation:
10sheets=10seconds
1sheet=1sheet÷10sheets x 10seconds
=1second
80sheets=80sheets÷1sheet x 1second
80seconds
hope this is helpful
Which choice is equivalent to √10*√5?
A. 5√2
B. 25√2
C. 5√10
D. 2√5
Answer: [tex]5\sqrt{2}[/tex]
Step-by-step explanation:
[tex]\sqrt{10} *\sqrt{5} =\sqrt{50} =\sqrt{2*5*5} =5\sqrt{2}[/tex]
Simplify by expressing fractional exponents instead of radicals.
Problem: The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72
inches and standard deviation 3.17 inches. Compute the probability that a simple random sample of size n=
10 results in a sample mean greater than 40 inches. That is, compute P(mean >40).
Gestation period The length of human pregnancies is approximately normally distributed with mean u = 266
days and standard deviation o = 16 days.
Tagged
Math
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days
or less?
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days
or less?
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of
the mean?
Know
Learn
Booste
V See
Answer:
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.
Step-by-step explanation:
To solve these questions, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.
This means that [tex]\mu = 38.72, \sigma = 3.17[/tex]
Sample of 10:
This means that [tex]n = 10, s = \frac{3.17}{\sqrt{10}}[/tex]
Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
This is 1 subtracted by the p-value of Z when X = 40. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}[/tex]
[tex]Z = 1.28[/tex]
[tex]Z = 1.28[/tex] has a p-value of 0.8997
1 - 0.8997 = 0.1003
0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.
Gestation periods:
[tex]\mu = 266, \sigma = 16[/tex]
1. What is the probability a randomly selected pregnancy lasts less than 260 days?
This is the p-value of Z when X = 260. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{260 - 266}{16}[/tex]
[tex]Z = -0.375[/tex]
[tex]Z = -0.375[/tex] has a p-value of 0.3539.
0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.
2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 20[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}[/tex]
[tex]Z = -1.68[/tex]
[tex]Z = -1.68[/tex] has a p-value of 0.0465.
0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.
3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?
Now [tex]n = 50[/tex], so:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}[/tex]
[tex]Z = -2.65[/tex]
[tex]Z = -2.65[/tex] has a p-value of 0.0040.
0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.
4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?
Sample of size 15 means that [tex]n = 15[/tex]. This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.
X = 276
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = 2.42[/tex]
[tex]Z = 2.42[/tex] has a p-value of 0.9922.
X = 256
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}[/tex]
[tex]Z = -2.42[/tex]
[tex]Z = -2.42[/tex] has a p-value of 0.0078.
0.9922 - 0.0078 = 0.9844
0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.