On average, Colby has noticed that 21 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probability that at most 6 trains will pass his house in a 12-hour time period

Answers

Answer 1

Answer:

10.16% probability that at most 6 trains will pass his house in a 12-hour time period

Step-by-step explanation:

We are dealing with the mean during a period of time, so we use the Poisson distribution to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

Colby has noticed that 21 trains pass by his house daily (24 hours)

We are working with 12 hour periods(half of 24), so [tex]\mu = \frac{21}{2} = 10.5[/tex]

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

What is the probability that at most 6 trains will pass his house in a 12-hour time period

[tex]P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)[/tex]

So

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-10.5}*(10.5)^{0}}{(0)!} = 0[/tex]

[tex]P(X = 1) = \frac{e^{-10.5}*(10.5)^{1}}{(1)!} = 0.0003[/tex]

[tex]P(X = 2) = \frac{e^{-10.5}*(10.5)^{2}}{(2)!} = 0.0015[/tex]

[tex]P(X = 3) = \frac{e^{-10.5}*(10.5)^{3}}{(3)!} = 0.0053[/tex]

[tex]P(X = 4) = \frac{e^{-10.5}*(10.5)^{4}}{(4)!} = 0.0139[/tex]

[tex]P(X = 5) = \frac{e^{-10.5}*(10.5)^{5}}{(5)!} = 0.0293[/tex]

[tex]P(X = 6) = \frac{e^{-10.5}*(10.5)^{6}}{(6)!} = 0.0513[/tex]

[tex]P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0 + 0.0003 + 0.0015 + 0.0053 + 0.0139 + 0.0293 + 0.0513 = 0.1016[/tex]

10.16% probability that at most 6 trains will pass his house in a 12-hour time period


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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answer:

Since the equation can be written in the form  

y

=

k

x

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y

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x

and  

k

. The constant of variation,  

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Statement 1: True

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Statement 2: False

Interval 2 goes up to the right. That is an increasing function, not a constant functions.

Statement 3: False

The graph increases in interval 2 but decreases in interval 4.

Statement 4: False

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Statement 5: True

Interval 3 is horizontal, so it is constant.

Answer:

Statements 1 and 5 are true. All others are false.

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

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