On the basis of intermolecular forces of attraction, rank the following three compounds in terms of increasing boiling point.

CH3CH2OH

CH3OCH3

CH3CH2CH3

a. (lowest bp) CH3CH2CH3 < CH3OCH3 < CH3CH2OH (highest bp)

b. (lowest bp) CH3CH2OH < CH3OCH3 < CH3CH2CH3 (highest bp)

c. (lowest bp) CH3OCH3 < CH3CH2OH < CH3CH2CH3 (highest bp)

d. (lowest bp) CH3CH2OH < CH3CH2CH3 < CH3OCH3 (highest bp)

e. (lowest bp) CH3CH2CH3 < CH3CH2OH < CH3OCH3 (highest bp)

Answers

Answer 1

Answer:

a. (lowest bp) CH3CH2CH3 < CH3OCH3 < CH3CH2OH (highest bp

Explanation:

CH3CH2OH is an alkanol. The intermolecular forces present within the molecules include dispersion forces, dipole-dipole attraction as well as hydrogen bonding which is the major intermolecular force of attraction present.

CH3OCH3 is an ether. The intermolecular forces present within the molecules are dispersion forces and dipole-dipole attraction.

CH3CH2CH3 is an alkane. The only intermolecular forces present is dispersion forces.

The order of increasing strength of these intermolecular forces is dispersion forces ,dipole-dipole forces<hydrogen bonding, the alkanol has the highest bioling point, followed by the ether and then the alkane with the lowest boiling point.

Answer 2

The ranking of the compounds in terms of increasing the boiling point is option a.

What is ethanol?

Ethanol i.e. (CH3-CH2-O-H) has three types of intermolecular interactions i.e. weak van der Waals interaction, dipole-dipole interaction, and strong intermolecular H-bonding interaction.

While on the other hand,  in dimethyl ether (CH3-O-CH3) have two types of interactions - weak van der Waals interaction, and dipole-dipole interaction.

In propane (CH3-CH2-CH3) has only weak van der Waals interaction.

So ethanol needed more energy to overcome this these interactions for the conversion to a liquid state to the gaseous state.

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Related Questions

Which is an example of the practical pursuit of alchemy

Answers

Answer:

A practical pursuit of alchemy was the development of metallurgy practices.

Explanation:

As alchemists always tried to turn various metals into other things, metalworking techniques were developed even though their experiments were often unsuccessful.

Answer: developing metalworking techniques

Explanation:

trust it!!

How will temperature affect the spontaneity of a reaction with positive H and S?
A. It will be spontaneous only at T = H/S.
B.Changing the temperature will not affect spontaneity.
C.A low temperature will make it spontaneous.
D.A high temperature will make it spontaneous.

Answers

Answer:

D.A high temperature will make it spontaneous.

Explanation:

we know that

Δ G = Δ H - TΔS

For spontaneous reaction

Δ G should be negative . If Δ G = 0

Δ H =  TΔS

T =   Δ H / Δ S

At temperature above this T , Δ G becomes negative if Δ S and ΔH are  positive .

So at a  high temperature will make it spontaneous.

Answer:

D. A high temperature will make it spontaneous.

Explanation:

A P E X

What does a decrease in temperature indicate about the molecules in a sample of liquid water? (3 points) a Decreased chemical energy of the molecules b Decreased kinetic energy of the molecules c Increased chemical energy of the molecules d Increased kinetic energy of the molecules

Answers

Answer:

option b is correct

Explanation:

when the temperature of liquid solid and gases increases the kinetic energy of their molecules increases but when the temperature of liquid solid or gases  decreases then kinetic energy of the molecule decreases

Answer:

B. Decreased kinetic energy of the molecules

Explanation:

The average kinetic energy of molecules determines the temperature of a substance.

Hotter objects

have faster-moving particles and higher temperatures

Temperature measures the averages because moving particles can absorb/release heat with each collision as heat is converted to kinetic energy and back.

Chemistry V22 flvs 6.01

What is the limiting reactant for the reaction below given that you start with 10.0 grams of Al (molar mass 26.98 g mol-1) and 19.0 grams of O2 (molar mass 32.00 g mol-1)? Equation: 4Al + 3O2 → 2Al2O3

Answers

Answer:

Al

Explanation:

4 Al  +  3 O₂  →  2 Al₂O₃

You need to figure out which one has the smaller mole ratio.  Convert both substances from grams to moles.

(10.0 g Al)/(26.98 g/mol) = 0.3706 mol Al

(19.0 g O₂)/(32.00 g/mol) = 0.5938 mol O₂

Now, use the mole ratios of reactant to product to see which substance produces the least amount of product.

(0.3706 mol Al) × (2 mol Al₂O₃/4 mol Al) = 0.1853 mol Al₂O₃

(0.5938 mol O₂) × (2 mol Al₂O₃/3 mol O₂) = 0.3958 mol Al₂O₃

Since aluminum produces the least amount of product, this is the limiting reagent.

Al is a limiting reagent. A further explanation is below.

Given equation,

[tex]4Al+3O_2 \rightarrow 2Al_2O_3[/tex]

So,

4 moles of Al reacts with 3 moles of O₂ to produce 2 moles of Al₂O₃.

Mass of Al = 10 gMolar mass = 26.98 g/mol

then,

Number of moles of Al,

= [tex]\frac{10 \ g}{26.98 \ g/mol}[/tex]

= [tex]3.706\times 10^{-1} \ moles[/tex]

Now,

Mass of O₂ = 19 gMolar mass = 32 g/mol

then,

Number of moles of O₂,

= [tex]\frac{19 \ g}{32 \ g/mol}[/tex]

= [tex]5.937\times 10^{-1} \ moles[/tex]

Now,

[tex]5.937\times 10^{-1} \ moles[/tex] of O₂ can react with,

= [tex]4\times \frac{5.937\times 10^{-1}}{3}[/tex]

= [tex]7.916\times 10^{-1} \ moles \ of \ Al[/tex]

But there is only [tex]3.706\times 10^{-1}[/tex] moles of Al available.

Thus the above approach is right.

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) Why is the Lewis structure for CO2 usually written as O = C = O rather than

O ≡ C - O ?

Answers

Answer:

The Lewis structure for CO2 is O = C = O rather than  O ≡ C - O because of the covalent nature of the bonds that makes CO2 a polar molecule and to become stable it is important to fill valence shell of both atoms equally.

CO2 can not be written as O ≡ C - O because then there will be one non-paired electron in the oxygen atom that can disturb the stability of CO2.

The compound on the right contains two functional groups. It is:________
A) an aldehyde and an ether
B) an aldehyde and an alcohol
C) a ketone and an ether
D) a ketone and an ester
E) a carboxylic acid and an ether

Answers

Answer : Option C is correct -- a ketone and an ether

Explanation:

It should be noted that Ketone and ether are the compound on the right that contain two functional groups. an aldehyde and an ether, an aldehyde and an alcohol, a ketone and an ester, and also a carboxylic acid and an ether don't contain two functional groups on the right.

Which process is an example of a chemical change?

Answers

Answer:

burning of paper

melting of lead

Answer:

d- activating a glow stick

Explanation:

Glow sticks produce light through a chemical reaction.

The standard cell potential for a reaction in an electrolytic cell is always:_____

a. Positive
b. Negative
c. Zero
d. Impossible to determine

Answers

Answer:

The correct answer is b. Negative

Explanation:

An electrolytic cell is based on a reduction- oxidation reaction which is non spontaneous. That means that the standard cell potencial (Eº) is negative. For this reason, an electrical potential must be applied in order to force the reaction. Conversely, a galvanic cell is based on a spontaneous redox reaction, so the galvanic cell produces electrical energy.

i need to know the measurements of this to the appropriate amount of significant figures

Answers

Answer:

[See Below]

Explanation:

13 cm.

Energy from radiation can cause chemical bonds to break. To break a nitrogen-nitrogen bond in N2 gas, 941kJ/mole is required.
a. Calculate the wavelength of radiation that could break the bond.
b. In what spectral range does this radiation occur?

Answers

Answer:

a) 1.269 × 10^-7 m

b) This wavelength occurs in the ultraviolet region of the electromagnetic spectrum

Explanation:

The energy required to break the bond= energy of the incident photon

E= 941 × 10^3/6.02 × 10^23 = 1.56 ×10^ -18 J

From

E= hc/λ

h= Plank's constant

c= speed of light

λ= wavelength of incident photon

λ= hc/E

λ= 6.6 ×10^-34 × 3 ×10^8/1.56 ×10^ -18 J

λ= 1.269 × 10^-7 m

b) This wavelength occurs in the ultraviolet region of the electromagnetic spectrum

The public is not yet able to ourchase cars powered by hydrogen fuel cells because engineers have to determine how the cars perform based on which scenario

Answers

Answer:

in real-world conditions

Explanation:

A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure of 783 Torr . What is the final volume of the gas? g

Answers

Answer:

the final volume of the gas is [tex]V_2[/tex] = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure [tex]P_{ext}[/tex]:

[tex]P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}[/tex]

[tex]P_{ext} = 1.03 \ atm[/tex]

The workdone W = [tex]P_{ext}[/tex]V

The change in volume ΔV= [tex]\dfrac{W}{P_{ext}}[/tex]

ΔV = [tex]\dfrac{130.1 \ J \times \dfrac{1 \ L \ atm}{ 101.325 \ J} }{1.03 \ atm }[/tex]

ΔV = [tex]\dfrac{1.28398717 }{1.03 }[/tex]

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is [tex]\Delta V = V_2 -V_1[/tex]

[tex]- V_2= - \Delta V -V_1[/tex]

multiply through by (-), we have:

[tex]V_2= \Delta V+V_1[/tex]

[tex]V_2[/tex] =  1250 mL + 61.5 mL

[tex]V_2[/tex] = 1311.5 mL

∴ the final volume of the gas is [tex]V_2[/tex] = 1311.5 mL

The final volume of the gas when the volume of 61.5 mL should be 1311.5 mL.

Calculation of the final volume:

Since

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

So, here the external pressure should be

= 783 * 1 / 760

= 1.03 atm

Now the change in volume is

= 130.1 J * 1 / 101.325 J / 1.03
= 1250 mL

Now the change in volume should be

= 1250 + 61.5

= 1311.5 mL

hence, The final volume of the gas when the volume of 61.5 mL should be 1311.5 mL.

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Plzzz fastttt answerrr

Which answer choices correctly describe why the number of known elements more then doubled by 1861

Answers

Answer:

Communication between scientists increased.

Technological advancements were made.

Explanation:

The options:

Metalworkers began using new metals.

 Communication between scientists increased.

 The American Civil War started.

 Technological advancements were made.

The reasons the number of known elements more than double by 1861 would be because technological advancements have been made and communication between scientists increased.

With the advancement in technology, more equipment become available and research became more sophisticated leading to new discoveries. The new discoveries would not have made much difference if they are not adequately communicated to other scientists.  

The product of the reaction between Aluminium Oxide (Al2O3) and Carbon (C) is Aluminium (Al) and carbon monoxide (CO). The reaction of 60.0 g of Al2O3 with 30.0 g of C produced 22.5 g of Al. What is the percent yield for this reaction?

Answers

Answer:

Percent yield = 70.8%

Explanation:

Equation of the reaction:

Al2O3 + 3C ----> 2Al + 3CO

From the reaction equation, 1 mole of Aluminum oxide produces 2 moles of Aluminum when reacted with 3 moles of carbon.

Molar mass of Aluminum oxide = 102 g; molar mass of Aluminum = 27 g; molar mass of C = 12

3 moles of C = 36 g

2 moles Al = 54 g

102 g of Al2O3 reacts with 36 g of C

60 g of Al2O3 will react with (36/102) × 60 g of C = 21.2 g of C

Therefore, Al2O3 is the limiting reactant while C is in excess.

102 g of Al2O3 produces 54 g of Al

60 g of Al2O3 will produce (54/102) × 60 of Al = 31.8 g of Al

Percent yield = (actual yield/ theoretical yield) × 100%

Percent yield = (22.5 g / 31.8 g) × 100%

Percent yield = 70.8 %

1. Determine whether or not the equation below is balanced. If it isn’t balanced, write the balanced form. Also, identify the reactant(s) and product(s) in this equation. Finally, label this as one of the five types of reactions: combination, decomposition, substitution, double replacement, or reversible.

Answers

Answer:

- Not balanced.

- Reactants: Zn  and HCI .

- Products: ZnCl₂ and  H₂.

- Substitution reaction.

Explanation:

Hello,

In this case, for the given reaction:

Zn  +  HCI  →  ZnCl₂ +  H₂

We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:

Zn  +  2HCI  →  ZnCl₂ +  H₂

And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:

Reactants: Zn  and HCI .

Products: ZnCl₂ and  H₂.

Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.

Best regards.

Answer:

The equation isn't balanced because there aren't equal numbers of hydrogen or chlorine atoms on both sides of the equation. To correct this, a coefficient of 2 must be placed in front of HCl on the left-hand side of the equation.

Explanation:

Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under standard conditions, and (NO2) = + 33.2 kJ/mol. Keep one decimal point. 2 NO(g) + O2(g) → 2 NO2(g) ∆Hrxn = –114.2 kJ

Answers

Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g)  ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

1. While searching through a an old trunk you found a treasure map that says a treasure chest was burried 27
chains due west of the US Capitol Building. The treasure chest has 50 talents of gold and is buried 3 chains deep
under ground. Through your research you have discovered that 1 talent is 30.2 kg and 1 chain is 20.1 meters. How
many meters from the US Capitol should you dig, and how deep will you have to dig to find the treasure chest?

Answers

Answer:

See the answer below

Explanation:

From the illustration;

1 chain = 20.1 meters

1 talent = 30.2 kg

The map says the treasure chest was buried 27 chains due west and 3 chains deep under the ground.

27 x 20.1 = 542.7 meters.

3 x 20.1 = 60.3 meters

This means that one would need to travel 542.7 meters due west from the US Capitol and dig 60.3 meters under the ground in order to locate the treasure chest.

The treasure chest has 50 talents of gold:

50 x 30.2 = 1,510 kg of gold.

Which of the following is not a technique that could be used to separate a mixture into its components?
a) stirring.
b) decanting.
c) filtration.
d) distillation.
e) none of the above.

Answers

Answer:

Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography.

Explanation:

You are very much welcom

Answer:

stirring. because it will mixup together

Both hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you opened a container of each gas in a corner of a large room, which odor would you detect first on the other side of the room? Assume the temperature is constant.

Answers

The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

What is Effusion rate?

Effusion rate is inversely proportional to molar mass. NH3 will have a higher average molecule velocity, so it will diffuse faster and will reach the other side of the room more quickly.

The concentration gradient, or the rise or fall in concentration from one site to another, the amount of surface area available for diffusion, and the distance the gas particles must travel all affect the diffusion rate.

The effusion of gas molecules into a vacuum through a small hole, as a pinhole in a balloon, is a process that involves movement of gaseous species comparable to diffusion.

Therefore, The molar mass of H2S is greater than the molar mass of NH3, making the velocity and effusion rate of NH3 particles faster.

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Answer the following questions in brief.
Why does silver get tarnished on exposure to air?​

Answers

Answer: When silver is exposed to sulfur-containing gases in the air, it discolours and then darkens as it reacts with the gas to form a surface layer of tarnish. This process is called tarnishing.

Hope this helped :)

At a fixed volume, a four-fold increase in the temperature of a gas will lead to _______ in pressure.

Answers

Answer:

Increase in pressure

Explanation:

The rise in temperature will increase the pressure of the gas.

Answer:

increase is ur answer

hope it helps u

plz mark as brainlist

Identify the following salts as neutral, acidic, or basic. Drag each item to the appropriate bin.
1. LiF
2. SrBr2
3. NH4CN
4. NH4Br
5. KCN
6. NH4ClO4
7. LiNO3
A. Neutral salts.
B. Acidic salts.
C. Basic salts.

Answers

Answer:

A. Neutral salts.  (7, 2)

B. Acidic salts.  (4, 6)

C. Basic salts. (1, 3, 5)

Explanation:

We must know where, do the ions come from. If they come from a weak acid or base, they can make hydrolysis in water, so OH⁻ and H⁺ are given to medium.

1. LiF → Li⁺ + F⁻

F⁻  +  H₂O  ⇄  HF + OH⁻

F⁻ can make the hydrolysis, and it gives OH⁻. Salt is basic.

2. SrBr₂ → Sr²⁺  + 2Br⁻

Both are weak and they can not hydrolyse. This salt is neutral.

3. NH₄CN →  NH₄⁺  + CN⁻

Both ions are strong, so they can make the hydrolysis. The thing is, while the ammonium gives protons, the cyanide give hydroxides. To determine how's the salt, we need to compare the Ka and Kb.

NH₄⁺  +  H₂O ⇄  NH₃  +  H₃O⁺   Ka = 5.7×10⁻¹⁰

CN⁻  + H₂O ⇄  HCN  +  OH⁻     Kb = 1.61×10⁻⁵

As  Kb > Ka, pH is basic.

If Ka > Kb, pH would be acidic.

4. NH₄Br →  NH₄  + Br⁻

Br⁻ does not hydrolize. The ammonium cation, reacts in water to give protons to medium that's why the salt will be acidic.

NH₄⁺  +  H₂O ⇄  NH₃  +  H₃O⁺   Ka

5.  KCN →  K⁺  + CN⁻

K⁺ does not hydrolize. The cyanide anion, reacts in water to give hydroxides to medium that's why the salt will be basic.

CN⁻  + H₂O ⇄  HCN  +  OH⁻     Kb

6. NH₄ClO₄ →  NH₄⁺  + ClO₄⁻

ClO₄⁻ comes from the perchlroric acid (a strong acid). It does not hydrolyze

NH₄⁺  +  H₂O ⇄  NH₃  +  H₃O⁺   Ka

Ammonium gives H⁺ to medium so the salt is acidic.

7. LiNO₃ → Li⁺  + NO₃⁻

Both ions does not make hydrolysis. They come from a strong base and a strong acid, so they are the conjugate weak acid and base, respectively.

The salt in this case, will be neutral.

A 500.0-mL buffer solution is 0.10 M in benzoic acid and 0.10 M in sodium benzoate and has an initial pH of 4.19. What is the pH of the buffer upon addition of 0.010 mol of NaOH?

Answers

Answer:

pH after the addition of NaOH is 4.37

Explanation:

When the amount of the weak acid = Amount of the conjugate base (As in the problem) pH = pKa. That means pKa of benzoic buffer is 4.19.

Now, to solve the pH of the buffer we need to use H-H equation for benzoic buffer:

pH = pKa + log [Benzoate] / [Benzoic acid]

pH = 4.19+ log [Benzoate] / [Benzoic acid]

You can take [] concentrations as the moles of both species.

When you add NaOH to the buffer, it reacts with benzoic acid producing more sodium benzoate and water, thus:

NaOH + Benzoic Acid → Sodium benzoate + Water.

Before the reaction, moles of benzoic acid and sodium benzoate were:

500.0mL = 0.500L × (0.10mol / L) = 0.050 moles

After the reaction, 0.010 moles of Benzoic acid are consumed and the same 0.010 moles of sodium benzoate are produced. That means moles of both species after reaction are:

[Benzoate] = 0.050 moles + 0.010 moles = 0.060 moles

[Benzoic acid] = 0.050 moles - 0.010 moles = 0.040 moles

Replacing in H-H equation:

pH = 4.19+ log [Benzoate] / [Benzoic acid]

pH = 4.19+ log [0.060mol] / [0.040mol]

pH = 4.37

pH after the addition of NaOH is 4.37

What is the partial pressure of nitrogen in a container that contains 3.96mol of oxygen, 7.49 mol of nitrogen and 1.19 mol of carbon dioxide when the total pressure is 563 mmHg?

Answers

Answer:

333.6 atm

Explanation:

The following data were obtained from the question:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Next, we shall determine the total number of mole in the container.

This can be obtained as follow:

Mole of O2 (nO2) = 3.96 moles

Mole of N2 (nN2) = 7.49 moles

Mole of CO2 (nCO2) = 1.19 moles

Total mole =?

Total mole = nO2 + nN2 + nCO2

Total mole = 3.96 + 7.49 + 1.19

Total mole = 12.64 moles

Next, we shall determine the mole fraction of N2.

This can be obtained as follow:

Mole fraction = mole of substance/total mole

Mole of N2 (nN2) = 7.49 moles

Total mole = 12.64 moles

Mole fraction of N2 =?

Mole fraction of N2 = 7.49/12.64

Finally, we shall determine the partial pressure of N2.

This can be obtained as follow:

Mole fraction of N2 = 7.49/12.64

Total pressure = 563 mmHg

Partial pressure of N2 =..?

Partial pressure = mole fraction x total pressure

Partial pressure of N2 = 7.49/12.64 x 563

Partial pressure of N2 = 333.6 atm

The, the partial pressure of nitrogen, N2 is 333.6 atm

5.195 kg + 10.95 kg + 73.2 kg

Answers

Answer: 89.345

Explanation:

What are three ways that a solid, liquid, gas and plasma are different?

Answers

Answer:

like, plasmas have no fixed shape or volume, and are less dense then solid or liquids but unlike ordinary gases, plasma are made up of atoms in which some or all of the electrons have been stripped away and positively charged nuclei, called ions, roem freely

A sample of serum of mass 25 g is cooled from 290 K to 275 K at constant pressure by the extraction of 1.2 kJ of energy as heat. Calcuate q and ∆H and estimate the heat capacity of the sample.

Answers

The answer would be 483/9

The numbers of nucleons required to generate complete shells in the nucleus are called:
A. nuclear numbers
B. shell numbers
C. special numbers
D. magic numbers

Answers

Answer:

The correct answer is option D, that is, magic numbers.

Explanation:

The magic number in nuclear physics refers to the number of nucleons, that is, either neutrons or protons, distinctly, such that their alignment results in the formation of complete shells within the nucleus of the atom. As a consequence, atomic nuclei comprising a magic number of neutrons or protons are much more stable in comparison to other nuclei.  

The seven most broadly known magic numbers are 2,8,20,28,50,85 and 126.  


What is the diameter of the coin to the nearest
millimeter?
36 mm
37 mm
38 mm
39 mm

Answers

Answer:

Explanation:

Diameter in the coin is the distance from side to side.

The numbers in the ruler are showing the centimeters. Each line is a subdivision in ten parts between centimeter and centimeter (Each line is equal to 1mm).

As you can see in the ruler, in the edge of the coin, the ruler is showing 3.8cm

As 1cm = 10mm:

3.8cm * (10mm / 1cm) =

38mm is the diameter of the coin to the nearest milimeter

Answer:

38m

Explanation:

Of the following, which is the dominant (strongest) type of intermolecular force present in RbCl(s)?
A. lon-dipole
B. lonic
C. Dispersion
D. Dipole-dipole
E. Hydrogen bonding

Answers

Answer:

B. Ionic

Explanation:

RbCl is ionic compound formed from the combination of rubidium (a strongly electropositive element) and chlorine (a strongly electronegative element).

The transfer of an electron from rubidium to chlorine leads to the formation of two oppositely charged ions Rb⁺ and Cl⁻.

In a solid crystal of RbCl, the major intermolecular forces of attraction are electrostatic forces of attraction between oppositely charged ions in the molecules of the crystalline solid.

Ion-dipole attraction only occur when the solid is dissolved in a polar molecule like water. Dispersion forces as well as dipole-dipole forces, though present are weak forces and contribute very little to intermolecular attraction. Hydrogen bonding is not present as there are no hydrogen atoms in solid RbCl.

The dominant (strongest) type of intermolecular force present in RbCl(s) is ionic force (Option B).

An ion-dipole attraction refers to a type of attraction between ions and neutral dipole molecules.

Ionic forces are commonly observed in different types of chemical solutions.

An ion-dipole force consists of a positive/negative ion that exerts an attractive force to the negative/positive end present in a polar molecule.

In conclusion, the dominant (strongest) type of intermolecular force present in RbCl(s) is ionic force (Option B).

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