On a particular stretch of highway, the State Police know that the average speed is 62 mph with a standard deviation of 5 mph. On a busy holiday weekend, the police are concerned that people travel too fast. So they randomly monitor speeds of a sample of 50 cars and record an average speed of 66 mph. Use central limit theorem to calculate

Answers

Answer 1

Using the normal distribution and the central limit theorem, it is found that there is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

It measures how many standard deviations the measure is from the mean.  After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X. By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem:

Mean of 62 mph, hence [tex]\mu = 62[/tex].Standard deviation of 5 mph, hence [tex]\sigma = 5[/tex].Sample of 50 cards, hence [tex]n = 50, s = \frac{5}{\sqrt{50}} = 0.7071[/tex]

The probability of a sample of 50 cars recording an average speed of 66 mph or higher is 1 subtracted by the p-value of Z when X = 66, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{66 - 62}{0.7071}[/tex]

[tex]Z = 5.66[/tex]

[tex]Z = 5.66[/tex] has a p-value of 1.

1 - 1 = 0.

There is a 0% probability of a sample of 50 cars recording an average speed of 66 mph or higher.

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Step-by-step explanation:

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It looks like the given differential equation is

(3x² + y²) y + (y² - x²) x dy/dx = 0

Multiply both sides by 1/x³ to get

(3 + y²/x²) y/x + (y²/x² - 1) dy/dx = 0

(Note that in order to do this, we must have x ≠ 0, which means that if a solution exists, it would have to be on either (-∞, 0) or (0, ∞).)

Now substitute z = y/x, or y = xz, from which we get dy/dx = x dz/dx + z. Making this replacement and simplifying yields a separable equation:

(3 + z²) z + (z² - 1) (x dz/dx + z) = 0

(3 + z²) z + (z² - 1) x dz/dx + (z² - 1) z = 0

(z² - 1) x dz/dx = -(2z³ + 2z)

x dz/dx = (2z³ + 2z)/(1 - z²)

(1 - z²)/(2z (z² + 1)) dz = dx/x

Integrate both sides. On the left, split up the expression into partial fractions.

[tex]\dfrac{1-z^2}{z(z^2+1)} = \dfrac az + \dfrac{bz+c}{z^2+1}[/tex]

[tex]\dfrac{1-z^2}{z(z^2+1)} = \dfrac{a(z^2+1)+(bz+c)z}{z(z^2+1)}[/tex]

[tex]1-z^2 = (a+b)z^2 + cz + a[/tex]

for which we find a = 1, b = -2, and c = 0:

[tex]\dfrac{1-z^2}{2z(z^2+1)} = \dfrac12 \left( \dfrac1z - \dfrac{2z}{z^2+1} \right)[/tex]

Integrating and simplifying yields

1/2 ∫ (1/z - 2z/(z² + 1)) dz = ∫ dx/x

1/2 (ln|z| - ln(z² + 1)) = ln|x| + C

1/2 ln|z / (z² + 1)| = ln|x| + C

ln(√(z/(z² + 1))) = ln|x| + C

exp[ln(√(z/(z² + 1)))] = exp[ln|x| + C]

√(z/(z² + 1)) = exp[ln|x|] exp[C]

√(z/(z² + 1)) = Cx

z/(z² + 1) = Cx²

Replacing z = y/x then gives us an implicit solution of

(y/x) / (y²/x² + 1) = Cx²

xy / (y² + x²) = Cx²

y / (y² + x²) = Cx

y = Cx (y² + x²)

Cxy² - y + Cx³ = 0

though we can solve for y explicitly (assuming x > 0) using the quadratic formula to end up with

y = (1 + √(1 - Cx⁴))/(Cx)

(the other solution only differs by the sign on the square root)

2. What is the largest composite number less than 40?

Answers

Answer:

39

Step-by-step explanation:

39

Step-by-step explanation:

13 × 3 = 39

The largest composite number less than 40 is 39

Please take a look at the picture

Answers

Answer:

A) -3/-11

Step-by-step explanation:

-3/-11-3/11

-3/-11

Reduce the fraction with -1.

3/11

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

If a submarine dives 378 feet in 14 seconds, the average change in elevation is feet per second.

Answers

Answer:

27 feet per second.

Step-by-step explanation:

You already have your time unit in second and length measurement in feet so just divide the two 378/14=27 feet per second.

Answer:

-27 feet per second

Step-by-step explanation:

378 ÷ 14 = 27

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Answers

Answer:

3/4x - 5 = x

= -3/10 -> -0.15

2 Decimal places = 0.150

Quick Computing installed its previous generation of computer chip manufacturing equipment 3 years ago. Some of that older equipment will become unnecessary when the company goes into production of its new product. The obsolete equipment, which originally cost $40 million, has been depreciated straight-line over an assumed tax life of 5 years, but it can be sold now for $18 million. The firm’s tax rate is 35%. What is the after-tax cash flow from the sale of the equipment?

Answers

The company's after-tax cash flow is a measure of the company's cash

generation ability.

The after-tax cash flow from the sale of the equipment is $16.1 million

Reasons:

The given parameter are;

Original cost of the equipment = $40 million

The type of depreciation = Straight line depreciation

Number of years of depreciation = 5 years

Current price at which it can be sold = $18 million

The tax rate of the firm = 35%

Required:

The after-tax cash flow from the sale of the equipment.

Solution:

The Cash Flow After Tax, CFAT, is given as follows;

CFAT = Net income + Amortization  + Depreciation  + Other non-Cash Cash Charges

The annual depreciation is given as follows;

[tex]Annual \ depreciation = \dfrac{\$40 \ million - \$18 \ million}{5 \ years} = \$4.4 \ million \ per \ year[/tex]

Selling the equipment gives;

The Earnings Before Tax (EBT) = $18 million

The Net Income = Income - Tax = $18 million - (35% × $18 million)

The Net Income = $11.7 million

Cash Flow After Tax CFAT = Net income + Depreciation

∴ CFAT = $11.7 million + $4.4 million = $16.1 million

The after-tax cash flow = $16.1 million

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

Mixed number: 5 1/10 and improper fraction: 52/10

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Answers

5*-3=-15

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Answer:

x = -15

Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

the slope for y = -9x + 15

Slope: -9

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Answer:

-9

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Step-by-step explanation:

y = mx + c

y = -9x + 15

so m = -9

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Answers

#5

Mohan read =2/5Sohan read=2/7

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Mohan read more pages.

#6

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

Angle B: 180-135=45° - supplementary angle rule

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Step-by-step explanation:

Elli left home8:30 and returned at 1:25how long was she away from home?














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3 hours and 45 minutes assuming its from am to pm

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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it's the graph c

Step-by-step explanation:

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Answer:

44

Step-by-step explanation:

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Hey there!

4x^2 - 8x + 8

= 4(-6)^2 - 8(-6) + 8

= 4(6)(6) - 8(-6) + 8

= 4(36) - (-48) + 8

= 144 - (-48) + 8

= 144 + 48 + 8

= 192 + 8

= 200

Therefore, your answer is: 200

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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Answer:

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Step-by-step explanation:

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The statement is true: the area under the graph line made with the x-axis

represents the change in position of the object on a velocity versus time

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Answer: True

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On the first three tests, Jhon scored 72 points. On the next test, he got a higher score. On the
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What were his grades on the second and third tests?

Answers

Answer:

Second test=88

Third test=89    Hope this helps please mark brainliest it helps a lot! Thanks!

Step-by-step explanation:

According to the question, here we got to know that John scored 72 points in the first test

In the second he scored higher than the 1st test

In the third he scored 1 mark more than the second test

His average in the three tests was 83

So,

Let's the marks scored in the 2nd test be x

Hence, in the third test he got x + 1

Average is 83

[tex] \frak{Average = \frac{{1}^{st} \: test + {2}^{nd} \: test + {3}^{rd} \: test }{3} } \\ \\ \dashrightarrow \frak{83 = \frac{72 + x + x + 1}{3}} \\ \\ \dashrightarrow \frak{83 = \frac{73 + 2x}{3}} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{249 - 73 = 2x} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{x = \frac{176}{2} } \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \dashrightarrow \frak{249 - 73 = 2x} \\ \\ \dashrightarrow \frak{249 = 73 + 2x } \\ \\ \star \qquad \boxed{ \green{\frak{x = 88}}} \\ \\ \sf{ \underline{{2}^{nd} \: test }} : \\ \\ \boxed{ \red{88}} \\ \\ \sf{ \underline{{3}^{rd} \: test }} : \\ \\ \rightarrow x + 1 \\ \\ \rightarrow 88 + 1 \\ \\ \boxed{ \red{ 89 }}[/tex]

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