Answer:
its true
Explanation:
Answer:
true
Explanation:
you stop on ground, ground vibrates and makes sound
Calculate the solubility of Co(OH)2, in g/L, in solutions that have been buffered to the following pHs.
Ksp=1.6*10^-15.
a. 7.00
b. 10.00
c. 4.00
Answer:
a. 14.9g/L
b. 1.49x10⁻⁶
c. 1.49x10⁷
Explanation:
You can write the buffer Ksp of Co(OH)₂ as follows:
Co(OH)₂(s) ⇄ Co²⁺ + 2OH⁻
Ksp = 1.6x10⁻¹⁵ = [Co²⁺] [OH⁻]²
To have buffered the solutions means [OH⁻] is fixed. From the equilibrium of water we can relate [OH⁻] with pH as follows:
[OH⁻] = 10^[14-pH]
With [OH⁻] and Ksp we can solve for [Co²⁺]. Its concentration is equal to solubility (That is the amount of Co(OH)₂ that can be dissolved).
[Co²⁺] is in mol/L. With molar mass of Co(OH)₂ -92.948g/mol-, We can obtain, in the end, its solubility in g/L.
-Molar concentration of [Co²⁺] and solubility:
a. [OH⁻] = 10^[14-7.00] = 1x10⁻⁷
[Co²⁺] = 1.6x10⁻¹⁵ / [1x10⁻⁷]²
[Co²⁺] = 0.16mol / L = Solubility.
In g/L = 0.16mol / L ₓ(92.948g/mol) =
14.9g/L
b. [OH⁻] = 10^[14-10.00] = 1x10⁻⁴
[Co²⁺] = 1.6x10⁻¹⁵ / [1x10⁻⁴]²
[Co²⁺] = 1.6x10⁻⁸mol / L = Solubility.
In g/L = 1.6x10⁻⁸mol / L ₓ(92.948g/mol) =
1.49x10⁻⁶g/L
c.[OH⁻] = 10^[14-4.00] = 1x10⁻¹⁰
[Co²⁺] = 1.6x10⁻¹⁵ / [1x10⁻¹⁰]²
[Co²⁺] = 1.6x10⁵mol / L = Solubility.
In g/L = 1.6x10⁵mol / L ₓ(92.948g/mol) =
1.49x10⁷g/L
As you can see, and as general rule, all hydroxides are solubles in acids.
Calculate the molarity of a solution containing 9.25 mol H2SO4 in 2.75 L of solution.
A) 9.25
B) 6.50
C) 3.36
D) 25.4
E) 33.6
Answer:
THE MOLARITY OF THE SOLUTION IS 3.36 MOLE/L
Explanation:
First we must understand what molarity is.
Molarity is the number of mole per unit volume of solution. In this question, 9.25 mole of H2SO4 was given in 2.75 L of solution.
Molarity is written in mole per dm3 or L.
So we can calculate the molarity:
9.25 ole of H2SO4 = 2.75 L of solution
The number of mole in 1 L of solution will be:
= 9.25 mole / 2.75 L
= 3.3636 mole/ L
In conclusion, the molarity of the solution is approximately 3.36 mole/L
Three 15.0-mL acid samples—0.10 M HA, 0.10 M HB, and 0.10 M H2C¬are all titrated with 0.100 M NaOH. If HA is a weak acid, HB is a strong acid, and H2C is a diprotic acid, which statement is true of all three titrations?
Answer:
All three titrations require the same volume of NaOH to reach the first equivalence point.
Explanation:
Statements are:
All three titrations have the same final pH.
All three titrations require the same volume of NaOH to reach the first equivalence point.
All three titrations have the same pH at the first equivalence point.
All three titrations have the same initial pH.
The pH of the titration depends of the nature of the acid: If the acid is a strong acid, pH at the equivalence of the titration is 7. For a weak acid equivalence point depends of the nature of the conjugate base and initial pH of the weak acid. For a diprotic acid also depends of the nature of the acid.
Thus:
All three titrations have the same initial pH, All three titrations have the same pH at the first equivalence point. and All three titrations have the same final pH. are the three FALSE.
As the concentrations of the acids is 0.10M and are titrated with 0.100M NaOH, The volume to reach the first equivalence point is the same for all the three acids.
Thus:
All three titrations require the same volume of NaOH to reach the first equivalence point.A 0.010 M aqueous solution of a weak acid HA has a pH of 4.0. What is the degree of ionization of HA in the solution
Answer:
[tex]\alpha =0.0009995[/tex]
Explanation:
Hello,
In this case, given the pH of the weak acid HA, we can obtain the concentration of hydrogen in the solution as shown below:
[tex]pH=-log([H^+]})[/tex]
[tex][H^+]=10^{-pH}=10^{-4.0}=1x10^{-4}M[/tex]
In such a way, the degree of ionization ([tex]\alpha[/tex]) is computed as:
[tex]Ka=\frac{\alpha ^2C_0}{1-\alpha}[/tex]
Whereas [tex]C_0[/tex] is 0.010 M and the acid dissociation constant is:
[tex]Ka=\frac{(1x10^{-4})^2}{1-1x10^{-4}}=1x10^{-4}[/tex]
Thus, solving for [tex]\alpha[/tex], we obtain:
[tex]\alpha =0.0009995[/tex]
Regards.
Which of the following is both a Lewis Base and a Brønsted Acid?
a) H2PO4–
b) BF3 F–
c) PO43–
d) NH4+
Answer:
d is answer of this question
A compound can be both Bronsted acid and Lewis base at the same time. An element that has both nature is H2PO4-.
A compound that can acts as both a Brønsted-Lowry acid and base together are generally called amphoteric compounds.
In 1923, chemists Johannes Nicolaus Brønsted and Thomas Martin Lowry in their various studies created definitions of acids and bases using the abilities of compounds to either donate or accept protons ( H+ ions). A Bronsted-Lowry acid is known as any substance that releases H + ions;
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what is the volume in cubic centimeters of a tablet weighing 210 mg
Answer:
1mg=0.001
210
210×0.001÷1
=0.21
If 5.0 mL of a Sports Drink with an absorbance reading of 0.34 was diluted with water to 10.0 mL and was read by the colorimeter, what is the expected absorbance of the solution
Answer:
the expected absorbance of the solution = 0.17
Explanation:
From the information given:
Using Beer's Lambert Law, we have
A = ∈CL
where;
A = Absorbance
∈ = extinction coefficient
C = concentration
L = cell length
Since Absorbance is associated with concentration.
Assuming the measurement were carried out in the same solution; Then ∈ and L will be constant and A ∝ C ----- (1)
Let consider the concentration to be C (mol/L)
5.0 mL of a Sports Drink = 5.0 mL × C (mol)/1000 mL
= 5C/1000 mL
was diluted with water to 10.0 mL
So, when diluted with water to 10.0 mL; we have:
The new concentration to be : [tex]\dfrac{(5 C \times 1000) \ mol }{(1000 \times 10 \times 1000)\ mL}[/tex]
Since :1000mL = 1 L
The new concentration = [tex]\dfrac{C \ mol }{2 \ L}[/tex]
As stated that the initial absorbance reading [tex]A_1[/tex] = 0.34
The expected absorbance reading will be [tex]A_2[/tex] = ???
From (1)
A ∝ C
∴
[tex]\dfrac{A_2}{A_1}=\dfrac{C_2}{C}[/tex]
[tex]A_2 = \dfrac{A_1}{C}[/tex]
[tex]A_2 = \dfrac{0.34}{2}[/tex]
[tex]A_2 = 0.17[/tex]
Thus ; the expected absorbance of the solution = 0.17
What volume, in mL, of 4.50 M NaOH is needed to prepare 250. mL of 0.300 M NaOH?
Answer:
16.7 mL
Explanation:
Convert 250 mL to L.
250 mL = 0.250 L
Calculate the amount of moles of NaOH in 250 mL of 0.300 M NaOH.
0.250 L × 0.300 M = 0.075 mol
Using this amount of moles, you need to find out what volume of 4.50 M will give you that many moles. You can do this by dividing the amount of moles by the molarity.
(0.075 mol)/(4.50 M) = 0.0167 L
Convert from L to mL.
0.0167 L = 16.7 mL
Which of the saturated solutions below would have the highest [OH- ]? a. M(OH)2 Ksp = 4.25 x 10-6 b. M(OH)2 Ksp = 7.39 x 10-4 c. M(OH)2 Ksp = 2.64 x 10-3 d. M(OH)2 Ksp = 8.52 x 10-8
Answer:
M(OH)2 Ksp = 2.64 x 10-3
Explanation:
Recall that for M(OH)2, its dissolution in water gives;
M(OH)2(s) ----> M^2+(aq) + 2OH^-(aq)
Ksp= x × (2x)^2
Ksp= 4x^3
a)
Ksp= 4.25 x 10^-6
Ksp= 4x^3
x= 3√Ksp/4
x= 3√4.25 x 10^-6/4
x= 1.02 ×10^-2 moldm-3
For 2 OH^- = 2 × 1.02 ×10^-2 moldm-3 = 2.04 ×10^-2 moldm-3
b)
Ksp= 7.39 x 10^-4
Ksp= 4x^3
x= 3√Ksp/4
x= 3√7.39 x 10^-4/4
x= 5.7 ×10^-2 moldm-3
For 2 OH^- = 2 × 5.7 ×10^-2 moldm-3= 11.4 ×10^-2 moldm-3
c)
Ksp= 2.64 x 10^-3
Ksp= 4x^3
x= 3√Ksp/4
x= 3√2.64 x 10^-3/4
x= 8.7 ×10^-2 moldm-3
For 2 OH^- = 2 × 8.7 ×10^-2 moldm-3 = 17.4 ×10^-2 moldm-3
d)
Ksp= 8.52 x 10^-8
Ksp= 4x^3
x= 3√Ksp/4
x= 3√8.52 x 10^-8/4
x= 2.77 ×10^-3 moldm-3
For 2 OH^- = 2 × 2.77 ×10^-3 moldm-3 = 5.54 ×10^-3 moldm-3
Hence, M(OH)2 Ksp = 2.64 x 10-3 has the highest [OH- ].
Complete and balance the molecular equation for the reaction between aqueous solutions of ammonium acetate and potassium sulfide.
Answer:[tex]2CH_3COONH_4(aq)+K_2S(aq)\rightarrow 2CH_3COOK(aq)+(NH_4)_2S(aq)[/tex]
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The balanced molecular reaction between aqueous solutions of ammonium acetate and potassium sulfide will be
[tex]2CH_3COONH_4(aq)+K_2S(aq)\rightarrow 2CH_3COOK(aq)+(NH_4)_2S(aq)[/tex]
The balanced molecular equation for the reaction between aqueous solutions of ammonium acetate and potassium sulfide is
[tex]2 CH_3COONH_4(aq) + K_2S(aq) \rightarrow 2 CH_3COOK(aq) + 2 NH_3(g) + H_2S(g)[/tex]
Let's consider the unbalanced molecular equation for the reaction between aqueous solutions of ammonium acetate and potassium sulfide. This is originally a double displacement reaction that would produce potassium acetate and ammonium sulfide. However, ammonium sulfide is unstable and will rapidly decompose into hydrogen sulfide and ammonia.
[tex]CH_3COONH_4(aq) + K_2S(aq) \rightarrow CH_3COOK(aq) + NH_3(g) + H_2S(g)[/tex]
We will balance it using the trial and error method.
We will:
balance K atoms by multiplying CH₃COOK by 2.balance C atoms by multiplying CH₃COONH₄ by 2.balance N atoms by multiplying NH₃ by 2.The balanced molecular equation is:
[tex]2 CH_3COONH_4(aq) + K_2S(aq) \rightarrow 2 CH_3COOK(aq) + 2 NH_3(g) + H_2S(g)[/tex]
The balanced molecular equation for the reaction between aqueous solutions of ammonium acetate and potassium sulfide is
[tex]2 CH_3COONH_4(aq) + K_2S(aq) \rightarrow 2 CH_3COOK(aq) + 2 NH_3(g) + H_2S(g)[/tex]
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A) The equilibrium between carbon dioxide gas and carbonic acid is very important in biology and environmental science.
CO2 (aq) + H2O (l) H2CO3 (aq)
Which one of the following is the correct equilibrium constant expression (Kc) for this reaction?
a) K =[H2CO3]/ [CO2]
b) K=[CO2]/ [H2CO3]
c) K=[H2CO3]/ [CO2][H2O]
d) K=[CO2][H2O]/ [H2CO3]
e) K=1/[H2CO3]
B) For the reaction PCl3(g) + Cl2(g) <-->PCl5(g) at a particular temperature, Kc = 24.3. Suppose a system at that temperature is prepared with [PCl3] = 0.10 M, [Cl2] = 0.15 M, and [PCl5] = 0.60 M. Which of the following is true based on the above?
a) Qc > Kc, the reaction proceeds from right to left to reach equilibrium
b) Qc < Kc, the reaction proceeds from right to left to reach equilibrium
c) Qc > Kc, the reaction proceeds from left to right to reach equilibrium
d) Qc < Kc, the reaction proceeds from left to right to reach equilibrium
e) Qc = Kc, the reaction is currently at equilibrium
Answer:
Explanation:
CO₂ (aq) + H₂O (l) ⇄ H₂CO₃ (aq)
Equilibrium constant
Kc = [H₂CO₃] / [CO₂] [H₂O]
B )
PCl₃(g) + Cl₂(g) <--> PCl₅(g)
Kc = 24.3 .
[PCl₃] = .10M ,
[Cl₂] = 0.15 M
[PCl₅] = 0.60 M.
Qc = [PCl₅] / [PCl₃] [Cl₂]
= .60 / .10 x .15
= 40
Qc > Kc
Hence the reaction will proceed from left to right to reach equilibrium . It is so because the product concentration is more .
Option C is the right choice .
Because people have unlimited wants and limited resources, they must
a. recycle and reuse resources.
b. create more resources.
c. make choices about which wants to satisfy.
d. produce more goods and services to satisfy their wants.
Answer:
a
Explanation:
Because they have a limited of thing so they have to reuse resources
Because people have unlimited wants and limited resources, they must recycle and reuse resources. The correct options are a.
What are resources?Resources are things that can be used by an individual or organization to carry out plans and projects. Resources can be natural things and artificial things, like money, raw material, and vehicles. Resources help people to run their life with all peace and ease.
Recycling is the process of gathering and converting resources into new goods that would otherwise be thrown away as waste. Your community and the environment may both benefit from recycling.
The resources are limited on earth and human consumption is increasing day by day. So to proper use of resources, we must reuse and recycle the resources.
Thus, the correct options are a. recycle and reuse resources.
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Which of the following statements is not true regarding acids? (2 points) Acids can be corrosive, causing damage to skin or clothing. Many fruits contain weak acids, giving them a sour taste. Acids react with bases in neutralization reactions to produce water. The hydroxide ion concentration is greater than the hydronium ion concentration.
Answer:
Acids do not react with bases in neutralization reactions to produce water.
Explanation:
Study the flow diagram below carefully.
Process C
Ethanol
Process A
Heavy
olis
Substance
B
...[2]
(a) Name
(0) Process A.
(ii) Process C
(b) Name substance B
..[1]
[1]
.[1]
(c) Give one significantce of process A
[Total:4]
11 | Page
ProccessA
Explanation:
Ethanol Heavy Oils
The d orbital electron configuration of octahedral complexes can either be described as high- spin with the maximum possible number of unpaired d-electrons, or low-spin containing one or more paired d-electrons. [Fe(H20)s]2 is a high-spin octahedral complex. What is its spin- state (S-?)? Draw a d-orbital splitting diagram for this complex and fill it with the appropriate number of electrons. Where does the final electron go in this diagram? If you were to oxidize this molecule do you think this would affect the bond lengths? Explain
Answer:
See explanation
Explanation:
Fe(H20)6]2+ is a high spin octahedral complex because water is weak field ligand. A high spin complex has a maximum number of unpaired d electrons.
The spin state of Fe(H20)6]2+ is S=2. The final electron goes into an eg orbital. If the metal is oxidized to Fe^3+, the bond lengths decreases. For an oxidation of M2+ complex to M3+, the M3+L bonds will be shorter due to the higher charge density on the metal. Since the occupation of the eg orbitals in both complexes is the same it then follows that that the difference in the bond lengths must be due to the charge alone.
In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 57.84 g of MgI₂ form, what is the percent yield?
Answer:
88.1% (to 3 s.f.)
Explanation:
Please see attached picture for full solution.
The equilibrium constant, Kp, for the following reaction is 0.160 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 15.9 L container at 298K contains NOBr at a pressure of 0.363 atm and NO at a pressure of 0.421 atm, the equilibrium partial pressure of Br2 is _________atm.
Consider the following reaction:
2NH3(g) N2(g) + 3H2(g) If 3.53 * 10-4 moles of NH3, 0.297 moles of N2, and 0.320 moles of H2 are at equilibrium in a 16.6 L container at 945 K, the value of the equilibrium constant, Kp, is ________.
Answer:
1. The partial pressure of Br₂ is 0.118951 atm 2) The value of Kp is 2.843 × 10².
Explanation:
1. The reaction at equilibrium will be:
2NOBr (g) ⇒ 2NO (g) + Br₂ (g)
The partial pressure of PNOBr is 0.363 atm, the partial pressure of NO is 0.421 atm, there is a need to find the partial pressure of Br₂, the value of Kp is 0.160. For the given reaction,
Kp = [PNO]² × [PBr₂] / [PNOBr]²
0.160 = [0.421]² × [PBr₂] / [0.363]²
0.160 = [0.177241 × [PBr₂] / 0.131769
[PBr₂] = 0.131769 × 0.160 / 0.177241
[PBr₂] = 0.118951 atm
The partial pressure of Br₂ is 0.118951 atm.
2) The reaction will be,
2NH₃ ⇔ N2 (g) + 3H₂ (g)
Kp is the equilibrium constant, and its value will be,
Kp = [PN₂] × [PH₂]³ / [PNH₃]² ------------------(i)
Considering the reactants in terms of molarity will be,
Kp = [N2] × [H₂]³ / [NH₃]²
Here, [N2] = 0.297 / 16.6 = 0.017892 M
[H₂] = 0.320/16.6 = 0.019277 M
[NH₃] = 3.53 × 10⁻⁴ / 16.6 = 2.12651 × 10⁻⁵ M
Now putting the values in equation (i) we get,
Kp = [0.017892] × [7.16399 × 10⁻⁶] / [4.52204 × 10⁻¹⁰]
Kp = 0.128167 × 10⁻⁶ / 4.52204 × 10⁻¹⁰
Kp = 2.8343 × 10²
Hence, the equilibrium constant is 2.8343 × 10²
Two volatile substances, A and B are dissolved in one another and the resulting solution has a vapor pressure of 137 torr. If the mole fraction of B is 0.230 and the vapor pressure of pure B is 162 torr, what is the vapor pressure of pure A in torr?
Answer:
Vapor pressure of pure A is 129.5torr
Explanation:
When two or more liquids produce an ideal solution, the vapour pressure of the mixture follows the equation (Raoult's law):
[tex]P_T = P_aX_a + P_bX_b[/tex]
Where P is vapour pressure and X mole fraction of liquids A and B. Pt is the pressure of the solution
As mole fraction of B is 0.230, mole fraction of A is:
[tex]1 =X_a+X_b\\1=X_a+0.230\\X_a=0.77[/tex]
Computing in Raoult's law with the given values:
[tex]137 torr= P_a0.77 + 162torr*0.23\\137 torr = 0.77P_a+37.26torr\\99.74torr = 0.77P_a\\P_a=129.5torr[/tex]
Vapor pressure of pure A is 129.5torrThe vapor pressure of pure A in torr is 129.5 torr
How to determine the mole fraction of AMole fraction of B = 0.23 Mole fraction of solution = 1Mole fraction of A =?Mole fraction of A = 1 – 0.23
Mole fraction of A = 0.77
How to determine the vapor pressure of ATotal pressure (P) = 137 torr Mole fraction of B (Xb) = 0.23 Vapor pressure of B (Pb) = 162 torrMole fraction of A (Xa) = 0.77Vapour pressure of A (Pa) =?P = XaPa + XbPb
137 = (0.77 × Pa) + (0.23 × 162)
137 = 0.77Pa + 37.26
Collect like terms
137 – 37.26 = 0.77Pa
99.74 = 0.77Pa
Divide both side by 0.77
Pa = 99.74 / 0.77
Pa = 129.5 torr
Thus, the vapor pressure of pure A is 129.5 torr
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2. Determine the molarity of the NaOH solution in each trial. a. Trial 1 Molarity: b. Trial 2 Molarity: 3. Calculate the average molarity of the NaOH solution. 4. Label the volumetric flask containing the NaOH solution with the average molarity.
Answer:
This question is incomplete
Explanation:
This question is incomplete but...
1) You can calculate the molarity of the NaOH for each trial by following the steps below.
The formula for Molarity (M) is
M = number of moles (n) ÷ volume (V)
where the unit of volume must be in Litres or dm³
The unit of molarity is mol/dm³ or mol/L or molar conc (M)
The final answer must have the unit of molarity
If the number of moles is not provided, look out for the mass of NaOH used and then calculate your number of moles (n) as
n = mass of NaOH used ÷ molar mass of NaOH
Where the atomic mass of sodium (Na) is 23, oxygen (O) is 16 and hydrogen (H) is 1. Hence, molar mass for NaOH is 23 + 16 + 1 = 40 g/mol
n = mass of NaOH used ÷ 40
2) Average Molarity will be (Trial 1 Molarity +Trial 2 Molarity) ÷ 2
Answer must be in mol/dm³ or mol/L or M
3) Label the volumentric flask containing the NaOH solution with the answer gotten from (2) above
The concentration of hydronium ions is greater than 1x10-7 for basic solutions
Answer:
false
Explanation:
I took the test
write the balanced nuclear equation for the radioactive decay of radium-226 to give radon-222, and determine the type of decay
Answer: DEAR THE ANSWER TO YOUR QUESTION IS,
Explanation: Consider the equation for the decay of radium-226 to radon-222, with the simultaneous loss of an alpha particle and energy in the form of a gamma ray. Radium-226 is the reactant; radon, an alpha particle, and a gamma ray are the products. The equation is:
shown in the attach figure
TYPE OF DECAY: as α-particle emmit in this reaction hence its the α-decay
It decays by emitting an alpha particle composed of two protons and two neutrons. The radium nucleus turns into radon-222 nucleus, itself radioactive, containing two protons and two neutrons less. The disintegration releases 4.6 million electronvolts of energy
PLS GIVE ME RATING IF YOU FIND IT HELPFULL SO THAT OTHER BE BENIFIT OF THAT ANSWEER
THANKS....
i need to know the measurements of this to the appropriate amount of significant figures
Answer:
[See Below]
Explanation:
I'd say 44 something. It's probably ml but I can't see what it says on the tube.
Would having different atmospheric pressures have an effect on the accuracy of gas laws? If so, which planets would be the most reliable and which would be the least?
Answer:
With the changes in atmospheric pressure, the gas laws also change accordingly, that is, the Charle's law, the Boyle's law, the Ideal Gas Law, and the Gay-Lussac's law changes with the change in atmospheric pressure. Therefore, the planets, which exhibits the constant value of atmospheric pressure will be more reliable, and those possessing different atmosphere or no atmosphere will be the least reliable.
How do scientists conduct scientific investigations?
Consider the words or phrases below and drop them in the bucket that you would most associate with the word or phrase in the thermodynamic context. In cases where you think they could go in two buckets, consider (even write down) what conditions are necessary for each condition. Thermo is all about the conditions...
Group the following words into
1. non equilibrium,
2 equilibrium phase cahnge, and
3. equilibrium reaction.
Heat of vaporization
saturated solution
mass movement
unsaturated solution
condensation
heat of fusion
vapor pressure
normal boiling poin
Ksp
solubility
Ka
Answer:
1) non equilibrium
mass movement
unsaturated solution
2)equilibrium phase change
Heat of vaporization
condensation
heat of fusion
normal boiling point
vapor pressure
3) equilibrium reaction
saturated solution
Ksp
solubility
Ka
Explanation:
Nonequilibrium processes are those processes that are irreversible. They often lead to an increase in entropy of the system.
In chemical systems, a state of equilibrium is said to have been attained when the rate of the forward process equals the rate of the reverse process. This is true for both chemical reaction and phase changes. A state of equilibrium connotes a constancy in physical properties of a system over a period of time.
A 50.0 mL sample containing Ni+2 was treated with 25.0 mL of .050 M EDTA to complex all of the Ni+2 and leave some excess EDTA in solution. the excess EDTA was then titrated with .050 M Zn+2, requiring 5.00 mL to reach equivalence point. What was the concentration of Ni+2 in the original solution? (EDTA forms complexes with metals in a 1:1 stoichiometry)
For any galvanic cell to operate at standard conditions,
a) ΔG° and ΔE° are both positive
b) ΔG° and ΔE° are both negative
c) ΔG° is positive and ΔE° is negative
d) ΔG° is negative and ΔE° is positive
Answer:
ΔG° is negative and ΔE° is positive
Explanation:
A galvanic cell produces electrical energy from spontaneous electrochemical processes.
In a galvanic cell, ∆E° is always positive since the reaction is spontaneous at room temperature.
Generally in thermodynamics, a negative value of ∆G shows a spontaneous chemical process. Hence in a galvanic cell, ΔG° is negative and ΔE° is positive.
Place the following atmospheric gases in order of abundance, from highest to lowest.
a. Carbon Dioxide
b. Other trace gases
c. Argon
d. Oxygen
e. Nitrogen
Explanation:
The percentage abundance of the following gases in the atmosphere is given as;
Carbon dioxide = 0.04 percent
Other trace gases = about a tenth of one percent of the atmosphere.
Argon = 0.93 percent
Oxygen = 21 percent
Nitrogen = 78 percent
Te order from highest to lowest is given as;
Nitrogen
Oxygen
Argon
Carbon dioxide
Other trace gases
Round off the following number to 3 digits 34,560
Answer:
3.46x10⁴
Explanation:
Hello,
In this case, we can see that the number 34,560 has five significant figures, it means that if we want to write it with three, we must take the 3, 4 and 5 only. Nevertheless, since the 6 after the five is greater than 5, we can round such five to 6, so we obtain:
346
However, the decimal places cannot get lost, therefore, we move the given thousand to the three, so the number turns out:
3.46x10⁴
Best regards.
2. (01.03 MC)
What energy transfer is occurring when a battery-powered toy rolls across the floor? (3 points)
Stored mechanical energy is converted to thermal energy.
Stored mechanical energy is converted to mechanical energy.
Stored chemical energy is converted to thermal energy.
Stored chemical energy is converted to mechanical energy
Answer:
stored chemical energy is converted into mechanical energy.
Explanation:
the chemical reactions happens in the battery turn into electricity that makes the toy rolls across the floor.
Answer:
stored chemical energy is converted into mechanical energy.
Explanation: